Datetimepicker form validation - php

Question

I've been trying to create a validation for my form. I've been looking around on how to disable weekends in date time picker as well as holidays. I am using this Jquery script from Trentrichardson http://trentrichardson.com/examples/timepicker/
I am sort of new in JS and am about to pull out my hair as I cannot find a way to make this code work:
$(document).ready(function(){
$('.timepicker').datetimepicker({ beforeShowDay: $.datepicker.noWeekends });
var natDays = [
[2, 26, 'ph'], [2, 6, 'ph'], [2, 17, 'ph']
];
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1
&& date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
});
I found this code yesterday, which is the correct answer(Can the jQuery UI Datepicker be made to disable Saturdays and Sundays (and holidays)?), but I can't get it to work. It doesn't show the holidays but weekends have been disabled(working).
Any ideas?

Answer 1

Checking whether a date is a Saturday or Sunday should not require a separate function:
if (date.getDay() % 6) {
// date is not a weekend
} else {
// date is a weekend
}
Checking for public holidays (which can be much more difficult given that dates change from year to year and place to place) can be easy too. Create a list of the dates in a set format (ISO8601 is convenient), then you can just test against current date:
// You may have a function like this already
// d is a javascript Date object
function dateToISO(d) {
function z(n){return (n<10? '0':'')+n}
return d.getFullYear() + '-' +
z(d.getMonth() + 1) + '-' +
z(d.getDate());
}
// s is a date string in ISO8601 format
function isPublicHoliday(s) {
var holidays = '2012-12-25 2012-12-26'; // list holidays
var m = holidays.match(s);
return !!(m && m.length);
}
isPublicHoliday(dateToISO(date)); // true for 2012-12-25
Of course you will want to implement the above differently, but it gives you the gist of it. Presumably the date picker returns a date object, or a formatted string that you can test. Testing against a string is very fast and saves a lot of hassle with arrays and functions. Very easy to maintain too, since the dates are quite human readable.