Output not displaying all rows - php

Question

Having an issue with the output of records from a query run to display records.... It only shows the first row as the code specifies and then the next results all in.. paragraphs? I don't know if it has something to do
<?php
include 'core/init.php';
include 'includes/overall/header.php';
?>
<div class="article" style="width:900px !important">
<?php
$result = $sql = mysql_query("SELECT * FROM ref_employees WHERE employerid={$user_data['user_id']} ")
or die('Error in query : $sql. ' .mysql_error());
echo "<table border='0' class='table'>
<tr>
<th>ID Number</th>
<th>Employee Number</th>
<th>FirstName</th>
<th>LastName</th>
<th>MiddleName</th>
<th>Job Title</th>
<th>Employement Status</th>
<th>Contact</th>
<th>Email</th>
<th>Edit</th>
</tr>";
if (mysql_num_rows($sql) > 0)
{
while ($row = mysql_fetch_array($sql)){
if ($row['employed'] == '1'){
echo "<tr>";
echo "<td>" . $row['idnumber'] . "</td>";
echo "<td>" . $row['empnumber'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['middlename'] . "</td>";
echo "<td>" . $row['jobtitle'] . "</td>";
echo "<td>" . $row['employed'] . "</td>";
echo "<td>" . $row['contactnum'] . "</td>";
echo "<td>" . $row['contactemail'] . "</td>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "</tr>";
echo "</tr>";
echo "</table>";
}
}
}
?>
</div>
<?php include 'includes/overall/footer.php';
?>

Answer 1

You are using closing table tag into loop as
while ($row = mysql_fetch_array($sql)){
....
....
...
echo "</table>";
}
use table closing tag out of loop as
while ($row = mysql_fetch_array($sql)){
....
....
...
}
echo "</table>";