Create Divs for each group of values - php

Question

I need to group all rows with matching roomcode. When I also group resort, it acts like it disables the grouping of roomcode and only gives me the results of the first row with a roomcode.
How can I group the resort column and still group matching roomcode columns? If I ungroup my resort code the query works correctly, but then I can't create separate divs for differing resorts.
The user is searching a date range, hence having multiple rows with the same roomcode, which fetches my points. This is why I am getting the sum of those points. My current way of grouping each resort for output HTML purposes is breaking that. I don't necessarily have to group the resorts, I just need each room at each resort created within its own DIV set. I have a basic example below.
Ideal HTML output
<div id="results">
<div id="resort resortcode">
<div id="roomresults">
<div id="room1"></div>
<div id="room2"></div>
</div>
</div>
<div id="resort2 resortcode2">
<div id="roomresults2">
<div id="room3"></div>
<div id="room4"></div>
</div>
</div>
</div>
This PHP code will group each set of results by resorts, but jacks up my price.
<?php
include("dbh.php");
mysqli_select_db($con, "checkavail") or die ("no database");
$checkin = $_POST['checkin'];
$checkout = $_POST['checkout'];
$occupants = $_POST['occupants'];
$sqlCommand=
"SELECT
MIN(staydate) AS checkin,
MAX(staydate) AS lastnight,
MIN(available) AS available,
ra.resort AS resortcode,
ri.resort,
ri.room,
ri.roomcode,
ri.view,
SUM(ra.points*'20') AS price,
ri.sqfoot,
ri.description,
ri.bedding,
ri.amenities,
ri.sleeps,
ri.sleep_details,
ri.layout_img AS layoutimg,
ri.room_img AS roomimg,
ri.roomimg_thumb
FROM resort_availability AS ra
LEFT JOIN room_info AS ri ON (ra.room = ri.roomcode)
WHERE staydate >= '$checkin' AND staydate = '$checkout'
AND sleeps >= '$occupants'
GROUP BY ri.roomcode
ORDER BY ri.resort, points
";
$result=mysqli_query($con, $sqlCommand) or die(mysqli_error($con));
$data = array();
while($row = $result->fetch_assoc())
{
$itemName = $row["resort"];
$resortCode = $row["resortcode"];
if ( !array_key_exists($itemName, $data)) {
$data[$itemName] = array ();
}
$data[$itemName][] = $row;
}
foreach ($data as $itemName => $rows) {
echo '<div class="resort ' ,$resortCode , '">';
echo '<div class="resort_header"><h1>', $itemName, '</h1></div>';
foreach ($rows as $row){
if ($row['available'] > 0) {
$roomresult = '<div class="room_result roomavailable">';
$available = '<button class="available">BOOK NOW</button>';
$filtavail = 'available';
}
else {
$roomresult = '<div class="room_result roomsoldout" style="">';
$available = '<button class="soldout">SOLD OUT</button>';
$filtavail = 'soldout';
}
echo $roomresult;
echo '<div class="room_thumb"></div>
<div class="room_info"><h4>'
,$row['room'], '-' ,$row['view'] ,
'</h4></div>
<div class="price"><center><h3>','' ,$row['price'],'</h3>' , $available ,'</center></div></div>';
}
echo '</div>';
}
?>
This PHP code gives me accurate results but does not allow me to Create a div with results based on each resort IE, I don't know how to create a Header with the resort name, separating each set of rooms by resort as it is in the first example.
<?php
include("dbh.php");
mysqli_select_db($con, "checkavail") or die ("no database");
$checkin = $_POST['checkin'];
$checkout = $_POST['checkout'];
$occupants = $_POST['occupants'];
$sqlCommand=
"SELECT
MIN(staydate) AS checkin,
MAX(staydate) AS lastnight,
MIN(available) AS available,
ra.resort AS resortcode,
ri.resort AS resort,
ri.room,
ri.roomcode AS roomcode,
ri.view,
SUM(ra.points) AS points,
ri.sqfoot,
ri.description,
ri.bedding,
ri.amenities,
ri.sleeps,
ri.sleep_details,
ri.layout_img AS layoutimg,
ri.room_img AS roomimg,
ri.roomimg_thumb
FROM resort_availability AS ra
LEFT JOIN room_info AS ri ON (ra.room = ri.roomcode)
WHERE staydate >= '$checkin' AND staydate < '$checkout'
AND sleeps >= '$occupants'
GROUP BY ri.resort, roomcode
ORDER BY ri.resort, points
";
$result=mysqli_query($con, $sqlCommand) or die(mysqli_error($con));
while($row = $result->fetch_assoc()) {
$pricecalc = ($row['points'])*20;
$price = number_format($pricecalc, 2);
//RESULTS BOX
if($row['available'] < "1"){
echo '<div id="'.$row['roomcode'].'-'.$row['resortcode'].'"','class="soldout roomresults room'.$row['resortcode'].'">';
}
if($row['available'] > "0"){
echo '<div id="'.$row['roomcode'].'-'.$row['resortcode'].'"','class="available roomresults room'.$row['resortcode'].'">';
}
//IMAGE BOX
echo '<div class="thumbnail"><img height="90" src="',$row['roomimg_thumb'],'">';
echo '</div>';
//ROOM DETAILS
echo '<div class="roomdetails">';
echo '<h4>'.$row['room'].' - '.$row['view'].'</h4>';
echo '<p>Sleeps: '.$row['sleep_details'].'</p>';
echo '<p class="clickfordetails">Click Image For Room Details</p>';
echo '</div>';
//PRICING BOX AND SUBMIT BUTTON
echo '<div class="price">';
echo '<h3>$',$price,'</h3>';
if ($row['available'] < "1"){
echo '<button type="button" class="soldoutbtn">SOLD OUT</button>';
}
if ($row['available'] > "0"){
echo '<button type="button" class="booknowbtn">BOOK NOW</button>';
}
echo '</div,$row>';
echo '</div></div>';
};
?>

Answer 1

Yes group by will give you the 1st record of the same group.
In my understanding , you want to show all the data but place all the records with the same roomcode together.
In that case, please change
GROUP BY ri.roomcode
ORDER BY ri.resort, points
to
ORDER BY ri.roomcode, ri.resort, points