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Closed 12 years ago.
Possible Duplicates:
Difference between dates
How to calculate the date difference between 2 dates using php
So, I have two dates. For instance, 2010-09-24 and 2010-09-25. I want to check if between those two dates the difference is 1 day.
I don't need to get a value of 86400 which means one day in seconds.
Don't forget that it can be 28, 28, 29, 30, 31 days in month.
Thanks.
What I have right now, but it doesn't work when there is difference between months:
$strto = strtotime($date);
$d1 = date('d', $strto);
$d2 = date('d', time());
echo $d2- $d1;
You can use strtotime to get the number of seconds in between
echo abs(strtotime('2010-09-24') - strtotime('2010-09-25'));
Don't use the day value - (eg date('d', ...)) - leave it as an integer (the result of strtotime()). Then subtract those dates, and then get the floor(difference / 86400).
Like so:
$dt = strtotime($date);
echo floor(abs(time() - $dt) / 86400);
You can do this nicely with the DateTime class if you have PHP 5.3:
<?php
$datetime1 = new DateTime('2010-09-25');
$datetime2 = new DateTime('2010-09-26');
$interval = $datetime1->diff($datetime2);
$intervaldays = (int) $interval->format('%R%d'); // %R signs the result +/-
This is probably less efficient than using strtotime methods, but it is very readable.
Why are you using date('d'... which returns the day of the month?
strtotime will create a UNIX-timestamp which is exactly what time() returns, so abs(time() - strtotime($date)) should already do the job. This way you don't have to worry how many days a month has as you're only working with timestamps.
This will get you the number of (complete) days:
floor( abs(time() - strtotime($date)) / 86400 )
Related
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 6 years ago.
Okay so basically I have two variables one called $day and another called $time what I'm trying to do is convert both of these into a unix time-stamp so for example;
$day = 'Monday';
$time = '14:00:00';
So what I'm looking for is a $timestamp variable that would echo out the next Monday coming up at 14:00:00 in a unix timestamp format.
I'm guessing the hardest part of this would be the fact that the day is not a specific date more a day of the week meaning it would have to select the next monday coming up, or the next tuesday... for example.
Thanks for any help.
The constructor for the DateTime class is pretty good at figuring this sort of thing out:
<?php
$day = 'Monday';
$time = '14:00:00';
$date = new DateTime("next $day $time");
echo $date->getTimestamp();
// 1475503200
$datetime = new DateTime();
echo $datetime->format('U');
Solution One:
mktime - Get Unix timestamp for a date
echo mktime(23, 24, 0, 11, 3, 2009);
1257290640
Returns the Unix timestamp corresponding to the arguments given. This timestamp is a long integer containing the number of seconds between the Unix Epoch (January 1 1970 00:00:00 GMT) and the time specified.
Arguments may be left out in order from right to left; any arguments thus omitted will be set to the current value according to the local date and time.
mktime($isAM ? $hrs : ($hrs + 12), $mins, $secs, $m, $d, $y);
To handle AM/PM just add 12 to hours if PM.
Solution Two:
strtotime Returns a timestamp on success, FALSE otherwise.
echo strtotime('2012-07-25 14:35:08' );
Output:
1343219708
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
increment date by one month
I have the following code to sum dates:
$var1 = date("d/m/Y");
$dia = substr($var1,0,2);
$mes = substr($var1,3,2);
$a_o = substr($var1,6,4);
$date = $a_o."-".$mes."-".$dia;
$new_date = strtotime( "+3 month", strtotime($date));
$new_date = date('d/m/Y', $new_date);
echo $new_date;
That is the normal method I found on php.net but when I tried to change $var1 with another date, for example, '21/07/2020' the result is '31/01/1970', I don't know what's wrong. I tried many forms but the result is the same.
How can I fix this? Or what other forms exist to add X months to a date?
Look into the date_add() function that was added for 5.3.0.
DateTime::add -- date_add — Adds an amount of days, months, years,
hours, minutes and seconds to a DateTime object
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "\n";
?>
There is also the date_modify() function that was added for 5.2.0.
DateTime::modify -- date_modify — Alters the timestamp
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
You're going about it completely wrong. date() gives you a nicely formatted STRING. If you want to do math with dates, you need to work with the native PHP date/time values, which are simple integers - unix time stamps.
You're taking that unix timestamp (the default value in date()), converting it to a string, taking apart that string, recombining the string in a different order, then converting it back to a timestamp, then converting the timestamp into a different formatted string. That's like going on a 500mile road trip so you can cross the street.
Any reason you can't simply do:
$new_date = date('d/m/Y', strtotime('+3 month'));
and eliminate everything else in your code snippet?
In your place, I'll trasform the date in timestamp, then I'll add the new date in seconds (i.e. 3 months are 60 * 60 * 24 * 90 = 7 776 000 secs.) and then transform back in date :P
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to find number of days between two dates using php
Collect the number of days between two dates, for example
02/11/2012
And between
02/12/2012
The result is the number of days = 1 day
try this
function dateDiff ($d1, $d2) {
return round(abs(strtotime($d1)-strtotime($d2))/86400);
}
The function uses the PHP ABS() absolute value to always return a postive number as the number of days between the two dates.
PHP >= 5.3 you can use DateTime::Diff:
<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
?>
echo (strtotime('02/12/2012') - strtotime('02/11/2012')) / (24*60*60);
This line converts both dates to unix timestamps, subtracts them and divides this by the amount of seconds in a day.
You can convert your date to a timestamp with the strtotime() function:
$date1 = strtotime("02/11/2012");
$date2 = strtotime("02/12/2012");
$difference = $date1 - $date2;
Then you have the difference in seconds which is a new timestamp, so you can convert this to days with the date() function:
$days = date("d", $difference);
This question already has answers here:
Finding the number of days between two dates
(34 answers)
Closed 3 years ago.
I would like to calculate the number of days remaining before a date. In my database I have a timestamp corresponding to the end date. For example Friday 30. I would like to say something like that :
7 days remaining... 6, 5, 4, etc
Can you help me please ?
$future = strtotime('21 July 2012'); //Future date.
$timefromdb = //source time
$timeleft = $future-$timefromdb;
$daysleft = round((($timeleft/24)/60)/60);
echo $daysleft;
$date1 = new DateTime("2016-01-01"); //current date or any date
$date2 = new DateTime("2016-12-31"); //Future date
$diff = $date2->diff($date1)->format("%a"); //find difference
$days = intval($diff); //rounding days
echo $days;
//it return 365 days omitting current day
$days = round((timestamp_from_database - time()) / 86400);
SELECT DATEDIFF(yourtimestamp, CURDATE()) AS days
doc ref: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_datediff
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
http://php.net/manual/ro/function.date-diff.php
This question already has answers here:
Closed 12 years ago.
Possible Duplicate:
How to find number of days between two dates using php
Is there a quick and easy way to calculate the difference in days between two date strings in this format (YYYY-MM-DD) with PHP (not MySQL)?
$date1 = new DateTime("2010-07-06"); //inclusive
$date2 = new DateTime("2010-07-09"); //exclusive
$diff = $date2->diff($date1);
echo $diff->format("%a"); //3
(PHP 5.3 and higher only)
The only solution I see for PHP < 5.2 is to loop:
strtotime("-1 days");
strtotime("-2 days");
...
strtotime("-n days");
until we get to the unix timestamp of the first date. That's conceptually, you can do it in a much more efficient way, by first guessing the number of days with the timestamp difference of the two days and then testing the neighborhood.
Why dividing by 86400 doesn't work
date_default_timezone_set("Europe/Lisbon");
$date1 = strtotime("2010-03-28");
$date2 = strtotime("2010-03-29");
echo ($date2-$date1)/86400; //gives 0.95833333333333
$date1 = strtotime("2010-10-31");
$date2 = strtotime("2010-11-01");
echo ($date2-$date1)/86400; //gives 1.0416666666667
As Gordon correctly has pointed out, dividing by 86400 would be a valid solution for this problem if the timezone was set to 'UTC' before – just don't forget to restore it to the previous value after.
You can use this function to get the number of days between two date("Y-m-d H:i:s"):
function dateDiff($dateStart, $dateEnd)
{
$start = strtotime($dateStart);
$end = strtotime($dateEnd);
$days = $end - $start;
$days = ceil($days/86400);
return $days;
}
Copied from the Duplicate I've linked below the question.
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