I need to be able to find the number of minutes passed in the current month so far. So from midnight of the first of the month until now.
How could I do this? So for example, 1AM on the first of the month would be give me 60 minutes.
Thanks
This should work for you:
$time = time();
$minutes = ($time-strtotime(date('Y-m-00', $time)))/60;
As of now $minutes === 15477.1
$seconds = time() - strtotime('2011-01-01 00:00:00');
$minutes = $seconds / 60;
To elaborate a bit more:
This is some simple manipulation of a unix timestamp (number of seconds since Jan 1, 1970). So you take the current timestamp and subtract what the timestamp would have been on the first of the month. This gives you total seconds that have elapsed this month. If you divide by 60, you get total minutes that have elapsed this month.
Related
I'm trying to know how many days have passed from a certain timestamp, but the problem is I can't set it up, so that after midnight will count it as another day.
Here is what I tried:
<?php
$now = time(); // or your date as well
$your_date = 1572123244;
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If I put a timestamp of five minutes before midnight (1572134100), five minutes after midnight should appear that "one day passed"
The usual way of counting the days passed since a given timestamp would be something like this:
$dt = date_create_from_format('U', 1572046200);
$diff = $dt->diff(new DateTime());
echo $diff->days;
But this counts the full 24 hour periods as days. In your case you want to count calendar dates irrespective of the time of day. I would recommend then to ceil the timestamp to the midnight.
$dt = date_create_from_format('U', 1572047700);
$dt->setTime(0, 0); // set time to 00:00
$now = new DateTime('now', new DateTimeZone('UTC')); // time now, but in UTC
$now->setTime(0, 0); // set time to 00:00
$diff = $dt->diff($now);
echo $diff->days;
I am not sure about your current time zone, but timestamps are by nature in UTC, hence you should probably normalize your local time to UTC as well.
What this code does is it sets both today's date and the timestamp you are comparing against to the midnight of the UTC day and then calculates the difference between the two. Taking the time out of equation, this will always count the full 24 hour days.
i try to make time difference with carbon
$dt = Carbon::parse('2018-07-15 00:00:00');
$now = Carbon::now('Asia/Dubai'); //set current time
$seconds = $now->diffInSeconds( $dt ); //difference turn into second
$days = $dt->diffInDays($dt->copy()->addSeconds($seconds));
$hours = $dt->diffInHours($dt->copy()->addSeconds($seconds)->subDays($days));
$minutes = $dt->diffInMinutes($dt->copy()->addSeconds($seconds)->subHours($hours));
$days result are 12 (its right).
$hours result are 8 (seems not right).
$minutes result are 17299 (clearly wrong).
how to get the result for example 12 day 5 hours 45 minutes
Actually functions like diffInSeconds give total difference in seconds that's why the number is so large,to get the minutes for the time difference right you can use -:
$minutes = ($now->minute - $dt->minute);
I'm struggling to to write a PHP function that would calculate time difference between two hours (minus the brake) and the result would be in decimal format. My inputs are strings in 24-hour format (hh:mm):
$start = '07:00'; //started at 7 after midnight
$brake = '01:30'; //1 hour and 30 minutes of brake
$finish = '15:00'; //finished at 3 afternoon
//the desired result is to print out '6.5'
example 2
$start = '19:00'; //started late afternoon
$brake = '00:30'; //30 minutes of brake
$finish = '03:00'; //finished at 3 after midnight
//the desired result is to print out '7.5'
I used to have following formula in MS Excel which worked great:
=IF(D12>=F12,((F12+1)-D12-E12)*24,(F12-D12-E12)*24) '7.5 worked hours
where
D12 - Start time '19:00
F12 - Finish time '03:00
E12 - Brake time '00:30
I tried to play with strtotime() with no luck. My PHP version is 5.4.45. Please help
To provide a solution that doesn't require as much mathematics or parsing of the time values.
Assuming the day is not known, we can also account for the offset of the finish time and start time, when the start time is late at night.
Example: https://3v4l.org/FsRbT
$start = '07:00'; //started at 7 after midnight
$break = '01:30'; //1 hour and 30 minutes of brake
$finish = '15:00'; //finished at 3 afternoon
//create the start and end date objects
$startDate = \DateTime::createFromFormat('H:i', $start);
$endDate = \DateTime::createFromFormat('H:i', $finish);
if ($endDate < $startDate) {
//end date is in the past, adjust to the next day
//this is only needed since the day the time was worked is not known
$endDate->add(new \DateInterval('PT24H'));
}
//determine the number of hours and minutes during the break
$breakPeriod = new \DateInterval(vsprintf('PT%sH%sM', explode(':', $break)));
//increase the start date by the amount of time taken during the break period
$startDate->add($breakPeriod);
//determine how many minutes are between the start and end dates
$minutes = new \DateInterval('PT1M');
$datePeriods = new \DatePeriod($startDate, $minutes, $endDate);
//count the number of minute date periods
$minutesWorked = iterator_count($datePeriods);
//divide the number of minutes worked by 60 to display the fractional hours
var_dump($minutesWorked / 60); //6.5
This will work with any time values within a 24 hour period 00:00 - 23:59. If the day the times were worked are known, the script can be modified to allow for the day to be given and provide more precise timing.
To do this, convert you string times into a unix timestamp. This is an integer number of seconds since the unix epoch (00:00:00 Coordinated Universal Time (UTC), Thursday, 1 January 1970, minus the number of leap seconds that have taken place since then). Do your math, then use the Date() function to format it back into your starting format:
<?php
$start = '19:00'; //started late afternoon
$break = '00:30'; //30 minutes of brake
$finish = '03:00'; //finished at 3 after midnight
//get the number of seconds for which we took a $break
//do this by converting break to unix timestamp, then extracting the hour and multiplying by 360
//and do the same extracting minutes and multiplying by 60
$breaktime = date("G",strtotime($break))*60*60 + date("i",strtotime($break))*60;
//get start time
$unixstart=strtotime($start);
//get finish time. Add a day if finish is tomorrow
if (strtotime($finish) < $unixstart) {
$unixfinish = strtotime('+1 day', strtotime($finish));
} else {
$unixfinish = strtotime($finish);
}
//figure out time worked
$timeworked = ($unixfinish - $unixstart - $breaktime) / 3600;
echo $timeworked;
?>
Another way, using DateTime. Basically, create 2 DateTime objects with the times of start and finish. To the start time, subtract the brake time, and the subtract from the result the end time.
You need to split the brake time in order to use modify().
<?php
$start = '07:00'; //started at 7 after midnight
$brake = '01:30'; //1 hour and 30 minutes of brake
$brakeBits = explode(":", $brake);
$finish = '15:00'; //finished at 3 afternoon
$startDate = \DateTime::createFromFormat("!H:i", $start);
$startDate->modify($brakeBits[0]." hour ".$brakeBits[1]." minutes");
$endDate = \DateTime::createFromFormat("!H:i", $finish);
$diff = $startDate->diff($endDate);
echo $diff->format("%r%H:%I"); // 06:30
Demo
I would like to show any give time in hours only.
Example:
Unix timestamp: 169200
Which is equal to 1 day and 23 hours...
But how can I convert this to hours so it shows 47:00:00 (47 hours)?
Thanks
Edit: It must show minutes and seconds too ;)
A unix timestamp is a number of seconds. There are 60 seconds per minute, 60 minutes per hour. So to convert from seconds to hours, divide by 60*60 = 3600.
If you need the minutes and seconds as well:
$timestamp = 169200;
$secs = $timestamp%60;
$mins = floor($timestamp/60);
$hours = floor($mins/60);
$mins = $mins%60;
printf("%02d:%02d:%02d", $hours, $mins, $secs);
http://ideone.com/gFKv2
$hours = $timestamp / 3600;
You could use floor() or ceil() to round the hour.
How to get duration in terms of minutes by subtracting a previous time stamp from the present time in PHP?
The format of time stamp is like
2009-12-05 10:35:28
I want to calculate how many minutes have passed.
How to do it?
To do this in MySQL use the TIMESTAMPDIFF function:
SELECT TIMESTAMPDIFF(MINUTE, date_lastaccess, NOW()) FROM session;
Where session is the table and date_lastaccess is a DATE / DATETIME field.
If you don't wanna add a library, you can do this pretty easily:
<?php
$date1 = "2009-12-05 10:35:28";
$date2 = "2009-12-07 11:58:12";
$diff = strtotime($date2) - strtotime($date1);
$minutes_passed = $diff/60;
echo $minutes_passed." minutes have passed between ".$date1." and ".$date2;
?>
Check out some pretty date libraries in PHP. Might have something for you. Here's one : http://www.zachleat.com/web/2008/02/10/php-pretty-date/
strtotime("now") - strtotime("2009-12-05 10:35:28")
That will get you seconds difference. Divide by 60 for minutes elapsed. If you have any information on the time zone of the initial timestamp, however, you'd need to adjust the "now" to a more comparable time
something like that
$second = strtotime('now') - strtotime($your_date);
$minute = $second / 60;
strtotime return the number of seconds since January 1 1970 00:00:00 UTC, so you can easily manipulate this. if you need don't want to have 35.5 minute you can use floor to round up the number. Last remark both time need to be in the same timezone or you are going to count the timezone difference also.
You could just use
$timestamp = time();
$diff = time() - $timestamp
$minutes = date( i, $diff );
function timeAgoMin($timestamp){
if(!is_int($timestamp)){
$timestamp = strtotime($timestamp);
}
return ((time() - $timestamp) / 60);
}