I am trying to make a loop that gets the name some other info about a product from a sql table - MySQL table
Then Creates a page that looks like that - Webpage
So Far I have this code that does show it but I cant figure out a way how to update the name of the dropdown menu so when I press submit It writes into another SQL table the name of the product and then how many of those products did the customer selected .
<?php
$sql = "SELECT * FROM product";
$result = $conn->query($sql);
while ( $row = mysqli_fetch_assoc($result) ) {
$columnValues[] = $row['ProductID'];
foreach($columnValues as $key => $value) {
$$key = $value;
while ($row = $result->fetch_assoc()) {
echo "<tr>\n". "<br>";
echo "##product-ID## ";
echo "<td>".$row['ProductID']. "</td>\n";
echo " ##product-name## ";
echo "<td>".$row['ProductName']."</td>\n";
echo "<td>\n";
echo " ##dropdown## ";
echo "<select id=$value>\n";
echo "<option value='1'>1</option>\n";
echo "<option value='2'>2</option>\n";
echo "<option value='3'>3</option>\n";
echo "<option value='4'>4</option>\n";
echo "<option value='5'>5</option>\n";
echo "<option value='6'>6</option>\n";
echo "</select>\n";
echo "</td>\n";
echo "</tr>\n";
}
}
}
$conn->close();
?>
<html>
<body>
<form method="POST" action="#" >
<input type="submit" name="Submit" value="Submit" /><br>
</form> </body>
</html>
I know I will most likely need a second php script for the capture of the post so help with that will be greatly appreciated too .
////////////////////////////////////////////////
So up to here I got it somehow - It loops and shows all the product . When I press submit it adds only the last product in the loop and it doesn't care of the drop down menu - Just adds a "2" .
The table where the script writes is simple - 4 columns OrderID1,productid1,ProductName1 orderedqnt1
Thanks in advance .
Index.php
<html>
<body>
<form method="POST" action="insert.php" >
<?php
session_start(); // session start for Variables to add to the sql in Insert.php
include("global.php"); // Stores the session Variables
## Conection part
$sql = "SELECT * FROM product";
$result = $conn->query($sql);
while ( $row = mysqli_fetch_assoc($result) ) {
$columnValues[] = $row['ProductID'];
foreach($columnValues as $key => $value) {
$$key = $value;
while ($row = $result->fetch_assoc()) {
echo "<tr>\n". "<br>";
echo "##product-ID## ";
echo "<td>".$row['ProductID']. "</td>\n";
echo " ##product-name## ";
echo "<td>".$row['ProductName']."</td>\n";
echo "<td>\n";
/* echo " ##dropdown## "; */
echo "<select id=" . $value . " name='dropdown'>\n";
echo "<option value=''>-</option>\n";
echo "<option value='1'>1</option>\n";
echo "<option value='2'>2</option>\n";
echo "<option value='3'>3</option>\n";
echo "<option value='4'>4</option>\n";
echo "<option value='5'>5</option>\n";
echo "<option value='6'>6</option>\n";
echo "</select>\n";
/* echo "</td>\n"; */
/* Echo ":::::value variable = "."$value"; */
echo "</tr>\n" . "<br>";
print_r ($value);
$_SESSION['GrabIDses']=mysqli_real_escape_string($conn,$row['ProductID']); //Grabs the ID of the product in Session Variable
$_SESSION['GrabNameses']=mysqli_real_escape_string($conn,$row['ProductName']); //Grabs the Name of the product in Session Variable
$_SESSION['GrabSKUses']=mysqli_real_escape_string($conn,$row['SKU']); //Grabs the SKU of the product in Session Variable
$_SESSION['Ordered']=mysqli_real_escape_string($conn,$value); //Grabs the Ordered Quantity for the product in Session Variable ????????????????
/* $GrabID = mysqli_real_escape_string($conn,$row['ProductID']);
$GrabName = mysqli_real_escape_string($conn,$row['ProductName']);
$GrabSKU = mysqli_real_escape_string($conn,$row['SKU']);
echo "----------------------"."$_SESSION['GrabSKUses']"."<br>"."$_SESSION['GrabIDses']"."<br>"."----------------------"; */
}
}
}
$conn->close();
echo "<br>";
?>
<input type="submit" name="Submit" value="Submit" /><br>
</form>
</body>
Insert.php
<?php
session_start(); // session start
$getvalue = $_SESSION['GrabIDses']; // session get
$getvalue1 = $_SESSION['GrabNameses']; // session get
$getvalue2 = $_SESSION['GrabSKUses']; // session get
$ordered11 = $_SESSION['Ordered']; // session get
echo $getvalue;
echo "||";
echo $getvalue1;
echo "||";
echo $getvalue2;
echo "||"."<br>";
print_r($_SESSION);
## Connection Part
if(isset($_POST['dropdown'])) {
echo("You order was completed" . "<br>");
$sql = "INSERT INTO testorder (productid1,ProductName1,orderedqnt1) VALUES ('$getvalue', '$getvalue1','$ordered11')";
if (mysqli_query($conn, $sql))
{ echo "New record created successfully"; }
else
{ echo "Error: " . $sql . "<br>" . mysqli_error($conn); }
mysqli_close($conn);
}
else {
echo" dhur";
}
?>
The < select>-Boxes have to be inside the form and inside the web page at all.
Enter a name-attribute in the < select>-Tag, to make the data available in the saving script vie $_POST
I am not sure, what you want to do, so I don't know if $row['ProductID'] is a reasonable name.
<html>
<body>
<form method="POST" action="#" >
<?php
$servername = "localhost";
$username = "root";
$password ="";
$dbname = "company";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM product";
$result = $conn->query($sql);
while ( $row = mysqli_fetch_assoc($result) ) {
$columnValues[] = $row['ProductID'];
foreach($columnValues as $key => $value) {
$$key = $value;
while ($row = $result->fetch_assoc()) {
echo "<tr>\n". "<br>";
echo "##product-ID## ";
echo "<td>".$row['ProductID']. "</td>\n";
echo " ##product-name## ";
echo "<td>".$row['ProductName']."</td>\n";
echo "<td>\n";
echo " ##dropdown## ";
echo "<select id='$value' name='{$row['ProductID']}'>\n";
echo "<option value='1'>1</option>\n";
echo "<option value='2'>2</option>\n";
echo "<option value='3'>3</option>\n";
echo "<option value='4'>4</option>\n";
echo "<option value='5'>5</option>\n";
echo "<option value='6'>6</option>\n";
echo "</select>\n";
echo "</td>\n";
/* Echo ":::::value variable = "."$value"; */
echo "</tr>\n";
}
}
}
$conn->close();
?>
<input type="submit" name="Submit" value="Submit" /><br>
</form>
</body>
</html>
<body>
<form method="POST" action="#" >
<?php
$servername = "localhost";
$username = "root";
$password ="";
$dbname = "company";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM product";
$result = $conn->query($sql);
while ( $row = mysqli_fetch_assoc($result) ) {
$columnValues[] = $row['ProductID'];
foreach($columnValues as $key => $value) {
$$key = $value;
while ($row = $result->fetch_assoc()) {
echo "<tr>\n". "<br>";
echo "##product-ID## ";
echo "<td>".$row['ProductID']. "</td>\n";
echo " ##product-name## ";
echo "<td>".$row['ProductName']."</td>\n";
echo "<td>\n";
echo " ##dropdown## ";
echo "<select id='$value' name='{$row['ProductID']}'>\n";
echo "<option value='1'>1</option>\n";
echo "<option value='2'>2</option>\n";
echo "<option value='3'>3</option>\n";
echo "<option value='4'>4</option>\n";
echo "<option value='5'>5</option>\n";
echo "<option value='6'>6</option>\n";
echo "</select>\n";
echo "</td>\n";
/* Echo ":::::value variable = "."$value"; */
echo "</tr>\n";
}
}
}
$conn->close();
?>
<input type="submit" name="Submit" value="Submit" /><br>
</form>
</body>
</html>
echo "<select id=$value>\n";
needs a name. So change to
echo "<select id=" . $value . " name='dropdown'>\n";
Then you need to make a second page, use
if(isset($_POST['dropdown'])) {
Then insert or update table with the info. I think you can get this part down quite easily :).
Edit:
while ( $row = mysqli_fetch_assoc($result) ) {
$columnValues[] = $row['ProductID'];
foreach($columnValues as $key => $value) {
$$key = $value;
while ($row = $result->fetch_assoc()) {
You're using 2 while loops. That's 1 to many.
Related
Got a table which stores information about pupils.
CREATE TABLE pupis (name TEXT, city TEXT, caretaker TEXT);
By opening this web-site, info from this table is showed.
There is a "Sort" button, which sorts all the pupils by their cities.
Also by clicking this button, a drop down list occurs near every pupil.
This list allows to choose a caretaker for a pupil.
This way, my question is how to send all chosen caretakers from numerous drop down lists by clicking single button? (UPDATE TABLE)
I am sorry I am new to PHP and right now I do not understand how to be here. I can only suggest to create arrays dynamically that consists of pupil id and its caretaker.
I've created this web-site especially for this question and this code is how that site works:
<?php
mb_internal_encoding("UTF-8");
$link = mysql_connect($mysql_host, $mysql_user, $mysql_password)
or die('' . mysql_error());
mysql_select_db($mysql_dbname) or die('');
mysql_set_charset('utf8');
$query = 'SELECT * FROM pupils';
$result = mysql_query($query) or die(mysql_error());
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\n";
}
echo "\t</tr>\n";
}
echo "</table>\n";
mysql_free_result($result);
mysql_close($link);
?>
<form action="" method="post">
<input type="submit" name="sort" value="Sort">
</form>
<?php
if (isset($_POST["sort"])) {
$link = mysql_connect($mysql_host, $mysql_user, $mysql_password)
or die(mysql_error());
mysql_select_db($mysql_dbname) or die();
mysql_set_charset('utf8');
$query = 'SELECT * FROM pupils WHERE city = "Moscow";' or die("died");
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) != 0) {
echo "<h1>Moscow</h1>";
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\t\t";
}
echo "<td><form action=\"\" method=\"post\">";
echo "<select name=\"choose_caretaker\" required>";
echo "<option value=\"0\">Choose a caretaker</option>";
echo "<option value=\"Caretaker1\">Caretaker1</option>";
echo "<option value=\"Caretaker2\">Caretaker2</option>";
echo "<option value=\"Caretaker3\">Caretaker3</option>";
echo "</select></td>";
echo "</form>";
echo "</tr>\n";
}
echo "</table>\n";
}
$query = 'SELECT * FROM pupils WHERE city = "London";' or die("died");
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) != 0) {
echo "<h1>London</h1>";
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\t\t";
}
echo "<td><form action=\"\" method=\"post\">";
echo "<select name=\"choose_caretaker\" required>";
echo "<option value=\"0\">Choose a caretaker</option>";
echo "<option value=\"Caretaker1\">Caretaker1</option>";
echo "<option value=\"Caretaker2\">Caretaker2</option>";
echo "<option value=\"Caretaker3\">Caretaker3</option>";
echo "</select></td>";
echo "</form>";
echo "</tr>\n";
}
echo "</table>\n";
}
mysql_free_result($result);
mysql_close($link);
}?>
<form action="" method="post">
<input type="submit" name="send_to_caretakers" value="Send">
</form>
<?if (isset($_POST["send_to_caretakers"])) {
$link = mysql_connect($mysql_host, $mysql_user, $mysql_password)
or die(' ' . mysql_error());
mysql_select_db($mysql_dbname) or die('');
mysql_set_charset('utf8');
echo "Sent to the caretakers";
$temp = $_REQUEST['choose_caretaker'];
echo $temp;
// Have no idea how it can designed
mysql_close($link); // Закрываем соединение
}
?>
To use array for "select name" e.g choose_caretaker[pupil_id]
add in "multiple" in select box to select mutiple
render your result in php. you will see your caretaker under a pupil in array format.
echo "<td><form action=\"\" method=\"post\">";
echo "<select name=\"choose_caretaker[$link['id']]\" multiple required>";
echo "<option value=\"0\">Choose a caretaker</option>";
echo "<option value=\"Caretaker1\">Caretaker1</option>";
echo "<option value=\"Caretaker2\">Caretaker2</option>";
echo "<option value=\"Caretaker3\">Caretaker3</option>";
echo "</select></td>";
echo "</form>";
<form action='movies.php' method='POST'>
Language: <select name="language">
<option selected>hindi</option>
<?php
require("config.php");
$result="SELECT language FROM movies";
$q = mysqli_query($conn,$result) or die(mysql_error());
while ($row=mysqli_fetch_array($q)) {
$s1=$row["language"];
echo "<option>
$s1
</option>";
}
echo "<br>"
?>
</select>
<br /> <br />
<input type='submit' value='Submit' />
</form>
<?php
$lang=#$_POST['language'];
$_SESSION["lang1"]=$lang;
/*
if($lang){
$sql = "SELECT name,language FROM movies WHERE language='$lang'";
$result = mysqli_query($conn,$sql);
if (mysqli_num_rows($result)>0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<div class="query"> <img src="images\tiles\bb.jpg"> ';
echo "<h3> " . $row["name"]."</h3>". "<br>";
echo "</div>";
}
} else {
echo "0 results";
}
}
*/
$page=#$_GET['page'];
if($page==""|| $page=="1")
{
$page1=0;
}
else{
$page1=($page*3)-3;
}
$sql = "SELECT name,language FROM movies WHERE language='". $_SESSION['lang1']."' limit $page1,3 ";
$result = mysqli_query($conn,$sql);
$a= mysqli_num_rows($result);
while ($list=mysqli_fetch_array($result))
{
echo $list['name'] . " : " . $list['language'] . "<br />";
}
$sql = "SELECT name,language FROM movies WHERE language='$lang'";
$result = mysqli_query($conn,$sql);
$a= mysqli_num_rows($result);
$numrows=$a;
$rowsperpage=3;
$totalpages= ceil($numrows/$rowsperpage);
echo "</br>";
for($b=1;$b<=$totalpages;$b++)
{
?><?php echo $b." ";?> <?php
}
?>
I get proper output on movies.php which is the first 3 rows from database,but when i click on the dynamically created pagination link like movies.php?page=2 then there is no output on this page.This code works fine if i manually set the
$_SESSION["lang1"]="English"; then i get proper output but when i take input from the form it doesnt work.
How do I refresh the table when I click EDIT NOW Button? or this is easier, how do I make refresh button to refresh the table? I have no knowledge on JSP to auto refresh. However, I manage to make an onchange event so when I choose menu, it will refresh upon changing. When I edit a data and submit, it does not refresh. How do I re-execute the echo of table? Thanks!
<?php
$selected='';
function get_options($select)
{
$conn = new mysqli('localhost', 'root', 'jared17', 'hbadb')
or die ('Cannot connect to db');
$result = $conn->query("select * from students");
$options='';
while ($row = $result->fetch_assoc())
{
$LRN = $row['LRN'];
$Last = $row['Last_Name'];
$First = $row['First_Name'];
if($LRN == $_GET['Students'])
{
$options.='<option value="'.$LRN.'" selected>'.$Last.', '.$First.'</option>';
}
else
{
$options.='<option value="'.$LRN.'">'.$Last.', '.$First.'</option>';
}
}
return $options;
}
if (isset($_GET['Students'])) {
$conn = new mysqli('localhost', 'root', 'jared17', 'hbadb')
or die ('Cannot connect to db');
$result = $conn->query("select * from students");
$lrn = $_GET['Students'];
$stmt = $conn->prepare("SELECT Last_Name, First_Name, Level, Q1, Q2, Q3, Q4, FINAL FROM english WHERE LRN = ?");
$stmt->bind_param('i', $lrn);
$stmt->execute();
$stmt->bind_result($last, $first, $level, $q1, $q2, $q3, $q4, $final);
$stmt->fetch();
echo "<table><tr><th>LRN</th><th>Name</th><th>Level</th><th>Q1</th><th>Q2</th><th>Q3</th><th>Q4</th><th>Final</th></tr>";
echo "<tr><td>$lrn</td><td>$last, $first</td><td>$level</td><td>$q1</td><td>$q2</td><td>$q3</td><td>$q4</td><td>$final</td></tr></table>";
}
echo "<html>";
echo "<body>";
echo "<form method=GET>";
echo "<select name=Students onchange=this.form.submit();>";
echo get_options();
echo "</select>";
echo "</form>";
echo "<form method=POST>";
///////////EDIT DATA
echo "Edit Data: ";
echo "<select name = 'Edit'>";
echo '<option value=Q1>Q1</option>';
echo '<option value=Q2>Q2</option>';
echo '<option value=Q3>Q3</option>';
echo '<option value=Q4>Q4</option>';
echo '<option value=FINAL>FINAL</option>';
echo '<input type="number" max="100" name="editdata" required>';
echo "</select>";
echo "<input type='submit' name='submit2' value='Edit Now'>";
if (isset($_POST['Edit'])) {
$conn2 = new mysqli('localhost', 'root', 'jared17', 'hbadb')
or die ('Cannot connect to db');
$upd = $_POST['Edit'];
$txt = $_POST['editdata'];
$now = "UPDATE english SET $upd='$txt' WHERE LRN='$lrn'";
$res = $conn2->query($now);
if (!$conn2->error) {
echo "Errormessage: $conn->error";
}
echo $now;
}
echo "</form>";
echo "</body>";
echo "</html>";
?>
I would use 2 pages view.php and edit.php. View would display the data with link to edit. When you click edit it would open edit.php to load the form to edit data and save it to db. Then issue the command
header("Location: view.php");
to reload the view.php and display the new data
I have uploaded the scripts I use as a basis for databases so you can see if this is what you want - feel free to amend any data it is just a test database. If you want more code just ask
www.cambodia.me.uk/php/view.php
Edited to include scripts as requested - sorry it is old code and mysql not mysqli
Connect script
<?php
/*
CONNECT-DB.PHP
Allows PHP to connect to your database
*/
// Database Variables (edit with your own server information)
$server = 'server';
$user = 'user';
$pass = 'pass';
$db = 'database';
// Connect to Database
$connection = mysql_connect($server, $user, $pass)
or die ("Could not connect to server ... \n" . mysql_error ());
mysql_select_db($db)
or die ("Could not connect to database ... \n" . mysql_error ());
?>
View script
<?php
include('remote-connect.php');
$result = mysql_query("SELECT * FROM stats")
or die(mysql_error());
echo "<p><b>View All</b> | <a href='view-paginated.php?page=1'>View Paginated</a></p>";
echo "<table border='1' cellpadding='10'>";
echo "<tr> <th>date</th> <th>Home Team</th> <th></th><th></th><th>Away Team</th> <th></th> </tr>";
while($row = mysql_fetch_array( $result )) {
echo "<tr>";
echo '<td>' . $row['date'] . '</td>';
echo '<td>' . $row['hometeam'] . '</td>';
echo '<td>' . $row['fthg'] . '</td>';
echo '<td>' . $row['ftag'] . '</td>';
echo '<td>' . $row['awayteam'] . '</td>';
echo '<td>Edit</td>';
//echo '<td>Delete</td>';
echo "</tr>";
}
echo "</table>";
?>
<p>Add a new record</p>
</body>
</html>
Edit script
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
function renderForm($id, $hometeam, $awayteam, $error)
{
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
?>
<form action="" method="post">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<div>
<p><strong>ID:</strong> <?php echo $id; ?></p>
<strong>First Name: *</strong> <input type="text" name="hometeam" value="<?php echo $hometeam; ?>"/><br/>
<strong>Last Name: *</strong> <input type="text" name="awayteam" value="<?php echo $awayteam; ?>"/><br/>
<p>* Required</p>
<input type="submit" name="submit" value="Submit">
</div>
</form>
</body>
</html>
<?php
}
include('remote-connect.php');
if (isset($_POST['submit']))
{
if (is_numeric($_POST['id']))
{
$id = $_POST['id'];
$hometeam = mysql_real_escape_string(htmlspecialchars($_POST['hometeam']));
$awayteam = mysql_real_escape_string(htmlspecialchars($_POST['awayteam']));
if ($hometeam == '' || $awayteam == '')
{
$error = 'ERROR: Please complete all mandatory fields!';
renderForm($id, $hometeam, $awayteam, $error);
}
else
{
mysql_query("UPDATE stats SET hometeam='$hometeam', awayteam='$awayteam' WHERE id='$id'")
or die(mysql_error());
// Go back to view page and redisplay the edited data
header("Location: view.php");
}
}
else
{
echo 'Error!';
}
}
else
{
if (isset($_GET['id']) && is_numeric($_GET['id']) && $_GET['id'] > 0)
{
$id = $_GET['id'];
$result = mysql_query("SELECT * FROM stats WHERE id=$id")
or die(mysql_error());
$row = mysql_fetch_array($result);
if($row)
{
$hometeam = $row['hometeam'];
$awayteam = $row['awayteam'];
renderForm($id, $hometeam, $awayteam, '');
}
else
{
echo "No results!";
}
}
else
{
echo 'Error!';
}
}
?>
</body>
</html>
It's so easy. If you fetch your table's values after edit or delete operation, sql will bring fresh data.
Hi Im creating a multiple search form using PHP,HTML,SQL with the use of functions, for example I have 3 search fields Firstname, lastname and email. I would let the user input from any of those, therefore i would be needing the if else statement, but to be able to satisfy all conditions it would take a lot of if else, so i think of using a function to output the table and place it inside the if else after the query on the database. But it seems that it could not be able to search in the database if I do it like this it outputs "0 results", but if i remove the function and place it on the end of my script I am able to search in the db but it could not detect my else condition which is "You have not yet entered any values"
function checkres()
{
//Get query on the database
$result = mysqli_query($conn, $sql);
//Check results
if (mysqli_num_rows($result) > 0)
{
//Headers
echo "<table border='1' style='width:100%'>";
echo "<tr>";
echo "<th>Image ID</th>";
echo "<th>Lastname</th>";
echo "<th>Firstname</th>";
echo "<th>Email</th>";
echo "<th>PhoneNumber</th>";
echo "</tr>";
//output data of each row
while($row = mysqli_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".$row['ID']."</td>";
echo "<td>".$row['LastName']."</td>";
echo "<td>".$row['FirstName']."</td>";
echo "<td>".$row['Email']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
}
if (!empty($sfname) && empty($slname) && empty($semail) )
{
$sql = "select * from Userlist where FirstName LIKE '%". $sfname ."%'" ;
checkres();
}
else if (!empty($sfname) && !empty($slname) && empty($semail))
{
$sql = "select * from Userlist where FirstName LIKE '%". $sfname ."%' AND LastName LIKE '%". %slname. "%'";
checkres();
}
else
{
echo "You have not yet entered any values ";
}
mysqli_close($conn);
?>
This is the new one
<form method="post" action="#" id="searchform">
First Name:<br>
<input type="text" name="fname">
<br>Last Name:<br>
<input type="text" name="lname">
<br>Email: <br>
<input type="text" name="email">
<br>
<input type="submit" name="submit" value="Search">
</form>
<?php
$sfname = $_POST["fname"];
$slname = $_POST["lname"];
$semail = $_POST["email"];
$servername = "xxx";
$username = "xxx";
$password = "xxx";
$dbname = "xxx";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
function checkres()
{
//Get query on the database
$result = mysqli_query($conn, $sql);
//Check results
if (mysqli_num_rows($result) > 0)
{
//Headers
echo "<table border='1' style='width:100%'>";
echo "<tr>";
echo "<th>Image ID</th>";
echo "<th>Lastname</th>";
echo "<th>Firstname</th>";
echo "<th>Email</th>";
echo "<th>PhoneNumber</th>";
echo "</tr>";
//output data of each row
while($row = mysqli_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".$row['ID']."</td>";
echo "<td>".$row['LastName']."</td>";
echo "<td>".$row['FirstName']."</td>";
echo "<td>".$row['Email']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
}
if(!empty($sfname) || !empty($slname) || !empty($semail)){
$emailQueryPart = !empty($semail) ? "Email LIKE '%$semail%'" : "";
$lastnameQueryPart = !empty($slname) ? "LastName LIKE '%$slname%'" : "";
$firstnameQueryPart = !empty($sfname) ? "FirstName LIKE '%$sfname%'" : "";
$arr = array($emailQueryPart, $lastnameQueryPart,$firstnameQueryPart);
$sql = "select * from Userlist";
for($i = 0; $i < count($arr); $i++){
if(!empty($arr[$i])){
if($i > 0){
$sql.= " AND ".$arr[$i];
}else{
$sql.= " WHERE ".$arr[$i];
}
}
}
}else{
echo "You must enter at least one value";
}
checkres();
mysqli_close($conn);
?>
You have a few errors:
$sql = "select * from Userlist where FirstName LIKE '%". $sfname ."%' AND LastName LIKE '%". %slname. "%'";
You have %slname instead of $slname.
Another mistake is in the program flow. Your else condition, which is saying :"You have not yet entered any values" will be reached in two cases:
When all fields are left blank
When all fields are filled with values.
You don't want that. You have to improve your logic, and build a query based on that, and that can be done like this:
function checkres()
{
//Get query on the database
$result = mysqli_query($conn, $sql);
//Check results
if (mysqli_num_rows($result) > 0)
{
//Headers
echo "<table border='1' style='width:100%'>";
echo "<tr>";
echo "<th>Image ID</th>";
echo "<th>Lastname</th>";
echo "<th>Firstname</th>";
echo "<th>Email</th>";
echo "<th>PhoneNumber</th>";
echo "</tr>";
//output data of each row
while($row = mysqli_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".$row['ID']."</td>";
echo "<td>".$row['LastName']."</td>";
echo "<td>".$row['FirstName']."</td>";
echo "<td>".$row['Email']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
}
if(!empty($sfname) || !empty($slname) || !empty($semail)){
$emailQueryPart = !empty($semail) ? "Email LIKE '$semail'" : "";
$lastnameQueryPart = !empty($slname) ? "LastName LIKE '%$slname%'" : "";
$firstnameQueryPart = !empty($sfname) ? "FirstName LIKE '%$sfname%'" : "";
$arr = array($emailQueryPart, $lastnameQueryPart,$firstnameQueryPart);
$sql = "select * from Userlist";
for($i = 0; $i < count($arr); $i++){
if(!empty($arr[$i])){
if($i > 0){
$sql.= " AND ".$arr[$i];
}else{
$sql.= " WHERE ".$arr[$i];
}
}
}
}else{
echo "You must enter at least one value";
}
checkres();
mysqli_close($conn);
?>
What you do is in my opinion a little bit confusing (and a little bit odd n terms of the program's flow structure).
You can simply use an array of variables for your input fields and then loop through the array to generate your SQL statement. So your HTML form would look like this:
<form method="post" action="#" id="searchform">
First Name:<br />
<input type="text" name="queryArray[FirstName]" />
<br />Last Name:<br />
<input type="text" name="queryArray[LastName]" />
<br />Email:<br />
<input type="text" name="queryArray[Email]" />
<br />
<input type="submit" name="submit" value="Search" />
</form>
A more clear structure would be if you define these 2 functions, which of course can be placed anywhere in your PHP code block:
function createSql($queryArray) {
if (is_array($queryArray)) {
$sql = null;
foreach ($queryArray as $key => $value) {
if ($value != null ) {
$addQuery = "`".$key."` LIKE '%".$value."%'";
if ($sql == null)
$sql = "SELECT * FROM `Userlist` WHERE ".$addQuery;
else
$sql = $sql." AND ".$addQuery;
}
return $sql;
}
}
function checkres($sql) {
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn)
die("Connection failed: " . mysqli_connect_error());
//Get query on the database
$result = mysqli_query($conn, $sql);
//Check results
if (mysqli_num_rows($result) > 0) {
//Headers
echo "<table border='1' style='width:100%'>";
echo "<tr>";
echo "<th>Image ID</th>";
echo "<th>Lastname</th>";
echo "<th>Firstname</th>";
echo "<th>Email</th>";
echo "<th>PhoneNumber</th>";
echo "</tr>";
//output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>".$row['ID']."</td>";
echo "<td>".$row['LastName']."</td>";
echo "<td>".$row['FirstName']."</td>";
echo "<td>".$row['Email']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
echo "</tr>";
}
echo "</table>";
} else
echo "0 results";
// Close connection
mysqli_close($conn);
}
Finally you will have to call the functions according to user activity:
if ($_POST != null) {
$sql = createSql($_POST[queryArray]);
checkres($sql);
}
An example how the SQL generation works is listed here
I'm trying to use HTML, PHP and MYSQL to pull data from a database and display it in a form (to later be edited). At this point I'm only trying to pull that data and display it in a form. (I'll worry about updating later). I pull the data but nothing displays in my textboxes:
<?php
$con = mysqli_connect("XXXXX"); //removed for privacy
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query="select * from VOLUNTEER";
echo '$query';
$result = mysqli_query($con, $query);
echo "<table>";
if ($result)
{
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo '<form method = "post" action="insertvolunteer.php">';
echo '<tr>';
echo '<td>First Name:</td>';
echo '<td>' . '<input type=text name=FirstName' . $row["FirstName"] . '</td>';
echo '<td>' . '<input type=hidden name=VolunteerId' . $row["VolunteerId"] . '</td>';
echo '</tr>';
}
}
echo "</form>";
echo "</table>";
mysqli_close($con);
?>
Text box data needs to be displayed on value as
echo '<td><input type="text" name="FirstName" value="'.$row["FirstName"].'"></td>';
connect.php
<?php
$server = "server";
$user = "user";
$password = "password";
$bd = "yourbd";
$connect = mysql_connect($server, $user, $password);
$connect = mysql_select_db("$bd", $connect);
if (!$connect){
echo mysql_error(); exit;
}
?>
namefile.php
<?php
include('connect.php');
$select = mysql_query("select * from VOLUNTEER");
while ($show = mysql_fetch_assoc($select)):
echo "<table>";
echo "<form method = 'post' action='insertvolunteer.php'>";
echo '<tr>';
echo '<td>First Name:</td>';
echo '<td><input type="text" name="FirstName" value="'.$show["FirstName"].'"></td>';
echo '<td><input type="text" name="FirstName" value="'.$show["VolunteerId"].'"></td>';
echo '</tr>';
echo "</form";
echo "</table>";
endwhile;
?>
When you create an MySQL query, you need to declare this. How?
$var = "SELECT * FROM SOMEWHERE"; wrong
$var = mysql_query("SELECT * FROM SOMEWHERE"); right
'n in echo '<td>' . '<input type=text name=FirstName' . $row["FirstName"] . '</td>';, you need to close the tag. And also have no need of separate <td> of <input>.
Try something like :)
#update I realized that you've got what was wished. Cheers.