I am trying to print number vertically and it must be in group
here is my code
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
for ($i = 1; $i <= $rows; $i++) {
for ($j = $i; $j <= 24; $j = $j + $rows) {
$count++;
if($count>$nums){
break;
}
echo "<div class='fleft'>$count</div>";
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
out of above
but i want output like for the first column
and next group number will start from where first group number end. in this case next group start from 25
please ask if any doubt
$nums = 105;
$rows = 8;
$colsize = 3;
$col = floor($nums / $rows);
$group = floor($col / $colsize);
$count = 0;
$groupsize = $rows * $colsize;
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
$modulo = 0;
$correction = 0;
$rest = $nums - $count;
if ($rest < $groupsize) {
$empty = $groupsize - $rest;
$correction = floor($empty / $colsize);
$modulo = $empty % $colsize;
}
for ($i = 1; $i <= $rows; $i++) {
$colind = 0;
for ($j = $i; $j <= $groupsize; $j = $j + $rows) {
$count++;
if ($count > $nums) {
break;
}
$val = $j + ($g * $groupsize);
$val -= $colind * $correction;
$modcor = $colind - ($colsize - $modulo);
if ( $modcor > 0 ) {
$val -= $modcor;
}
echo "<div class='fleft'>" . $val . "</div>";
$colind++;
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
This works:
Also, you can change number of digits, columns or size of column
for($group = 0; $group < 3; $group++){
for($row =1 ; $row <= 8; $row++){
for($col = 0; $col <= 2; $col++){
echo ($group*24)+ $row + 8 * $col; echo " ";
}
echo "\n";
}
}
This code will print the number in the requested format. You need to modify according to your need.
may be i am mad , made a simple alter .... try this
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$letCounter=0; //added a counter
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
for ($i = 1; $i <= $rows; $i++) {
$letCounter=0; //reset counter on each loop
for ($j = $i; $j <= 24; $j = $j + $rows)
{
$count++;
if($count>$nums)
{break;}
//made an alter in the below line , some math :)
echo "<div class='fleft'>".($letCounter++ * $rows +$i)."</div>";
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
Thanks !
This May work
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$flag = true;
for($c=1;$c<=$col;$c++)
{
if($c%$group== 1)
{
echo "Group Start";
$flag = false;
}
for ($i = 1; $i <= $rows; $i++) {
$count++;
echo "<div class='fleft'>$count</div>";
echo "<div class='clear'></div>";
}
echo "Line End";
if($c%$group == 2&& $flag)// Check here for your requirement
echo "Group End </br>";
$flag = true;
}
Related
I'm trying to look for a number with maximum divisors in a range of 1 - 10000.
I succeeded, but then I wish to verify if there exist more than two max divisors and print them out. My array is really the problem. How can I clear an array and assign a new integer to it in an if else if statement?
Here is what I have tried:
function countDivisors(){
$input = 10000;
$maxNumOfDiv = -1;
$intWMaxDivs = -1;
$curNumOfDiv = 0;
$arr = array();
for($i=1; $i <= $input; $i++) {
$curNumOfDiv = 0;
for ($j = 1; $j < $i; $j++){
if ($i % $j == 0)
$curNumOfDiv++;
}
if($curNumOfDiv = $maxNumOfDiv){
$arr[] = $i;
$intWMaxDivs = $i;
$maxNumOfDiv = $curNumOfDiv;
} else if($curNumOfDiv > $maxNumOfDiv){
$arr = array();
$arr[] = $intWMaxDivs
$maxNumOfDiv = $curNumOfDiv;
}
}
for ($i; $i < count($arr); $i++){
echo $arr[$i]['intWMaxDivs'];
echo $arr[$i]['maxNumOfDiv'];
}
$div = [];
$maxDivKey = false;
$maxDiv = 0;
for($i = 1; $i <= 10000; $i++) {
for ($j = 1; $j < $i; $j++){
if ($i % $j == 0){
$div[$i][] = $i.'/'.$j.'='.$i/$j;
}
if($j == $i-1){
$count = count($div[$i]);
$div[$i]['count'] = $count;
if($maxDiv < $count){
$maxDiv = $count;
$maxDivKey = $i;
}
}
}
}
echo '<h1>Max divisors:</h1>';
print_r($div[$maxDivKey]);
//print_r($div);
I may be misunderstanding this question a little. If you are looking for a single number with maximum number of dividers, it should be something like this.
<?php
$max_num=10000;
$start_num=1;
$max_divs=-1;
$max_number=-1;
$numbers=array();
$max_divs_arr=array();
for($i=$start_num;$i<=$max_num;$i++)
{
$divs=0;
$div_array=array();
for($j=$start_num;$j<=$i;$j++)
{
if($i%$j==0)
{
$divs++;
$div_array[]=$j;
}
}
if($divs==$max_divs)
$max_divs_arr[$i]=$div_array;
if($divs>$max_divs)
{
$max_divs_arr=array();
$max_divs=$divs;
$max_divs_arr[$i]=$div_array;
}
}
foreach($max_divs_arr as $number=>$divisors)
echo "\nNumber with most divisors is $number\nIt has $max_divs divisors\nThose divisors are:".implode(',',$divisors);
Write a PHP code to print following number pattern:
147
258
369
I am trying like this but its shows me shows below. how to convert column to row pattern.
<?php
$num = "";
for($i=1;$i<=9;$i++) {
$num .= $i;
if($i%3==0){
$num .="<br />";
}
}
echo $num;
?>
please help me
You need to use for loop inside for loop to achieve this. Below is the code
$num = "";
for( $i = 1; $i <= 3; $i++ ) {
for( $j = 0; $j <= 2; $j++) {
$k = $i + ( $j * 3 );
$num .= $k;
}
$num .= "<br />";
}
echo $num;
Here is another way to get this output.
for($i = 1; $i <= 3; $i++) {
$print = $i;
for($j = 1; $j <= 3; $j++) {
echo $print;
$print = $print + 3;
}
echo "<br />";
}
This question already has answers here:
How to get whole and decimal part of a number?
(20 answers)
Closed 1 year ago.
I want to get the breakdown of the charges but im stock on the decimal point, it should be the output i fill.out below. please see and check my code if there is lacking. it really could help me much. Ill show the output of my code.
$charge = 1600.50;
$base = 750;
$difference = $charge - $base;
$installment = $charge / 750;
$remainder = ($charge % 750);
$counter = 1;
if (is_float($charge)) {
if($remainder == 0) {
$count = 0;
for ($i=1; $i <= round($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
} else {
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
}
} else {
if($remainder == 0){
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
} else {
if($difference < 0){
echo $remainder."\n";
} else {
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
}
}
}
This is the output of my code.
750
750
100
0.50
But the correct output would be this.
750
750
100.50
I hope there is anyone could help me to solve this problem. it took weeks but im not able to solve this.
I don't know if i faced your problem correctly, but according to your desired output the following will do the trick.
else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
// echo $remainder."\n";
echo $remainder + $charge-floor($charge); // get fractial part of your $charge and add it to your remainder
}
$counter = $counter + 1;
}
/* unnecessary if-statement, is already checked by surrounding if-statement
if(is_float($charge)){
*/
// echo 'TRUE';
// $exploadedAmount = explode('.', $charge);
// echo "0.".$exploadedAmount[1];
}
}
I really don't understand what are you trying to do but isn't it better to write the code in partly functions?
anyways by editing this part of your code I manage to output the result you want:
$charge = 1600.50;
$base = 750;
$difference = $charge - $base;
$installment = $charge / 750;
$remainder = ($charge % 750);
$counter = 1;
if (is_float($charge)) {
// echo "TRUE";
if($remainder == 0){
$count = 0;
for ($i=1; $i <= round($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
}
else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}
$counter = $counter + 1;
}
if(is_float($charge)){
// if you want to concatinate the number to previuse one you must do it here
// the extra 0.5 is echo here
$exploadedAmount = explode('.', $charge);
echo "$remainder.".$exploadedAmount[1];
}
}
}
else{
if($remainder == 0){
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
}
else{
if($difference < 0){
echo $remainder."\n";
}else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
}
}
}
The output will be :
750 750 100.5
echo ".".$exploadedAmount[1]."0" ;
At line number 63 , if u change that number and 0 adding at the beginning and end means your can get that accurate output and also it is applicable for other phone numbers also.
I have to make a diamond-shaped asterisk using for loop, inside a table. It has to have "blank" <td> spaces before and after the asterisks to move and make it look centered, so it looks like a diamond. How do I do that? (I used PHP inside an HTML code.)
Code without the <tr> and <td> tags, it looked like a diamond because it was center aligned:
<center>
<?php
echo "<table border = 1>";
// loop for the pyramid
for($i = 1; $i <= 10; $i += 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}
// loop for the inverted pyramid, so it looks like a diamond
for($i = 7; $i >= 1; $i -= 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}
echo "</table>";
?>
</center>
Code with the <tr> and <td> tags, need "spaces" for it to look like it's center aligned:
<?php
echo "<table border = 1>";
// loop for the pyramid
echo "<tr>";
for($i = 1; $i <= 10; $i += 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "</tr>";
}
echo "</tr>";
// loop for the inverted pyramid, so it looks like a diamond
for($i = 7; $i >= 1; $i -= 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "<br />";
echo "</tr>";
}
echo "</table>";
?>
Please help!
Here is new Code with your solution. I have added logic to put blank td forward and backward to *
<?php
echo "<table border = 1>";
// loop for the pyramid
echo "<tr>";
$max = $initAmount = 10;
for($i = 1; $i <= $initAmount; $i += 2) {
$max = $max -2;
$halfTD = (int)$max/2;
echo "<tr>";
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
echo "</tr>";
}
echo "</tr>";
// loop for the inverted pyramid, so it looks like a diamond
$max = $initAmount = 10;
for($i = 7; $i >= 1; $i -= 2) {
$max = $max -2;
$diff = $initAmount - $max;
$blankTd = $diff/2;
echo "<tr>";
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
echo "</tr>";
}
echo "</table>";
?>
I used the code below without using a table to make a diamond shape.
<div style="text-align: center">
<?php
$n = 8;
if($n === 1){ die("input must be greater than 1"); }
$nn = ($n * 2);
$m = (ceil($nn / 2) + 1);
$temp = 0;
for($x = 1; $x <= $nn; $x++){
$temp = (($x < $m) ? ($temp + 1) : ($temp - 1));
$total = ($temp > 1 ? ((2 * $temp) - 1) : $temp);
echo nl2br(str_repeat('* ', $total) . "\r\n");
}
?>
I used the code below.
<div style="text-align: center">
<?php
$n = 8;
if($n === 1){ die("input must be greater than 1"); }
$nn = ($n * 2);
$m = (ceil($nn / 2) + 1);
$temp = 0;
for($x = 1; $x <= $nn; $x++){
$temp = (($x < $m) ? ($temp + 1) : ($temp - 1));
$total = ($temp > 1 ? ((2 * $temp) - 1) : $temp);
echo nl2br(str_repeat('* ', $total) . "\r\n");
}
?>
<?php
for($i=0;$i<=5;$i++){
for($j=5;$j>=$i;$j--){
echo ' ';
}
for($k=0;$k<=$i;$k++){
echo '*';
}
echo '<br />';
}
for($i=0;$i<=4;$i++){
for($k=0;$k<=$i+1;$k++){
echo ' ';
}
for($j=4;$j>=$i;$j--){
echo '*';
}
echo '<br />';
}
?>
What I want to get with for loop. Something will be like this.
*
**
***
****
*****
****
***
**
*
This thing I want to create right now I have this code.
<?php
$i = 1;
$end = 5;
$star = "*";
for($i; $i <= $end; $i++){
for($b=1; $b <= $i; $b++){
echo $star;
}
if($i == $end){
for($c=1; $c <= $end; $c++ ){
for($d=i; $d >= 2; $d--){
echo $star;
}
echo "<br>";
}
}
};
?>
And it's working fine with
*
**
***
****
*****
But then I need opposite loop first 4 then 3 then 2 then 1...
Where am I going wrong with this?
Just for fun. Try this:
$stars = 1;
for ($i = 0; $i < 9; $i++) {
for ($s = 1; $s <= $stars; $s++) {
echo "*";
}
echo "\n";
$stars += ($i<4)?1:-1;
}
And, for even more fun, one with just one for loop:
$stars = 0;
$starctr = 0;
for ($i = 0; $i < 25; $i++) {
echo "*";
if ($stars == $starctr) {
echo "\n";
$stars += ($i<14)?1:-1;
$starctr = 0;
} else {
$starctr++;
}
}
Can using nested for loop. Example:
$n = 5;
for($i = 1; $i <= $n; $i++){
for($j = 1; $j <= $i; $j++){
echo '*';
}
echo '<br />';
}
for($i = $n-1; $i >= 1; $i--){
for($j = $i; $j >= 1; $j--){
echo '*';
}
echo '<br />';
}
Another technique using array_fill(), array_map(), array_reverse()
$n = 5; $arr = array();
for($i = 1; $i <= $n; $i++){
$arr[] = array_fill(0, $i, '*');
}
array_map(function($v){echo join('', $v) . '</br>';},$arr);
unset($arr[count($arr) - 1]); //remove last index value
array_map(function($v){echo join('', $v) . '</br>';},array_reverse($arr));
<?php
for($i=0;$i<=6;$i++){
for($k=6;$k>=$i;$k--){
echo " ";
}
for($j=1;$j<=$i;$j++){
echo "* ";
}
echo "<br>";
}
for($i=5;$i>=1;$i--){
for($k=6;$k>=$i;$k--){
echo " ";
}
for($j=1;$j<=$i;$j++){
echo "* ";
}
echo "<br>";
}
?>
This can be achieved with only 2 for loops.
$offset = 1;
for ($i = 1; $i > 0; $i += $offset)
{
for($j = 1; $j <= $i; $j++){
echo '*';
}
echo '<br />';
if ($i === 5)
$offset = -1;
}
<?php
$i = 1;
$end = 5;
$star = "*";
for($i; $i <= $end; $i++){
for($b=1; $b <= $i; $b++){
echo $star;
}
};
for($c=$send; $c>=2; $c-- ){
for($d=$end; $d >= 2; $d--){
echo $star;
}
echo "<br>";
};
?>
Using a single for loop:
$end = 5;
$out = array();
for ($i=0;$i<$end;++$i)
{
$out[] = str_repeat('*', $i+1);
}
echo implode(PHP_EOL, $out).PHP_EOL;
array_pop($out);
$out = array_reverse($out);//remove last ****** <-- only one line with 5 stars
echo implode(PHP_EOL, $out).PHP_EOL;
Replace PHP_EOL with <br> if you want to, but this is the least loopy way to write this code I can think of
live demo
Here's a recursive attempt:
function ladder($n, $counter=1, &$acc=array())
{
if ($counter == ($n*2)) {
return implode($acc);
}
if ($counter <= $n) {
$acc[$counter] = str_repeat('*', $counter) . "\n";
$counter++;
}
if ($counter > $n) {
$diff = (int) $n-$counter;
$acc[$counter] = str_repeat('*', $n+$diff) . "\n";
$counter++;
}
return ladder($n, $counter, $acc);
}
print_r(ladder(5));