This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to find number of days between two dates using php
Days left - subscription expire?
I have code that should echo how many days has been from date (2012-10-01) to today.
$datetime1 = date_create('2012-10-01');
$datetime2 = date_create();
$day1 = date_format($datetime1, 'Y-m-d');
$day2 = date_format($datetime2, 'Y-m-d');
$day = $day2 - $day1 / (60 * 60 * 24);
echo $day;
I cant get any right solution, so any ideas how I should do this?
Check this out Finding the number of days between two dates
Sample code (for your date) below:
$now = time();
$your_date = strtotime('2012-10-01');
$datediff = $now - $your_date;
echo floor($datediff/(60*60*24));
Related
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 7 years ago.
I have two dates assigned in variable $date1 and $date2..
Here is the code..
if (isset($_POST['check_in']))
{
$date1=date('Y-m-d', strtotime($_POST['check_in']));
}
if (isset($_POST['check_in']))
{
$date2=date('Y-m-d', strtotime($_POST['check_out']));
}
For example if date1="2015-05-21" and date2="2015-05-23".I want the difference of date as 2
Use DateTime class. Try with -
$date1=new DateTime("2015-05-21");
$date2=new DateTime("2015-05-23");
$interval = $date1->diff($date2);
echo $interval->format('%R%a days');
Output
+2 days
DateTime()
Since strtotime returns unixtime, the difference in seconds can be calculated by simply subtracting the one strtotime from the other:
$seconds = strtotime($_POST['check_out']) - strtotime($_POST['check_in']);
Then to find the days:
$days = $seconds / 60 / 60 / 24;
Here you go:
https://php.net/manual/en/datetime.diff.php
Code with various examples.
Here's one I like:
<?php
$datetime1 = date_create('2015-05-21');
$datetime2 = date_create('2015-05-23');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
?>
I hope this helps :)
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 9 years ago.
If I have a given date in the format yyyy-mm-dd, how can I calculate the difference in days to the current date ?
I just want to check whether this date is more than one week (7 days) old compared to the current date.
date_default_timezone_set('Europe/Warsaw');
$from = strtotime('2013-11-01');
$today = time();
$difference = $today - $from;
echo floor($difference / 86400); // (60 * 60 * 24)
or
date_default_timezone_set('Europe/Warsaw');
$datetime1 = new DateTime('2013-11-01');
$datetime2 = new DateTime('2013-11-15');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%a');
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How many days until XXX date?
Currently I am using this code to determine how many days left till an expected day. But this code shows unexpected result. For example if $last_date is 26 December 2012, then I will get 0 day(s) left. But it should be 1 day(s) left. I think my problem is only with floor() function. Isn't it?
$timezone = "Asia/Dhaka";
if(function_exists('date_default_timezone_set')) date_default_timezone_set($timezone);
$now = time();
$last_date = strtotime("$year-$month-$day");
$datediff = $last_date - $now;
$day_left=floor($datediff/(60*60*24));
echo "$day_left day(s) left.";
N:B: My timezone is +6 GMT, I mean Asia/Dhaka.
As per the PHP documentation:
<?php
$year = '2012';
$month = '12';
$day = '26';
$current_date = new DateTime(date('Y-m-d'), new DateTimeZone('Asia/Dhaka'));
$end_date = new DateTime("$year-$month-$day", new DateTimeZone('Asia/Dhaka'));
$interval = $current_date->diff($end_date);
echo $interval->format('%a day(s)');
?>
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Date Difference in php?
Compare 2 timestamps in PHP and get the days between?
I've 2 dates like 15/02/2012 and 18/03/2012, I need to know the number of days difference between them. Does such a utility exist in php?
date_diff is what you want.
$diff = (int) ( abs(strtotime($date1) - strtotime($date2)) / (60 * 60 * 24) );
echo 'diff:' . $diff
PHP has a function for this:
http://www.php.net/manual/en/datetime.diff.php
Example
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Output
+2 days
You could turn those dates into timestamps:
$ts1 = strtotime("15-02-2012");
$ts2 = strtotime("18-03-2012");
$diff = ($ts2 - $ts1)/86400;
echo $diff . " days";
This question already has answers here:
Finding the number of days between two dates
(34 answers)
Closed 3 years ago.
I would like to calculate the number of days remaining before a date. In my database I have a timestamp corresponding to the end date. For example Friday 30. I would like to say something like that :
7 days remaining... 6, 5, 4, etc
Can you help me please ?
$future = strtotime('21 July 2012'); //Future date.
$timefromdb = //source time
$timeleft = $future-$timefromdb;
$daysleft = round((($timeleft/24)/60)/60);
echo $daysleft;
$date1 = new DateTime("2016-01-01"); //current date or any date
$date2 = new DateTime("2016-12-31"); //Future date
$diff = $date2->diff($date1)->format("%a"); //find difference
$days = intval($diff); //rounding days
echo $days;
//it return 365 days omitting current day
$days = round((timestamp_from_database - time()) / 86400);
SELECT DATEDIFF(yourtimestamp, CURDATE()) AS days
doc ref: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_datediff
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
http://php.net/manual/ro/function.date-diff.php