implement a function for holidays in a year? - php

Question

I have a list of holidays like:
var holiDays =[[2013,01,01,'New Years Day'],[2013-05-27, 'Memorial Day']]
and showing on the celender but this list is hard coded so i want a function in php so that all holidays list visible year wise.
$(function() {
$("#id_holiday_date").datepicker({
beforeShowDay: setHoliDays
});
// set holidays function which is configured in beforeShowDay
function setHoliDays(date) {
for (i = 0; i < holiDays.length; i++) {
if (date.getFullYear() == holiDays[i][0]
&& date.getMonth() == holiDays[i][1] - 1
&& date.getDate() == holiDays[i][2]) {
return [true, 'holiday', holiDays[i][3]];
}
}
return [true, ''];
}
});
this function work properly in date picker.this date picker takes date from hardcoded array.
I want a function like that:
function calculateHolidays($year = '') {
$holiDays = Array();
$year = ($year != '') ? $year : date('Y'); //Default Current Year
$newYear = "$year-01-01";
$temp = "$year-05-00 last monday";
$memorialDay = strtotime($temp);//last Monday of May for Current Year
thanks in advance

Answer 1

I'd take a look at PEAR date holidays if I were you.

Answer 2

Here is one way to do it - if you want to find all the brackets [] for a given year:
function display_holidays($year,$list){
echo "<ul>";
$list=str_replace(array('[[',']]','],['),array('[',']',']|['),$list);
$list=explode("|",$list);
foreach($list as $item){
// find the items with the correct year
if(strstr($item,"[".$year)){
echo "<li>".$item."</li>";
}
}
echo "</ul>";
}
Usage example:
$list="[[2012,01,01,'New Years Day'],[2013,05,27, 'Memorial Day']]";
$year=2013;
display_holidays($year,$list);
the outcome will be:
<ul>
<li>[2013,05,27, 'Memorial Day']</li>
</ul>
ps: but please explain in more detail what you want to achieve.