Automatically Change Date Weekly (php) - php

Is it possible to update a date every week automatically with php?
For instance, I have a weekly forecast that is updated every Monday. The title would read something like "Forecast for Friday June 28th."
<h1>- Forecast for Friday June 28th -</h1>
Then on the following monday, I would like to automatically update the date in the title to the next occurring Friday.
is this possible with php?

This is what you're looking for:
switch (date('N'))
{
case 5:
$time = time();
break;
case 6:
case 7:
$time = strtotime('last Friday');
break;
default:
$time = strtotime('next Friday');
}
echo date('l F jS', $time);
Check the date function for different formatting options.
Although are you sure you want to wait until Monday until showing the forecast for the next Friday? Surely it should update to the following week on the Saturday (otherwise you'll be forecasting a past date)? If so, just remove the case 6/case 7 section.

Yes. Take a look at date() for formatting and strtotime() to quickly create relative timestamps:
The following should get you started:
echo date('l F jS', strtotime('monday'));
Note: If you're using PHP > 5.3 you should look at the DateTime class.

It's very simple coded to explain as much simple as possible. The script calculates how many days left until next Friday, if $today is not Friday.
Hope that helps you!
<?php
$now = time(); // current timestamp
$today = date("w", $now); // "w" returns the weekday (number)
$friday = 5; // 5th day of the week (sunday = 0)
if ($today == $friday) {
$ts = $now; // today is friday, don't change the timestamp
$daysLeft = 0; // no days left!
} else {
if ($today == 6) {
$daysLeft = 6; // saturday is bigger then friday
} else {
$daysLeft = $friday-$today; // get the left days
}
$ts = $now + 84600 * $daysLeft; // now + seconds of one day * days left
}
?>
<h1>
- Forecast for <?php echo date("D M d", $ts) ?>-
</h1>

$currDay = date('w');
$delta = $currDay==6 ? 6 : 5-$currDay;
$date = new DateTime();
$date->add(new DateInterval('P'.$delta.'D'));
echo $date->format('D M jS');

Related

How to perform if statement for a certain timeperiod

I want to perform certain tasks in PHP between Monday 10:00am till Saturday 10:00am and I want to perform other tasks between Saturday 10:30am till Monday 10am. Every week.
I am sorry if that's a silly question. Any help would be highly appreciated.
if you are running a time triggered task run a cron job or if it is a user triggered like website and you want to change page according to day then use if else statement to select task.
you can get the time in weekday and hour:minute::second for if else selection using this
$d = new DateTime('Sunday,23:23:48 '); //set time day time format
echo $d->format('l , H:i:s ');
$date = new DateTime(); // get current datetime
echo $date->format('l , H:i:s '); //php get time in day time format
//output example Sunday , 23:23:48 Sunday , 23:34:47
$currentTime = time();
$time = date('H:i',$currentTime);
$date = date('h:i:s a', time());
$timestamp = strtotime($date);
$day = date('D', $timestamp);
if ( ( ($day == "Sat") && ($time < 11) ) || ($day == "Mon" && $time > 9) )
{
# weekday then truncate table
}

PHP: Week starts on Monday, but "monday this week" on a Sunday gets Monday next week

Here's a summary of the issue: On Sundays, strtotime('this week') returns the start of next week.
In PHP, the week seems to start on Monday. But, on any day except Sunday, this code
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
Outputs the date of this week's Monday, when it seems like it should be outputting last weeks Monday. It seems like, in this case, PHP is treating both Sunday and Monday as the the start of the week. It's now Monday, Dec 10, 2012, or 2012-12-10. date('Y-m-d', strtotime('sunday last week')) returns 2012-12-09 - yesterday.
Is this a bug, or am I missing something? It seems like a bug this obvious should be fairly well known, but I can't find anything about it. Is the only way to get the start of the week to use some special handling for Sundays?
$week_offset = (int) 'sunday' == date('l');
$week_start = strtotime("-$week_offset monday"); // 1 or 0 Mondays ago
As far as I can tell, this is a bug. I see no logical reason why strtotime('this week'); should return a future date. This is a pretty major bug. In my particular case, I had a leaderboard that showed the users with the most points since the beginning of the week. But on Sundays, it was empty because strtotime returned a timestamp for a future date. I was doubtful, because just I don't know how this could have gone unnoticed, but I couldn't find any other reports of this bug.
Thanks for all your time and help, folks.
This answer is late, but it's something that I've been struggling with. Every solution I've tried so far has malfunctioned for one reason or another. This is what I ended up with that worked for me. (though it may be look pretty, it at least works).
$thisMonday = strtotime('next Monday -1 week', strtotime('this sunday'));
Here is how you can get Monday of current week:
echo date("Y-m-d", strtotime(date('o-\\WW')));
It's not ideal but this is what I resorted to using:
if(date('N') == 7) {
$date = date('Y-m-d',strtotime('monday last week'));
} else {
$date = date('Y-m-d',strtotime('monday this week'));
}
I think the only problem with your coding is TimeZone.
Solution:
Set your own time Zone. Here is the example of my own time zone:
Example
date_default_timezone_set('Asia/Kolkata');
Set the above line before calling any time function.
Have a nice day.
I think instead of trying
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
you should try
echo date('Y-m-d', strtotime('monday last week'));
Try this code
// set current date
$date = date("m/d/Y");
$ts = strtotime($date); // also $ts = time();
// find the year and the current week
$year = date('o', $ts);
$week = date('W', $ts);
// print week for the current date
$i = 1; // 1 denotes the first day of week
$ts = strtotime($year.'W'.$week.$i);
echo $day = date("l", $ts); // generate the name of day
echo "<br>";
echo $day = date("Y-m-d", $ts); // generate the date
You will get the the date of current week, whether you are on monday you will get the date of that monday.
If you want the most recent monday:
function mostRecentMonday(){
if(date("w") == 1){
return strtotime("midnight today");
} else {
return strtotime("last monday");
}
}
Easy to modify to use DateTime, or, to even specify a different date to use as the base.
Based on Bryant answer :
$first_week_date = date('d F Y', strtotime('next Monday -1 week', strtotime('this sunday')));
$last_week_date = date('d F Y', strtotime('next Monday -1 week + 6 days', strtotime('this sunday')));
This is for thos looking for a friendly solution that works with any day.
function getWeekStart($week_start_day = "Monday") {
$week_days = array("Sunday"=>0,"Monday"=>1,"Tuesday"=>2,"Wednesday"=>3,"Thursday"=>4,"Friday"=>5,"Saturday"=>6,);
if(!isset($week_days[$week_start_day])) {
return false;
} else {
$start_day = $week_days[$week_start_day];
$today = date("w");
$one_day = (60 * 60 * 24);
if($today < $start_day) {
$days_difference = 7 - ($start_day - $today);
} else {
$days_difference = ($today - $start_day);
}
$week_starts = strtotime(date("Y-m-d 00:00:00")) - ($one_day * $days_difference);
return $week_starts;
}
}
//Test: If today is Monday, it will return today's date
echo date("Y-m-d H:i:s", getWeekStart("Monday"));

Getting first / last date of the week

Is it possible to get the first / last date of a week using PHP's Relative Date Time format?
I've tried to do:
date_default_timezone_set('Europe/Amsterdam');
$date = new DateTime();
$date->modify('first day of this week'); // to get the current week's first date
echo $date->format('Y-m-d'); // outputs 2011-12-19
$date->modify('first day of week 50'); // to get the first date of any week by weeknumber
echo $date->format('Y-m-d'); // outputs 2011-12-18
$date->modify('last day of this week'); // to get the current week's last date
echo $date->format('Y-m-d'); // outputs 2011-12-17
$date->modify('last day of week 50'); // to get the last date of any week by weeknumber
echo $date->format('Y-m-d'); // outputs 2011-12-18
As you can see it doesn't output the correct dates.
According to the docs this should be possible if I'm correct.
Am I doing something terrible wrong?
EDIT
I need to use PHP's DateTime for dates in the far future.
UPDATE
It gets only stranger now. I've done some more testing.
Windows PHP 5.3.3
2011-12-01
Warning: DateTime::modify() [datetime.modify]: Failed to parse time string (first day of week 50) at position 13 (w): The timezone could not be found in the database in C:\Users\Gerrie\Desktop\ph\Websites\Charts\www.charts.com\public\index.php on line 9
2011-12-01
2011-11-30
Warning: DateTime::modify() [datetime.modify]: Failed to parse time string (last day of week 50) at position 12 (w): The timezone could not be found in the database in C:\Users\Gerrie\Desktop\ph\Websites\Charts\www.charts.com\public\index.php on line 15
2011-11-30
Linux 5.3.8
2011-12-01
2011-12-01
2011-11-30
2011-11-30
I'm a big fan of using the Carbon library, which makes this sort of thing really easy. For example:
use Carbon\Carbon;
$monday = Carbon::now()->startOfWeek()
$sunday = Carbon::now()->endOfWeek()
Or, if you'd prefer to have Sunday be the first day of your week:
use Carbon\Carbon;
Carbon::setWeekStartsAt(Carbon::SUNDAY);
Carbon::setWeekEndsAt(Carbon::SATURDAY);
$sunday = Carbon::now()->startOfWeek()
$saturday = Carbon::now()->endOfWeek()
According to docs the format strings "first day of" and "last day of" are only allowed for months, not for weeks. See http://www.php.net/manual/en/datetime.formats.relative.php
If you combine first and last day of with a week statement the result either blows the parser or is something that you did not expect (usually the first or last day of a month, not a week).
The difference that you see between Win and Linux is probably only because of different error reporting settings.
To get the first and last day of the current week use:
$date->modify('this week');
$date->modify('this week +6 days');
To get the first and last day of week 50 use:
$date->setISODate(2011, 50);
$date->setISODate(2011, 50, 7);
EDIT:
If you want to use the modify method for absolute week numbers you have to use the formats defined in http://www.php.net/manual/en/datetime.formats.compound.php:
$date->modify('2011W50');
$date->modify('2011W50 +6 days');
if first day of week is Monday
$date->modify('Monday this week');
else if first day is Sunday
$date->modify('Sunday this week');
because in different countries first day of week maybe Monday or Sunday
This is what I am using to get the first and last day of the week from any date.
In this case, monday is the first day of the week...
$date = date('Y-m-d'); // you can put any date you want
$nbDay = date('N', strtotime($date));
$monday = new DateTime($date);
$sunday = new DateTime($date);
$monday->modify('-'.($nbDay-1).' days');
$sunday->modify('+'.(7-$nbDay).' days');
function getweek_first_last_date($date)
{
$cur_date = strtotime($date); // Change to whatever date you need
// Get the day of the week: Sunday = 0 to Saturday = 6
$dotw = date('w', $cur_date);
if($dotw>1)
{
$pre_monday = $cur_date-(($dotw-1)*24*60*60);
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==1)
{
$pre_monday = $cur_date;
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==0)
{
$pre_monday =$cur_date -(6*24*60*60);;
$next_sunday = $cur_date;
}
$date_array = array();
$date_array['start_date_of_week'] = $pre_monday;
$date_array['end_date_of_week'] = $next_sunday;
return $date_array;
}
$date = '2013-12-22';
getweek_first_last_date($date);
Output :
$array_of_week = Array
(
[start_date_of_week] => 1387152000
[end_date_of_week] => 1387670400
)
$start_date =date('d/m/Y', $array_of_week['start_date_of_week'])
<code>
function getlastweek_first_last_date()
{
$cur_date = strtotime(date('Y-m-d')); // Change to whatever date you need
// Get the day of the week: Sunday = 0 to Saturday = 6
$previousweekcurdate = $cur_date - (7*24*3600);
$cur_date = $previousweekcurdate;
$dotw = date('w', $cur_date);
if($dotw>1)
{
$pre_sunday = $cur_date-(($dotw-1)*24*60*60) - (24*60*60);
$next_satday = $cur_date+((7-$dotw)*24*60*60)- (24*60*60);
}
else if($dotw==1)
{
$pre_sunday = $cur_date- (24*60*60);
$next_satday = $cur_date+((7-$dotw)*24*60*60)- (24*60*60);
}
else if($dotw==0)
{
$pre_sunday =$cur_date -(6*24*60*60)- (24*60*60);
$next_satday = $cur_date- (24*60*60);
}
$pre_sunday = date('Y-m-d',$pre_sunday)." 00:00:00";
$next_satday = date('Y-m-d',$next_satday)." 23:59:59";
$date_array = array();
$date_array['sdoflw'] = $pre_sunday;
$date_array['edoflw'] = $next_satday;
return $date_array;
}
$date_array = getlastweek_first_last_date();
echo $start_date_of_week = $date_array['sdoflw'];
echo $end_date_of_week = $date_array['edoflw'];
</code>
Simply you can get the date as follows
first day of week is Monday
date('Y-m-d',strtotime('Monday this week'));
if first day is Sunday
date('Y-m-d',strtotime('Sunday this week'));

PHP Check Particular Day

I need to change shipping day to next Tuesday if the day is Friday.Here is my code.
$tomorrow = mktime(0,0,0,date("m"),date("d")+$tt+1,date("Y"));
$duedate = date("d - M D", $tomorrow);
$str = substr($duedate, 9, 11);
$fri='Fri';
$sat='Sat';
if(strcmp($str,$fri)==0)
{
$tomorrow = mktime(0,0,0,date("m"),date("d")+4,date("Y"));
$duedate = date("d - M D", $tomorrow);
}
But i think the if loop is not checking friday correctly.So adding 4 to $tommorrow is also not working.Any pointers?
This should be enough:
if (date('N') == 5) {
//set duedate to next Tuesday
$DateTime = new DateTime('now');
$DateTime->add(new DateInterval('P4D')); //add 4 days
$dueDate = $DateTime->format('your format');
}
N gives back an ISO standardized number which is 5 for friday. Date needs no second argument, in that case it takes the current timestamp.
See http://www.php.net/manual/en/book.datetime.php for more information on DateTime.
$tomorrow = mktime(0,0,0,date("m"),date("d")+$tt+1,date("Y"));
$duedate = date("d - M D", $tomorrow);
if (date("N", $tomorrow) == 5) {
$tomorrow = mktime(0,0,0,date("m"),date("d")+4,date("Y"));
$duedate = date("d - M D", $tomorrow);
}
Firstly try extracting the day just using the date function, for example:
date('D'); // Mon through Sun
or
date('N'); // 1 (for Monday) through 7 (for Sunday)
Secondly use the strtotime function to add days to a date, for example:
strtotime("+4 day",$date); // Add 4 days to date
$nextTuesday = strtotime('next tuesday');

increment date by one month

Let's say I have a date in the following format: 2010-12-11 (year-mon-day)
With PHP, I want to increment the date by one month, and I want the year to be automatically incremented, if necessary (i.e. incrementing from December 2012 to January 2013).
Regards.
$time = strtotime("2010.12.11");
$final = date("Y-m-d", strtotime("+1 month", $time));
// Finally you will have the date you're looking for.
I needed similar functionality, except for a monthly cycle (plus months, minus 1 day). After searching S.O. for a while, I was able to craft this plug-n-play solution:
function add_months($months, DateTime $dateObject)
{
$next = new DateTime($dateObject->format('Y-m-d'));
$next->modify('last day of +'.$months.' month');
if($dateObject->format('d') > $next->format('d')) {
return $dateObject->diff($next);
} else {
return new DateInterval('P'.$months.'M');
}
}
function endCycle($d1, $months)
{
$date = new DateTime($d1);
// call second function to add the months
$newDate = $date->add(add_months($months, $date));
// goes back 1 day from date, remove if you want same day of month
$newDate->sub(new DateInterval('P1D'));
//formats final date to Y-m-d form
$dateReturned = $newDate->format('Y-m-d');
return $dateReturned;
}
Example:
$startDate = '2014-06-03'; // select date in Y-m-d format
$nMonths = 1; // choose how many months you want to move ahead
$final = endCycle($startDate, $nMonths); // output: 2014-07-02
Use DateTime::add.
$start = new DateTime("2010-12-11", new DateTimeZone("UTC"));
$month_later = clone $start;
$month_later->add(new DateInterval("P1M"));
I used clone because add modifies the original object, which might not be desired.
strtotime( "+1 month", strtotime( $time ) );
this returns a timestamp that can be used with the date function
You can use DateTime::modify like this :
$date = new DateTime('2010-12-11');
$date->modify('+1 month');
See documentations :
https://php.net/manual/en/datetime.modify.php
https://php.net/manual/en/class.datetime.php
UPDATE january 2021 : correct mistakes raised by comments
This solution has some problems for months with 31 days like May etc.
Exemple : this jumps from 31st May to 1st July which is incorrect.
To correct that, you can create this custom function
function addMonths($date,$months){
$init=clone $date;
$modifier=$months.' months';
$back_modifier =-$months.' months';
$date->modify($modifier);
$back_to_init= clone $date;
$back_to_init->modify($back_modifier);
while($init->format('m')!=$back_to_init->format('m')){
$date->modify('-1 day') ;
$back_to_init= clone $date;
$back_to_init->modify($back_modifier);
}
}
Then you can use it like that :
$date = new DateTime('2010-05-31');
addMonths($date, 1);
print_r($date);
//DateTime Object ( [date] => 2010-06-30 00:00:00.000000 [timezone_type] => 3 [timezone] => Europe/Berlin )
This solution was found in PHP.net posted by jenspj : https://www.php.net/manual/fr/datetime.modify.php#107592
(date('d') > 28) ? date("mdY", strtotime("last day of next month")) : date("mdY", strtotime("+1 month"));
This will compensate for February and the other 31 day months. You could of course do a lot more checking to to get more exact for 'this day next month' relative date formats (which does not work sadly, see below), and you could just as well use DateTime.
Both DateInterval('P1M') and strtotime("+1 month") are essentially blindly adding 31 days regardless of the number of days in the following month.
2010-01-31 => March 3rd
2012-01-31 => March 2nd (leap year)
Please first you set your date format as like 12-12-2012
After use this function it's work properly;
$date = date('d-m-Y',strtotime("12-12-2012 +2 Months");
Here 12-12-2012 is your date and +2 Months is increment of the month;
You also increment of Year, Date
strtotime("12-12-2012 +1 Year");
Ans is 12-12-2013
I use this way:-
$occDate='2014-01-28';
$forOdNextMonth= date('m', strtotime("+1 month", strtotime($occDate)));
//Output:- $forOdNextMonth=02
/*****************more example****************/
$occDate='2014-12-28';
$forOdNextMonth= date('m', strtotime("+1 month", strtotime($occDate)));
//Output:- $forOdNextMonth=01
//***********************wrong way**********************************//
$forOdNextMonth= date('m', strtotime("+1 month", $occDate));
//Output:- $forOdNextMonth=02; //instead of $forOdNextMonth=01;
//******************************************************************//
Just updating the answer with simple method for find the date after no of months. As the best answer marked doesn't give the correct solution.
<?php
$date = date('2020-05-31');
$current = date("m",strtotime($date));
$next = date("m",strtotime($date."+1 month"));
if($current==$next-1){
$needed = date('Y-m-d',strtotime($date." +1 month"));
}else{
$needed = date('Y-m-d', strtotime("last day of next month",strtotime($date)));
}
echo "Date after 1 month from 2020-05-31 would be : $needed";
?>
If you want to get the date of one month from now you can do it like this
echo date('Y-m-d', strtotime('1 month'));
If you want to get the date of two months from now, you can achieve that by doing this
echo date('Y-m-d', strtotime('2 month'));
And so on, that's all.
Thanks Jason, your post was very helpful. I reformatted it and added more comments to help me understand it all. In case that helps anyone, I have posted it here:
function cycle_end_date($cycle_start_date, $months) {
$cycle_start_date_object = new DateTime($cycle_start_date);
//Find the date interval that we will need to add to the start date
$date_interval = find_date_interval($months, $cycle_start_date_object);
//Add this date interval to the current date (the DateTime class handles remaining complexity like year-ends)
$cycle_end_date_object = $cycle_start_date_object->add($date_interval);
//Subtract (sub) 1 day from date
$cycle_end_date_object->sub(new DateInterval('P1D'));
//Format final date to Y-m-d
$cycle_end_date = $cycle_end_date_object->format('Y-m-d');
return $cycle_end_date;
}
//Find the date interval we need to add to start date to get end date
function find_date_interval($n_months, DateTime $cycle_start_date_object) {
//Create new datetime object identical to inputted one
$date_of_last_day_next_month = new DateTime($cycle_start_date_object->format('Y-m-d'));
//And modify it so it is the date of the last day of the next month
$date_of_last_day_next_month->modify('last day of +'.$n_months.' month');
//If the day of inputted date (e.g. 31) is greater than last day of next month (e.g. 28)
if($cycle_start_date_object->format('d') > $date_of_last_day_next_month->format('d')) {
//Return a DateInterval object equal to the number of days difference
return $cycle_start_date_object->diff($date_of_last_day_next_month);
//Otherwise the date is easy and we can just add a month to it
} else {
//Return a DateInterval object equal to a period (P) of 1 month (M)
return new DateInterval('P'.$n_months.'M');
}
}
$cycle_start_date = '2014-01-31'; // select date in Y-m-d format
$n_months = 1; // choose how many months you want to move ahead
$cycle_end_date = cycle_end_date($cycle_start_date, $n_months); // output: 2014-07-02
function dayOfWeek($date){
return DateTime::createFromFormat('Y-m-d', $date)->format('N');
}
Usage examples:
echo dayOfWeek(2016-12-22);
// "4"
echo dayOfWeek(date('Y-m-d'));
// "4"
$date = strtotime("2017-12-11");
$newDate = date("Y-m-d", strtotime("+1 month", $date));
If you want to increment by days you can also do it
$date = strtotime("2017-12-11");
$newDate = date("Y-m-d", strtotime("+5 day", $date));
For anyone looking for an answer to any date format.
echo date_create_from_format('d/m/Y', '15/04/2017')->add(new DateInterval('P1M'))->format('d/m/Y');
Just change the date format.
//ECHO MONTHS BETWEEN TWO TIMESTAMPS
$my_earliest_timestamp = 1532095200;
$my_latest_timestamp = 1554991200;
echo '<pre>';
echo "Earliest timestamp: ". date('c',$my_earliest_timestamp) ."\r\n";
echo "Latest timestamp: " .date('c',$my_latest_timestamp) ."\r\n\r\n";
echo "Month start of earliest timestamp: ". date('c',strtotime('first day of '. date('F Y',$my_earliest_timestamp))) ."\r\n";
echo "Month start of latest timestamp: " .date('c',strtotime('first day of '. date('F Y',$my_latest_timestamp))) ."\r\n\r\n";
echo "Month end of earliest timestamp: ". date('c',strtotime('last day of '. date('F Y',$my_earliest_timestamp)) + 86399) ."\r\n";
echo "Month end of latest timestamp: " .date('c',strtotime('last day of '. date('F Y',$my_latest_timestamp)) + 86399) ."\r\n\r\n";
$sMonth = strtotime('first day of '. date('F Y',$my_earliest_timestamp));
$eMonth = strtotime('last day of '. date('F Y',$my_earliest_timestamp)) + 86399;
$xMonth = strtotime('+1 month', strtotime('first day of '. date('F Y',$my_latest_timestamp)));
while ($eMonth < $xMonth) {
echo "Things from ". date('Y-m-d',$sMonth) ." to ". date('Y-m-d',$eMonth) ."\r\n\r\n";
$sMonth = $eMonth + 1; //add 1 second to bring forward last date into first second of next month.
$eMonth = strtotime('last day of '. date('F Y',$sMonth)) + 86399;
}
I find the mtkime() function works really well for this:
$start_date="2021-10-01";
$start_date_plus_a_month=date("Y-m-d", mktime(0, 0, 0, date("m",strtotime($start_date))+1, date("d",strtotime($start_date)), date("Y",strtotime($start_date))));
result: 2021-11-01
I like to subtract 1 from the 'day' to produce '2021-10-31' which can be useful if you want to display a range across 12 months, e.g. Oct 1, 2021 to Sep 30 2022
$start_date_plus_a_year=date("Y-m-d", mktime(0, 0, 0, date("m",strtotime($start_date))+12, date("d",strtotime($start_date))-1, date("Y",strtotime($start_date))));
result: 2022-09-30
The correct answer to the exact question asked is Giuseppe Canale's answer from earlier. I'm going to answer a slightly more generic question of how to increment the date by an arbitrary number of months, however.
<?php
/**
* Will return a timestamp corresponding to first day of the month that is N months into the future.
* #param int $months_later number of months into the future: 0 for current one
* #param string $today if supplied will be used as the "now" time
* #return int
*/
function rel_month_to_time($months_later, $today=null) {
if ($months_later===0) {
return is_null($today) ? time() : strtotime($today);
}
return strtotime('first day of next month', rel_month_to_time($months_later-1, $today));
}
As is many times the case, you can use recursion for these "human problems" like calendars. The above can be used to return a timestamp corresponding to "next month" -- the way we humans think of it.
<?php echo date('Y-m-d', rel_month_to_time(1, '2023-01-30'));
// 2023-02-01
As pointed by #NetVicious i corrected the code, it should work with all dates, some example:
2013-01-30 will be 2013-02-28
2013-05-15 will be 2013-05-15
2013-05-31 will be 2013-06-30
This code uses the DateTime class to create a new date object, then it adds 1 month to the date using the modify method. Next, it gets the day of the next month using the format method. If the next month's day doesn't match the original day, it modifies the date to the last day of the previous month using the modify method.
$original_date = "2013-01-30";
$original_day = date("d", strtotime($original_date));
$date = new DateTime($original_date);
$date->modify('+1 month');
$next_month_day = $date->format('d');
if ($next_month_day != $original_day) {
$date->modify('last day of previous month');
}
$new_date = $date->format('Y-m-d');
echo $new_date;
All presented solutions are not working properly.
strtotime() and DateTime::add or DateTime::modify give sometime invalid results.
Examples:
- 31.08.2019 + 1 month gives 01.10.2019 instead 30.09.2019
- 29.02.2020 + 1 year gives 01.03.2021 instead 28.02.2021
(tested on PHP 5.5, PHP 7.3)
Below is my function based on idea posted by Angelo that solves the problem:
// $time - unix time or date in any format accepted by strtotime() e.g. 2020-02-29
// $days, $months, $years - values to add
// returns new date in format 2021-02-28
function addTime($time, $days, $months, $years)
{
// Convert unix time to date format
if (is_numeric($time))
$time = date('Y-m-d', $time);
try
{
$date_time = new DateTime($time);
}
catch (Exception $e)
{
echo $e->getMessage();
exit;
}
if ($days)
$date_time->add(new DateInterval('P'.$days.'D'));
// Preserve day number
if ($months or $years)
$old_day = $date_time->format('d');
if ($months)
$date_time->add(new DateInterval('P'.$months.'M'));
if ($years)
$date_time->add(new DateInterval('P'.$years.'Y'));
// Patch for adding months or years
if ($months or $years)
{
$new_day = $date_time->format("d");
// The day is changed - set the last day of the previous month
if ($old_day != $new_day)
$date_time->sub(new DateInterval('P'.$new_day.'D'));
}
// You can chage returned format here
return $date_time->format('Y-m-d');
}
Usage examples:
echo addTime('2020-02-29', 0, 0, 1); // add 1 year (result: 2021-02-28)
echo addTime('2019-08-31', 0, 1, 0); // add 1 month (result: 2019-09-30)
echo addTime('2019-03-15', 12, 2, 1); // add 12 days, 2 months, 1 year (result: 2019-09-30)
put a date in input box then click the button get day from date in jquery
$(document).ready( function() {
$("button").click(function(){
var day = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
var a = new Date();
$(".result").text(day[a.getDay()]);
});
});
<?php
$selectdata ="select fromd,tod from register where username='$username'";
$q=mysqli_query($conm,$selectdata);
$row=mysqli_fetch_array($q);
$startdate=$row['fromd'];
$stdate=date('Y', strtotime($startdate));
$endate=$row['tod'];
$enddate=date('Y', strtotime($endate));
$years = range ($stdate,$enddate);
echo '<select name="years" class="form-control">';
echo '<option>SELECT</option>';
foreach($years as $year)
{ echo '<option value="'.$year.'"> '.$year.' </option>'; }
echo '</select>'; ?>

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