pass a jquery variable to php code - php

this is my php code
require 'functions/connection.php';
$conn = Connect();
$result = mysqli_query($conn,"SELECT * FROM employee ORDER BY id asc");
echo "
<tr>
<th>Id</th>
<th>First name</th>
<th>Last name</th>
<th>Salary</th>
<th>Start Date</th>
<th>Department</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['salary'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['department'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
and this is my jquery code
<script>
$('.sort').click(function(){
var value = $(this).attr('data-val');
var field_name = $(this).attr('data-field');
$.post( "getEmployee.php", {value:value, field_name:field_name}, function( data ) {
$('.responstable').html(data);
});
if(value=="asc"){
$x="asc";
}
else{
$x="desc";
}
});
</script>
i would like to pass the variable x from the jquery code to the php so i can order my database asc or desc like this:
result = mysqli_query($conn,"SELECT * FROM employee ORDER BY id $x");

In your jquery code
$.post( "getEmployee.php", { sort: "asc" } );
In your php code using
$_POST['sort']

Related

table class not working after inserting sql database inside

I firstly did the table layout and made sure everything is working, after connecting the table to a database and trying to put the records inside it, everything worked perfectly, but the class didnt, i have now the boring table without the layout made.
<body>
<h1>Employees</h1>
<table class="responstable">
<?php
require 'connection.php';
$conn = Connect();
$result = mysqli_query($conn,"SELECT * FROM employee");
echo "<table border='1'>
<tr>
<th>Id</th>
<th>First name</th>
<th>Last name</th>
<th>Salary</th>
<th>Start Date</th>
<th>Department</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['salary'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['department'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
<script src='http://cdnjs.cloudflare.com/ajax/libs/respond.js/1.4.2/respond.js'></script>
</body>
</html>
the table class is "responstable"
table tag is defined in 2 places.try removing this.
echo "<table border='1'>
or remove the table tag at the top after h1 tag and add the class to the table tag defined in the echo as,
complete code
<body>
<h1>Employees</h1>
<?php
require 'connection.php';
$conn = Connect();
$result = mysqli_query($conn,"SELECT * FROM employee");
echo "<table border='1' class='responstable'>
<tr>
<th>Id</th>
<th>First name</th>
<th>Last name</th>
<th>Salary</th>
<th>Start Date</th>
<th>Department</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['salary'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['department'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
<script src='http://cdnjs.cloudflare.com/ajax/libs/respond.js/1.4.2/respond.js'></script>
</body>
</html>

How to concatenate a row variable taken from a different query to an existing query?

I was hoping to get anyone's opinion on why this certain variable won't print out. Variable $sum from the $qsl_ query is not printing along with the other table row data.
<?php
$sql_ = "SELECT SUM(`points`) AS value_sum FROM `history` WHERE `userid` = '$id'";
$result = mysql_query($sql_);
#echo mysql_error();
$row = mysql_fetch_assoc($result);
$sum = $row['value_sum'];
$sql = "SELECT * FROM users";
$myData = mysql_query($sql);
echo "<table id=\"table\" class=\"table table-striped\">
<thead>
<tr>
<th>ID</th>
<th>Email</th>
<th>First Name</th>
<th>Last Name</th>
<th>Model</th>
<th>Year</th>
<th>Plate Number</th>
<th>City</th>
<th>Country</th>
<th>Points</th>
</tr></thead>";
while($record = mysql_fetch_array($myData)){
echo "<tr>";
echo "<td>" . $record['id'] . "</td>";
echo "<td>" . $record['email'] . "</td>";
echo "<td>" . $record['firstName'] . "</td>";
echo "<td>" . $record['lastName'] . "</td>";
echo "<td>" . $record['model'] . "</td>";
echo "<td>" . $record['Year'] . "</td>";
echo "<td>" . $record['plateNumber'] . "</td>";
echo "<td>" . $record['city'] . "</td>";
echo "<td>" . $record['country'] . "</td>";
echo "<td>" . $sum . "</td>";
}
echo "</table>";
?>
This is my current output where the points column won't produce:
I apologize if my code appears inefficient, I am a struggling student fanatic of PHP. I appreciate direct answers; however, learning is my key here. Thanks in advance!
$sql = "SELECT users.*, sum(history.points) as points FROM users left join history on users.id=history.userid group by users.id";
$myData = mysql_query($sql);
echo "<table id=\"table\" class=\"table table-striped\">
<thead>
<tr>
<th>ID</th>
<th>Email</th>
<th>First Name</th>
<th>Last Name</th>
<th>Model</th>
<th>Year</th>
<th>Plate Number</th>
<th>City</th>
<th>Country</th>
<th>Points</th>
</tr></thead>";
while($record = mysql_fetch_array($myData)){
echo "<tr>";
echo "<td>" . $record['id'] . "</td>";
echo "<td>" . $record['email'] . "</td>";
echo "<td>" . $record['firstName'] . "</td>";
echo "<td>" . $record['lastName'] . "</td>";
echo "<td>" . $record['model'] . "</td>";
echo "<td>" . $record['Year'] . "</td>";
echo "<td>" . $record['plateNumber'] . "</td>";
echo "<td>" . $record['city'] . "</td>";
echo "<td>" . $record['country'] . "</td>";
echo "<td>" . $record['points'] . "</td>";
}
echo "</table>";
It seems that I might have had my code jungled, thank you #abhi and #msfoster for your healthy inputs.
<?php
$sql = "SELECT * FROM users";
$myData = mysql_query($sql);
echo "<table id=\"table\" class=\"table table-striped\">
<thead>
<tr>
<th>ID</th>
<th>Email</th>
<th>First Name</th>
<th>Last Name</th>
<th>Model</th>
<th>Year</th>
<th>Plate Number</th>
<th>City</th>
<th>Country</th>
<th>Points</th>
</tr></thead>";
while($record = mysql_fetch_array($myData)){
$id = $record['id'];
$sql_ = "SELECT SUM(`points`) AS value_sum FROM `history` WHERE `userid` = '$id'";
$result = mysql_query($sql_);
#echo mysql_error();
$row = mysql_fetch_assoc($result);
$sum = $row['value_sum'];
echo "<tr>";
echo "<td>" . $id . "</td>";
echo "<td>" . $record['email'] . "</td>";
echo "<td>" . $record['firstName'] . "</td>";
echo "<td>" . $record['lastName'] . "</td>";
echo "<td>" . $record['model'] . "</td>";
echo "<td>" . $record['Year'] . "</td>";
echo "<td>" . $record['plateNumber'] . "</td>";
echo "<td>" . $record['city'] . "</td>";
echo "<td>" . $record['country'] . "</td>";
echo "<td>" . $sum . "</td>";
echo "</tr>";
}
echo "</table>";
?>
My output is finally:
query is correct but as you shown
var_dump($row) = "array (size=1) 'value_sum' => null "
so it have 'null' because of that its showing blank;
but for this you can use join also .
$row = mysql_fetch_assoc($result); returns an array of "rows". Since you want the first row you need to access it $sum = $row[0]['value_sum'];

MySQL query working in workbench, but does not work via PHP interface

I have a MySQL query that I know to be working in Workbench/Sequel Pro that appears to return empty in my PHP code:
$SQL = "SELECT * FROM staff, invigilation, exam, occupation, room, module
WHERE staffID='$inputID'
AND invigilation.examID=exam.exam_ID
AND exam.exam_ID=occupation.examID
AND room.room_ID=occupation.roomID
AND exam.module_ID=module.module_ID
AND staff.password='$inputPassword'";
$result = mysql_query($SQL);
if($db_field = mysql_fetch_assoc($result)) {
echo "
<table border='1'>
<tr>
<th>Exam ID</th>
<th>Module ID</th>
<th>Module name</th>
<th>Duration</th>
<th>Start time</th>
<th>Room</th>
</tr>";
while ($db_field = mysql_fetch_assoc($result)) {
echo "
<tr>
";
echo "<td>" . $db_field['exam_ID'] . "</td>";
echo "<td>" . $db_field['module_ID'] . "</td>";
echo "<td>" . $db_field['module_name'] . "</td>";
echo "<td>" . $db_field['duration'] . "</td>";
echo "<td>" . $db_field['start_datetime'] . "</td>";
echo "<td>" . $db_field['room_name'] . "</td>";
echo "
</tr>";
}
} else {
echo "Incorrect login details. Please try again";
die();
}
The result of this code is the first table row (Exam ID, Module ID etc.) is displayed but the table content is not.
I cannot work out why this is happening. Other than the SQL query, the code is identical to code used elsewhere (where it is working fine).
You are doing mysql_fetch_assoc twice. The first time it reads the record and prints the table header. The second time there are no more records so it doesn't print a row.
Change
if($db_field = mysql_fetch_assoc($result)) {
to
if(mysql_num_rows($result) > 0) {
Try this. You are using mysql_fetch_assoc($result); two times, First time it get result and second time there is no result.
$SQL = "SELECT * FROM staff, invigilation, exam, occupation, room, module
WHERE staffID='$inputID'
AND invigilation.examID=exam.exam_ID
AND exam.exam_ID=occupation.examID
AND room.room_ID=occupation.roomID
AND exam.module_ID=module.module_ID
AND staff.password='$inputPassword'";
$result = mysql_query($SQL);
$db_field = mysql_fetch_assoc($result)
if($db_field != "" ) {
echo "
<table border='1'>
<tr>
<th>Exam ID</th>
<th>Module ID</th>
<th>Module name</th>
<th>Duration</th>
<th>Start time</th>
<th>Room</th>
</tr>";
while ($db_field) {
echo "
<tr>
";
echo "<td>" . $db_field['exam_ID'] . "</td>";
echo "<td>" . $db_field['module_ID'] . "</td>";
echo "<td>" . $db_field['module_name'] . "</td>";
echo "<td>" . $db_field['duration'] . "</td>";
echo "<td>" . $db_field['start_datetime'] . "</td>";
echo "<td>" . $db_field['room_name'] . "</td>";
echo "
</tr>";
}
} else {
echo "Incorrect login details. Please try again";
die();
}

Output not displaying all rows

Having an issue with the output of records from a query run to display records.... It only shows the first row as the code specifies and then the next results all in.. paragraphs? I don't know if it has something to do
<?php
include 'core/init.php';
include 'includes/overall/header.php';
?>
<div class="article" style="width:900px !important">
<?php
$result = $sql = mysql_query("SELECT * FROM ref_employees WHERE employerid={$user_data['user_id']} ")
or die('Error in query : $sql. ' .mysql_error());
echo "<table border='0' class='table'>
<tr>
<th>ID Number</th>
<th>Employee Number</th>
<th>FirstName</th>
<th>LastName</th>
<th>MiddleName</th>
<th>Job Title</th>
<th>Employement Status</th>
<th>Contact</th>
<th>Email</th>
<th>Edit</th>
</tr>";
if (mysql_num_rows($sql) > 0)
{
while ($row = mysql_fetch_array($sql)){
if ($row['employed'] == '1'){
echo "<tr>";
echo "<td>" . $row['idnumber'] . "</td>";
echo "<td>" . $row['empnumber'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['middlename'] . "</td>";
echo "<td>" . $row['jobtitle'] . "</td>";
echo "<td>" . $row['employed'] . "</td>";
echo "<td>" . $row['contactnum'] . "</td>";
echo "<td>" . $row['contactemail'] . "</td>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "</tr>";
echo "</tr>";
echo "</table>";
}
}
}
?>
</div>
<?php include 'includes/overall/footer.php';
?>
You are using closing table tag into loop as
while ($row = mysql_fetch_array($sql)){
....
....
...
echo "</table>";
}
use table closing tag out of loop as
while ($row = mysql_fetch_array($sql)){
....
....
...
}
echo "</table>";

Approve Form submit

I have trouble with creating an approval form as am still php beginner,
the idea is
user submit a form am setting a default value"0" in the approved row at the table..
so behind the scenes the admin shows all members from this table where approved="0"
and this is the code
<code>
<?php
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</code>
I just want to add checkbox for every table user and when checked thier status changed to 1 in approved column
thanks all
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
$i = 1; //counter for the checkboxes so that each has a unique name
echo "<form action='process.php' method='post'>"; //form started here
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
<th>Update</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "<td><input type='checkbox' name='check[$i]' value='".$row['ID']."'/>";
echo "</tr>";
$i++;
}
echo "</table>";
echo "<input type='submit' name='approve' value='approve'/>";
echo "</form>";
mysql_close($con);
Now comes process.php
if(isset($_POST['approve'])){
if(isset($_POST['check'])){
foreach ($_POST['check'] as $value){
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die (mysql_error());
}
}
}
though you are using mysql_* functions here, i recommend you to use PDO
EDIT:
As per your request, this is the update.
Change this code in your admin panel script:
echo "<input type='submit' name='approve' value='approve'/>";
Delete the above line and add this instead:
echo "<input class='action' type='button' name='approve' value='approve' />";
echo "<input class='action' type='button' name='edit' value='edit' />";
echo "<input class='action' type='button' name='delete' value='delete' />";
echo "<input type='hidden' name='action' value='' id='action' />"; //Action (edit, approve or delete) will be set here which will be passed as POST variable on form submission
Now you will need some javascript to do some tricks.
Add the following code preferably head section in your admin panel script
<script type="text/javascript" src="jquery-1.7.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.action').click(function(){
var action = $(this).attr('name');
$('#action').val(action);
$(this).closest('form').submit();
})
})
</script>
Now comes the modification in process.php file
if (isset($_POST['approve'])) {
if (isset($_POST['check'])) {
foreach ($_POST['check'] as $value) {
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die(mysql_error());
}
}
} elseif(isset($_POST['edit'])){
//do the edit things here
} elseif(isset($_POST['delete'])){
foreach ($_POST['check'] as $value){
$sql = "DELETE FROM post WHERE ID=$value";//modify it
mysql_query($sql) or die(mysql_error());
}
}
NOTE
You may not want to mutiple checkbox for edit. You just need to tweak the javascript code above a little and it'l send the ID as a post variable on form submission from which you can retreive the details for one entry and then edit functions will come. I'l leave it to you. try it, post your trial code here and i'l give you a solution if it doesn't work.

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