This question already has answers here:
Finding the number of days between two dates
(34 answers)
Closed 3 years ago.
I would like to calculate the number of days remaining before a date. In my database I have a timestamp corresponding to the end date. For example Friday 30. I would like to say something like that :
7 days remaining... 6, 5, 4, etc
Can you help me please ?
$future = strtotime('21 July 2012'); //Future date.
$timefromdb = //source time
$timeleft = $future-$timefromdb;
$daysleft = round((($timeleft/24)/60)/60);
echo $daysleft;
$date1 = new DateTime("2016-01-01"); //current date or any date
$date2 = new DateTime("2016-12-31"); //Future date
$diff = $date2->diff($date1)->format("%a"); //find difference
$days = intval($diff); //rounding days
echo $days;
//it return 365 days omitting current day
$days = round((timestamp_from_database - time()) / 86400);
SELECT DATEDIFF(yourtimestamp, CURDATE()) AS days
doc ref: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_datediff
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
http://php.net/manual/ro/function.date-diff.php
Related
This question already has answers here:
PHP subtract 1 month from date formatted with date ('m-Y')
(11 answers)
Closed 5 years ago.
How do i properly minus 1 month for the current month ?
$current_month1 = date('m');
$current_month = $current_month1-1;
echo $current_month;
//current ouput
6
//desired output
06
check the following:
$now = new \DateTime("now");
$past = $now->modify("-1 month");
DateTime::modify docs
Also you can do it using DateInterval, the docs has example.
You can use date in combination with strtotime for this.
echo date('m', strtotime('last month')); // 06
The m operator in date will get you:
echo date('m', strtotime('now - 1 month'));
Gives 06.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How many days until XXX date?
Currently I am using this code to determine how many days left till an expected day. But this code shows unexpected result. For example if $last_date is 26 December 2012, then I will get 0 day(s) left. But it should be 1 day(s) left. I think my problem is only with floor() function. Isn't it?
$timezone = "Asia/Dhaka";
if(function_exists('date_default_timezone_set')) date_default_timezone_set($timezone);
$now = time();
$last_date = strtotime("$year-$month-$day");
$datediff = $last_date - $now;
$day_left=floor($datediff/(60*60*24));
echo "$day_left day(s) left.";
N:B: My timezone is +6 GMT, I mean Asia/Dhaka.
As per the PHP documentation:
<?php
$year = '2012';
$month = '12';
$day = '26';
$current_date = new DateTime(date('Y-m-d'), new DateTimeZone('Asia/Dhaka'));
$end_date = new DateTime("$year-$month-$day", new DateTimeZone('Asia/Dhaka'));
$interval = $current_date->diff($end_date);
echo $interval->format('%a day(s)');
?>
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to find number of days between two dates using php
Days left - subscription expire?
I have code that should echo how many days has been from date (2012-10-01) to today.
$datetime1 = date_create('2012-10-01');
$datetime2 = date_create();
$day1 = date_format($datetime1, 'Y-m-d');
$day2 = date_format($datetime2, 'Y-m-d');
$day = $day2 - $day1 / (60 * 60 * 24);
echo $day;
I cant get any right solution, so any ideas how I should do this?
Check this out Finding the number of days between two dates
Sample code (for your date) below:
$now = time();
$your_date = strtotime('2012-10-01');
$datediff = $now - $your_date;
echo floor($datediff/(60*60*24));
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
PHP last day of the month
Is there any function like $date->getMonthDays() or $date->getLastDayOfMonth() in PHP to get the number of days in a given month (or the last day number)?
$start = new DateTime('2012-02-01');
$end = clone $start;
// Interval = last day of the month minus current day in $start
$interval = $start->getLastDayOfMonth() - intval($start->format('j'));
$end->add(new DateInterval('P' . $interval . 'D'));
EDIT: thanks, voted to close, it's a duplicate, sorry for asking...
The php date function gives you the number of days in the month with 't'
date("t");
See: http://php.net/manual/en/function.date.php
It's simple to get last month date
echo date("Y-m-t", strtotime("-1 month") ) ;
echo date("Y-m-1", strtotime("-1 month") ) ;
at March 3 returns
2011-02-28
2011-02-1
t gives you the total number of days in the current month. j gives you the current day of the month.
Using modify and some subtraction from format-ing the datetime, you can get to the end of the month.
$date = new DateTime();
$lastDayOfMonth = $date->modify(
sprintf('+%d days', $date->format('t') - $date->format('j'))
);
This question already has answers here:
Closed 12 years ago.
Possible Duplicates:
Difference between dates
How to calculate the date difference between 2 dates using php
So, I have two dates. For instance, 2010-09-24 and 2010-09-25. I want to check if between those two dates the difference is 1 day.
I don't need to get a value of 86400 which means one day in seconds.
Don't forget that it can be 28, 28, 29, 30, 31 days in month.
Thanks.
What I have right now, but it doesn't work when there is difference between months:
$strto = strtotime($date);
$d1 = date('d', $strto);
$d2 = date('d', time());
echo $d2- $d1;
You can use strtotime to get the number of seconds in between
echo abs(strtotime('2010-09-24') - strtotime('2010-09-25'));
Don't use the day value - (eg date('d', ...)) - leave it as an integer (the result of strtotime()). Then subtract those dates, and then get the floor(difference / 86400).
Like so:
$dt = strtotime($date);
echo floor(abs(time() - $dt) / 86400);
You can do this nicely with the DateTime class if you have PHP 5.3:
<?php
$datetime1 = new DateTime('2010-09-25');
$datetime2 = new DateTime('2010-09-26');
$interval = $datetime1->diff($datetime2);
$intervaldays = (int) $interval->format('%R%d'); // %R signs the result +/-
This is probably less efficient than using strtotime methods, but it is very readable.
Why are you using date('d'... which returns the day of the month?
strtotime will create a UNIX-timestamp which is exactly what time() returns, so abs(time() - strtotime($date)) should already do the job. This way you don't have to worry how many days a month has as you're only working with timestamps.
This will get you the number of (complete) days:
floor( abs(time() - strtotime($date)) / 86400 )