How to get the decimal point on the whole number [duplicate] - php

Question

This question already has answers here:
How to get whole and decimal part of a number?
(20 answers)
Closed 1 year ago.
I want to get the breakdown of the charges but im stock on the decimal point, it should be the output i fill.out below. please see and check my code if there is lacking. it really could help me much. Ill show the output of my code.
$charge = 1600.50;
$base = 750;
$difference = $charge - $base;
$installment = $charge / 750;
$remainder = ($charge % 750);
$counter = 1;
if (is_float($charge)) {
if($remainder == 0) {
$count = 0;
for ($i=1; $i <= round($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
} else {
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
}
} else {
if($remainder == 0){
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
} else {
if($difference < 0){
echo $remainder."\n";
} else {
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
}
}
}
This is the output of my code.
750
750
100
0.50
But the correct output would be this.
750
750
100.50
I hope there is anyone could help me to solve this problem. it took weeks but im not able to solve this.

Answer 1

I don't know if i faced your problem correctly, but according to your desired output the following will do the trick.
else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
// echo $remainder."\n";
echo $remainder + $charge-floor($charge); // get fractial part of your $charge and add it to your remainder
}
$counter = $counter + 1;
}
/* unnecessary if-statement, is already checked by surrounding if-statement
if(is_float($charge)){
*/
// echo 'TRUE';
// $exploadedAmount = explode('.', $charge);
// echo "0.".$exploadedAmount[1];
}
}

Answer 2

I really don't understand what are you trying to do but isn't it better to write the code in partly functions?
anyways by editing this part of your code I manage to output the result you want:
$charge = 1600.50;
$base = 750;
$difference = $charge - $base;
$installment = $charge / 750;
$remainder = ($charge % 750);
$counter = 1;
if (is_float($charge)) {
// echo "TRUE";
if($remainder == 0){
$count = 0;
for ($i=1; $i <= round($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
if(is_float($charge)){
$exploadedAmount = explode('.', $charge);
echo "0.".$exploadedAmount[1];
}
}
else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}
$counter = $counter + 1;
}
if(is_float($charge)){
// if you want to concatinate the number to previuse one you must do it here
// the extra 0.5 is echo here
$exploadedAmount = explode('.', $charge);
echo "$remainder.".$exploadedAmount[1];
}
}
}
else{
if($remainder == 0){
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
echo $base."\n";
}
}
else{
if($difference < 0){
echo $remainder."\n";
}else{
$count = 0;
for ($i=1; $i <= ceil($installment); $i++) {
$count = $count + 1;
if($counter != ceil($installment)){
echo $base."\n";
}else{
echo $remainder."\n";
}
$counter = $counter + 1;
}
}
}
}
The output will be :
750 750 100.5

Answer 3

echo ".".$exploadedAmount[1]."0" ;
At line number 63 , if u change that number and 0 adding at the beginning and end means your can get that accurate output and also it is applicable for other phone numbers also.