im storing the timestamp in mysql database in (INT) column, And i want to search the rows with between the dates. Anyone would please help what should be the Sql query to find the rows between two dates?
dates are entered like
FROM DATE = 15-10-2011
END DATE = 01-11-2011
It depends on what algorithm you use to convert the date strings to int values.
If the algoritm is mototonic, for example: If a day (say 15-10-2011) is converted to n (say 5037), then the next day (16-10-2011) is always converted to n+1 (so 5038 in this example.)
then you could just use:
WHERE IntField BETWEEN MySpecialConvertDateToIntFunction('15-10-2011')
AND MySpecialConvertDateToIntFunction('01-11-2011')
If your field stores different timsetamps as different integers (and the conversion is monotonic), you could change the above code slightly to:
WHERE IntField >= MySpecial...Function('15-10-2011')
AND IntField < MySpecial...Function('02-11-2011') --- notice the date+1
But it's usually better to use a field of the MySQL DATE type for storing dates. Unless you want to store dates before 1000 or after 9999 off course.
If you want to store timestamps, there's also a TIMESTAMP type. Read the
MySQL docs: DATETIME, DATE, and TIMESTAMP Types
You can use The BETWEEN operator, which selects a range of data between two values. The values can be numbers, text, or dates.
You can see there:
http://w3schools.com/sql/sql_between.asp
I would ask you to set data type as timestamp/datestamp & then
//php code
$date1=date ('Y-m-d' , strtotime ( "15-10-2011") );
$date2=date ('Y-m-d' , strtotime ( "01-11-2011") );
//sql code
SELECT * FROM tbl_mytbl WHERE DATE(attr_date) <'$date2' AND DATE(attr_date) >'$date1'
Can you use the mysql FROM_UNIXTIME function dev.mysql.com - function from_unixtime
SELECT *
FROM 'table'
WHERE FROM_UNIXTIME(intTimestamp)
BETWEEN
date ('Y-m-d' , strtotime ( '15-10-2011') )
AND ('Y-m-d' , strtotime ( '01-11-2011'));
I had made a mistake with the date input but have fixed.
Related
I have a field name 'orderdate' (type Date format yyyy-mm-dd).when i am executing the following query it doesnot show any result.What may be the problem, is the date format used in my query creating problem.plz soggest any solution .I can not change the format of orderdate in table. my query is
SELECT
stationerytype,
txntype,
stationeryqtyrecd,
stationeryqtyissued,
stationeryissueddate,
orderdate,
SUM(stationeryqtyrecd) as ttlreceived
FROM tblstationerystock
WHERE
(
stationerytype ='A4 White Ream' AND
txntype ='received'
) AND orderdate<07/09/21
Simply enclose your date in a Single ' quote or Double " qoute like orderdate<'2021-07-09'; and kindly try using the default MySQL Date Format yyyy-MM-dd.
SELECT stationerytype,
txntype,
stationeryqtyrecd,
stationeryqtyissued,
stationeryissueddate,
orderdate,SUM(stationeryqtyrecd) as ttlreceived
FROM tblstationerystock
WHERE (stationerytype ='A4 White Ream' AND txntype ='received') AND orderdate<'2021-07-09';
MySQL DATE is one of the five temporal data types used for managing date values. MySQL uses yyyy-mm-dd format for storing a date value. This format is fixed and it is not possible to change it.
For example, you may prefer to use mm-dd-yyyy format but you can’t. Instead, you follow the standard date format and use the DATE_FORMAT function to format the date the way you want.
Check this.
i'm working on codeigniter and mysql db. I have run in to a issue where i need to show recent data as per date.
i have table name tbl_tournament where i'm going to fetch tournament data whose tournament_end_date >= $todays_date
My Query
$today = date("d/m/Y");
$this->db->select('*');
$this->db->from('tbl_tournament');
$this->db->where('is_deleted', FALSE);
$this->db->where('tournament_end_date_time >=', $today);
$this->db->order_by('tournament_start_date_time');
$query = $this->db->get();
return $query->result_array();
the output of this query is empty array
array();
When i manually change tournament_end_date_time = 01/04/2018 in database and query $this->db->where('tournament_end_date_time >=', '01/04/2017'); i get results. But when i change date in query as $this->db->where('tournament_end_date_time >=', '31/12/2017'); i get empty array.
In Mysql database i have used varchar as the data type tournament_end_date_time
Thank in Advance.
You store datetimes as strings (with VARCHAR type), hence they're compared as strings - character by character. For obvious reasons, '3' character is greater than '1'. That's why with filter set...
WHERE tournament_end_date_time >= '31/12/2017'
... you'll only get the results where corresponding values start from '31/12' - in other words, of December, 31 (of 2017 - or any year after it).
To solve the problem, you can use STR_TO_DATE() MySQL function to convert the existing column value to an actual date. Note that the param will be treated as a date literal as it follows 'YYYY-MM-DD' format:
WHERE STR_TO_DATE(tournament_end_date_time, '%d/%m/%Y') >= '2017-12-31'
... or, in PHP syntax, following CodeIgniter conventions:
$this->db->where(array(
"STR_TO_DATE(tournament_end_date_time, '%d/%m/%Y') >=" => date("Y-m-d")
));
A better choice is doing a single-time update operation on this column to convert all its values to DATE type at once.
I want to compare dates retrieved from oracle database in php. but i don't know how to convert month name like Sep to SEP. I don't know how to convert month in capital letters. I want to convert 2015-09-01 formate to 03-SEP-15.
//sDate: 2015-09-01 eDate: 2015-09-03
$date1=date('d-M-Y', strtotime($sDate));
$date2=date('d-M-Y', strtotime($eDate));
// CREATEDATE: 03-SEP-15 02.44.42.000000 PM
QUERY:
$stid = oci_parse($conn, "SELECT * FROM table1 WHERE CAST(CREATEDATE AS DATE) between '".$sDate."' AND '".$eDate."'");
ERROR:
Warning: oci_execute(): ORA-01861: literal does not match format string
In Oracle you can convert a string into a date using the to_date() function. And a date to a string using the to_char() function
Example
to_date('01-JAN-2015','DD-MON-YYYY')
will return a value of type date.
Now, in your query you must make sure that the values in your "between" statement are date values. The only way to ensure that is to make $sDate a atring value and use the to_date function.
Assuming that your date strings are in format 01-JAN-2015...
$stid = oci_parse($conn,
"SELECT *
FROM table1
WHERE CAST(CREATEDATE AS DATE)
between to_date('".$sDate."','DD-MON-YYYY')
AND to_date('".$eDate."','DD-MON-YYYY')");
See also the Oracle documentation on date formats.
http://docs.oracle.com/cd/B28359_01/server.111/b28286/sql_elements004.htm
So you have a date string like this: '2015-09-01' and you want to convert it to '01-09-2015' to be used in a query.
If you want to debug if the issue is in how you handle the date conversion in php try to do:
list($year,$month,$day)=explode('-',$date);
$months = ['','JAN','FEB','MAR','APR','MAY','JUN','JUL','AUG','SEP','OCT','NOV','DEC'];
$date = implode('-',$day,$months[$month],$year);
Then try to run the query. You don't need to take the string, convert it into a date (unix timestamp) and convert it back to a string if you just need to change the order of the elements in the date. You have to follow your approach if you want to manipulate your date adding or removing some time or stuffs like that.
If the query is still in error and you are sure that dates in your db are stored with that pattern than the issue is in the query syntax
I want to convert the data on which I have the format
$dateToday = date("d-m-Y");
so the value of $dateToday is 27-12-2012
Then I want to save it to the database with the mysql data type date. How to keep the value of 27-12-2012 it can be stored in the mysql database with the format 2012-12-27?
Help me please. Thank you
Yes, you can convert the date with strtotime();
$dateToday = date("d-m-Y");
$newDate = date("Y-m-d", strtotime($dateToday));
OUTPUT: 2012-12-27
And then you can store data to your database.
When you have to recover the date you can reverse this operation like this:
$dateFromDatabase = "2012-12-27";
$reverseDate = date("d-m-Y", strtotime($dateFromDatabase));
OUTPUT: 27-12-2012
(corrected "Y-m-d" to "d-m-Y" in 2nd date call)
this is how it works:
You have to store your data in the proper mysql format. It will allow you to make whatever ordering, aggregating, filtering and calculating your dates.
But when you need to display your data, you may convert it in whatever format you wish, using mysql DATE_FORMAT() function:
SELECT DATE_FORMAT(dt,'%d-%m-%Y') as dtf FROM TABLE
will give you dtf field formatted in your custom format
i'll show u how to do that.
To explain i create one table called testtable1 it contain only one column called
col1 of type DATE
Table creation query is given below
CREATE TABLE `testtable1` (
`col1` DATE NULL DEFAULT NULL
)
Following query will work as you need.
In the first line i declared a string variable. In the second line i converted that string to your required date format and inserted into table.
set #var1='27-12-2012';
insert into testtable1 values(STR_TO_DATE(#var1, '%d-%m-%Y'))
You could also try to use the mysql function for converting to a date from a string, i.e
STR_TO_TIME
.
The SQL query could be
INSERT INTO foo_table (foo_date)
VALUES (STR_TO_DATE('27-12-2012','%d,%m,%Y'))
If you want to store data in MYSQL table in this format, you need to declare the column as varchar.
Because the datetime store date in a different format like 'yyyy-mm-dd hh:mm:ss'
The output is wrong This cannot show the date from the database .This show 1970/01/01.....
$date=Date($year."/". $month."/". $day);
$date=Date("Y-m-d", strtotime($date));
echo $date;enter code here
Try this
$dateToday = date("d-m-Y");
$dateForMysql = date('Y-m-d', $dateToday));
i have column named postDate defined as timestamp.
when i print it directly:
echo $result['postDate'];
i do get that what is stored(eg. 2011-03-16 16:48:24)
on the other hand when i print it through date function:
echo date('F/j/Y',$result['postDate'])
i get December/31/1969
what am i doing wrong?
many thanks
try this.
date('F/j/Y',strtotime($result['postDate']));
as timestamp is required, not formatted date as second parameter.
or you can also try
SELECT UNIX_TIMESTAMP(postDate) as postDateInt from myTable
instead of SELECT postDate from myTable
and then have this in your code.
date('F/j/Y',$result['postDateInt']);
The PHP date function looks for an int time() as the 2nd param. Try using strtotime()
echo date('F/j/Y', strtotime($result['postDate']) );
Why not format the date as needed in your MySQL query?
SELECT DATE_FORMAT(postDate, '%M/%D/%Y') as date from table
The PHP `date()' function expects a number for the second parameter - ie a unix timestamp.
You can convert a SQL date string (or virtually any other date string) into a timestamp in PHP by using the strtotime() function. At least two other answers have already suggested this.
However, I would suggest that you'd be better off getting the date out of your database in unix timestamp format in the first place. You can do this by querying using the MySQL UNIX_TIMESTAMP() function, as follows:
SELECT UNIX_TIMESTAMP(mydatefield) AS mydatefield_timestamp FROM mytable
..obviously, replacing the field and table names as appropriate.
Then you will get the date in timestamp format in your returned dataset in PHP, which you can pass directly into the date() function as follows:
echo date('F/j/Y',$result['mydatefield_timestamp']);
Hope that helps.