i have column named postDate defined as timestamp.
when i print it directly:
echo $result['postDate'];
i do get that what is stored(eg. 2011-03-16 16:48:24)
on the other hand when i print it through date function:
echo date('F/j/Y',$result['postDate'])
i get December/31/1969
what am i doing wrong?
many thanks
try this.
date('F/j/Y',strtotime($result['postDate']));
as timestamp is required, not formatted date as second parameter.
or you can also try
SELECT UNIX_TIMESTAMP(postDate) as postDateInt from myTable
instead of SELECT postDate from myTable
and then have this in your code.
date('F/j/Y',$result['postDateInt']);
The PHP date function looks for an int time() as the 2nd param. Try using strtotime()
echo date('F/j/Y', strtotime($result['postDate']) );
Why not format the date as needed in your MySQL query?
SELECT DATE_FORMAT(postDate, '%M/%D/%Y') as date from table
The PHP `date()' function expects a number for the second parameter - ie a unix timestamp.
You can convert a SQL date string (or virtually any other date string) into a timestamp in PHP by using the strtotime() function. At least two other answers have already suggested this.
However, I would suggest that you'd be better off getting the date out of your database in unix timestamp format in the first place. You can do this by querying using the MySQL UNIX_TIMESTAMP() function, as follows:
SELECT UNIX_TIMESTAMP(mydatefield) AS mydatefield_timestamp FROM mytable
..obviously, replacing the field and table names as appropriate.
Then you will get the date in timestamp format in your returned dataset in PHP, which you can pass directly into the date() function as follows:
echo date('F/j/Y',$result['mydatefield_timestamp']);
Hope that helps.
Related
i have used Now() and it stores something like "2017-01-10 19:28:58" in database which is the current time of user's device.
But i want it like January 10 at 7:28pm . how to do it in simple way. please help
You can use PHP date function with its formatting options
<?php
echo date("F d \a\t g:ia");
If you want more detailed formatting please visit the PHP manual here. You can find everything you need with detailed examples.
you could use the PHP date function
date(F d \a\t\ g:ia);
Your post is ambiguous, but it sounds like you are referring to the SQL NOW() function. The format of the data stored could be a DATETIME or TIMESTAMP or a combination of DATE and TIME columns. The format you get when you retrieve this value from the database depends on that data storage format, your query, and how the value is dealt with when it gets into PHP.
If you want to reformat it using SQL, consider a function like DATE_FORMAT. Assuming your column with the date is called my_column, here's a sample query.
SELECT DATE_FORMAT(my_column, '%M %e at %l:%i%p');
EDIT: you can also use DATE_FORMAT on the result of the NOW() function:
SELECT DATE_FORMAT(NOW(), '%M %e at %l:%i%p');
You might have to tweak the second parameter to get the date format you want.
If your date is stored as a string (VARCHAR or whatever) in your database, then you would need to convert it to a timestamp or datetime first and then use the PHP date function to output the variant you want. Assuming $row is a record from your data table:
$date_string = $row["my_column"];
$stamp = strtotime($date_string); // NOTE that this will assume some timezone
if (!$stamp) {
die("Could not create a timestamp from the date");
}
echo date("F j \a\t g:ia);
You could also use PHP'S DateTime functions which are more modern, if somewhat verbose in usage.
I have a calendar in html form and I want to insert this date into MySQL. The default MySQL date is 0000-00-00. But in my country the format is DD/MM/YYYY. So what to do to fix it. Thank you. I am using PHP.
You must use one format in your HTML page, and another format in your database.
So, if you want to store a date like this '12/05/2008' into mySql, you must transform it like this:
$date = '12/05/2008';
$dateToStore = date('Y-m-d', strtotime(str_replace('/','-',$date)));
And if you wonder why, you need to replace the '/' with '-' to make php know that the first part of the data string is the day, and then the month (as I think is your case).
MySQL the date format is always YYYY-MM-DD. To convert it to another format, you need to manually convert the retrieved date to the desired format like
$displayDate=date("d/M/Y", strtotime($mysqldate));
Method 1
You cant insert into DD/MM/YYYY format. Instead while rendering it in view file you can change into desired format.
<?php
$date = $result['db_date']; // I ASSUMED YOUR DB FIELD IS db_date
$desiredFormat = date('d/m/Y', strtotime($date)); // CONVERTING INTO YOUR FORMAT
echo '<pre>'; print_r($desiredFormat); // DISPLAYING IT
?>
Method 2
You can retrieve from database in your desired format using below
SELECT *, DATE_FORMAT(YOUR_DATE_FIELD, "%m/%d/%Y") AS date FROM YOUR_TABLE;
Use MySQL STR_TO_DATE
Try this mysql query :-
INSERT INTO `table`(`date`) VALUES (STR_TO_DATE('10/10/2015', '%d/%m/%Y'))
I want to convert the data on which I have the format
$dateToday = date("d-m-Y");
so the value of $dateToday is 27-12-2012
Then I want to save it to the database with the mysql data type date. How to keep the value of 27-12-2012 it can be stored in the mysql database with the format 2012-12-27?
Help me please. Thank you
Yes, you can convert the date with strtotime();
$dateToday = date("d-m-Y");
$newDate = date("Y-m-d", strtotime($dateToday));
OUTPUT: 2012-12-27
And then you can store data to your database.
When you have to recover the date you can reverse this operation like this:
$dateFromDatabase = "2012-12-27";
$reverseDate = date("d-m-Y", strtotime($dateFromDatabase));
OUTPUT: 27-12-2012
(corrected "Y-m-d" to "d-m-Y" in 2nd date call)
this is how it works:
You have to store your data in the proper mysql format. It will allow you to make whatever ordering, aggregating, filtering and calculating your dates.
But when you need to display your data, you may convert it in whatever format you wish, using mysql DATE_FORMAT() function:
SELECT DATE_FORMAT(dt,'%d-%m-%Y') as dtf FROM TABLE
will give you dtf field formatted in your custom format
i'll show u how to do that.
To explain i create one table called testtable1 it contain only one column called
col1 of type DATE
Table creation query is given below
CREATE TABLE `testtable1` (
`col1` DATE NULL DEFAULT NULL
)
Following query will work as you need.
In the first line i declared a string variable. In the second line i converted that string to your required date format and inserted into table.
set #var1='27-12-2012';
insert into testtable1 values(STR_TO_DATE(#var1, '%d-%m-%Y'))
You could also try to use the mysql function for converting to a date from a string, i.e
STR_TO_TIME
.
The SQL query could be
INSERT INTO foo_table (foo_date)
VALUES (STR_TO_DATE('27-12-2012','%d,%m,%Y'))
If you want to store data in MYSQL table in this format, you need to declare the column as varchar.
Because the datetime store date in a different format like 'yyyy-mm-dd hh:mm:ss'
The output is wrong This cannot show the date from the database .This show 1970/01/01.....
$date=Date($year."/". $month."/". $day);
$date=Date("Y-m-d", strtotime($date));
echo $date;enter code here
Try this
$dateToday = date("d-m-Y");
$dateForMysql = date('Y-m-d', $dateToday));
im storing the timestamp in mysql database in (INT) column, And i want to search the rows with between the dates. Anyone would please help what should be the Sql query to find the rows between two dates?
dates are entered like
FROM DATE = 15-10-2011
END DATE = 01-11-2011
It depends on what algorithm you use to convert the date strings to int values.
If the algoritm is mototonic, for example: If a day (say 15-10-2011) is converted to n (say 5037), then the next day (16-10-2011) is always converted to n+1 (so 5038 in this example.)
then you could just use:
WHERE IntField BETWEEN MySpecialConvertDateToIntFunction('15-10-2011')
AND MySpecialConvertDateToIntFunction('01-11-2011')
If your field stores different timsetamps as different integers (and the conversion is monotonic), you could change the above code slightly to:
WHERE IntField >= MySpecial...Function('15-10-2011')
AND IntField < MySpecial...Function('02-11-2011') --- notice the date+1
But it's usually better to use a field of the MySQL DATE type for storing dates. Unless you want to store dates before 1000 or after 9999 off course.
If you want to store timestamps, there's also a TIMESTAMP type. Read the
MySQL docs: DATETIME, DATE, and TIMESTAMP Types
You can use The BETWEEN operator, which selects a range of data between two values. The values can be numbers, text, or dates.
You can see there:
http://w3schools.com/sql/sql_between.asp
I would ask you to set data type as timestamp/datestamp & then
//php code
$date1=date ('Y-m-d' , strtotime ( "15-10-2011") );
$date2=date ('Y-m-d' , strtotime ( "01-11-2011") );
//sql code
SELECT * FROM tbl_mytbl WHERE DATE(attr_date) <'$date2' AND DATE(attr_date) >'$date1'
Can you use the mysql FROM_UNIXTIME function dev.mysql.com - function from_unixtime
SELECT *
FROM 'table'
WHERE FROM_UNIXTIME(intTimestamp)
BETWEEN
date ('Y-m-d' , strtotime ( '15-10-2011') )
AND ('Y-m-d' , strtotime ( '01-11-2011'));
I had made a mistake with the date input but have fixed.
Hi i'm inserting a date entry into a field that has a Type Timestamp and field default CURRENT_TIMESTAMP ...my insert value will look like this
'.($data[16] == '' ? CURRENT_DATE() : $data[16]).'
how would I format the CURRENT_DATE() to be 30-Nov-10 to match what $data[16] format would be if not present. Also should I change the Field Type to Date and not Timestamp?
date($format,strtotime(CURRENT_DATE)) works for me.
CURRENT_DATE() is a MySQL function. You could use it as a string literal:
$sql_date = ($date == '') ?
"DATE_FORMAT(CURRENT_DATE(),'%d-%b-%y')" : "'$date'";
mysql_query("UPDATE foo SET date=$sql_date");
This assumes that $date is safe for SQL insertion.
Or you could just use PHP:
if (!$date) $date = date('%d-%M-%y');
mysql_query("UPDATE foo SET date='$date'");
Personally, I would generally use the PHP solution as it makes it easier to use the same query with the same safe parameter placeholders (not used in this example) regardless of how you build the date.
Also should I change the Field Type to Date and not Timestamp
If the time is irrelevant, then it should be a date field. However, if it's a date/timestamp field (and not a text field), you should be inserting in the YYYY-MM-DD format, and the above code is useless.
That is, if the field is text, then the above code could be useful. However, if you are storing simply a date into a single field, you should use a date field, In that case, the format you insert should always be in YYYY-MM-DD. When you retrieve the data, you can format it in the way you want for display.
Well without any further information
all i can tell you is
you should look into the function date and it's second arg
where you put a timestamp which you could create with mktime alt. strtotime
This question doesn't make sense.. I'm assuming you want to output the current date.. in which case you can change the format with the following:
$today = date("M/d/y");
also, time() will output the current date to the second in a unix timestamp
$today = time();