I have trouble with creating an approval form as am still php beginner,
the idea is
user submit a form am setting a default value"0" in the approved row at the table..
so behind the scenes the admin shows all members from this table where approved="0"
and this is the code
<code>
<?php
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</code>
I just want to add checkbox for every table user and when checked thier status changed to 1 in approved column
thanks all
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
$i = 1; //counter for the checkboxes so that each has a unique name
echo "<form action='process.php' method='post'>"; //form started here
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
<th>Update</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "<td><input type='checkbox' name='check[$i]' value='".$row['ID']."'/>";
echo "</tr>";
$i++;
}
echo "</table>";
echo "<input type='submit' name='approve' value='approve'/>";
echo "</form>";
mysql_close($con);
Now comes process.php
if(isset($_POST['approve'])){
if(isset($_POST['check'])){
foreach ($_POST['check'] as $value){
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die (mysql_error());
}
}
}
though you are using mysql_* functions here, i recommend you to use PDO
EDIT:
As per your request, this is the update.
Change this code in your admin panel script:
echo "<input type='submit' name='approve' value='approve'/>";
Delete the above line and add this instead:
echo "<input class='action' type='button' name='approve' value='approve' />";
echo "<input class='action' type='button' name='edit' value='edit' />";
echo "<input class='action' type='button' name='delete' value='delete' />";
echo "<input type='hidden' name='action' value='' id='action' />"; //Action (edit, approve or delete) will be set here which will be passed as POST variable on form submission
Now you will need some javascript to do some tricks.
Add the following code preferably head section in your admin panel script
<script type="text/javascript" src="jquery-1.7.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.action').click(function(){
var action = $(this).attr('name');
$('#action').val(action);
$(this).closest('form').submit();
})
})
</script>
Now comes the modification in process.php file
if (isset($_POST['approve'])) {
if (isset($_POST['check'])) {
foreach ($_POST['check'] as $value) {
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die(mysql_error());
}
}
} elseif(isset($_POST['edit'])){
//do the edit things here
} elseif(isset($_POST['delete'])){
foreach ($_POST['check'] as $value){
$sql = "DELETE FROM post WHERE ID=$value";//modify it
mysql_query($sql) or die(mysql_error());
}
}
NOTE
You may not want to mutiple checkbox for edit. You just need to tweak the javascript code above a little and it'l send the ID as a post variable on form submission from which you can retreive the details for one entry and then edit functions will come. I'l leave it to you. try it, post your trial code here and i'l give you a solution if it doesn't work.
Related
I'm trying to update a mySQL table after a button click..The button click is not the problem but I wonder how I can get the klant_pk which is unique to update a certain record in mySQL. As you see I print out the mySql table at first. So is there anyone who know how I can get the according klant_pk after I click on a button in the table..
Thanks
$result = mysqli_query($con, "SELECT * FROM bestelling");
echo "Bestellingen";
echo "<table border='1' align='center'>
<tr>
<th>Bestelling_pk</th>
<th>Klant_pk</th>
<th>Product</th>
<th>Commentaar</th>
<th>Tijd</th>
<th> Voortgang </th>
<th> Status </th>
</tr>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['bestelling_pk'] . "</td>";
echo "<td>" . $row['klant_pk'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['opmerking'] . "</td>";
echo "<td>" . $row['tijd'] . "</td>";
echo "<td> <input type='button' value='In Wacht' onclick='return change(this);' />";
echo "<td>" . $row['status'] . "</td>";
echo "</tr>";
}
echo "</table>";
while ($row = mysqli_fetch_array($result)) {
...
echo "<td id='klank_pk_".$row['klant_pk']."'>" . $row['klant_pk'] . "</td>";
...
echo "<td> <input type='button' value='In Wacht' onclick='change(getElementById('klank_pk_".$row['klant_pk']."').value);' />";
...
}
i wanted to ask I would I add up the points of all the drivers in the table produced below by the following code as this only displays points of all the drivers in each row ... There is a table Points which has points, position and a table Drivers having forename, surname.
<?php
session_start();
if ( !isset($_SESSION['loggedin']) ) {
header("Location: login.php");
}
$con=mysqli_connect("xxxxx","xxxxx","xxxxx","xxxx");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT Drivers.forename, Drivers.surname, Teams.name, Teams.engine, Points.points
From Drivers, Teams, Points");
echo "<table border='1'>
<tr>
<th>First name</th>
<th>Last name</th>
<th>Team Name</th>
<th>Engine</th>
<th>Points</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['forename'] . "</td>";
echo "<td>" . $row['surname'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['engine'] . "</td>";
echo "<td>" . $row['points'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
in your code, before the $while
$counter=0
while($row = mysqli_fetch_array($result))
{
$counter += $row['points'];
echo "<tr>";
echo "<td>" . $row['forename'] . "</td>";
echo "<td>" . $row['surname'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['engine'] . "</td>";
echo "<td>" . $row['points'] . "</td>";
echo "</tr>";
}
echo $counter; //echoes sum of points
I am stuck in one of my application module. I have to set multiple delete options in my application.
I have used the below code. The designing is perfectly fine. All what I want to add multiple delete options in it.
Below is the code which I have tried out:
<html>
<head>
<title>Strad Hosting Limited -Web Hosting</title>
<script language="javascript">
function validate()
{
var chks = document.getElementsByName('checkbox[]');
var hasChecked = false;
for (var i = 0; i < chks.length; i++)
{
if (chks[i].checked)
{
hasChecked = true;
break;
}
}
if (hasChecked == false)
{
alert("Please select at least one.");
return false;
}
return true;
}
</script>
</head>
<body >
<?php
$con=mysqli_connect("localhost","stradsol","D#v,b5TnQ!D!","stradsol_sales");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<form name='form1' method='post' action='' onSubmit='return validate();'>";
echo "<table border='1' style='
background-color: white;'>
<tr>
<th></th>
<th>id</th>
<th style='padding-left: 11px;'>Lead Generated Date </th>
<th>name</th>
<th>email</th>
<th>contacts</th>
<th>requirement</th>
<th style='display:none;'>Company name</th>
<th style='display:none;'>Address</th>
<th>Next Follow-Up date</th>
<th>Final_Details</th>
<th style='display:none;'>Status</th>
<th style='padding-left: 12px; display:none;'>Lead Closed Date</th>
<th>EDIT</th>
<th>Follow-up History</th>
<th>Add Follow-up</th>
<th>Delete Record</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input name='checkbox[]' type='checkbox' id='checkbox[]' value='".$rows['id']."'></td>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td><a href='config_info.php?id=" . $row['id'] . "'>".$row['name']."</a></td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['contacts'] . "</td>";
echo "<td>" . $row['requirement'] . "</td>";
echo "<td style='display:none;'>" . $row['company_name'] . "</td>";
echo "<td style='display:none;'>" . $row['address'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['final_details'] . "</td>";
echo "<td style='display:none;'>" . $row['status'] . "</td>";
echo "<td style='display:none;'>" . $row['lead_close'] . "</td>";
echo "<td><a href='edit_eg1.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "<td><a href='Follow_history.php?id=" . $row['id'] . "'>Follow_history</a></td>";
echo "<td><a href='add_follow.php?id=" . $row['id'] . "'>Followup</a></td>";
echo "<td><a href='delete.php?id=" . $row['id'] . "'>Delete</a></td>";
echo "</tr>";
}
echo "<tr><td><input name='delete' type='submit' id='delete' value='Delete'></td></tr>";
$count=mysqli_num_rows($result);
if(isset($_POST['delete'])){
for($i=0;$i<count($_POST['checkbox']);$i++){
$del_id=$_POST['checkbox'][$i];
$sql = "DELETE FROM Persons WHERE id='$del_id'";
echo $sql;
$result2 = mysqli_query($con,$sql);
}
// if successful redirect to delete_multiple.php
if($result2)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_table_del.php\">";
}
}
mysqli_close($con);
echo "</table>";
echo "</form>";
?>
<br><br>
[ Back To Home ]
</body>
</html>
I am stuck, the query is not working I think. I don't know what I am missing.
Try replacing
$sql = "DELETE FROM Persons WHERE id='$del_id'";
With
$sql = "DELETE FROM Persons WHERE id=$del_id";
I'm assuming the ID is a number so the single quotes aren't needed.
I am trying to retrieve records from db and put them into a table. I want to have an update button which can do some processing. Here is the code. It outputs properly. However the update button (image) doesn't work. Please help
<?php
echo "</br>";
echo "<table border='1'>
<tr>
<th>Order ID</th>
<th>Customer Number</th>
<th>Order Items</th>
<th>Transaction Time</th>
<th>Amount</th>
</tr>";
$con = mysql_connect('localhost', 'root', '');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("kaka", $con);
$sql="SELECT * FROM orders WHERE status = 'NRDY'";
$result2 = mysql_query($sql);
while($row1 = mysql_fetch_array($result2))
{
echo "<div class=\"update\"><form method='post' action=\"test.php\">\n";
echo "<tr>";
echo "<td><input type='hidden' name='order_id' value='".$row1['order_id']."'>" .$row1['order_id']. "</td>";
echo "<td><input type='hidden' name='cust_num' value='".$row1['cust_num']."'>" .$row1['cust_num']. "</td>";
echo "<td><input type='hidden' name='items' value='".$row1['items']."'>" .$row1['items']. "</td>";
echo "<td><input type='hidden' name='order_time' value='".$row1['order_time']."'>" .$row1['order_time']. "</td>";
echo "<td><input type='hidden' name='order_id' value='".$row1['amount']."'>" .$row1['amount']. "</td>";
//echo "<td>" . $row1['order_id'] . "</td>";
//echo "<td>" . $row1['cust_num'] . "</td>";
//echo "<td>" . $row1['items'] . "</td>";
//echo "<td>" . $row1['order_time'] . "</td>";
//echo "<td>" . $row1['amount'] . "</td>";
echo "<td>" . "<input type=\"image\" src=\"images/update.png\" alt=\"Update Row\" class=\"update\" title=\"Update Row\">\n" . "</td>";
echo "</tr>";
echo "</form></div>";
}
echo "</table>";
?>
Here is test.php
<?php
echo $_POST['order_id'];
?>
Use a validator. You aren't allowed to wrap divs or forms around table rows. Some browsers recover from this error by moving the div/form so it is outside the table (leaving the content behind). Your inputs are therefore not inside a form so shouldn't be expected to do anything.
im making some application form in PHP.
im putting all info returned from the database into a table.
Now i want to create a button on each line that changes something in the DB of that line.
but i have no idea to do that :S
Thank you!
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Email</th>
<th>age</th>
<th>position</th>
<th>experience</th>
<th>motivation</th>
<th>date</th>
<th>status</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['position'] . "</td>";
echo "<td>" . $row['exp'] . "</td>";
echo "<td>" . $row['motivation'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . '<input type="submit" name="submit" value="accept">' . "</td>";
echo "</tr>";
}
echo "</table>";
EDIT: get it working using another script:
echo "<td>Approve</td>";
and edit.php:
<?php
include("dbconnect.php");
$member_id = $_GET['id'];
$status = $_GET['status'];
echo $member_id;
echo $status;
if ($status == 'app')
$query = "update apps set status = 'approved' where id = $member_id";
mysql_query($query) or die (mysql_error());
?>
Create small form with parameters in the cell you want the button to do smth. This is the simpliest approach (approach with refresh).
One more solution is to use AJAX on button click and forward action to some endpoint. This way it would be dynamic and probably what you are want to implement.
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Email</th>
<th>age</th>
<th>position</th>
<th>experience</th>
<th>motivation</th>
<th>date</th>
<th>status</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['position'] . "</td>";
echo "<td>" . $row['exp'] . "</td>";
echo "<td>" . $row['motivation'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . '<form type="POST"><input type="hidden" name="whatever" value="$row['id']"><input type="submit" name="submit_btn" value="accept"></form>' . "</td>";
echo "</tr>";
}
echo "</table>";
in this way, you could get a form in each row of the table. Now, you just need to use php POST function.
if(isset($_POST['submit_btn']))
{
//whatever u need to do
}