Retrieve checkbox options after submit - php

Question

I am building this function which echo-s all table fields and has a checkbox along with it.
I need to print this fields after submission, i have this code, and no i haven't started something, not because i don't want but because i don't have any idea how to.. so i'm asking your help.
I need to print information in report.php please help.
<form action='report.php' method='post'>
<?php // Script 12.7 - sopping.php
$db = mysql_connect('localhost', 'root', '');
mysql_select_db('db_up', $db);
echo "<table border='1' class='tabtext'>";
$result = mysql_query("SELECT * FROM hostess");
$numrows = mysql_num_rows($result);
$numfields = mysql_num_fields($result);
// show headers
echo '<thead><tr>';
for ($field = 0; $field < $numfields; $field++) {
$field_name = mysql_field_name($result, $field); // instead of $i
echo '<th><label><input type="checkbox" name="checkbox[' . $field_name . '][]" value="1"/> ' . $field_name . '</label></th>';
}
echo '</tr></thead>';
echo '<tbody>';
for ($row = 0; $row < $numrows; $row++) {
$data = mysql_fetch_assoc($result);
echo '<tr>';
for ($field = 0; $field < $numfields; $field++) {
$field_name = mysql_field_name($result, $field);
if (isset($_POST['checkbox'][$field_name])) {
echo '<td>' . $data[$field_name] . '</td>';
}
}
echo '</tr>';
}
echo '</tbody>';
echo '</table>';
?>
<input type='submit' value='Submit' />
</form>
The report.php
<?php // Script 12.7 - sopping.php
$db = mysql_connect('localhost', 'root', '');
mysql_select_db('db_up', $db);
foreach($_POST['checkbox'] as $key => $value)
?>

Answer 1

Try this one:
if(isset($_POST['Submit'])) {
echo "<pre>";
$checked = implode(',', $_POST['checkbox']);
echo $checked;
}