I have three tables named issue_details, nature_payments, and rci_records. Now I have this query which joins this three tables.
SELECT issue_details.issue_date AS Date,
issue_details.check_no AS Check_No,
payees.payee_name AS Name_payee,
nature_payments.nature_payment AS Nature_of_Payment,
issue_details.issue_amount AS Checks_issued,
issue_details.nca_balance AS Nca_balance
FROM
issue_details
INNER JOIN
nature_payments ON
issue_details.nature_id = nature_payments.nature_id
INNER JOIN
payees ON
issue_details.payee_id = payees.payee_id
ORDER BY Date Asc, Check_no ASC
On my column in Nca_balance, this is a computed differences of every issuances of check. But you may not know what really the process of how I got the difference but to make it simple, let's say that I have another query
that dynamically get also the difference of this nca_balance column. Here is the query:
SELECT r.*,
(#tot := #tot - issue_amount) as bank_balance
FROM (SELECT #tot := SUM(nca_amount) as nca_total FROM nca
WHERE account_type = 'DBP-TRUST' AND
year(issue_date) = year('2015-01-11') AND
month(issue_date) = month('2015-01-11')
)
vars CROSS JOIN issue_details r
WHERE r.account_type = 'DBP-TRUST' AND
r.issue_date = '2015-01-11'
ORDER BY r.issue_date, r.check_no
I know it you may not get my point but I just want to replace the first query of the line
issue_details.nca_balance AS Nca_balance
with my own computation on my second query.
Please help me combine those two query into a single query. Thanks
Related
I am running this query, and I am getting ** #1241 - Operand should contain 1 column(s)** error:
SELECT `forumCategories`.`id`, `forumCategories`.`name`, `forumCategories`.`order`, `forumCategories`.`description`, `forumCategories`.`date_created`, COUNT(forumPosts.forumCategory_id) as postCount,
(SELECT `forumPosts`.*, `forumChildPosts`.`id`, `forumChildPosts`.`forumPost_id`, COUNT(forumChildPosts.forumPost_id) as childCount FROM `forumChildPosts` LEFT JOIN `forumPosts` ON `forumPosts`.`id` = `forumChildPosts`.`forumPost_id` GROUP BY `forumPosts`.`id`) AS childCount
FROM `forumCategories`
LEFT JOIN `forumPosts` ON `forumCategories`.`id` = `forumPosts`.`forumCategory_id`
GROUP BY `forumCategories`.`id`
ORDER BY `forumCategories`.`order` DESC
I have 3 tables:
forumCategories
forumPosts | forumPosts.forumCategory_id = forumCategories.id
forumChildPosts | forumChildPosts.forumPosts_id = forumPosts.id
I want to count all posts for the forum category, and them I want to count all the child posts that belongs to that forum category. How can I do this?
You can't select several items with a subselect and then give them one name. Now you're getting everything from forumPosts, something from forumChildPosts etc and trying to put that into a single column, childCount. This is not allowed.
It might be enough to remove all other result columns from that select and only leave the count?
I couldn't try it, is that makes sense ? But you can't get nested results from mysql due to its limitation, MYSQL is a Matrix table.
SELECT `forumCategories`.`id`,
`forumCategories`.`name`,
`forumCategories`.`order`,
`forumCategories`.`description`,
`forumCategories`.`date_created`,
COUNT(forumPosts.forumCategory_id) AS postCount,
(SELECT COUNT(forumChildPosts.forumPost_id) AS childCount FROM `forumChildPosts` LEFT JOIN `forumPosts` ON `forumPosts`.`id` = `forumChildPosts`.`forumPost_id` GROUP BY `forumPosts`.`id`) AS childCount
FROM `forumCategories`
LEFT JOIN `forumPosts` ON `forumCategories`.`id` = `forumPosts`.`forumCategory_id`
GROUP BY `forumCategories`.`id`
ORDER BY `forumCategories`.`order` DESC
I am trying to only show unique userIds (userIds are (0,1,2,3,4,5,6,7,8,9 etc...) for the query I am running. I tried using DISTINCT in my query, but it only shows me unique values of the rows that have 2 or more of the same userId.
Is there a way I can use php to only show the unique values. My weak points are arrays and it makes it more complicated because its using data from a MySQLi query.
Example right now I have with the query now (lets say its GROUP BY rentPaid DESC and the rent total is 800.00 for all users):
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
3--------400.00------April
1--------200.00------April
1--------100.00------April
Example desired output:
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
Can I do this with MYSQL because I tried DISTINCT and it wouldn't work, how about PHP?
Query:
SELECT
properties.*,
leases.*,
users.userId, users.primaryPhone,
CONCAT(users.userFirstName,' ',users.userLastName) AS user,
admins.adminName, payments.*
FROM
properties
LEFT JOIN leases ON properties.propertyId = leases.propertyId
LEFT JOIN assigned ON properties.propertyId = assigned.propertyId
LEFT JOIN admins ON assigned.adminId = admins.adminId
LEFT JOIN users ON properties.propertyId = users.propertyId
LEFT JOIN payments ON properties.propertyId = payments.propertyId
WHERE
payments.rentMonth = '$currentMonth' AND
payments.rentYear = '$currentYear'
Edit: Please excuse my formatting, this is my first post.
Edit: Added query....its long, but works lol. I only want unique userIds (no double or triple userIds etc...)
I suspect this is what you want:
SELECT userID, MAX(rentPaid) AS maxRentPaid, rentMonth
FROM yourTable
WHERE rentMonth = "April"
GROUP BY userID
ORDER BY maxRentPaid
I'm working with the join plus union plus group by query, and I developed a query something like mentioned below:
SELECT *
FROM (
(SELECT countries_listing.id,
countries_listing.country,
1 AS is_country
FROM countries_listing
LEFT JOIN product_prices ON (product_prices.country_id = countries_listing.id)
WHERE countries_listing.status = 'Yes'
AND product_prices.product_id = '3521')
UNION
(SELECT countries_listing.id,
countries_listing.country,
0 AS is_country
FROM countries_listing
WHERE countries_listing.id NOT IN
(SELECT country_id
FROM product_prices
WHERE product_id='3521')
AND countries_listing.status='Yes')) AS partss
GROUP BY id
ORDER BY country
And I just realised that this query is taking a lot of time to load results, almost 8 seconds.
I was wondering if there is the possibility to optimize this query to the fastest one?
If I understand the logic correctly, you just want to add a flag for the country as to whether or not there is a price for a given product. I think you can use an exists clause to get what you want:
SELECT cl.id, cl.country,
(exists (SELECT 1
FROM product_prices pp
WHERE pp.country_id = cl.id AND
pp.product_id = '3521'
)
) as is_country
FROM countries_listing cl
WHERE cl.status = 'Yes'
ORDER BY country;
For performance, you want two indexes: countries_listing(status, country) and
product_prices(country_id, product_id)`.
Depending on how often it is executed, prepared statements could help. See PDO for more information.
I have a table structure with three tables: profiles, profile_subrubriek and rubrieken. I query the data with the following query:
SELECT profiles.hoofdrubriek, profiles.plaats
, profiles.bedrijfsnaam, profiles.gemeente, profiles.bedrijfsslogan
, profiles.straatnaam, profiles.huisnummer, profiles.postcode
, profiles.telefoonnummer, profiles.fax, profiles.email
, profiles.website, profiles.bedrijfslogo
FROM profiles INNER JOIN profile_subrubriek ON profiles.ID=profile_subrubriek.profile_id
INNER JOIN rubrieken ON profile_subrubriek.subrubriek_id=rubrieken.ID
where (
rubrieken.rubriek = 'Aannemersbedrijven'
OR
profiles.hoofdrubriek = 'Aannemersbedrijven')
AND profiles.gemeente = 'Dongen'
The result, 0 rows. That is not correct. If I take out the Inner Join and only incorporate the 'hoofdrubriek' column in the WHERE clausule I get about 25 rows as a result, that is correct. So this query (modified version of the above) does actually work:
SELECT profiles.hoofdrubriek, profiles.plaats, profiles.bedrijfsnaam
, profiles.gemeente, profiles.bedrijfsslogan, profiles.straatnaam
, profiles.huisnummer, profiles.postcode, profiles.telefoonnummer
, profiles.fax, profiles.email, profiles.website, profiles.bedrijfslogo
FROM profiles where (profiles.hoofdrubriek = 'Aannemersbedrijven')
AND profiles.gemeente = 'Dongen'
What am I doing wrong?
Thanks!
Probably the joined tables don't contain referenced values. Try LEFT JOIN instead of INNER JOIN.
Start troubleshooting with this query.
select count(*) records
FROM profiles INNER JOIN profile_subrubriek ON profiles.ID=profile_subrubriek.profile_id
If records is greater than 1, add this line and run it again:
INNER JOIN rubrieken ON profile_subrubriek.subrubriek_id=rubrieken.ID
Keep adding bits of your original query, one by one, until records is zero. The last thing you added will be the reason.
I have been doing a lots of research online and from my understanding i think my query is ok
That is why i need your help to point me out what im doing wrong.
What My Query Should Do
My query should fetch our stock level from both warehouse
Problem Is
if the product is not in both warehouse the query dont give any result.
Ok so first i have two database of warehouse stock level. that look like that.
Databases
-warehouse1
-warehouse2
Table
-product
Columns
-id
-SKU
-qty
So my Query is
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE
warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku'
ORDER BY
(1_qty + 2_qty) DESC
if i make the where clause like this
WHERE warehouse1.product.SKU = '$sku'
it is then working but i can't get stock from both warehouse.
What should i do if i want to receive the stock level from both warehouse even if there is no product that im asking for in this database.
Thanks
Try a FULL OUTER JOIN. You're using a LEFT JOIN. That requires that the DB fetch all records that match your WHERE clause on the LEFT side of the join, which is warehouse1, and any potentially matching records from warehouse2 (the right side of the join). If a SKU exists only in warehouse2, you don't see it.
Switching to a FULL OUTER JOIN forces the DB to fetch all matching records from BOTH sides of the join, regardless of which side(s) the matching records exist on.
you can also do this with a union
(SELECT
warehouse1.product.id as 1_id,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty
FROM `warehouse1`.`product`
WHERE
warehouse1.product.SKU = '$sku' )
union
(SELECT
warehouse2.product.id as 2_id ,
warehouse2.product.SKU,
warehouse2.product.qty as 2_qty
FROM `warehouse2`.`product`
WHERE warehouse2.product.SKU = '$sku' )
Combine your OR's in () (... OR ...):
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE (warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku')
ORDER BY
(1_qty + 2_qty) DESC