PHP - Order in a while loop - php

Question

<div class="row">
<?php
$r=mysql_query("SELECT * FROM advertisements WHERE $filter exposure!='0' AND `status`='2' AND (clicks_left_micro>0 OR clicks_left_mini>0 OR clicks_left_standard>0 OR clicks_left_extended>0) ORDER BY exposure DESC");
while($ar=mysql_fetch_array($r)):
echo "<div class='span4'> text here text here</div>";
endwhile;
?>
</div>
As you can see in the $r query, I am ordering by exposure. The exposure field can contain the numbers from 1-3. What I am trying to do is to create a new row for each exposure number. Example:
Advertisements that have exposure = 1, will be in the first row
Below that, will be advertisements that have exposure = 2
And last, there will be advertisements that have exposure = 3
The way it is now, the advertisements/span4 divs are just being echoed out next to each other. I want to sort them inside the while loop in <div class='row'></div>

Answer 1

What about something like this:
<div class="row">
<?php
$r=mysql_query("SELECT * FROM advertisements WHERE $filter exposure!='0' AND `status`='2' AND (clicks_left_micro>0 OR clicks_left_mini>0 OR clicks_left_standard>0 OR clicks_left_extended>0) ORDER BY exposure DESC");
$row1 = '';
$row2 = '';
$row3 = '';
while($ar=mysql_fetch_array($r)):
if($ar['exposure'] == 1)
$row1 .= '<span>Your code here for row 1</span>';
else if($ar['exposure'] == 2)
$row2 .= '<span>Your code here for row 2</span>';
else if($ar['exposure'] == 3)
$row3 .= '<span>Your code here for row 3</span>';
endwhile;
?>
<table>
<tr>
<td><?php echo $row1; ?></td>
<td><?php echo $row2; ?></td>
<td><?php echo $row3; ?></td>
</tr>
</table>
</div>
Of course you will have to adjust it to your needs, but this is the idea.
EDIT: As some other people have noticed, you should not use mysql_* functions anymore.

Answer 2

Since they are ordered by exposure, you can simply do :
$curExpo = null;
while( ... ) {
if( $curExpo !== $row['exposure']) {
create new row
$curExpo = $row['exposure'];
}
}