I'm trying to create multiple tables with a query, but it doesn't seem to work. I'm using PHP code to execute the query. Below is my PHP code, my query and my error.
My PHP code:
<?php
$conn=mysql_connect("localhost","secret","secret") or die("Kan geen verbinding maken met de DB server");
mysql_select_db("secret",$conn) or die("Kan database niet selecteren");
$query_file = 'tables.txt';
$fp = fopen($query_file, 'r');
$sql = fread($fp, filesize($query_file));
fclose($fp);
mysql_select_db('test_db');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not create table: ' . mysql_error());
}
mysql_close($conn);
?>
My query:
CREATE TABLE pages(
id INT NOT NULL AUTO_INCREMENT,
pagid VARCHAR(32) NOT NULL,
title VARCHAR(32) NOT NULL,
content TEXT NOT NULL,
image VARCHAR(65) NOT NULL,
youtube VARCHAR(32) NOT NULL,
primary key ( id ));
CREATE TABLE members(
id INT NOT NULL AUTO_INCREMENT,
username VARCHAR(65) NOT NULL,
password VARCHAR(65) NOT NULL,
primary key ( id ));
CREATE TABLE news(
id INT NOT NULL AUTO_INCREMENT,
pagid VARCHAR(32) NOT NULL,
title VARCHAR(32) NOT NULL,
content TEXT NOT NULL,
image VARCHAR(150) NOT NULL,
youtube VARCHAR(32) NOT NULL,
date VARCHAR(32) NOT NULL,
primary key ( id ));
CREATE TABLE gallery(
id INT NOT NULL AUTO_INCREMENT,
image VARCHAR(65) NOT NULL,
title VARCHAR(65) NOT NULL,
description TEXT NOT NULL,
url VARCHAR(200) NOT NULL,
category VARCHAR(65) NOT NULL,
primary key ( id ));
My error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE members( id INT NOT NULL AUTO_INCREMENT, username VARCHA' at line 10
Does anyone have any idea what I'm doing wrong here?
Try this:
$q1 = "CREATE TABLE pages(
id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
pagid VARCHAR(32) NOT NULL,
title VARCHAR(32) NOT NULL,
content TEXT NOT NULL,
image VARCHAR(65) NOT NULL,
youtube VARCHAR(32) NOT NULL)";
$q2 = "CREATE TABLE members(
id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
username VARCHAR(65) NOT NULL,
password VARCHAR(65) NOT NULL)";
mysql_query($q1);
mysql_query($q2);
If you're using mysql_query, it only supports one query at a time.
However, I would recommend you avoid using mysql_* functionality as its depreciated. Try mysqli or PDO
You're propably using mysql_query. The documentation explicitly states that multiple queries are not supported. As each of your create statements is an own query, you'll have to split up your query string.
Related
I'm trying to create following table . query works in phpmyadmin but doesn't work in php script. pls point out mistake in my code. Thank You
$sql = "CREATE TABLE IF NOT EXISTS `portal` (
`id` int(255) NOT NULL AUTO_INCREMENT,
`message_sid` varchar(255) NOT NULL,
`name` varchar(255) NOT NULL,
`number` varchar(255) NOT NULL,
`message` text NOT NULL,
`created_at` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
`status` varchar(50) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1";
if (mysqli_query($conn, $sql)) {
echo "Table portal created successfully";
} else {
echo "Error creating table: " . mysqli_error($conn);
}
I'm getting this error:
You have an error in your SQL syntax;
check the manual that corresponds to your MariaDB server version for the
right syntax to use near '`id` int(255) NOT NULL AUTO_INCREMENT,
`message_sid` varchar(255) NOT NULL' at line 2
I have done this by checking if table exists in php, on false create a new table
creating table would be best to export an already existing one with phpmyadmin and then just use it as query syntax
Take the single quotes off of your table and row names
also if you make the id a primary key auto-increment, do not make it not null, this will cause a error.
I am unsure why the down votes....
CREATE TABLE IF NOT EXISTS portal (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
message_id VARCHAR(30) NOT NULL,
name VARCHAR(30) NOT NULL,
email VARCHAR(50) NOT NULL,
number VARCHAR(50) NOT NULL,
message text NOT NULL,
created_at datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
status VARCHAR(50) NOT NULL )ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1
This will work
I have the following PHP page to create a table using a text file.
table_create.php
<?php
include $db;
$query_file = "sql.txt";
$fp = fopen($query_file, 'r');
$sql = fread($fp, filesize($query_file));
fclose($fp);
$retval = mysql_query($sql);
if(! $retval )
{
die("Could not create the tables<br>");
}
echo "Table created successfully<br>";
?>
sql.txt
CREATE TABLE ht_account (
id int(11) NOT NULL AUTO_INCREMENT,
date date NOT NULL,
type varchar(50) NOT NULL,
mode varchar(50) NOT NULL,
party varchar(50) NOT NULL,
payee varchar(50) NOT NULL,
rate decimal(13,2) NOT NULL,
box int(11) NOT NULL,
amount decimal(13,2) NOT NULL,
token varchar(50) NOT NULL,
remarks varchar(50) NOT NULL,
user varchar(50) NOT NULL,
user_confirm varchar(50) NOT NULL,
status varchar(50) NOT NULL);
CREATE TABLE ht_bank (
id int(11) NOT NULL AUTO_INCREMENT,
name varchar(50) NOT NULL,
ac_no varchar(50) NOT NULL,
address varchar(50) NOT NULL);
CREATE TABLE ht_user_role (
id int(11) NOT NULL AUTO_INCREMENT,
value varchar(50) NOT NULL);
When I try to create a single table in the sql.txt file, the code works perfectly.
For example:
CREATE TABLE ht_account (
id int(11) NOT NULL AUTO_INCREMENT,
date date NOT NULL,
type varchar(50) NOT NULL,
mode varchar(50) NOT NULL,
party varchar(50) NOT NULL,
payee varchar(50) NOT NULL,
rate decimal(13,2) NOT NULL,
box int(11) NOT NULL,
amount decimal(13,2) NOT NULL,
token varchar(50) NOT NULL,
remarks varchar(50) NOT NULL,
user varchar(50) NOT NULL,
user_confirm varchar(50) NOT NULL,
status varchar(50) NOT NULL);
But when I try to create multiple tables, It does not create any table. I doubt that the format in the sql.txt may be incorrect.
The format is, almost sure, correct but mysql_query doesn't work with multiple queries:
mysql_query() sends a unique query (multiple queries are not
supported) to the currently active database on the server that's
associated with the specified link_identifier.
It's better to use mysqli functions because mysql ones are deprecated for PHP 5.5 and mysqli has the function mysqli_multi_query that you need.
If you still want to use mysql functions you could do something like:
$sql_array=explode(';',$sql);
foreach ($sql_array as $s) {
if(! mysql_query($s)){
echo mysql_error()."<br>";
}
}
I have below code I am trying to run..Connection is successfully created but still mysqli_query does not create a table.What I am missing...
here is the script I am executing...
error_reporting(E_ALL);
ini_set('display_errors', '1');
$con=mysqli_connect("localhost","xxxxxx","xxxxx","xxx");
if (mysqli_connect_errno()) {
echo mysqli_connect_error();
exit();
} else {
echo "Successful database connection";
}
$tbl_users = "CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
lastname VARCHAR(255) NOT NULL,
email VARCHAR(255) NOT NULL,
password VARCHAR(255) NOT NULL,
gender ENUM('m','f') NULL,
state VARCHAR(255) NULL,
country VARCHAR(255) NULL,
userlevel ENUM('admin','user') NOT NULL DEFAULT 'user',
ip VARCHAR(255) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (email)
)";
$query = mysqli_query($con, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
You need to change your Primary key to the auto_increment column, remove it from email, you can set this (email) to unique if it should be
CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL // >>> PRIMARY KEY //<<< AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
[Err] 1075 - Incorrect table definition; there can be only one auto column and it must be defined as a key
PRIMARY KEY (email) is the issue. Make id your primary key.
I am trying to create a table in a php script and I am getting an SQL error. I can't find it or figure out how to fix it. I do have $table defined earlier in the script. Thanks in advance!
$newtable = "CREATE TABLE $table (id INT(11) NOT NULL AUTO_INCREMENT, time datetime NOT NULL,punchtype VARCHAR(255) NOT NULL,groupname VARCHAR(255) NOT NULL, dept VARCHAR(255) NOT NULL, notes VARCHAR(255))";
Error Message: Incorrect table definition; there can be only one auto column and it must be defined as a key
try this, it works
$newtable = "CREATE TABLE $table
(id INT(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
time datetime NOT NULL,
punchtype VARCHAR(255) NOT NULL,
groupname VARCHAR(255) NOT NULL,
dept VARCHAR(255) NOT NULL,
notes VARCHAR(255))";
I restarted the MySQL service and I attempted to use my PHP programs delete function to delete an existing row but I'm finding although the delete queries were counted the row was not deleted. I tried applying on delete cascade to the foreign key of the child table but that did not seem to have an effect. I'm wondering why the delete would be doing nothing.
CREATE TABLE `customers` (
`idcustomers` int(11) NOT NULL AUTO_INCREMENT,
`firstname` varchar(45) DEFAULT NULL,
`lastname` varchar(45) DEFAULT NULL,
`address1` varchar(45) DEFAULT NULL,
`address2` varchar(45) DEFAULT NULL,
`city` varchar(45) DEFAULT NULL,
`state` varchar(45) DEFAULT NULL,
`zip` varchar(45) DEFAULT NULL,
`phone` varchar(45) DEFAULT NULL,
`email` varchar(45) DEFAULT NULL,
`cell` varchar(45) DEFAULT NULL,
PRIMARY KEY (`idcustomers`),
UNIQUE KEY `idcustomers_UNIQUE` (`idcustomers`)
) ENGINE=InnoDB AUTO_INCREMENT=54 DEFAULT CHARSET=latin1
CREATE TABLE `events` (
`idevents` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(250) DEFAULT NULL,
`start` datetime DEFAULT NULL,
`end` datetime DEFAULT NULL,
`allday` varchar(50) DEFAULT NULL,
`url` varchar(1000) DEFAULT NULL,
`customerid` int(11) NOT NULL,
`memo` longtext,
`dispatchstatus` varchar(45) DEFAULT NULL,
PRIMARY KEY (`idevents`),
KEY `FK_events` (`customerid`),
CONSTRAINT `FK_events` FOREIGN KEY (`customerid`) REFERENCES `customers` (`idcustomers`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=18 DEFAULT CHARSET=latin1
Com_delete 2
The PHP looks like this:
<?php
session_start();
date_default_timezone_set("America/Los_Angeles");
if($_SESSION['loggedin'] != TRUE)
{
header("Location: index.php");
}
require_once('../php.securelogin/include.securelogin.php');
$mysqli = new mysqli($ad_host, $ad_user, $ad_password, "samedaycrm");
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$customerid = $_SESSION['customer_id'];
$tSQL = "delete from events where customerid = \"$customerid\"";
$result = $mysqli->query($tSQL);
$tSQL = "delete from customers where idcustomers = \"$customerid\"";
$result = $mysqli->query($tSQL);
echo $mysqli->error;
?>
Assuming that the customerid and idcustomers columns are both numeric it should be fine. You should not need to quote the variables in those queries btw, then you wouldnt need to escape them. You may try:
$tSQL = "delete from events where customerid = $customerid";
but it should not be any different than what you used already. Of course if you are not sure of the type of the column you can use:
$tSQL = "delete from events where customerid = '".$customerid."'";
or you can get away with:
$tSQL = "delete from events where customerid = '$customerid'";
but I have always hated that for some reason.
if all of that fails troubleshoot by spitting out the $customerid (or even the whole $tSQL) variable and then trying the query manually in phpmyadmin or toad or whatever db client you use, and see what it tells you. If it just says 0 rows affected, then run it like a select instead. Tailor to fit.