How can convert the below youtube urls
$url1 = http://www.youtube.com/watch?v=136pEZcb1Y0&feature=fvhl
$url2 = http://www.youtube.com/watch?feature=fvhl&v=136pEZcb1Y0
into
$url_embedded = http://www.youtube.com/v/136pEZcb1Y0
using Regular Expressions?
Here's an example solution:
PHP:
preg_replace('/.+(\?|&)v=([a-zA-Z0-9]+).*/', 'http://youtube.com/watch?v=$2', 'http://www.youtube.com/watch?v=136pEZcb1Y0&feature=fvhl');
Match:
^.+(\?|&)v=([a-zA-Z0-9]+).*$
Replace with:
http://youtube.com/watch?v=$2
Here's how it works: regex analyzer.
suicideducky's answer is fine, but you changed the requirements. Try
preg_match($url1, "/v=(\w+)/", $matches);
$url_embedded = "http://www.youtube.com/v/" . $matches[1];
In case the wrong version was still cached, I meant $matches[1]!
add the string "http://www.youtube.com/watch/"
to the result of applying the regex "v=(\w+)" to the url(s) should do the job.
\w specifies alphanumeric characters (a-z, A-Z, 0-9 and _) and will thus stop at the &
EDIT for updated question.
My approach seems a little hackish.
so get the result of applying the regex "v=(\w+)" and then apply the regex "(\w+)" to it.
Then prefix it with the string "http://www.youtube.com/v/".
so to sum up:
"http://www.youtube.com/v/" + ( result of "(\w+)" applies to the result of ( "v=(\w+)" applied to the origional url ) )
EDITED AGAIN this approach assumes you are using a regex function that matches a substring instead of the whole string
Also, MvanGeest's version is superior to mine.
Related
I have this link, and i need to work only with the numbers from that link.
How would i extract them?
I didn't find any answer that would work with codepcetion.
https://www.my-website.com/de/booking/extras#tab-nav-extras-1426
I tired something like this.
$I->grabFromCurrentUrl('\d+');
But i won't work.
Any ideas ?
Staying within the framework:
The manual clearly says that:
grabFromCurrentUrl
Executes the given regular expression against the current URI and
returns the first capturing group. If no parameters are provided, the
full URI is returned.
Since you didn't used any capturing groups (...), nothing is returned.
Try this:
$I->grabFromCurrentUrl('~(\d+)$~');
The $ at the end is optional, it just states that the string should end with the pattern.
Also note that the opening and closing pattern delimiters you would normally use (/) are replaced by tilde (~) characters for convenience, since the input string has a great chance to contain multiple forward slashes. Custom pattern delimiters are completely standard in regexp, as #Naktibalda pointed it out in this answer.
You can use parse_url() to parse entire URL and then extract the part which is most interested for you. After that you can use regex to extract only numbers from the string.
$url = "https://www.my-website.com/de/booking/extras#tab-nav-extras-1426";
$parsedUrl = parse_url($url);
$fragment = $parsedUrl['fragment']; // Contains: tab-nav-extras-1426
$id = preg_replace('/[^0-9]/', '', $fragment);
var_dump($id); // Output: string(4) "1426"
A variant using preg_match() after parse_url():
$url = "https://www.my-website.com/de/booking/extras#tab-nav-extras-1426";
preg_match('/\d+$/', parse_url($url)['fragment'], $id);
var_dump($id[0]);
// Outputs: string(4) "1426"
I'm trying to retrieve the followed by count on my instagram page. I can't seem to get the Regex right and would very much appreciate some help.
Here's what I'm looking for:
y":{"count":
That's the beginning of the string, and I want the 4 numbers after that.
$string = preg_replace("{y"\"count":([0-9]+)\}","",$code);
Someone suggested this ^ but I can't get the formatting right...
You haven't posted your strings so it is a guess to what the regex should be... so I'll answer on why your codes fail.
preg_replace('"followed_by":{"count":\d')
This is very far from the correct preg_replace usage. You need to give it the replacement string and the string to search on. See http://php.net/manual/en/function.preg-replace.php
Your second usage:
$string = preg_replace(/^y":{"count[0-9]/","",$code);
Is closer but preg_replace is global so this is searching your whole file (or it would if not for the anchor) and will replace the found value with nothing. What your really want (I think) is to use preg_match.
$string = preg_match('/y":\{"count(\d{4})/"', $code, $match);
$counted = $match[1];
This presumes your regex was kind of correct already.
Per your update:
Demo: https://regex101.com/r/aR2iU2/1
$code = 'y":{"count:1234';
$string = preg_match('/y":\{"count:(\d{4})/', $code, $match);
$counted = $match[1];
echo $counted;
PHP Demo: https://eval.in/489436
I removed the ^ which requires the regex starts at the start of your string, escaped the { and made the\d be 4 characters long. The () is a capture group and stores whatever is found inside of it, in this case the 4 numbers.
Also if this isn't just for learning you should be prepared for this to stop working at some point as the service provider may change the format. The API is a safer route to go.
This regexp should capture value you're looking for in the first group:
\{"count":([0-9]+)\}
Use it with preg_match_all function to easily capture what you want into array (you're using preg_replace which isn't for retrieving data but for... well replacing it).
Your regexp isn't working because you didn't escaped curly brackets. And also you didn't put count quantifier (plus sign in my example) so it would only capture first digit anyway.
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
I got the following URL
http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego
and I want to extract
B000NO9GT4
that is the asin...to now, I can get search between the string, but not in this way I require. I saw the split functin, I saw the explode. but cant find a way out...also, the urls will be different in length so I cant hardcode the length two..the only thing which make some sense in my mind is to split the string so that
http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/
become first part
and
B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego
becomes the 2nd part , from the second part , I should extract B000NO9GT4
in the same way, i would want to get product name LEGO-Ultimate-Building-Set-Pieces from the first part
I am very bad at regex and cant find a way out..
can somebody guide me how I can do it in php?
thanks
This grabs both pieces of information that you are looking to capture:
$url = 'http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego';
$path = parse_url($url, PHP_URL_PATH);
if (preg_match('#^/([^/]+)/dp/([^/]+)/#i', $path, $matches)) {
echo "Description = {$matches[1]}<br />"
."ASIN = {$matches[2]}<br />";
}
Output:
Description = LEGO-Ultimate-Building-Set-Pieces
ASIN = B000NO9GT4
Short Explanation:
Any expressions enclosed in ( ) will be saved as a capture group. This is how we get at the data in $matches[1] and $matches[2].
The expression ([^/]+) says to match all characters EXCEPT / so in effect it captures everything in the URL between the two / separators. I use this pattern twice. The [ ] actually defines the character class which was /, the ^ in this case negates it so instead of matching / it matches everything BUT /. Another example is [a-f0-9] which would say to match the characters a,b,c,d,e,f and the numbers 0,1,2,3,4,5,6,7,8,9. [^a-f0-9] would be the opposite.
# is used as the delimiter for the expression
^ following the delimiter means match from the beginning of the string.
See www.regular-expressions.info and PCRE Pattern Syntax for more info on how regexps work.
You can try
$str = "http://www.amazon.com/LEGO-Ultimate-Building-Set-Pieces/dp/B000NO9GT4/ref=sr_1_1?m=ATVPDKIKX0DER&s=toys-and-games&ie=UTF8&qid=1350518571&sr=1-1&keywords=lego" ;
list(,$desc,,$num,) = explode("/",parse_url($str,PHP_URL_PATH));
var_dump($desc,$num);
Output
string 'LEGO-Ultimate-Building-Set-Pieces' (length=33)
string 'B000NO9GT4' (length=10)
I'm trying to convert a Notepad++ Regex to a PHP regular expression which basically get IDs from a list of URL in this format:
http://www.example.com/category-example/1371937-text-blah-blah-blah-2012.html
http://www.example.com/category-example/1471337-text-blah-blah-2-blah-2010.html
Using Notepad++ regex function i get the output that i need in two steps (a list of comma separated IDs)
(.*)/ replace with space
-(.*) replace with comma
Result:
1371937,1471337
I tried to do something similar with PHP preg_replace but i can't figure how to get the correct regex, the below example removes everything except digits but it doesn't work as expected since there can be also numbers that do not belong to ID.
$bb = preg_replace('/[^0-9]+/', ',', $_POST['Text']);
?>
Which is the correct structure?
Thanks
If you are matching against:
http://www.example.com/category-example/1371937-text-blah-blah-blah-2012.html
To get:
1371937
You would:
$url = "http://www.example.com/category-example/1371937-text-blah-blah-blah-2012.html";
preg_match( "/[^\d]+(\d+)-/", $url, $matches );
$code = $matches[1];
.. which matches all non-numeric characters, then an unbroken string of numbers, until it reaches a '-'
If all you want to do is find the ID, then you should use preg_match, not preg_replace.
You've got lost of options for the pattern, the simplest being:
$url = 'http://www.example.com/category-example/1371937-text-blah-blah-blah-2012.html';
preg_match('/\d+/', $url, $matches);
echo $matches[0];
Which simply finds the first bunch of numbers in the URL. This works for the examples.