I'm trying to match a certain string of the url using preg_match but I need to match either one or the other string and I can't find the correct syntax.
What I'm using now is:
$is_url_en = preg_match ("/\b95\b/i", $iframeurl);
This searches for the number "95" in the url. However I also want to match "en" as well but I don't know how to use the 'or' delimiter. I've seen somewhere the following:
$is_url_en = preg_match ("/\b95\b/i|/\ben\b/i", $iframeurl);
...but it doesn't work. Any hints please?
Don't repeat the / and /i. Those delimit the regex so they should only be there once.
$is_url_en = preg_match ("/\b95\b|\ben\b/i", $iframeurl);
You could then simplify this to:
$is_url_en = preg_match ("/\b(95|en)\b/i", $iframeurl);
Related
I'm trying to retrieve the followed by count on my instagram page. I can't seem to get the Regex right and would very much appreciate some help.
Here's what I'm looking for:
y":{"count":
That's the beginning of the string, and I want the 4 numbers after that.
$string = preg_replace("{y"\"count":([0-9]+)\}","",$code);
Someone suggested this ^ but I can't get the formatting right...
You haven't posted your strings so it is a guess to what the regex should be... so I'll answer on why your codes fail.
preg_replace('"followed_by":{"count":\d')
This is very far from the correct preg_replace usage. You need to give it the replacement string and the string to search on. See http://php.net/manual/en/function.preg-replace.php
Your second usage:
$string = preg_replace(/^y":{"count[0-9]/","",$code);
Is closer but preg_replace is global so this is searching your whole file (or it would if not for the anchor) and will replace the found value with nothing. What your really want (I think) is to use preg_match.
$string = preg_match('/y":\{"count(\d{4})/"', $code, $match);
$counted = $match[1];
This presumes your regex was kind of correct already.
Per your update:
Demo: https://regex101.com/r/aR2iU2/1
$code = 'y":{"count:1234';
$string = preg_match('/y":\{"count:(\d{4})/', $code, $match);
$counted = $match[1];
echo $counted;
PHP Demo: https://eval.in/489436
I removed the ^ which requires the regex starts at the start of your string, escaped the { and made the\d be 4 characters long. The () is a capture group and stores whatever is found inside of it, in this case the 4 numbers.
Also if this isn't just for learning you should be prepared for this to stop working at some point as the service provider may change the format. The API is a safer route to go.
This regexp should capture value you're looking for in the first group:
\{"count":([0-9]+)\}
Use it with preg_match_all function to easily capture what you want into array (you're using preg_replace which isn't for retrieving data but for... well replacing it).
Your regexp isn't working because you didn't escaped curly brackets. And also you didn't put count quantifier (plus sign in my example) so it would only capture first digit anyway.
I'm trying to write a very simple markup language in PHP that contains tags like [x=123], and I need to be able to match that tag and extract only the value of x.
I'm assuming the answer involves regex but maybe I'm wrong.
So if we had a string:
$str = "F9F[x=]]^$^$[x=123]#3j3E]]#J";
And a regular expression to match:
/^\[x=.+\]$/
How would we get only the ".+" portion of the matching string into a variable?
You can use preg_match to search a string for a regular expression.
Check out the documentation here: http://www.php.net/manual/en/function.preg-match.php for more information on how to use it (as well as some examples). You might also want to take a look at preg_grep.
Following code should work for you:
$str = "F9F[x=]]^$^$[x=123]#3j3E]]#J";
if (preg_match('~\[x=(?<valX>\d+)\]~', $str, $match))
echo $match['valX'] . "\n";
OUTPUT:
123
I got the following URL
http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego
and I want to extract
B000NO9GT4
that is the asin...to now, I can get search between the string, but not in this way I require. I saw the split functin, I saw the explode. but cant find a way out...also, the urls will be different in length so I cant hardcode the length two..the only thing which make some sense in my mind is to split the string so that
http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/
become first part
and
B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego
becomes the 2nd part , from the second part , I should extract B000NO9GT4
in the same way, i would want to get product name LEGO-Ultimate-Building-Set-Pieces from the first part
I am very bad at regex and cant find a way out..
can somebody guide me how I can do it in php?
thanks
This grabs both pieces of information that you are looking to capture:
$url = 'http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego';
$path = parse_url($url, PHP_URL_PATH);
if (preg_match('#^/([^/]+)/dp/([^/]+)/#i', $path, $matches)) {
echo "Description = {$matches[1]}<br />"
."ASIN = {$matches[2]}<br />";
}
Output:
Description = LEGO-Ultimate-Building-Set-Pieces
ASIN = B000NO9GT4
Short Explanation:
Any expressions enclosed in ( ) will be saved as a capture group. This is how we get at the data in $matches[1] and $matches[2].
The expression ([^/]+) says to match all characters EXCEPT / so in effect it captures everything in the URL between the two / separators. I use this pattern twice. The [ ] actually defines the character class which was /, the ^ in this case negates it so instead of matching / it matches everything BUT /. Another example is [a-f0-9] which would say to match the characters a,b,c,d,e,f and the numbers 0,1,2,3,4,5,6,7,8,9. [^a-f0-9] would be the opposite.
# is used as the delimiter for the expression
^ following the delimiter means match from the beginning of the string.
See www.regular-expressions.info and PCRE Pattern Syntax for more info on how regexps work.
You can try
$str = "http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego" ;
list(,$desc,,$num,) = explode("/",parse_url($str,PHP_URL_PATH));
var_dump($desc,$num);
Output
string 'LEGO-Ultimate-Building-Set-Pieces' (length=33)
string 'B000NO9GT4' (length=10)
I'm trying to match the value of query v in the following regex:
http:\/\/www\.domain\.com\/videos\/video.php\?.*v=([a-z0-9-_]+)
A sample url:
http://www.domain.com/videos/video.php?v=9Gu0sd2dmm91B9b1
The url is always www and I'm only trying to match the v value. Does anyone know what's wrong with my syntax?
Use the parse_url() function. It's way easier to use:
$url_components = parse_url("http://www.domain.com/videos/video.php?v=9Gu0sd2dmm91B9b1");
echo $url_components['query'];
From there I think you can do the rest and slice off the first couple of letters. Once you do that you're left with only the stuff after v=.
you forget the capital letters
http:\/\/www\.domain\.com\/videos\/video.php\?.*v=([a-zA-Z0-9-_]+)
You are not escaping the period '.' in video.php. I also use a different delimiter if I am escaping paths/URL's - like this:
preg_match( "#http://www\.domain\.code/videos/video\.php\?.*v=([^&]*)#", $url, $matches );
If the v= is in the middle of the query string,
v=([^&]*)
.. will match everything up to another & symbol, just in case characters other than alphas and _,- end up in there for some reason.
How can convert the below youtube urls
$url1 = http://www.youtube.com/watch?v=136pEZcb1Y0&feature=fvhl
$url2 = http://www.youtube.com/watch?feature=fvhl&v=136pEZcb1Y0
into
$url_embedded = http://www.youtube.com/v/136pEZcb1Y0
using Regular Expressions?
Here's an example solution:
PHP:
preg_replace('/.+(\?|&)v=([a-zA-Z0-9]+).*/', 'http://youtube.com/watch?v=$2', 'http://www.youtube.com/watch?v=136pEZcb1Y0&feature=fvhl');
Match:
^.+(\?|&)v=([a-zA-Z0-9]+).*$
Replace with:
http://youtube.com/watch?v=$2
Here's how it works: regex analyzer.
suicideducky's answer is fine, but you changed the requirements. Try
preg_match($url1, "/v=(\w+)/", $matches);
$url_embedded = "http://www.youtube.com/v/" . $matches[1];
In case the wrong version was still cached, I meant $matches[1]!
add the string "http://www.youtube.com/watch/"
to the result of applying the regex "v=(\w+)" to the url(s) should do the job.
\w specifies alphanumeric characters (a-z, A-Z, 0-9 and _) and will thus stop at the &
EDIT for updated question.
My approach seems a little hackish.
so get the result of applying the regex "v=(\w+)" and then apply the regex "(\w+)" to it.
Then prefix it with the string "http://www.youtube.com/v/".
so to sum up:
"http://www.youtube.com/v/" + ( result of "(\w+)" applies to the result of ( "v=(\w+)" applied to the origional url ) )
EDITED AGAIN this approach assumes you are using a regex function that matches a substring instead of the whole string
Also, MvanGeest's version is superior to mine.