I am trying to show events that occur either today or on a later date where today is specifically the problem.
public function getInspirationsMeetingIds()
{
$ids = [];
if (($inspirationMeetings = $this->getCustomField('meetings'))) {
foreach ($inspirationMeetings as $meeting) {
$row = new Inspiration($meeting['meeting']);
$dateFrom = $row->getCustomField('date');
if (strtotime($dateFrom) >= time()) {
$ids[] = $row->getId();
}
}
}
return $ids;
}
For some reason this will only show events that are greater than time() and not the events that are today, but then when i try this:
if (strtotime($dateFrom) <= time()) {
$ids[] = $row->getId();
}
Today's and older events are shown.
I think you need to add a timestamp to your datefrom.
Strtotime will add noon if time is omitted.
See this example https://3v4l.org/cYKO4
if (strtotime($dateFrom ) >= strtotime(date("Y-m-d 00:00"))) {
Will make it show all of datefrom
Edit added the 00:00 at the wrong side
Use the DateTime class http://php.net/manual/en/class.datetime.php
time() gives seconds since Jan 1st 1970. The chance that you hit the exact second is very small, so it will hardly ever match.
Instead, create a date with the time.
$date = new DateTime($dateFrom); // or DateTime::createFromFormat($format, $dateFrom);
$today = new DateTime();
if ($date >= $today) {
// should work
}
I would like to get the first date in the future from an array of dates. I've tried to write my own function, which did not get the job done.
private static function getClosestDate($date, array $dates, $last) {
$interval = array();
$now = strtotime(date('Y-m-d'));
foreach ($dates as $d) {
$dateTime = strtotime($date);
$toTime = strtotime($d);
// Do not parse dates older than today
if (strtotime($d) < $now) { continue 1; }
// Only do dates in the future
if ($toTime < $dateTime) { continue 1; }
$interval[] = abs($dateTime - $toTime);
}
// If there is no interval, use the latest date
if (!count($interval)) {
return $last;
}
asort($interval);
$closest = key($interval);
return $dates[$closest];
}
This code works but it also works the other way around. Next to that, when there is no last date, it should use the $last parameter which is the last date.
The reason I want to know this is because I have a range of dates on which people can book nights on. I want to know the difference in days to calculate the amount of nights they can book. Calculating a difference in dates is easy, but I do need to know when the next booking appears. These are provided in the $dates parameter.
What should I change in my code to get it fixed (I've tried to continue the foreach whenever the date was in the past based on the $date parameter) or can someone provide me the code?
I've fixed the problem myself. Instead of using the dates array I'm now using the date as key in the interval to retrieve the date again. This does work properly.
private static function getClosestDate($date, array $dates, $last) {
$interval = array();
$now = strtotime(date('Y-m-d'));
foreach ($dates as $d) {
$dateTime = strtotime($date);
$toTime = strtotime($d);
// Do not parse dates older than today
if (strtotime($d) < $now) { continue 1; }
// Only do dates in the future
if ($toTime < $dateTime) { continue 1; }
$interval[$d] = abs($dateTime - $toTime);
}
// If there is no interval, use the latest date
if (!count($interval)) {
return $last;
}
asort($interval);
$closest = key($interval);
return $closest;
}
I have some PHP code to calculate the number of days between two specific dates. The difference should not count Sundays and Saturdays. Also, I have an array of dates, which includes holidays, which also need to be skipped.
I gave the starting date as 01-05-2015 and ending date as 01-06-2015. I gave the entire days in the month of may as array. Thus the difference should be 1 day. But I am getting the output as 7. What is the problem? Here is the code.
function dateRange($first, $last) {
$dates = array();
$current = strtotime($first);
$now = $current;
$last = strtotime($last);
while( $current <= $last ) {
if (date('w', $current) != 0){
$dates[] = date('d-m-Y', $current);
}
$current = strtotime('+1 day', $current);
}
unset($dates[0]);
return $dates;
}
$datea = "01-05-2015";
$date = "01-06-2015";
$hdsarray = array("1-05-2015","2-05-2015","4-05-2015","5-05-2015","7-05-2015","8-05-2015","9-05-2015","11-05-2015","12-05-2015","14-05-2015","15-05-2015","16-05-2015","18-05-2015","19-05-2015","21-05-2015","22-05-2015","23-05-2015","25-05-2015","26-05-2015","28-05-2015","29-05-2015","30-05-2015");
$datesarray = dateRange($datea, $date);
$result = array_diff($hdsarray,$datesarray);
$date_diff = sizeof($result);
echo $date_diff;
The only problem I can see is in the usage of array_diff, It actually includes the sat and sun which is excluded by dateRange function, if not found in holidays list.
Instead, you can pass your holiday dates in dateRange function, and filter over there.
function dateRange($first, $last, $excludeDates) {
$dates = array();
$current = strtotime($first);
$now = $current;
$last = strtotime($last);
while( $current <= $last ) {
if (date('w', $current) != 0 && date('w', $current) != 6 && !in_array(date('j-m-Y', $current), $excludeDates)){
$dates[] = date('d-m-Y', $current);
}
$current = strtotime('+1 day', $current);
}
return $dates;
}
$datea = "01-05-2015";
$date = "01-06-2015";
$hdsarray = array("1-05-2015","2-05-2015","4-05-2015","5-05-2015","7-05-2015","8-05-2015","9-05-2015","11-05-2015","12-05-2015","14-05-2015","15-05-2015","16-05-2015","18-05-2015","19-05-2015","21-05-2015","22-05-2015","23-05-2015","25-05-2015","26-05-2015","28-05-2015","29-05-2015","30-05-2015");
$datesarray = dateRange($datea, $date, $hdsarray);print_r($datesarray);
Result:
Array
(
[0] => 06-05-2015
[1] => 13-05-2015
[2] => 20-05-2015
[3] => 27-05-2015
[4] => 01-06-2015
)
All the 5 dates come in the result, are not sat, sun, and also not there in holidays list.
It seems that there are several problems here. First, as pointed out by others the condition:
if (date('w', $current) != 0){
only checks for Sundays, if it should also include Saturday's it should be:
if (date('w', $current) != 0 && date('w', $current) != 6){
Secondly, it seems that the $hdsarray array does not contain all of the days in May. It seems that all of the Wednesdays are missing.
The third issue is that you are using array_diff on two arrays, one containing Dates and the other ones containing Strings. From the documentation:
Two elements are considered equal if and only if (string) $elem1 ===
(string) $elem2. In words: when the string representation is the same.
In your $hdsarray you are using "1-05-2015" to denote the first day of the month, while:
echo date('d-m-Y', strtotime("1-05-2015"));
results in "01-05-2015". You will need to add an additional 0 in $hdsarray for these dates or work with dates as well.
Last but not least, the current algorithm will not work correctly if the $hdsarray contains dates for a Saturday or Sunday, the result of array_diff will still contain these dates. Since you want to filter the result of daterange the array_filter function might be more suitable.
Despite an answer has already been provided, here is a little snippet with a class handling everything for you:
<?php
class dateRange {
protected $start, $end, $daysToExclude, $datesToExclude;
function __construct($dateStart, $dateEnd, $daysToExclude, $datesToExclude) {
$this->start = $dateStart;
$this->end = $dateEnd;
$this->daysToExclude = $daysToExclude;
$this->datesToExclude = $this->fixFormat($datesToExclude);
}
public function getRangeLength ($callback = null) {
$tmp = array();
$now = strtotime($this->start);
$to = strtotime($this->end);
while ( $now <= $to ) {
if (!in_array(date("w", $now), $this->daysToExclude)) {
$tmp[] = date('d-m-Y', $now);
}
$now = strtotime('+1 day', $now);
}
is_callable($callback) && call_user_func($callback, array_diff($tmp,$this->datesToExclude));
return count(array_diff($tmp,$this->datesToExclude));
}
private function fixFormat($el) {
if (!is_array($el)) {
return false;
}
else {
foreach ($el as &$value) {
$value = date("d-m-Y",strtotime($value));
}
return $el;
}
}
}
?>
I decided to keep your current logic (using date_diff), but I thought that, in the future, you may have your boss telling you "You know what? I don't want to have mondays aswell there" so, with the current system, you will have to edit your function manually and, perhaps, you won't remember anymore what you did.
The class above expects four parameters:
dateStart (d-m-Y format)
dateEnd (d-m-Y format)
daysToExclude (array with IDs of the days to exclude -> example array(0,6) to exclude saturdays and sundays).
datesToExclude (array with the dates to exclude, every format supported).
The class will automatically fix the datesToExclude array format in order to allow you to use date_diff.
Here is an example to use it, following your case:
<?php
$dateStart = "01-05-2015";
$dateEnd = "01-06-2015";
$daysToExclude = array(0,6);
$exclusions = array(
"1-05-2015",
"2-05-2015",
"4-05-2015",
"5-05-2015",
"7-05-2015",
"8-05-2015",
"9-05-2015",
"11-05-2015",
"12-05-2015",
"14-05-2015",
"15-05-2015",
"16-05-2015",
"18-05-2015",
"19-05-2015",
"21-05-2015",
"22-05-2015",
"23-05-2015",
"25-05-2015",
"26-05-2015",
"28-05-2015",
"29-05-2015",
"30-05-2015"
);
$dateRange = new dateRange($dateStart, $dateEnd, $daysToExclude, $exclusions);
echo $dateRange->getRangeLength();
?>
The code above outputs 5.
The function getRangeLength also accepts a callback and will return the array resulting of the date_diff operation, so you can also:
$dateRange->getRangeLength(function($res) {
echo "Literal output: <br />";
print_r($res);
echo "<br />count is: " . count($res);
});
The above outputs:
Literal output:
Array ( [3] => 06-05-2015 [8] => 13-05-2015 [13] => 20-05-2015 [18] => 27-05-2015 [21] => 01-06-2015 )
count is: 5
So if you later will need to remove mondays too, you will be able to easily do that by changing daysToExclude to array(0,1,6);
Hope this will be helpful to anyone else who will need this, despite a valid answer has already been posted.
Your original problem, in any case, was pretty much related to the array_diff function, which was NOT doing its job because of the fact that the date strings were not compatible, because "1-01-2015" is different from "01-01-2015", unless you first convert BOTH of them to times and then back to dates.
The code is fine (except that $nowis not used at all). The problem is the $hdsarray is wrong:
It should $hdsarray = array("01-05-2015", "02-05-2015", "04-05-2015", "05-05-2015", "07-05-2015", "08-05-2015", "09-05-2015",...);
date('d-m-Y', $current);will always return a leading 0 for all days between 1 and 9.
That's where the difference comes from.
i have a date input javascript that lets users add as many dates onto the database at once, this is using implode and stores as one big string like 2015-01-01 2015-01-02 etc...
I also want this to find out if one of those days contains a weekend day. I have no idea how the string and date parameters meet with this.
$week_end_check = array();
$week_end_check = implode(' ',date('D'), strtotime($_POST['dates']));
if ((strpos($week_end_check,'Sun')) || (strpos($week_end_check,'Sat' ))) {
$weekend = '1';
}
the above wont work as I know but can somebody help me...you can understand what i am after by the above i hope.
Here's a less contrived way to do this:
$weekend = false;
foreach($_POST['dates'] as $date) {
$day = (new DateTime($date))->format('D');
if (in_array($day, array('Sun', 'Sat'))) {
$weekend = true;
break;
}
}
Set $weekend to false by default
Loop through each date
Get the day of the week
Check to see if it "Sun" or "Sat"
Set $weekend to true
End the loop once we know a weekend day has been found
Please use this example. .
$string = "2015-01-01 2015-01-02 2015-01-04 2015-01-06";
$array = explode(" ",$string);
$weekend_array = array();
$total = count($array);
for($i=0;$i<$count;$i++)
{
$my_day = date("D", strtotime($array[$i]));
if($my_day=="Sun" || $my_day=="Sat")
{
$weekend_array[] = $array[$i];
}
}
echo "<pre>";
print_r($weekend_array);
echo "<pre>";
This question already has answers here:
I have 2 dates in PHP, how can I run a foreach loop to go through all of those days?
(13 answers)
Closed 1 year ago.
I want to fill an array with values. The keys of this array should be readable dates in the format 'YEAR-MONTH-DAY'. Starting point is '2010-5-25'.
The process should abort on the current date. Obviously, all dates should be valid dates.
I thought about doing this loop. But it seems that PHP is not able to check the condition of more than one in a 'for' loop. It does not give me any warnings or errors, though.
for ($d = 25, $m = 5, $y = 2010,
$this_day = date('j'),
$this_month = date('n'),
$this_year = date('Y');
($y <= $this_year) && ($m <= $this_month) && ($d <= $this_day);
$d++)
{
$values[$y.'-'.$m.'-'.$d] = 0; //fill array
$d++;
if(!checkdate($m, $d, $y)){
$d = 1;
$m++;
if($m > 12) { $m = 1; $y++; }
}
}
Doing this with nested loops would be rather painful.
One solution would be to use integer times as keys and then convert them later in another loop into the readable dates.
Is there a more efficient way?
Here is code that does some error checking, for example, valid dates provided and start date cannot be bigger than end date:
function arrayKeyDates($start, $end='now') {
// can use DateTime::createFromFormat() instead
$startDate = new DateTime($start);
$endDate = new DateTime($end);
if ($startDate === false) {
// invalid start date.
return;
}
if ($endDate === false) {
// invalid end date.
return;
}
if ($startDate > $endDate) {
// start date cannot be greater than end date.
return;
}
$dates = array();
while($startDate <= $endDate) {
$dates[$startDate->format('Y-n-j')] = 0;
$startDate->modify('+1 day');
}
return $dates;
}
print_r(arrayKeyDate('2014-11-30'));
I get the following output:
Array
(
[2014-11-30] => 0
[2014-12-1] => 0
[2014-12-2] => 0
[2014-12-3] => 0
[2014-12-4] => 0
[2014-12-5] => 0
[2014-12-6] => 0
[2014-12-7] => 0
)
Error handling code is left to you.
UPDATE (DateTime::createFromFormat)
If you want to create the DateTime objects using a custom format you can, in my function, you can do something like this:
$startDate = DateTime::createFromFormat('Y-n-j', $start);
Where $start would have the value 2010-5-25.
For more information, see: http://php.net/manual/en/datetime.createfromformat.php
$startDate = new \DateTime('2010-05-25');
$endDate = new \DateTime();
$interval = new \DateInterval('P1D');
$period = new \DatePeriod ($startDate, $interval, $endDate);
$dates = array();
foreach ($period as $key => $date) {
$dates[$date->format('Y-m-d')] = null;
}
var_dump($dates);
Simply you can try using strtotime(). Example:
$values = array();
$oldDate = strtotime('2010-05-25');
while($oldDate <= time()){
$values[date('Y-m-d', $oldDate)] = 'Your value';
$oldDate += 86400;
//Other codes
}
I know this is an old question, but might be helpful for new viewers a shorter version
$dummyArray = array_fill(1, 7, 0);
$dates = array_flip(array_map(function($val, $idx) {
return date_create('2010-5-25')->modify('-' . $idx . ' days')->format('Y-m-d');
}, $dummyArray, array_keys($dummyArray)));
I'm basically generating a dummy array which is going to have the numbers of days I want to extract as index, and then converting those to dates with array_map, after which I just flip the array to have the dates as keys instead of values
I took the liberty to clean up your code a little to make it readable:
<?php
$this_day = date('j');
$this_month = date('n');
$this_year = date('Y');
echo sprintf("Today: d-m-y: %s-%s-%s\n", $this_day, $this_month, $this_year);
for ($d = 25, $m = 5, $y = 2010;
($y <= $this_year) && ($m <= $this_month) && ($d <= $this_day);
$d++) {
echo sprintf("Date: d-m-y: %s-%s-%s\n", $d, $m, $y);
$values[$y.'-'.$m.'-'.$d] = 0; //fill array
$d++;
if(!checkdate($m, $d, $y)){
$d = 1;
$m++;
if($m > 12) { $m = 1; $y++; }
}
}
This shows that the code works perfectly well. That is if you chose the correct condition!
Today is the 07th, but your initial values start with the 25th which falsifies the condition. To verify chose a start day of '02' and see the output...
I guess you want to re-check your condition. Most likely it is something else you want to express...
First of all; the loop doesn't execute because you are checking separately if year number is lower then current year number, etc. But today is the 7th, and you start at the 25th of may 2010:
$d = 25;
$this_day = date('j'); // today: 7
$loop = $d <= $this_day; // evaluates to false
Because the 'day-check' evaluates to false, the whole expression evaluates to false. So the loop will only start to run on december the 25th.
You can better use the DateTime object to construct the dates and perform modifications on the created object. This will also safe you a lot of sweat with stuff like leap years etc. Example:
for (
$start = new DateTime('2010-05-25'),
$today = new DateTime('now') ;
$start->diff($today)->format('%a') >= 0 ;
$start->modify('+1 day')
) {
$values[$start->format('Y-m-d')] = 0;
}
easy does it!