html table to display php photo gallery - php

Question

I need to display a photo gallery in a table, I want five pictures on each line, but can't find the way to insert </tr><tr> after each fifth picture.
Here's my code:
<?php
// table name
$tbl_name=gallery1;
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
while($rows= mysql_fetch_assoc($result)){
$id = $rows['id'];
$path = $rows['path'];
$image_name = $rows['image_name'];
$title = $rows['title'];
?>
<img src="<?php echo $path."/".$image_name;?>" height="120"/>Name:<?php echo $title;?>
<?php
echo "<form action='pictry.php' enctype='multipart/form-data' method='post'>
<input name='file[]' type='hidden' value='".$image_name."' />
<input name='id' type='hidden' id='id' value='".$id."'/>
<input type='submit' name='button' id='button' value='Delete Picture' /></form>";
}
?>

Answer 1

Replace the line
while($rows= mysql_fetch_assoc($result)){
with
for($i = 0; $rows= mysql_fetch_assoc($result); ++$i) {
Then you place something like this into the for loop.
if($i % 5 == 0) { /* insert stuff */ }

Answer 2

Untested Code
<?php
$perrow = 5;
$i = 0;
echo '<table>';
echo '<tr>';
while($rows = mysql_fetch_assoc($result)) {
echo '<td><img src=[grapresultfromrows] /></td>';
++$i;
if($i == $perrow) {
$i = 0;
echo '</tr>';
echo '<tr>';
}
}
// If not a multiple of $perrow you need to add extra cells
for($i; $i < $perrow; ++$i) {
echo '<td></td>';
}
echo '</tr>';
echo '</table>';
?>