PHP How to Delete Multiple Records using Checkbox - php

Question

I have a little problem regarding with deleting multiple records in my table. I used checkbox in order to delete them but it doesn't work. I don't know what would be the exact CODE for it.
Here is my PHP code
<?php
echo "<form action='#'>
<fieldset>
<input type='text' name='search' value='' id='searchtalents' placeholder='Search Keywords..' size='40'/>
</fieldset>
</form>";
echo "<form name='tmsform' method='POST' action=''>";
$sql = "SELECT * FROM talentinfo WHERE 1 LIMIT 10";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ({$sql}) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found";
exit;
}
echo"<div id='talentinfo'><table id='mr_database' name='myform' style='border:1px solid #fff;' cellspacing=0 cellpading='2' class='pretty'>
<thead>
<tr>
<th></th>
<th></th>
<th></th>
<th>Mr Tracking Number</th>
<th>First Name</th>
<th>Middle Name</th>
<th>Last Name</th>
<th>Address</th>
<th>Contact Number</th>
<th>School</th>
<th>Course</th>
<th>Year Graduated</th>
<th>Position Considered</th>
<th>Referred Location</th>
<th>Unit</th>
</tr>
</thead>";
$counter = 40000;
while ($row = mysql_fetch_assoc($result)) {
$filled = (($counter % 2) == 1) ? "style='background-color:#BCD9E1;'" : "" ;
$id = $row['talents_id'];
echo "<tbody><tr {$filled} class='tmsdel'>";
echo "<td><a href ='#' rel='#edit_talents{$counter}'><center><img src='img/edit.gif' width='25' height='21' title='Edit'></center></a></td>";
echo "<td><a href ='#' id=".$row['talents_id'].'&idelete=talents'." class='delete'><center><img src='img/delete.png' width='25' height='21' title='Delete'></center></a></td>";
echo "<td><input type='checkbox' name='checkbox[]' id='check".$row['talents_id']."' value='".$row['talents_id'].'&idelete=talents'."'/></td>";
echo "<td><a href='#' rel='#tracing_number{$counter}' style='text-decoration:none; font-weight:bold; color:#444;'>" . $row ['mr_tracking_number'] . "</a></td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['middlename'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['contact_number'] . "</td>";
echo "<td>" . $row['school'] . "</td>";
echo "<td>" . $row['course'] . "</td>";
echo "<td>" . $row['year_graduated'] . "</td>";
echo "<td>" . $row['position_considered'] . "</td>";
echo "<td>" . $row['referred_location'] . "</td>";
echo "<td>" . $row['unit'] . "</td>";
echo "</tr></tbody>";
?>
And here is my Javascript
$(function(){
$(document).ready(function(){
});
$("#delete-all").click(function(){
$("#mr_database").remove();
$.ajax({
url: "modules/delete-all.php",
type: "get",
async: false,
data: "check"
});
});
});

Answer 1

Please follow steps:
First you need to apply any class name to your all checkboxes.
Call function on button click for delete then
var allVals = '';
$("#delete-all").click(function(){
$('.checkboxclass :checked').each(function() {
allVals = allVals + $(this).val() + ',';
});
}
Then you need to pass allVals variables in ajax and post to .php file
Like: data: 'ids=' + allVals in $.ajax
In last you can get this variable in php file and do delete process on it.
Like: $ids = explode(',', $_REQUEST['ids'); and use ids in mysql query
Hope this helps you.

Answer 2

Rather simple answer since what i am seeing here is a script to view the table and delete the html in the browser but not the data on the server.
You need to write the modules/delete-all.php script mentioned here:
url: "modules/delete-all.php"
which should contain the " delete * FROM talentinfo " SQL Query.
This however will seamlessly delete all table contents. So you might want to do a prompt:
$("#delete-all").click(function(){
Check = confirm("Do you really want to delete ALL DATA ? (Hint: there is no undo)");
if (Check == true) {
$("#mr_database").remove();
$.ajax({
url: "modules/delete-all.php",
type: "get",
async: false,
data: "check"
});
}
});
The delete_all.php should delete all, so just do:
<?php
$sql = "delete * FROM talentinfo ";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ({$sql}) from DB: " . mysql_error();
exit;
} else {
print "ok";
}
?>