Write a PHP code to print following number pattern:
147
258
369
I am trying like this but its shows me shows below. how to convert column to row pattern.
<?php
$num = "";
for($i=1;$i<=9;$i++) {
$num .= $i;
if($i%3==0){
$num .="<br />";
}
}
echo $num;
?>
please help me
You need to use for loop inside for loop to achieve this. Below is the code
$num = "";
for( $i = 1; $i <= 3; $i++ ) {
for( $j = 0; $j <= 2; $j++) {
$k = $i + ( $j * 3 );
$num .= $k;
}
$num .= "<br />";
}
echo $num;
Here is another way to get this output.
for($i = 1; $i <= 3; $i++) {
$print = $i;
for($j = 1; $j <= 3; $j++) {
echo $print;
$print = $print + 3;
}
echo "<br />";
}
Related
I'm trying to look for a number with maximum divisors in a range of 1 - 10000.
I succeeded, but then I wish to verify if there exist more than two max divisors and print them out. My array is really the problem. How can I clear an array and assign a new integer to it in an if else if statement?
Here is what I have tried:
function countDivisors(){
$input = 10000;
$maxNumOfDiv = -1;
$intWMaxDivs = -1;
$curNumOfDiv = 0;
$arr = array();
for($i=1; $i <= $input; $i++) {
$curNumOfDiv = 0;
for ($j = 1; $j < $i; $j++){
if ($i % $j == 0)
$curNumOfDiv++;
}
if($curNumOfDiv = $maxNumOfDiv){
$arr[] = $i;
$intWMaxDivs = $i;
$maxNumOfDiv = $curNumOfDiv;
} else if($curNumOfDiv > $maxNumOfDiv){
$arr = array();
$arr[] = $intWMaxDivs
$maxNumOfDiv = $curNumOfDiv;
}
}
for ($i; $i < count($arr); $i++){
echo $arr[$i]['intWMaxDivs'];
echo $arr[$i]['maxNumOfDiv'];
}
$div = [];
$maxDivKey = false;
$maxDiv = 0;
for($i = 1; $i <= 10000; $i++) {
for ($j = 1; $j < $i; $j++){
if ($i % $j == 0){
$div[$i][] = $i.'/'.$j.'='.$i/$j;
}
if($j == $i-1){
$count = count($div[$i]);
$div[$i]['count'] = $count;
if($maxDiv < $count){
$maxDiv = $count;
$maxDivKey = $i;
}
}
}
}
echo '<h1>Max divisors:</h1>';
print_r($div[$maxDivKey]);
//print_r($div);
I may be misunderstanding this question a little. If you are looking for a single number with maximum number of dividers, it should be something like this.
<?php
$max_num=10000;
$start_num=1;
$max_divs=-1;
$max_number=-1;
$numbers=array();
$max_divs_arr=array();
for($i=$start_num;$i<=$max_num;$i++)
{
$divs=0;
$div_array=array();
for($j=$start_num;$j<=$i;$j++)
{
if($i%$j==0)
{
$divs++;
$div_array[]=$j;
}
}
if($divs==$max_divs)
$max_divs_arr[$i]=$div_array;
if($divs>$max_divs)
{
$max_divs_arr=array();
$max_divs=$divs;
$max_divs_arr[$i]=$div_array;
}
}
foreach($max_divs_arr as $number=>$divisors)
echo "\nNumber with most divisors is $number\nIt has $max_divs divisors\nThose divisors are:".implode(',',$divisors);
How best can i solve this with less code as possible below is the problem
*****
****x
***xx
**xxx
*****
**xxx
***xx
****x
*****
this is my code that i want to improve:
<?php
for ($i=0; $i < 5 ; $i++) {
if($i >= 1 & ($i <= 3))
{
for ($t=0; $t < 5-$i ; $t++)
echo "*";
for ($t=0; $t < $i ; $t++)
echo "x";
}
else
for ($j=0; $j < 5 ; $j++)
echo "*";
echo "<br/>";
}
for ($f=1; $f < 5 ; $f++) {
for ($j=0; $j < $f+1; $j++)
echo "*";
for ($v=3; $v>= $f; $v--)
echo "x";
echo "<br/>";
}
?>
To create string with repeated symbols you can use str_repeat. Using this function your code can be simplified to:
$num = 5;
for ($i = $num; $i > 1; $i--) {
echo str_repeat('*', $i) . str_repeat('x', $num - $i) . PHP_EOL;
}
echo str_repeat('*', $num) . PHP_EOL;
for ($i = 2; $i <= $num; $i++) {
echo str_repeat('*', $i) . str_repeat('x', $num - $i) . PHP_EOL;
}
Even if you cannot use php core functions, you can write you own function to create same results as str_repeat:
function createLine($starsCount, $XCount) {
$result = '';
for ($i = 0; $i < $starsCount; $i++) {
$result .= '*';
}
for ($i = 0; $i < $XCount; $i++) {
$result .= 'x';
}
return $result;
}
And rewrite code as:
$num = 5;
for ($i = $num; $i > 1; $i--) {
echo createLine($i, $num - $i) . PHP_EOL;
}
echo createLine($num, 0) . PHP_EOL;
for ($i = 2; $i <= $num; $i++) {
echo createLine($i, $num - $i) . PHP_EOL;
}
Draw a staircase of height N like this:
#
##
###
####
#####
######
Staircase of height 6, note the last line should have zero spaces.
My solution does not work correctly
function draw($size)
{
for ($i = 1; $i <=$size ; $i++)
{
$spaces = $size-$i;
while ($spaces)
{
echo " ";
$spaces--;
}
$stairs = 0;
while ($stairs < $i)
{
echo "#";
$stairs++;
}
echo "<br/>";
}
}
draw(6);
//output
#
##
###
####
#####
######
It is not printing the spaces, I tried \n, PHP.EOL still it didn't work. Any suggestions?
Although other solutions are all good , here is my code as well.
$max=5;
for ( $i =1 ; $i<=$max;$i++) {
for ( $space = 1; $space <= ($max-$i);$space++) {
echo " ";
}
for ( $hash = 1; $hash <= $i;$hash ++ ) {
echo "#";
}
echo "\n";
}
//PHP
$n = 6; // Number of rows.
for($i=1;$i<=$n;$i++){
echo str_repeat(' ', $n-$i) . str_repeat('#', $i);
echo '\n';
}
for(var i = 0; i < n; i++)
{
var s = "";
for(var j = 0; j < n; j++)
{
if(n - i - 2 < j)
{
s += "#";
}
else
{
s += " ";
}
}
console.log(s);
}
for ($i=0; $i<$n; $i++){
for ($j=0; $j<$n; $j++){
if($i+$j>$n-2){
echo "#";
} else {
echo " ";
}
if($j==$n-1 && $i+$j<$n*2-2){ //The second part is to dont break the last line
echo "\n";
}
}
}
Here's another solution:
$int = 7;
for($i = 1; $i<=$int; $i++){
printf('%1$s%2$s%3$s',str_repeat(" ",$int-$i),str_repeat("#",$i),"\n");
}
From official PHP documentation:
str_repeat
$n = 6;
for ($i = 0; $i < $n; $i++) {
$pad = 1;
for ($space = 0; $space < $n-$i-1; $space++) {
$pad++;
}
echo str_pad('#', $pad,' ',STR_PAD_LEFT);
for ($j = 0; $j < $i; $j++) {
echo '#';
}
echo '<br>';
}
Took me a while but finally I manage to do it following OFC (A. Sharma) Example.
<?php
$handle = fopen("php://stdin","r");
$n = intval(fgets($handle));
for ($rows = 0; $rows < $n; $rows++) {
for ($columns = 0; $columns < $n - $rows - 1; $columns++) {
echo " ";
}
for ($columns = 0; $columns < $rows + 1; $columns++) {
echo "#";
}
echo "\n";
}
?>
Use PHP functions range() and str_repeat() for an elegant solution:
function staircase($n){
foreach (range(1, $n) as $i)
print( str_repeat(' ',$n-$i).str_repeat('#',$i)."\n");
}
demo
Check if n is between 0 and 101 ( 0 < n <= 100)
Loop through each row
2.1 print spaces according to the last item position
2.2 print the items
Separate rows
The code below explains everything...
function staircase($n) {
// check if n is between 0 and 101 (0 < n <=100)
if( 0 < $n && $n > 100 ) {
} else {
// Loop through each row
for($i = 1; $i <= $n; $i++) {
// print spaces according to the last item position
$si = 1;
while( $si <= ($n - $i)){
print(" ");
$si++;
}
// print the items
for($j = 1; $j <= $i; $j++) {
print("#");
}
// separate rows
print("\n");
}
}
}
Output: For n = 6
#
##
###
####
#####
######
After playing around with the code and trying/failing couple of times I finally got it right. Notice how in order to print the space and new line I am using "\n". Previous "<br/>" and " " for space didn't work.
Break line will come out of the loop every row number. So if we have $n=4 then every 4 spaces after break line will be echoed.
I have made 2 loops to fill in all fields in the staircase.
The tricky part here is to have them right aligned. This is where if statement comes in place.
Reference link:
Hackerrank Challenge
// Complete the staircase function below.
function staircase($n) {
for($i=1; $i<=$n; $i++){
for($j=1; $j <= $n; $j++){
if( ($n - $i) < $j ){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}
Try This
$n=6;
for($i=1;$i<=$n;$i++){
for($spaces=1;$spaces<=($n-$i);$spaces++){
echo " ";
}
for($staires=0;$staires<$i;$staires++){
echo "#";
}
echo "\n";
}
This worked for me
$n = 6;
function staircase($n) {
for($i=1; $i <= $n; $i++){
for($j=1; $j <= $n; $j++){
if($j > $n-$i){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}
Use print(' '), if you want to go to next line put print(' ')."\n"
JavaScript:
Solution:
function StairCase(n){
let x = [];
for(let i = 0; i<n; i++){
while(x.length < n){
x.push(" ");
}
x.shift();
x.push("#");
console.log(x.join(''));
} } //StairCase(6)
What I want to get with for loop. Something will be like this.
*
**
***
****
*****
****
***
**
*
This thing I want to create right now I have this code.
<?php
$i = 1;
$end = 5;
$star = "*";
for($i; $i <= $end; $i++){
for($b=1; $b <= $i; $b++){
echo $star;
}
if($i == $end){
for($c=1; $c <= $end; $c++ ){
for($d=i; $d >= 2; $d--){
echo $star;
}
echo "<br>";
}
}
};
?>
And it's working fine with
*
**
***
****
*****
But then I need opposite loop first 4 then 3 then 2 then 1...
Where am I going wrong with this?
Just for fun. Try this:
$stars = 1;
for ($i = 0; $i < 9; $i++) {
for ($s = 1; $s <= $stars; $s++) {
echo "*";
}
echo "\n";
$stars += ($i<4)?1:-1;
}
And, for even more fun, one with just one for loop:
$stars = 0;
$starctr = 0;
for ($i = 0; $i < 25; $i++) {
echo "*";
if ($stars == $starctr) {
echo "\n";
$stars += ($i<14)?1:-1;
$starctr = 0;
} else {
$starctr++;
}
}
Can using nested for loop. Example:
$n = 5;
for($i = 1; $i <= $n; $i++){
for($j = 1; $j <= $i; $j++){
echo '*';
}
echo '<br />';
}
for($i = $n-1; $i >= 1; $i--){
for($j = $i; $j >= 1; $j--){
echo '*';
}
echo '<br />';
}
Another technique using array_fill(), array_map(), array_reverse()
$n = 5; $arr = array();
for($i = 1; $i <= $n; $i++){
$arr[] = array_fill(0, $i, '*');
}
array_map(function($v){echo join('', $v) . '</br>';},$arr);
unset($arr[count($arr) - 1]); //remove last index value
array_map(function($v){echo join('', $v) . '</br>';},array_reverse($arr));
<?php
for($i=0;$i<=6;$i++){
for($k=6;$k>=$i;$k--){
echo " ";
}
for($j=1;$j<=$i;$j++){
echo "* ";
}
echo "<br>";
}
for($i=5;$i>=1;$i--){
for($k=6;$k>=$i;$k--){
echo " ";
}
for($j=1;$j<=$i;$j++){
echo "* ";
}
echo "<br>";
}
?>
This can be achieved with only 2 for loops.
$offset = 1;
for ($i = 1; $i > 0; $i += $offset)
{
for($j = 1; $j <= $i; $j++){
echo '*';
}
echo '<br />';
if ($i === 5)
$offset = -1;
}
<?php
$i = 1;
$end = 5;
$star = "*";
for($i; $i <= $end; $i++){
for($b=1; $b <= $i; $b++){
echo $star;
}
};
for($c=$send; $c>=2; $c-- ){
for($d=$end; $d >= 2; $d--){
echo $star;
}
echo "<br>";
};
?>
Using a single for loop:
$end = 5;
$out = array();
for ($i=0;$i<$end;++$i)
{
$out[] = str_repeat('*', $i+1);
}
echo implode(PHP_EOL, $out).PHP_EOL;
array_pop($out);
$out = array_reverse($out);//remove last ****** <-- only one line with 5 stars
echo implode(PHP_EOL, $out).PHP_EOL;
Replace PHP_EOL with <br> if you want to, but this is the least loopy way to write this code I can think of
live demo
Here's a recursive attempt:
function ladder($n, $counter=1, &$acc=array())
{
if ($counter == ($n*2)) {
return implode($acc);
}
if ($counter <= $n) {
$acc[$counter] = str_repeat('*', $counter) . "\n";
$counter++;
}
if ($counter > $n) {
$diff = (int) $n-$counter;
$acc[$counter] = str_repeat('*', $n+$diff) . "\n";
$counter++;
}
return ladder($n, $counter, $acc);
}
print_r(ladder(5));
I am trying to print number vertically and it must be in group
here is my code
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
for ($i = 1; $i <= $rows; $i++) {
for ($j = $i; $j <= 24; $j = $j + $rows) {
$count++;
if($count>$nums){
break;
}
echo "<div class='fleft'>$count</div>";
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
out of above
but i want output like for the first column
and next group number will start from where first group number end. in this case next group start from 25
please ask if any doubt
$nums = 105;
$rows = 8;
$colsize = 3;
$col = floor($nums / $rows);
$group = floor($col / $colsize);
$count = 0;
$groupsize = $rows * $colsize;
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
$modulo = 0;
$correction = 0;
$rest = $nums - $count;
if ($rest < $groupsize) {
$empty = $groupsize - $rest;
$correction = floor($empty / $colsize);
$modulo = $empty % $colsize;
}
for ($i = 1; $i <= $rows; $i++) {
$colind = 0;
for ($j = $i; $j <= $groupsize; $j = $j + $rows) {
$count++;
if ($count > $nums) {
break;
}
$val = $j + ($g * $groupsize);
$val -= $colind * $correction;
$modcor = $colind - ($colsize - $modulo);
if ( $modcor > 0 ) {
$val -= $modcor;
}
echo "<div class='fleft'>" . $val . "</div>";
$colind++;
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
This works:
Also, you can change number of digits, columns or size of column
for($group = 0; $group < 3; $group++){
for($row =1 ; $row <= 8; $row++){
for($col = 0; $col <= 2; $col++){
echo ($group*24)+ $row + 8 * $col; echo " ";
}
echo "\n";
}
}
This code will print the number in the requested format. You need to modify according to your need.
may be i am mad , made a simple alter .... try this
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$letCounter=0; //added a counter
for ($g = 0; $g <= $group; $g++) {
echo "<div class='group'>";
for ($i = 1; $i <= $rows; $i++) {
$letCounter=0; //reset counter on each loop
for ($j = $i; $j <= 24; $j = $j + $rows)
{
$count++;
if($count>$nums)
{break;}
//made an alter in the below line , some math :)
echo "<div class='fleft'>".($letCounter++ * $rows +$i)."</div>";
}
echo "<div class='clear'></div>";
}
echo "</div>";
}
Thanks !
This May work
$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$flag = true;
for($c=1;$c<=$col;$c++)
{
if($c%$group== 1)
{
echo "Group Start";
$flag = false;
}
for ($i = 1; $i <= $rows; $i++) {
$count++;
echo "<div class='fleft'>$count</div>";
echo "<div class='clear'></div>";
}
echo "Line End";
if($c%$group == 2&& $flag)// Check here for your requirement
echo "Group End </br>";
$flag = true;
}