I have a field name 'orderdate' (type Date format yyyy-mm-dd).when i am executing the following query it doesnot show any result.What may be the problem, is the date format used in my query creating problem.plz soggest any solution .I can not change the format of orderdate in table. my query is
SELECT
stationerytype,
txntype,
stationeryqtyrecd,
stationeryqtyissued,
stationeryissueddate,
orderdate,
SUM(stationeryqtyrecd) as ttlreceived
FROM tblstationerystock
WHERE
(
stationerytype ='A4 White Ream' AND
txntype ='received'
) AND orderdate<07/09/21
Simply enclose your date in a Single ' quote or Double " qoute like orderdate<'2021-07-09'; and kindly try using the default MySQL Date Format yyyy-MM-dd.
SELECT stationerytype,
txntype,
stationeryqtyrecd,
stationeryqtyissued,
stationeryissueddate,
orderdate,SUM(stationeryqtyrecd) as ttlreceived
FROM tblstationerystock
WHERE (stationerytype ='A4 White Ream' AND txntype ='received') AND orderdate<'2021-07-09';
MySQL DATE is one of the five temporal data types used for managing date values. MySQL uses yyyy-mm-dd format for storing a date value. This format is fixed and it is not possible to change it.
For example, you may prefer to use mm-dd-yyyy format but you can’t. Instead, you follow the standard date format and use the DATE_FORMAT function to format the date the way you want.
Check this.
Related
I have a calendar in html form and I want to insert this date into MySQL. The default MySQL date is 0000-00-00. But in my country the format is DD/MM/YYYY. So what to do to fix it. Thank you. I am using PHP.
You must use one format in your HTML page, and another format in your database.
So, if you want to store a date like this '12/05/2008' into mySql, you must transform it like this:
$date = '12/05/2008';
$dateToStore = date('Y-m-d', strtotime(str_replace('/','-',$date)));
And if you wonder why, you need to replace the '/' with '-' to make php know that the first part of the data string is the day, and then the month (as I think is your case).
MySQL the date format is always YYYY-MM-DD. To convert it to another format, you need to manually convert the retrieved date to the desired format like
$displayDate=date("d/M/Y", strtotime($mysqldate));
Method 1
You cant insert into DD/MM/YYYY format. Instead while rendering it in view file you can change into desired format.
<?php
$date = $result['db_date']; // I ASSUMED YOUR DB FIELD IS db_date
$desiredFormat = date('d/m/Y', strtotime($date)); // CONVERTING INTO YOUR FORMAT
echo '<pre>'; print_r($desiredFormat); // DISPLAYING IT
?>
Method 2
You can retrieve from database in your desired format using below
SELECT *, DATE_FORMAT(YOUR_DATE_FIELD, "%m/%d/%Y") AS date FROM YOUR_TABLE;
Use MySQL STR_TO_DATE
Try this mysql query :-
INSERT INTO `table`(`date`) VALUES (STR_TO_DATE('10/10/2015', '%d/%m/%Y'))
In my database field there in date and time saved using time(); function.
I want to compare that one with given date in date format like '20/02/2015 '
my query is like:
select view,optin,insertTime,isUnique from sg_page_report as PR where insertTime='20/02/2015'"
where insertTime contains different format date like '1393587636'
How can I resolve this one?
WHERE FROM_UNIXTIME(insertTime)='2015-02-20'
Or you can do it like
$ts=mktime(0,0,0,2,20,2015); // or
//$ts=strtotime('20/02/2015'); // inefficient
And your query can be modified to look like
WHERE insertTime=$ts
I want to convert the data on which I have the format
$dateToday = date("d-m-Y");
so the value of $dateToday is 27-12-2012
Then I want to save it to the database with the mysql data type date. How to keep the value of 27-12-2012 it can be stored in the mysql database with the format 2012-12-27?
Help me please. Thank you
Yes, you can convert the date with strtotime();
$dateToday = date("d-m-Y");
$newDate = date("Y-m-d", strtotime($dateToday));
OUTPUT: 2012-12-27
And then you can store data to your database.
When you have to recover the date you can reverse this operation like this:
$dateFromDatabase = "2012-12-27";
$reverseDate = date("d-m-Y", strtotime($dateFromDatabase));
OUTPUT: 27-12-2012
(corrected "Y-m-d" to "d-m-Y" in 2nd date call)
this is how it works:
You have to store your data in the proper mysql format. It will allow you to make whatever ordering, aggregating, filtering and calculating your dates.
But when you need to display your data, you may convert it in whatever format you wish, using mysql DATE_FORMAT() function:
SELECT DATE_FORMAT(dt,'%d-%m-%Y') as dtf FROM TABLE
will give you dtf field formatted in your custom format
i'll show u how to do that.
To explain i create one table called testtable1 it contain only one column called
col1 of type DATE
Table creation query is given below
CREATE TABLE `testtable1` (
`col1` DATE NULL DEFAULT NULL
)
Following query will work as you need.
In the first line i declared a string variable. In the second line i converted that string to your required date format and inserted into table.
set #var1='27-12-2012';
insert into testtable1 values(STR_TO_DATE(#var1, '%d-%m-%Y'))
You could also try to use the mysql function for converting to a date from a string, i.e
STR_TO_TIME
.
The SQL query could be
INSERT INTO foo_table (foo_date)
VALUES (STR_TO_DATE('27-12-2012','%d,%m,%Y'))
If you want to store data in MYSQL table in this format, you need to declare the column as varchar.
Because the datetime store date in a different format like 'yyyy-mm-dd hh:mm:ss'
The output is wrong This cannot show the date from the database .This show 1970/01/01.....
$date=Date($year."/". $month."/". $day);
$date=Date("Y-m-d", strtotime($date));
echo $date;enter code here
Try this
$dateToday = date("d-m-Y");
$dateForMysql = date('Y-m-d', $dateToday));
I am trying to insert a date in my Database which I get from a php input.
The code I am using to insert the value looks like this
$length = strrpos($fristdatum, " ");
$newDate = explode(".", substr($fristdatum, $length));
$fristdatum = $newDate[2] . "-" . $newDate[1] . "-" . $newDate[0];
Lets say I enter 14.12.2012 as the date if I echo $fristdatum I get 2012-12-14 but as soon as I insert it in my MySQL DB it turn to 2014.12.20 any ideas?
The Column Type is date. The insert is somewhat like this
mysql_query("INSERT INTO sch_anschreiben (date)values('$fristdatum'))
there are more values but I guess that doesn't matter
Thanks in Advance!
Well thanks for the help guys i figured it out i used $fristdatum in a array for str_replace ,after i formated it, like this
$patern = array("[Date]")
$words=array($fristdatum)
$content = str_replace($patern, $words, $content);
and after that inserted it in the DB now I changed it so it would format after the str_replace and it seems to work just fine.
also would appreciate if someone could explain me why^^.
Instead of explode and hard coded conversion, prefere using DateTime::createFromFormat if you have PHP 5.3 or later.
$date = DateTime::createFromFormat('d. m. Y',$fristdatum);
echo $date->format('Y-m-d');//echoes 2012-12-14
Now that you correct your script to register your dates the right way, you should ensure your database is good.
You can use this request I think :
UPDATE yourtable SET yourdate=CONCAT(MONTH(yourdate),'-',DAY(yourdate),'-',YEAR(yourdate)) WHERE MONTH(yourdate) > 12
The DATE type is used for values with a date part but no time part. MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The supported range is '1000-01-01' to '9999-12-31'.
The DATETIME type is used for values that contain both date and time parts. MySQL retrieves and displays DATETIME values in 'YYYY-MM-DD HH:MM:SS' format. The supported range is '1000-01-01 00:00:00' to '9999-12-31 23:59:59'.
The TIMESTAMP data type is used for values that contain both date and time parts. TIMESTAMP has a range of '1970-01-01 00:00:01' UTC to '2038-01-19 03:14:07' UTC.
So if you want to store it like 14-12-2012 then use its datatype as varchar.
Convert it into Y-M-D format. You should directly put 2012-12-14 onto your database.
im storing the timestamp in mysql database in (INT) column, And i want to search the rows with between the dates. Anyone would please help what should be the Sql query to find the rows between two dates?
dates are entered like
FROM DATE = 15-10-2011
END DATE = 01-11-2011
It depends on what algorithm you use to convert the date strings to int values.
If the algoritm is mototonic, for example: If a day (say 15-10-2011) is converted to n (say 5037), then the next day (16-10-2011) is always converted to n+1 (so 5038 in this example.)
then you could just use:
WHERE IntField BETWEEN MySpecialConvertDateToIntFunction('15-10-2011')
AND MySpecialConvertDateToIntFunction('01-11-2011')
If your field stores different timsetamps as different integers (and the conversion is monotonic), you could change the above code slightly to:
WHERE IntField >= MySpecial...Function('15-10-2011')
AND IntField < MySpecial...Function('02-11-2011') --- notice the date+1
But it's usually better to use a field of the MySQL DATE type for storing dates. Unless you want to store dates before 1000 or after 9999 off course.
If you want to store timestamps, there's also a TIMESTAMP type. Read the
MySQL docs: DATETIME, DATE, and TIMESTAMP Types
You can use The BETWEEN operator, which selects a range of data between two values. The values can be numbers, text, or dates.
You can see there:
http://w3schools.com/sql/sql_between.asp
I would ask you to set data type as timestamp/datestamp & then
//php code
$date1=date ('Y-m-d' , strtotime ( "15-10-2011") );
$date2=date ('Y-m-d' , strtotime ( "01-11-2011") );
//sql code
SELECT * FROM tbl_mytbl WHERE DATE(attr_date) <'$date2' AND DATE(attr_date) >'$date1'
Can you use the mysql FROM_UNIXTIME function dev.mysql.com - function from_unixtime
SELECT *
FROM 'table'
WHERE FROM_UNIXTIME(intTimestamp)
BETWEEN
date ('Y-m-d' , strtotime ( '15-10-2011') )
AND ('Y-m-d' , strtotime ( '01-11-2011'));
I had made a mistake with the date input but have fixed.