I've got a dynamic page which I'm loading from an external PHP file when the booking link is clicked.
My issue is the jQuery code I need to run straight after it sometimes tries to execute before the PHP page is fully loaded (the follow and remove parts specifically). So when I try load the div, jQuery works sometimes, and other times not.
From what I've seen on other examples $(document).ready(function() is supposed to prevent the jQuery executing until the page is fully loaded, however since I'm loading a specific div (content) and not the entire page it seems to not work?
$(document).ready(function(){
$(document).on('click', '.booking', function (){
$('#content').load('calendar.php');
$.getJSON(url,data, function(data) {
$.each(data, function(index, data) {
$("#blocksid"+data.slot_id).css("background-color","#009cd0");
$("#follow"+data.slot_id).hide();
$("#remove"+data.slot_id).show();
});
});
return false;
});
});
Thanks in advance for any assistance!
To achieve what you are expecting in a predicable way you should run dependent javascript code
after loading content to div. Just create a call-back function for load method and have your dependent code inside it.
$('#content').load("calendar.php", function() {
//put the code here, that you need to run after loading content to above div
});
You need to set:
$.ajaxSetup({ async: false });
and then turn it back on by:
$.ajaxSetup({ async: true });
or use
$.ajax({
async:false
});
Related
Something weird - I have the script inside the bootstrap modal.
sometimes the script is loaded and works and sometimes it doesn't.
here is a URL for example:
https://ns6.clubweb.co.il/~israelig/sites/followmyroutes/test_sec.php
Click on the button and see the modal, then close the modal and open it again. After the couple of times, the scripts inside the modal stops working (scripts like form validation [when you submit it], image browser)
How can I fix it so all the script will work every time?
The way you populate the html is right or not suggested to be advised by coders. Check again from where you got the documentation.
your existing code from backend call
$(document).on('ready', function() {
$("#input-8").fileinput({
});
});
Try changing like
$(document).on('ready', function() {
setImageUploader();
});
function setImageUploader(){
$(document).find("#input-8").fileinput({
});
}
And also
$.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info,
success: function(data) {
$modal.find('.modal-body').html(data);
setTimeout(function(){ //added this line.
setImageUploader()
})
}
});
i think the problem in the syncronisation of the request, you can use Ajax reque
It looks like your common libraries like jquery bootstrap-datepicker, fileinput theme etc are being get every time the modal is launched.
This may cause a sort of namespace corruption or some weird side effect of the kind you seem to see.
You could put all the common libraries outside of the modal to prevent this from happening.
the problem in the ajax request, I means you maste waite while the request it's done.
var request = $.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info
});
request.done(function(data) {
$modal.find('.modal-body').html(data);
});
I have two Ajax functions that are on the same div, the first one executes when complete page is fully loaded and call the ccslider method, instead the second one checks which menu ID I clicked, on the menu, to load dynamically different contents for different pages.
I can see the content loaded (eg: pictures) but unfortunately I don't see them in the ccslider; it seems that the slider is not executed.
But I know that works just because if I test it, removing the swapContent() function and place my PHP code with the MySQL query inside my main page the pictures are loaded inside the working ccslider.
Any hint on how to fix this problem?
$(window).load(function(){
$('#sliding').slider({
_Options: {
imageWidth: 300,
imageHeight: 200
}
});
});
function swapContent(cv) {
var url = "testing_cover.php";
$.post(url, {contentVar: cv}, function(data) {
$("#sliding").html(data).show();
});
}
You might have to call the slider method again inside the swapContent() function. Try this.
function swapContent(cv) {
var url = "testing_cover.php";
$.post(url, {contentVar: cv}, function(data) {
$("#sliding").html(data).show();
$('#sliding').slider({
_Options: {
imageWidth: 300,
imageHeight: 200
}
});
});
}
I have no access to the kind of plugin you're using, but from what it seems, you're probably modifying the HTML structure needed for it's functionality. Try inserting the HTML to a wrapper inside the #sliding element as opposed to directly in it.
I read this question, and I'm pretty sure it's 90% of what I need, but I'm after something more than just this, and my success formulating my query in Google has been less than stellar.
What I'd like to do
I have a form on a site that, when submitted, needs to connect with a database, and then the user needs to be apprised of the result. I'm trying to get the result page to load in a modal jQuery dialog instead of forcing a full page reload. At present, I'm just trying to create a jQuery dialog that replaces the contents of a <div> with the product of a PHP file. I know I will get the PHP file's execution result this way. That's what I'm after, but it currently is not working.
My code currently looks like this:
$(document).ready(function() {
$("#dialog").get('include.php', function(data) {
$("div#dialog").html(data);
});
});
And include.php is simply:
<?
echo "<h1>Loaded</h1>";
?>
When I load the page, the original contents of #dialog are still there. I have a strong suspicion that what I'm failing to grasp isn't major, but I've had bad luck finding the fix. I'm a web dev newbie. How do I wwebsite as on the internet?
You are calling get on a jQuery result. That'a a different method than $.get, the one you should be using:
$(document).ready(function() {
$.get('include.php', function(data) {
$("div#dialog").html(data);
});
});
i have been using Ajax call for the same purpose. So try this :
$(document).ready(function() {
$.ajax('include.php',
success : function(data) {
$("#dialog").html(data);
});
});
If you want to replace the entire contents of the #dialog DOM object with the HTML you load, then you probably want to use .load():
$(document).ready(function() {
$("#dialog").load('include.php', function(data) {
// no need to set the html here as .load() already does that
});
});
I'm trying to load a PHP document dynamically which uses some jQuery events on the same script so after loading the webpage the jQuery effects don't work.
For example:
$(document).ready(
function(){
main();
function main()
{
$('#game1').hover(
function(){ $('#info1 p').slideDown('fast'); },
function(){ $('#info1 p').slideUp('fast'); }
);
$("#izquierda a").click(function()
{
$('#izquierda ul').hide();
$('#content').slideDown();
$('#menu').slideDown();
$('#contentMin').hide();
$("#gameContent").load("content.php", main()); // i try loading main() again so the effects would have some effect? doesn't work though
});
}
});
And in content.php I load data from a database and place it in a div called #game1 which uses the hover effect but it doesn't work after I loaded content.php. Without having it loaded from content.php the same script works.
So how can i make it work?
Sorry im new to this, thanks!
Since the server needs to render the code, you need to use AJAX here. Look up the jQuery ajax function: http://api.jquery.com/jQuery.ajax/.
$("#gameContent").ajax({
url: "content.php",
success: function(){ main(); }
});
I want to load the external page's data into a div along with the javascript functions(though the js file is same for both of them, the functions do not work). The file loads fine into the page, but the javascript function don't work properly.
My Code-
var emaild = $("#hidden").val();
var div = $("#mydiv");
var refreshId = setInterval(function() {
$.getScript("js.js", function() {
div.html($("#load").load('posts.php?id='+emaild));
});
}, 6000);
$.ajaxSetup({ cache: false });
Thanks in advance. Hope I get a solution soon! :D
You may have a problem here:
div.html($("#load").load('posts.php?id='+emaild));
$.html() expects an html string and you're giving it a deferred instead. It may not be the cause of your script not running, but good to eliminate anyhow.
Is there a reason why you're using $("#load").load when you want the output of the call to go inside div. In other words, isn't this what you really want?
div.load('posts.php?id=' + emaild);