Counting the number of results from a large database - php

Question

I got a two database tables, one has 165 entries. For each of those, I got to browse the 1-million-entry table and see how many times is each of those 165 entries mentioned.
"odds_provider" has 165 entries, "bettingoffer" has a million entries.
$SQL = "SELECT
odds_provider.id AS id,
odds_provider.name AS name,
COUNT(bettingoffer.odds_providerFK) AS betcount
FROM odds_provider
INNER JOIN
bettingoffer
ON bettingoffer.odds_providerFK = odds_provider.id
WHERE
odds_provider.active = 'yes'
GROUP BY
odds_provider.id,
odds_provider.name
ORDER BY betcount DESC";
$result = mysql_query($SQL);
while ($db_field = mysql_fetch_assoc($result)) {
echo $db_field['id'] , " " , $db_field['name'] , " " , $db_field['betcount'] , "</BR>";
}
It does what's intended but it takes forever. Is there a faster way?

Answer 1

This one should be faster, especially if there not many inactive ids.
SELECT id, name, betcount
FROM (
SELECT
odds_providerFK as id,
COUNT(*) as betcount
FROM bettingoffer
WHERE active = 'yes'
GROUP BY odds_providerFK
ORDER BY betcount DESC) as counts
USING (id);

Answer 2

You should be able to join the two tables using SQL. It would be best to not do a COUNT(*) though. You can get better performance by specifying the specific column you would want to count.
SELECT
op.id,
op.name,
COUNT(bo.odds_providerFK) AS bet_offering_count
FROM
odds_provider op
INNER JOIN
bettingoffer bo
ON bo.odds_providerFK = op.id
WHERE
op.active = 'yes'
GROUP BY
op.id,
op.name

Answer 3

You can do it in much better way using SQL Join queries. You don't have to search the 2nd table for each individual record in 1st table. You can establish a JOIN relationship between the tables.
It would be more helpful if you would have pasted the schema definition of both of your tables, but in general this is how JOIN queries works.
Kindly refer to these tutorials about how JOIN queries work.