I read this question, and I'm pretty sure it's 90% of what I need, but I'm after something more than just this, and my success formulating my query in Google has been less than stellar.
What I'd like to do
I have a form on a site that, when submitted, needs to connect with a database, and then the user needs to be apprised of the result. I'm trying to get the result page to load in a modal jQuery dialog instead of forcing a full page reload. At present, I'm just trying to create a jQuery dialog that replaces the contents of a <div> with the product of a PHP file. I know I will get the PHP file's execution result this way. That's what I'm after, but it currently is not working.
My code currently looks like this:
$(document).ready(function() {
$("#dialog").get('include.php', function(data) {
$("div#dialog").html(data);
});
});
And include.php is simply:
<?
echo "<h1>Loaded</h1>";
?>
When I load the page, the original contents of #dialog are still there. I have a strong suspicion that what I'm failing to grasp isn't major, but I've had bad luck finding the fix. I'm a web dev newbie. How do I wwebsite as on the internet?
You are calling get on a jQuery result. That'a a different method than $.get, the one you should be using:
$(document).ready(function() {
$.get('include.php', function(data) {
$("div#dialog").html(data);
});
});
i have been using Ajax call for the same purpose. So try this :
$(document).ready(function() {
$.ajax('include.php',
success : function(data) {
$("#dialog").html(data);
});
});
If you want to replace the entire contents of the #dialog DOM object with the HTML you load, then you probably want to use .load():
$(document).ready(function() {
$("#dialog").load('include.php', function(data) {
// no need to set the html here as .load() already does that
});
});
Related
The problem is this:
I have a simple, two fields form which I submit with Ajax.
Upon completion I reload two div's to reflect the changes.
Everything is working perfect except a jQuery plugin. It's a simple plugin that can be called with simple
function(){
$('.myDiv').scrollbars();
}
It's simple and easy to use, but it doesn't work on Ajax loaded content. Here is the code I use to post form and reload div's:
$(function() {
$('#fotocoment').on('submit', function(e) {
$.post('submitfotocoment.php', $(this).serialize(), function (data) {
$(".coment").load("fotocomajax.php");
}).error(function() {
});
e.preventDefault();
});
});
I've tried creating a function and calling it in Ajax succes:, but no luck. Can anyone show me how to make it work ? How can that simple plugin can be reloaded or reinitialized or, maybe, refreshed. I've studied a lot of jQuery's functions, including ajaxStop, ajaxComplete ... nothing seems to be working or I'm doing something wrong here.
If you're loading elements dynamically after DOM Document is already loaded (like through AJAX in your case) simple binding .scrollbars() to element won't work, even in $(document).ready() - you need to use "live" event(s) - that way jQuery will "catch" dynamically added content:
$(selector).live(events, data, handler); // jQuery 1.3+
$(document).delegate(selector, events, data, handler); // jQuery 1.4.3+
$(document).on(events, selector, data, handler); // jQuery 1.7+
Source: jQuery Site
Even if I am totally against using such plugins, which tries to replicate your browser's components, I'll try to give some hints.
I suppose you are using this scrollbars plugin. In this case you may want to reinitialize the scrollbars element, and there are many ways to do this. You could create the element again like in the following example
<div class="holder">
<div class="scrollme">
<img src="http://placekitten.com/g/400/300" />
</div>
</div>
.....
$('.scrollme').scrollbars();
...
fakedata = "<div class='scrollme'>Fake response from your server<br /><img src='http://placekitten.com/g/500/300' /></div>";
$.post('/echo/html/', function(response){
$('.holder').html(fakedata);
$('.scrollme').scrollbars();
});
If you want to update the contents of an already initialized widget instead, then things gets more complicated. Once your plugin initialize, it moves the content in some custom wrappers in order to do its 'magic', so make sure you update the correct element, then trigger the resize event on window, pray and hopefully your widget gets re-evaluated.
If it doesn't help, then try to come up with some more details about your HTML structure.
I want to thank everyone of you who took their time to answer me with this problem I have. However, the answer came to me after 4 days of struggle and "inventions" :), and it's not a JS or Jquery solution, but a simple logic in the file.
Originally, I call my functions and plugins at the beginning of the document in "head" tag, like any other programmer out here (there are exceptions also ).
Then my visitors open my blog read it and they want to post comments. But there are a lot of comments, and I don't want to scroll the entire page, or use the default scroll bars, simply because they're ugly and we don't have cross browser support to style that, just yet.
So I .post() the form with the comment, and simply reload the containing all of them. Naturally .scrollbars() plugin doesn't work. Here come the solution.
If I put this :
<script>$('.showcoment').scrollbars();</script>
in the beginning of my loaded document (with load() ), will not work, because is not HTML and it's getting removed automatically. BUT !!! If i do this:
<div><script>$('.showcoment').scrollbars();</script></div>
at the same beginning of loaded document, MAGIC .... it works. The logic that got me there I found it in the basics of javascript. If your script is inside an HTML element, it will be parsed without any problem.
Thank you all again, and I hope my experience will help others.
If I understand you correctly, try this:
var scrollelement = $('.myDiv').scrollbars();
var api = scrollelement.data('jsp');
$(function () {
$('#fotocoment').on('submit', function (e) {
$.post('submitfotocoment.php', $(this).serialize(), function (data) {
$(".coment").load("fotocomajax.php");
api.reinitialise();
}).error(function () {
});
e.preventDefault();
});
});
reinitialise - standart api function, updates scrolbars.
(Not sure if I missed an already similar answered question…)
On click of a button, I'm loading various images from a database via PHP/MySQL and appending it to the body (the actual images are of course not stored in the database, the correct selection of the images is based on a posted variable).
My goal is to display a loading indicator after pressing the button and hiding the indicator after all the image data has completely loaded and displayed. This may be an easy to solve callback issue but I'm just getting started with AJAX. :)
The following is the code I currently managed to come up with. I'm guessing the load() function is not really the right one here?
Thanks for your help!
$("#somebutton").click(function(){
alert("fetching…");
$.post('loadmore.php', {
somevariable: somevariable
},
function(data){
$("body").append(data);
$(window).load(function(){
alert("finished loading…");
});
});
});
The function you have with the finished loading... alert is a success callback, so it gets executed once the AJAX call has finished. This means you don't need to use $(window).load.
Also, you can use the html method on an element to change its contents and display a message.
Something like this would work fine:
$("#somebutton").click(function(){
$('#divID').html('Loading...');
$.post('loadmore.php', {
somevariable: somevariable
},
function(data){
$("body").append(data);
$('#divID').html('');
});
});
Read the docs http://api.jquery.com/jQuery.ajax/
Use the success callback to append the body and then the complete and error callbacks to clear things up correctly.
$("#somebutton").click(function(){
alert("fetching…");
$.post('loadmore.php', {
somevariable: somevariable
})
.success(function(data){$("body").append(data)})
.error(function(){alert("oh dear")})
.complete(function(){alert("finished loading…")});
});
Remember to always have a fallback for removing the loader - nothing worse than just having a loader and no way to remove it from the page and continue using the application / web site.
I managed to solve my problem by reading and tweaking the code in the following article.
The function load() with the equation containing the self-explanatory variables [imagesLoaded >= imageCount] did the trick.
Know when images are done loading in AJAX response
For a website I'm making for school, I'm trying my hand at using Jquery extensively for the first time, and even though I managed quite a bit so far, I'm stuck at two (most likely related) problems.
I'm aware that the upcoming case is somewhat long, but I feel it's necessary to submit all relevant code for everyone reading this to get a good image of what is happening.
Basically, the website is one index.html file, with the CSS thrown in, a few buttons, and one div with the ID content. I use this code to make this work:
<script type="text/javascript">
if ($('#content').innerHTML == " "){
$(document).ready(function(){
$('#content').load('main_text.html');
});
}
</script>
<script type="text/javascript">
function loadContent(elementSelector, sourceURL) {
$(""+elementSelector+"").load(""+sourceURL+"");
}
</script>
Then there is one content page, named search.html, which only contains a form that submits a search string to a search.php page (through ajax) that should then place the search results immediately back into a div called search_results in that same search.html file. The jquery that I use for this:
<script type='text/javascript'>
$(document).ready(function(){
$("#search_results").slideUp();
$("#search_button").click(function(e){
e.preventDefault();
ajax_search();
});
$("#search_term").keyup(function(e){
e.preventDefault();
ajax_search();
});
});
function ajax_search(){
$("#search_results").show();
var search_val=$("#search_term").val();
$.post("Functions/search.php", {search_term : search_val}, function(data){
if (data.length>0){
$("#search_results").html(data);
}
})
}
</script>
The issue that I'm having is as followed:
Before I had the first line of code: if ($('#content').innerHTML == " "){; implemented, I would open the site, main_text.html would nicely be loaded in, I could navigate to other subpages fine. But typing in something in the form field in search.html did not display any results (just typing should already trigger the function). When I hit the search button on this form, instead of seeing query results, the main_text.html file load again in the #content div. This made me assume that perhaps, somehow, that the code:
$(document).ready(function(){
$('#content').load('main_text.html');
});
was being called again unwanted. Hency why I implemented that check for whether innerHTML existed.
However, now, when I first load the page, the #content div does not load any initial content at all. (The section on the webpage just becomes black, like my page background) I have to click any button to get some content loaded again in my main content div. Also, when I now go back to the search.html, the typing anything to get results, like previously, still does not work. If I now hit the search button, I get the initial result again of what I'd see when I just opened the page: a blacked out #content div.
So somehow, the biggest issue is in the fact that the jquery to get results from my PHP do not seem to work. My problem with the content.innerhtml check might well be obsolete if the issue with the searchresults not displaying in the #search_result div on the search.html is fixed.
Anyone have any idea's what I could do to fix this. Or otherwise, what other approaches I could take for the kind of website I'm making. Since I'm trying to learn jquery here, better approaches are always appreciated, I'd rather learn myself doing this the right way and all. :)
Thanks for your time.
Few things to note here:
<script type="text/javascript">
if ($('#content').innerHTML == " "){
$(document).ready(function(){
$('#content').load('main_text.html');
});
}
</script>
<script type="text/javascript">
function loadContent(elementSelector, sourceURL) {
$(""+elementSelector+"").load(""+sourceURL+"");
}
</script>
In the above, you are testing to see if there is a space in the innerHTML of the element with an id of content.
jQuery uses .html() or .text() to make comparisons against the data being held within a container, so if you want to maintain using jQuery principles, change this line. Going along the same thought process, you are preparing an IF statement on an element before the document is actually ready and loaded.
You should move the document.ready function to the outside of the if statement. This will allow you to ensure that the element is available at DOM, and you can indeed perform checks against this element.
<script type="text/javascript">
$(document).ready(function(){
if ($('#content').html("")){
$('#content').load('main_text.html');
}
});
</script>
Also, while being readily provided and fully functional, I would recommend starting off using $.ajax instead of $.get / $.post. I have personal preferences as to why I think this, but I won't go into that, it's just that, personal.
$.ajax({
url: "Functions/search.php",
type: 'POST',
data: "search_term="+search_val,
success: function(data){
if (data.length>0){
$("#search_results").html(data);
}
});
Lastly, you should be using the GET method and NOT the POST method. Based on REST/SOAP practices, you are retrieving data from the server, and not posting data to the server. It's best practice to follow those two simple ideas. This isn't because web servers will have a difficult time interpreting the data; but, instead, it's to prepare you for working on larger scale application deployment, or future team-environments. This way everyone on the team has an expectation as to what method will be used for what purpose.
Anyway, long story short, you also leave semicolons off of the end of your closing }) brackets. While this is not an issue, nor will it cause flaws in your development, coding is all about uniformity. You've used the closing ; everywhere else, so try and maintain that same uniform design.
Best of luck.
I'm building a website which has a page that users can add content to, and they can rearrange the divs to whichever position and size they want. I'd like to have a save button which saves the current position of each div; however, I don't want the page to refresh each time (I'm also going to have an auto-save, which will have to save the information in the background).
I can't figure out how to post the data to the server though, without causing the page to reload. I figure I need some kind of AJAX request, but can't find anything that tells me how to do that (all the AJAX examples I can find seem to be about reading data from the server). I think I'm just starting to go round in circles now, but I can't get my head around this at all - I know it's probably not a hard thing to do, but I keep getting confused by the different examples.
So, first of all, is this the best way to do it? And, if so, can someone point me to a straightforward example of posting data via AJAX? I'm already using jQuery, so can use that for the Ajax as well.
Thanks.
Super simple AJAX with jQuery:
$.ajax({
url: '/save-the-stuff-url',
type: 'POST',
data: {
// information about your divs, etc.
'foo' : 'bar'
},
success: function(response) {
// if the AJAX call completes successfully, this function will get called.
alert('POST successful!');
}
});
Give it a shot!
Here, try this for AJAX:
$.post("example.php", {
from : "ajax", // put some info in these - they are the params
time : "2pm",
data : "save"
},
function(data) { // callback function - data always passed to it
$("#success").html(data); // do something with that data
}
);
And put this somewhere:
<span id='success'></span>
And then, try this example for example.php:
<?php
if(isset($_POST['from']) and $_POST['from'] == 'ajax'){
echo "<span style='color: green;'>Saved!</span>";
}
else {
echo "<span style='color: red;'>Failure!</span>";
}
?>
And then just modify these to fit your needs, probably changing the file of target. Whatever the script outputs is what is given to the ajax request. This means that if this was my PHP script:
<?php echo "Aloha!"; ?>
And this was my javascript:
$("#output").load("myScript.php");
Then #output would have "Aloha!" in it.
Hope this helps!
Please go through the Jquery site for various examples of post.
HTH
and the jQuery docs pages are a great way to learn jQuery.. the page for post is http://docs.jquery.com/Post
you may also want to look at jQuery draggables if you're not using that yet..
http://docs.jquery.com/UI/API/1.8/Draggable
you can fire a save tied to your draggable object being let go rather easily with
$( ".selector" ).draggable({
stop: function(event, ui) { ... }
});
Trying to load an external php file into another onClick. Iframes will not work as the size of the content changes with collapsible panels. That leaves AJAX. I was given a piece of code
HTML
Get data
<div id="myContainer"></div>
JS
$('#getData').click(function(){
$.get('data.php', { section: 'mySection' }, function(data){
$('#myContainer').html(data);
});
});
PHP:
<?php
if($_GET['section'] === 'mySection') echo '<span style="font-weigth:bold;">Hello World</span>';
?>
I have tested it here http://www.divethegap.com/scuba-diving-programmes-dive-the-gap/programme-pages/dahab-divemaster/divemaster-trainingA.php and get the most unexpected results. It certainly loads the right amount of items as it says in the lower bar on safari but I see three small calendars and that is it. Can anyone see where I have made a mistake?
First things first, you want to have the jQuery bit inside the ready function $(document).ready(function(){..}. In your test page, there is already a ready function at the top which contains the line $('a[rel*=facebox]').facebox(), so you might want to put the code there.
Secondly, you want to prevent the link from going to the default action, which is to load the url '#'. You do that with the preventDefault() method.
I tested and confirmed that the following code should work for you:
<script type="text/javascript">
$(document).ready(function(){
$('#getData').click(function(event){
event.preventDefault();
$.get('test.php', { cat: 16 }, function(data){
$('#myContainer p').html(data);
});
});
});</script>
You can find more details and examples of jQuery's get function here.
http://net.tutsplus.com/tutorials/javascript-ajax/how-to-load-in-and-animate-content-with-jquery/ this tutorial may helps you