Checking if thumbnail exists in PHP - php

Question

My directory structure looks like that.
...photo-album1/
...photo-album1/thumbnails/
Lets say we have image1.jpg inside photo-album1/. Thumbnail of this file is tn_image1.jpg
What I wanna do is to check every file inside photo-album1/ if they have thumbnail in photo-album1/thumbnails/. If they have just continue if not, send file name to another function : generateThumb()
How can I do that?

Answer 1

<?php
$dir = "/path/to/photo-album1";
// Open directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
// Walk through directory, $file by $file
while (($file = readdir($dh)) !== false) {
// Make sure we're dealing with jpegs
if (preg_match('/\.jpg$/i', $file)) {
// don't bother processing things that already have thumbnails
if (!file_exists($dir . "thumbnails/tn_" . $file)) {
// your code to build a thumbnail goes here
}
}
}
// clean up after ourselves
closedir($dh);
}
}

Answer 2

$dir = '/my_directory_location';
$files = scandir($dir);//or use
$files =glob($dir);
foreach($files as $ind_file){
if (file_exists($ind_file)) {
echo "The file $filexists exists";
} else {
echo "The file $filexists does not exist";
}
}

Answer 3

The easy way is to use PHP's glob function:
$path = '../photo-album1/*.jpg';
$files = glob($path);
foreach ($files as $file) {
if (file_exists($file)) {
echo "File $file exists.";
} else {
echo "File $file does not exist.";
}
}
Credit to soul above for the basics. I'm just adding glob to it.
EDIT: As hakre points out, glob only returns existing files, so you can speed it up by just checking to see if the filename is in the array. Something like:
if (in_array($file, $files)) echo "File exists.";