I have below code I am trying to run..Connection is successfully created but still mysqli_query does not create a table.What I am missing...
here is the script I am executing...
error_reporting(E_ALL);
ini_set('display_errors', '1');
$con=mysqli_connect("localhost","xxxxxx","xxxxx","xxx");
if (mysqli_connect_errno()) {
echo mysqli_connect_error();
exit();
} else {
echo "Successful database connection";
}
$tbl_users = "CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
lastname VARCHAR(255) NOT NULL,
email VARCHAR(255) NOT NULL,
password VARCHAR(255) NOT NULL,
gender ENUM('m','f') NULL,
state VARCHAR(255) NULL,
country VARCHAR(255) NULL,
userlevel ENUM('admin','user') NOT NULL DEFAULT 'user',
ip VARCHAR(255) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (email)
)";
$query = mysqli_query($con, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
You need to change your Primary key to the auto_increment column, remove it from email, you can set this (email) to unique if it should be
CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL // >>> PRIMARY KEY //<<< AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
[Err] 1075 - Incorrect table definition; there can be only one auto column and it must be defined as a key
PRIMARY KEY (email) is the issue. Make id your primary key.
Related
I'm trying to create following table . query works in phpmyadmin but doesn't work in php script. pls point out mistake in my code. Thank You
$sql = "CREATE TABLE IF NOT EXISTS `portal` (
`id` int(255) NOT NULL AUTO_INCREMENT,
`message_sid` varchar(255) NOT NULL,
`name` varchar(255) NOT NULL,
`number` varchar(255) NOT NULL,
`message` text NOT NULL,
`created_at` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
`status` varchar(50) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1";
if (mysqli_query($conn, $sql)) {
echo "Table portal created successfully";
} else {
echo "Error creating table: " . mysqli_error($conn);
}
I'm getting this error:
You have an error in your SQL syntax;
check the manual that corresponds to your MariaDB server version for the
right syntax to use near '`id` int(255) NOT NULL AUTO_INCREMENT,
`message_sid` varchar(255) NOT NULL' at line 2
I have done this by checking if table exists in php, on false create a new table
creating table would be best to export an already existing one with phpmyadmin and then just use it as query syntax
Take the single quotes off of your table and row names
also if you make the id a primary key auto-increment, do not make it not null, this will cause a error.
I am unsure why the down votes....
CREATE TABLE IF NOT EXISTS portal (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
message_id VARCHAR(30) NOT NULL,
name VARCHAR(30) NOT NULL,
email VARCHAR(50) NOT NULL,
number VARCHAR(50) NOT NULL,
message text NOT NULL,
created_at datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
status VARCHAR(50) NOT NULL )ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1
This will work
I have it set up to echo when my tables create but the users table just won't, I've looked at multiple solutions but none of them has helped here my code
<?
phpinclude_once("index.php");
$tbl_users = "CREATE TABLE IF NOT EXISTS users
(
id INT(11) NOT NULL AUTO_INCREMENT,
username VARCHAR(16) NOT NULL,
email VARCHAR(64) NOT NULL,
password VARCHAR(64) NOT NULL,
gender ENUM('m','f') NOT NULL,
website VARCHAR(64) NULL,
country VARCHAR(64) NULL,
userlevel ENUM('a','b','c','d') NOT NULL DEFAULT a,
avatar VARCHAR(64) NULL,
ip VARCHAR(64) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
notescheck DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT 0,
PRIMARY KEY (id)),
UNIQUE KEY username (username,email))";
$query = mysqli_query($db_spooky, $tbl_users);
if ($query === TRUE)
{
echo "<h3>user table created OK :) </h3>";
}
else
{
echo "<h3>user table NOT created :( </h3>";
}
?>
CREATE TABLE IF NOT EXISTS users (id INT(11) NOT NULL AUTO_INCREMENT
,username VARCHAR(16) NOT NULL
,email VARCHAR(64) NOT NULL,password VARCHAR(64) NOT NULL
,gender ENUM('m','f') NOT NULL
,website VARCHAR(64) NULL
,country VARCHAR(64) NULL
,userlevel ENUM('a','b','c','d') NOT NULL DEFAULT 'a'
,avatar VARCHAR(64) NULL
,ip VARCHAR(64) NOT NULL
,signup DATETIME NOT NULL
,lastlogin DATETIME NOT NULL
,notescheck DATETIME NOT NULL,activated ENUM('0','1') NOT NULL DEFAULT 0
,PRIMARY KEY (id)
,UNIQUE KEY username (username,email))
Learn to organize your code instead of writing it in one long line for one, and two, ENUM default for a needs to be in single quotes and you had an extra closing bracket. The code above is the corrected version.
I did this earlier and it worked just fine and I even brought in another table and it was created just fine. I am stuck.
Here is the table that is not working.
<?php
include_once('dbconx.php');
$tbl_pages = "CREATE TABLE IF NOT EXISTS pages (
id INT(11) NOT NULL AUTO_INCREMENT,
label VARCHAR(20) NOT NULL,
title VARCHAR(50) NOT NULL,
body TEXT NOT NULL,
slug VARCHAR(50) NOT NULL,
create TIMESTAMP NOT NULL,
updated TIMESTAMP NULL,
PRIMARY KEY(id),
)";
$query = mysqli_query($dbcon, $tbl_pages);
if ($query === TRUE) {
echo "<h3>Pages table created OK :) </h3>";
} else {
echo "<h3>Pages table NOT created :( </h3>";
}
?>
One of your field names is a MySQL reserved words create. Try changing the field name to something like created. See MySQL Keywords and Reserved Words
You also have an extra comma after the primary key definition.
Try this query:
$tbl_pages = "CREATE TABLE IF NOT EXISTS pages (
id INT(11) NOT NULL AUTO_INCREMENT,
label VARCHAR(20) NOT NULL,
title VARCHAR(50) NOT NULL,
body TEXT NOT NULL,
slug VARCHAR(50) NOT NULL,
created TIMESTAMP NOT NULL,
updated TIMESTAMP NULL,
PRIMARY KEY(id)
)";
You can also echo mysqli_error if it fails so you can see details of the error.
i'm very new to mysql and I am trying to create a database that can store users emails and passwords on one table and the values they input on another table, how do I join the tables to make sure that the inputted values are linked to the correct user. This is the code I've been using but it won't allow the value to be stored while the foreign key is run, but if I remove the foreign key I can store the value. Please help.
CREATE TABLE IF NOT EXISTS `data` (
`user_id` int(11) NOT NULL AUTO_INCREMENT,
`email` varchar(51) NOT NULL,
`password` varchar(15) NOT NULL,
PRIMARY KEY (`user_id`),
UNIQUE KEY `email_UNIQUE` (`email`)
)
CREATE TABLE IF NOT EXISTS `gluco` (
`G_id` int(11) NOT NULL AUTO_INCREMENT,
`bloods` decimal(4,2) NOT NULL,
`time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`user_id` int(11) NOT NULL,
FOREIGN KEY (`user_id`) REFERENCES `data`(`use_id`),
UNIQUE KEY `G_id_UNIQUE` (`G_id`)
)
<?php
include('db.php');
if (!isset($_POST['reading'])) { //checking if user has entered this page directly
include('contactus.php');
} else {
if (isset($_POST['reading'])&&$_POST['reading']==""||!isset($_POST['reading'])) {
$error[] = "fill in your blood/glucose";
}
$reading = mysql_real_escape_string($_POST['reading']);
$sql = "SELECT * FROM gluco WHERE bloods = '$reading'";
if(isset($error)){
if(is_array($error)){
echo "<div class=\"error\"><span>please check the errors and refill the form<span><br/>";
foreach ($error as $ers) {
echo "<span>".$ers."</span><br/>";
}
echo "</div>";
include('contactus.php');
}
}
if(!isset($error)){
$sreading=mysql_real_escape_string($_POST['reading']);
$sip=mysql_real_escape_string($_SERVER['HTTP_HOST']);
$save = mysql_query("INSERT INTO `gluco` ( `bloods` )VALUES ('$sreading')");
if($save){
echo "<div class=\"success\"><span>Your reading has been successfully stored</span><br/></div>";
} else {
echo "<div class=\"warning\"><span>Some Error occured during processing your data</div>";
}
}
}
?>
your code is correct in its logic. But theres an error on the referenced column name:
CREATE TABLE IF NOT EXISTS `data` (
`user_id` int(11) NOT NULL AUTO_INCREMENT,
`email` varchar(51) NOT NULL,
`password` varchar(15) NOT NULL,
PRIMARY KEY (`user_id`),
UNIQUE KEY `email_UNIQUE` (`email`)
)
CREATE TABLE IF NOT EXISTS `gluco` (
`G_id` int(11) NOT NULL AUTO_INCREMENT,
`bloods` decimal(4,2) NOT NULL,
`time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`user_id` int(11) NOT NULL,
FOREIGN KEY (`user_id`) REFERENCES `data`(`user_id`),
UNIQUE KEY `G_id_UNIQUE` (`G_id`)
)
and on this line:
$save = mysql_query("INSERT INTO `gluco` ( `bloods` )VALUES ('$sreading')");
you are not setting the user_id in your insert statement, so, the foreign key will not work and the insert will not be made. So, you'll need to have the user id stored in a variable (since i don't know the context and the scope in the code, i can't help you setting this variable). So, your code should be like that:
$save = mysql_query("INSERT INTO gluco (bloods, user_id)VALUES ('$sreading', $user_id)");
I am having trouble with my create a table .php script, It creates all tables in the database except one which is 'useroptions'. I am new to php but still understand it to an extent, feedback and help would be greatly appreciated.
<?php
include_once("php_includes/db_connect.php");
$tbl_users = "CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(100) NOT NULL,
lastname VARCHAR(100) NOT NULL,
email VARCHAR(255) NOT NULL,
password VARCHAR(255) NOT NULL,
gender ENUM('m','f') NOT NULL,
avatar VARCHAR(255) NULL,
ip VARCHAR(255) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
notescheck DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (id),
UNIQUE KEY email (email)
)";
$query = mysqli_query($db_connect, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_useroptions = "CREATE TABLE IF NOT EXISTS useroptions (
id INT(11) NOT NULL,
question VARCHAR(255) NULL,
answer VARCHAR(255) NULL,
PRIMARY KEY (id),
UNIQUE KEY email (email)
)";
$query = mysqli_query($db_connect, $tbl_useroptions);
if ($query === TRUE) {
echo "<h3>useroptions table created OK :) </h3>";
} else {
echo "<h3>useroptions table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_friends = "CREATE TABLE IF NOT EXISTS friends (
id INT(11) NOT NULL AUTO_INCREMENT,
user1 VARCHAR(100) NOT NULL,
user2 VARCHAR(100) NOT NULL,
datemade DATETIME NOT NULL,
accepted ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_friends);
if ($query === TRUE) {
echo "<h3>friends table created OK :) </h3>";
} else {
echo "<h3>friends table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_blockedusers = "CREATE TABLE IF NOT EXISTS blockedusers (
id INT(11) NOT NULL AUTO_INCREMENT,
blocker VARCHAR(100) NOT NULL,
blockee VARCHAR(100) NOT NULL,
blockdate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_blockedusers);
if ($query === TRUE) {
echo "<h3>blockedusers table created OK :) </h3>";
} else {
echo "<h3>blockedusers table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_status = "CREATE TABLE IF NOT EXISTS status (
id INT(11) NOT NULL AUTO_INCREMENT,
osid INT(11) NOT NULL,
account_name VARCHAR(100) NOT NULL,
author VARCHAR(100) NOT NULL,
data TEXT NOT NULL,
postdate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_status);
if ($query === TRUE) {
echo "<h3>status table created OK :) </h3>";
} else {
echo "<h3>status table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_photos = "CREATE TABLE IF NOT EXISTS photos (
id INT(11) NOT NULL AUTO_INCREMENT,
user VARCHAR(100) NOT NULL,
gallery VARCHAR(16) NOT NULL,
filename VARCHAR(255) NOT NULL,
description VARCHAR(255) NULL,
uploaddate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_photos);
if ($query === TRUE) {
echo "<h3>photos table created OK :) </h3>";
} else {
echo "<h3>photos table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_notifications = "CREATE TABLE IF NOT EXISTS notifications (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(100) NOT NULL,
initiator VARCHAR(100) NOT NULL,
app VARCHAR(255) NOT NULL,
note VARCHAR(255) NOT NULL,
did_read ENUM('0','1') NOT NULL DEFAULT '0',
date_time DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_notifications);
if ($query === TRUE) {
echo "<h3>notifications table created OK :) </h3>";
} else {
echo "<h3>notifications table NOT created :( </h3>";
}
?>
Also I'm getting this error when I click on database ?
Error
SQL query:
SELECT tracking_active
FROM `phpmyadmin`.`pma_tracking`
WHERE db_name = 'circle'
AND table_name = 'blockedusers'
ORDER BY version DESC
MySQL said:
1146 - Table 'phpmyadmin.pma_tracking' doesn't exist
Your useroptions create table statement has an invalid unique key ref: UNIQUE KEY email (email). There is no column email on useroptions. Remove it and it will likely run clean.
As for the query issue, not really sure what you're trying to do.