I am trying to only show unique userIds (userIds are (0,1,2,3,4,5,6,7,8,9 etc...) for the query I am running. I tried using DISTINCT in my query, but it only shows me unique values of the rows that have 2 or more of the same userId.
Is there a way I can use php to only show the unique values. My weak points are arrays and it makes it more complicated because its using data from a MySQLi query.
Example right now I have with the query now (lets say its GROUP BY rentPaid DESC and the rent total is 800.00 for all users):
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
3--------400.00------April
1--------200.00------April
1--------100.00------April
Example desired output:
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
Can I do this with MYSQL because I tried DISTINCT and it wouldn't work, how about PHP?
Query:
SELECT
properties.*,
leases.*,
users.userId, users.primaryPhone,
CONCAT(users.userFirstName,' ',users.userLastName) AS user,
admins.adminName, payments.*
FROM
properties
LEFT JOIN leases ON properties.propertyId = leases.propertyId
LEFT JOIN assigned ON properties.propertyId = assigned.propertyId
LEFT JOIN admins ON assigned.adminId = admins.adminId
LEFT JOIN users ON properties.propertyId = users.propertyId
LEFT JOIN payments ON properties.propertyId = payments.propertyId
WHERE
payments.rentMonth = '$currentMonth' AND
payments.rentYear = '$currentYear'
Edit: Please excuse my formatting, this is my first post.
Edit: Added query....its long, but works lol. I only want unique userIds (no double or triple userIds etc...)
I suspect this is what you want:
SELECT userID, MAX(rentPaid) AS maxRentPaid, rentMonth
FROM yourTable
WHERE rentMonth = "April"
GROUP BY userID
ORDER BY maxRentPaid
Related
I have two tables.
One table has everything I need including a cardId(PK)
The other name is a user type table. This table stores the userId and the cardId(FK).
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM USERCARDS uc
INNER JOIN CARDINDEX ci ON uc.cardId = ci.cardId
WHERE uc.userId = 'USER_ID'
So for this query, it will display the cardId, year, name, and number from the CARDINDEX. It will only display the cards that the user has saved in USERCARDS.
I want to do the opposite. If a user is looking at, lets just say, 5 cards, but the CARDINDEX has 50 cards, this query will display the information for the five cards. However, for a new query, I would want to show the remaining 45 cards. Basically, they cant add a card they already are following.
I tried to have uc.cardId != ci.cardId but that didn't work. Im kind of lost.
You can phrase this as a LEFT JOIN:
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM CARDINDEX ci LEFT JOIN
USERCARDS uc
ON uc.cardId = ci.cardId AND
uc.userId = 'USER_ID'
WHERE uc.cardID IS NULL;
Alternatively, you could write this using `NOT EXISTS:
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM CARDINDEX ci
WHERE NOT EXISTS (SELECT 1
FROM USERCARDS uc
WHERE uc.cardId = ci.cardId AND
uc.userId = 'USER_ID'
);
I have two tables, one for registered users and one to store votes.
We are logging in with registrants.id and registrants.zipcode. Once they vote their votes are inserted into the votes table, along with their Registration ID.
Im trying to right a select statement that returns a record that will select all the records for Matched ID and Zipcode, but the ID is not in the Votes.voter column. i have tried all kinds of variations of all the joins i can think of. is it something simple i am missing.
SELECT * FROM registrants
LEFT JOIN votes on registrants.id = votes.voter
WHERE registrants.id = 1 AND registrants.zipcode = 46706 and votes.voter <> 1
Perhaps a not exists query:
select * from registrants
where registrants.zipcode = '46706'
and not exists (select 1 from votes where registrants.id = votes.voter)
I am trying to learn about SQL joins and trying to apply them to an application I am building. I am doing a query to find a "game record" on a schedule based on a specific game id. But on this game record; for the "h_team" and the "v_team"; only the ids of the teams are on the game record. And so what I want to do is join the "teams" table and look up the two different team_names of the "h_team" and "v_team". I have it also pull in a "division name" as well using a join since only the division id is stored on the game record. I have gotten this all to work fine; except I do not know how to get the results separately for the "team_name" for h_team and v_team. Basically the key for each one is just "team_name"; I will paste in my code and then explain further:
$array_game_id6=32;
$sql = "SELECT * FROM playoff_schedule LEFT OUTER JOIN teams on playoff_schedule.h_team = teams.team_id || playoff_schedule.v_team = teams.team_id LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id WHERE tom_game_id=$array_game_id6";
foreach ($dbh->query($sql) as $resultsg39)
{
$h_team=$resultsg39[h_team];
$v_team=$resultsg39[v_team];
$po_div_id=$resultsg39[po_div_id];
$round=$resultsg39[round];
$game_id=$resultsg39[game_id];
$date=$resultsg39[date];
$timestamp=$resultsg39[timestamp];
$h_score=$resultsg39[h_score];
$v_score=$resultsg39[v_score];
$tom_game_id=$resultsg39[tom_game_id];
$h_name=$resultsg39[team_name];
$div_name=$resultsg39[playoff_name];
}
the problem comes in when i am trying to get the results of the query and store them all in the different variables…
the last two "$h_name" and "$div_name" are being pulled from the JOINs all the prior ones are on the game record itself…
what I want to do is store both the names from "v_team" and "h_team" in the respective variables $h_name and $v_name;
I have it storing the $h_name no problem; but i do not know how to make it store both $h_name and $v_name separately as they are both values in the column "team_name" from "teams" table. So I just need to somehow make it so when i get my results it can tell the difference between the two different "team_names" and I can store them in the two different variables…
If this is not clear please let me know.
Thanks!
***** UPDATE 10:49pm EST 2/5/2015
have made some progress on this but my query is not working; I think it is a problem with the aliases and such are not right; here is my non-working query as it is right now:
$sth = $dbh->prepare("SELECT home_team.team_name as home_team_name, visiting_team.team_name as visiting_team_name,
h_team, v_team, po_div_id, round, game_id, date, timestamp, h_score, v_score, tom_game_id, playoff_name FROM playoff_schedule
LEFT OUTER JOIN teams as home_team on playoff_schedule.h_team = teams.team_id
LEFT OUTER JOIN teams as visiting_team on playoff_schedule.v_team = teams.team_id
LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6");
$sth->execute();
$article_list = $sth->fetchAll(PDO::FETCH_ASSOC);
foreach ($article_list as $row => $link) {
$h_team=$link['h_team'];
$v_team=$link['v_team'];
$po_div_id=$link['po_div_id'];
$round=$link['round'];
}
if anyone can spot a problem with my new query I would really appreciate it!
I think what you are trying to do is:
select home_team.team_name as home_team_name,
visiting_team.team_name as visiting_team_name
from playoff_schedule
join team as home_team on playoff_schedule.h_team = teams.team_id
join team as visiting_team on playoff_schedule.v_team = teams.team_id
You can join to the same table as many times as you want to. In this case, it makes sense, because you really are trying to get two different bits of information.
Based on your last edit, the following query appears to work:
SELECT home_team.team_name AS home_team_name,
visiting_team.team_name AS visiting_team_name,
h_team,
v_team,
playoff_schedule.po_div_id,
round,
game_id,
date,
timestamp,
h_score,
v_score,
tom_game_id,
playoff_name
FROM playoff_schedule
LEFT OUTER JOIN teams AS home_team
ON playoff_schedule.h_team = home_team.team_id
LEFT OUTER JOIN teams AS visiting_team
ON playoff_schedule.v_team = visiting_team.team_id
LEFT OUTER JOIN playoff_divisions
ON playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6
You can check the query and the schema at: SQLFiddle
A couple of thing that might be happening:
Is the query itself running?
What happens if you run the query in a mySQL client?
Are there any PHP errors in your log?
Could you post the schema itself?
Is $array_game_id6 actually an array of values? In that case, you need to use "in" as opposed to "=" in your where clause.
With regard to your updated query, I think the main thing you are missing is using the aliases in your JOIN conditions. You should keep your table aliases consistent throughout your query. Also, IMO its better to keep table aliases short so they are easier to read:
So applying those things to your query:
SELECT h.team_name as h_team_name, v.team_name as v_team_name, s.h_team, s.v_team, s.po_div_id, s.round, s.game_id, s.date, s.timestamp, s.h_score, s.v_score, s.tom_game_id, s.playoff_name
FROM playoff_schedule s
LEFT OUTER JOIN teams h ON (
s.h_team = h.team_id
)
LEFT OUTER JOIN teams as v ON (
s.v_team = v.team_id
)
LEFT OUTER JOIN playoff_divisions d ON (
s.po_div_id = d.po_div_id
)
WHERE s.tom_game_id = ?
Now I'm not 100% sure of your schema so I may have referenced some of the columns to the wrong table but you should be able to sort that out.
My table description is as follows
**entry_table**
- serial(int)
- s_name(varchar)
- user_id(int)
- id(int)
**Students_details**
- id(int)
- user_id(int)
- student_name(varchar)
- adress(varchar)
**User_login**
- user_id(int)
- user_name(varchar)
- password(varchar)
- alotment(bool)
Scenario is that the students apply for multiple scholarships. Their selections are stored in the entry_table's s_name, user_id and id fields.
My next step is to build a sorted list of all the students who applied for a particular scholarship eg:"scholarship1".
This list should also show the student's name(student_name field of the students_details table)
The lists are to be sorted according to two types of scholarships that the system offers(merit and need). Applicants of the merit scholarship are required to be sorted in descending order using the ratio(obtained marks/ total marks). However, the need scholarship is to be shorted in ascending order as it uses the ratio(family income/no. of non-earning family members)
I tried to join my tables using
$query = "SELECT *FROM entry_table, students_details
WHERE entry_table.id=students_details.id
group by entry.s_id,entry.student_id";
Please help in the sorting as per type problem. Also the above query helps joining the tables but doesnt achieve the purpose.
thanking you in advance
select * from entry_table inner join students_details on entry_table.id=students_details.id order by entry.student_id asc;
First thing you should connect tables properly.
$query = "SELECT sd.student_name, et.s_name FROM Student_details AS sd LEFT JOIN
entry_table AS et ON et.user_id = sd.user_id LEFT JOIN
user_login AS ul ON ul.user_id = sd.user_id
WHERE et.s_name = 'merit'
ORDER BY et.s_name DESC
UNION ALL
SELECT sd.student_name, et.s_name FROM Student_details AS sd LEFT JOIN
entry_table AS et ON et.user_id = sd.user_id LEFT JOIN
user_login AS ul ON ul.user_id = sd.user_id
WHERE et.s_name = 'need'
ORDER BY et.s_name ASC"
If you need a list you don't need to group, as far as you don't need a count number on any field or unique rows.
This is what I have in the top of my head, maybe do the trick I didn't test it, but maybe give you an idea.
I can't see the ratio field on your tables.
Use Join instead where to connect tables, makes more sense and improve query performance.
Next time, put SQL table code, is more useful to give a better response.
Sorry for my english!!!
I'm having a struggle here trying to grab some data from 3 database tables..
The idea is that users can fill out their profile with several fields, and I'm storing every profile field, field values and the users selected value in separate tables.
The structure of the tables look like this:
Table 'profile_fields'
- id
- name
- sort
- status (enum '0', '1')
Table 'profile_field_values'
- id
- profile_field_id
- name
Table 'user_profile_fields'
- user_id
- profile_field_id
- profile_field_value_id
Would be really nice if you could tell me how to construct this query, and why you used the JOIN you did.
Also, how would this table layout scale when the userbase grows?
Thank you so much in advance!
Edit:
OK, I still can't figure out how to make it return all the fields from 'profile_fields' along with the users selected option from 'user_profile_fields'. If the user hasn't selected a value, it should just be null.
This is my (non-functional) query so far:
SELECT PF.id AS field_id, PF.name AS field_name, UPF.profile_field_value_id AS value_id, PF.type, PFV.name
FROM profile_fields PF
LEFT JOIN profile_fields_values PFV ON PFV.profile_field_id = PF.id
LEFT JOIN user_profile_fields UPF ON UPF.user_id=1 AND PF.id = UPF.profile_field_id
WHERE length(PF.name) > 0 and PF.status = '1'
ORDER BY PF.sort
This query seems to work, but it does not fetch the name of the value from 'profile_field_values':
SELECT PF.id AS field_id, PF.name AS field_name, UPF.profile_field_value_id AS value_id, PF.type
FROM profile_fields PF
LEFT JOIN user_profile_fields UPF ON UPF.user_id =1
AND PF.id = UPF.profile_field_id
WHERE LENGTH( PF.name ) >0
AND PF.status = '1'
ORDER BY PF.sort
I think you have some unnecessary complexity in there. Maybe you should try
Table 'profile_fields'
id
name
sort
status (enum '0', '1')
Table 'profile_field_values'
id
user_id
profile_field_id
value
why are there 3 tables?
Seems like simple JOINs should work:
SELECT pf.id, pf.name, pf.sort, pf.status,
pfv.id, pfv.profile_field_id, pfv.name,
upf.user_id, upf.profile_field_id, upf.profile_field_value_id
FROM profile_fields pf
INNER JOIN profile_field_values pfv
ON pf.id = pfv.profile_field_id
INNER JOIN user_profile_fields upf
ON upf.profile_field_value_id = pfv.id AND upf.profile_field_id = pf.id
A Visual Explanation of SQL Joins
This uses an INNER JOIN to select all matching records from each table -- review the post to tell the difference between an INNER and an OUTER join.