Something weird - I have the script inside the bootstrap modal.
sometimes the script is loaded and works and sometimes it doesn't.
here is a URL for example:
https://ns6.clubweb.co.il/~israelig/sites/followmyroutes/test_sec.php
Click on the button and see the modal, then close the modal and open it again. After the couple of times, the scripts inside the modal stops working (scripts like form validation [when you submit it], image browser)
How can I fix it so all the script will work every time?
The way you populate the html is right or not suggested to be advised by coders. Check again from where you got the documentation.
your existing code from backend call
$(document).on('ready', function() {
$("#input-8").fileinput({
});
});
Try changing like
$(document).on('ready', function() {
setImageUploader();
});
function setImageUploader(){
$(document).find("#input-8").fileinput({
});
}
And also
$.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info,
success: function(data) {
$modal.find('.modal-body').html(data);
setTimeout(function(){ //added this line.
setImageUploader()
})
}
});
i think the problem in the syncronisation of the request, you can use Ajax reque
It looks like your common libraries like jquery bootstrap-datepicker, fileinput theme etc are being get every time the modal is launched.
This may cause a sort of namespace corruption or some weird side effect of the kind you seem to see.
You could put all the common libraries outside of the modal to prevent this from happening.
the problem in the ajax request, I means you maste waite while the request it's done.
var request = $.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info
});
request.done(function(data) {
$modal.find('.modal-body').html(data);
});
Related
I've got a PHP form set up and it works fine on it's own but now that I've hooked it up with AJAX I'm getting duplicate submissions when someone submits the form so even though they've only submitted the form once it's added the details to the database multiple times.
From my testing it seems as though its sending the data twice but looking at the submissions from other people it's possible that it's doing it more than twice under certain circumstances but I haven't been able to replicate that.
Here is the code I was using initially:
$("#email-gather").submit(function(e) {
var url = "https://www.ruroc.com/emailgather.php";
$.ajax({
type: "POST",
url: url,
data: $("#email-gather").serialize(),
complete: function(data) {
$('.email-win input.button').val("submitted").attr('disabled', 'disabled').css({'background-color' : '#b34c4c','text-shadow' : 'none'});
}
});
e.preventDefault();
});
I have had a look around to find a solution and I saw a few people with similar issues saying that .live should be used instead of .submit so I amended my code this this:
$( "#email-gather" ).live( "submit", function() {
event.preventDefault();
var url = "https://www.ruroc.com/emailgather.php";
$.ajax({
type: "POST",
url: url,
data: $("#email-gather").serialize(),
complete: function(data) {
$('.email-win input.button').val("submitted").attr('disabled', 'disabled').css({'background-color' : '#b34c4c','text-shadow' : 'none'});
}
});
});
However this also resulted with the same issue so I'm hoping you might have a solution to this issue. I appreciate any help you can provide on the matter.
In the second part of code (that should work), you have event.preventDefault but event is not defined. try to add function(event) and it must work.
Else in the first one, you can put the prevent default before ajax call and take away the second submit. You need to add a return true in the ajax function to tell you script that the submit was successfull.
I've got a dynamic page which I'm loading from an external PHP file when the booking link is clicked.
My issue is the jQuery code I need to run straight after it sometimes tries to execute before the PHP page is fully loaded (the follow and remove parts specifically). So when I try load the div, jQuery works sometimes, and other times not.
From what I've seen on other examples $(document).ready(function() is supposed to prevent the jQuery executing until the page is fully loaded, however since I'm loading a specific div (content) and not the entire page it seems to not work?
$(document).ready(function(){
$(document).on('click', '.booking', function (){
$('#content').load('calendar.php');
$.getJSON(url,data, function(data) {
$.each(data, function(index, data) {
$("#blocksid"+data.slot_id).css("background-color","#009cd0");
$("#follow"+data.slot_id).hide();
$("#remove"+data.slot_id).show();
});
});
return false;
});
});
Thanks in advance for any assistance!
To achieve what you are expecting in a predicable way you should run dependent javascript code
after loading content to div. Just create a call-back function for load method and have your dependent code inside it.
$('#content').load("calendar.php", function() {
//put the code here, that you need to run after loading content to above div
});
You need to set:
$.ajaxSetup({ async: false });
and then turn it back on by:
$.ajaxSetup({ async: true });
or use
$.ajax({
async:false
});
I've this script:
<script>
$(document).ready(function() {
$('#signUpForm').submit(function() {
$.ajax({
type: 'POST',
url: "process.php",
data: $("#signUpForm").serialize(),
success: function(data)
{
$('#errors').show();
$('#errors').append(data);
}
});
return false;
});
});
</script>
It displays errors from php script. And right now every time I click submit button, new errors are added to old ones. I wonder, is it possible to reset old errors and show just new, after I click submit button?
Use $('#errors').html(data); instead of $('#errors').append(data);, When you use .append(), you add to the content you already had. .html() replaces the content.
Another alternative might be to empty first and then append. Like $('#errors').empty().append(data);
I wonder why do you have $('#errors').show();? If it was hidden first, maybe better to put .show() after the .html() / .append()`
Use $('#errors').empty().append(data);
I have this JavaScript code:
$(document).ready(function(){
$('#sel').change(function(){
$.ajax({
type: "POST",
url: "modules.php?name=TransProject_Management&file=index",
data: "&op=index_stat&stat="+$(this).val(),
cache: false,
success: function(data) {
//alert(data);
$("#ajax_results").html(data);
}
});
});
});
On status change i need to refresh a div without page reload. But it returns blank page. If i try alert the result on success, i get the response, also i checked with inspect element, its ok. The problem is that it returns blank page.
The file i'm working on, is the same( modules.php?name=TransProject_Management&file=index ) i called in ajax.
the html:
<body>
//...
<div id="ajax_results">
//.....
//somewhere here is the select option <select id="sel">......</select>
//.....
</div>
</body>
Any help, would be very appreciated.
use the following code to return your response html:
echo json_encode(array($your_response));
Then in your javascript, you will need to reference the data as:
success: function(data) {
$("#ajax_results").html(data[0]);
}
since it is now an array.
this in your ajax function refers to the jQuery XHR object, NOT the $('#sel') object. Just assign it to a variable before the ajax function like var sel = $(this) then use it later inside the function. Try this:
$('#sel').change(function(){
var sel = $(this);
$.ajax({
type: "POST",
url: "modules.php?name=TransProject_Management&file=index",
data: "&op=index_stat&stat="+sel.val(),
cache: false,
success: function(data) {
//alert(data);
$("#ajax_results").html(data);
}
});
});
});
Hmm, first glance the code looks good. Have you tried using Chrome debug tools? Hit F12 and check the Network tab, this will show you what is being returned. You can also debug without using an alert so you can step through to see what exactly the properties are.
Just thought, you might need to add 'd' to the data returned. Anyway, if you do what I suggested above, put a pause break on the line and run the code you will see what you need.
Based on your comments below the question, it seems that you are using the same script to display your page and to call in the javascript. This script seems to return a complete html page, starting with the <html> tag.
A page can only have one <html> tag and when you try to dump a complete html page inside an element in another page, that will lead to invalid html and unpredictable results.
The solution is to have your ajax script only return the necessary elements / html that needs to be inserted in #ajax_results, nothing more.
I have a web application which features a bunch of different items, which are generated from a MySQL table. As users scroll through it, I want them to be able to click a link next to the item which will insert the request into a MySQL database. Normally, I’d do this by creating a PHP page (which I will do anyways) that grabs the item name & user id from the URI using the $_GET method & inserts it into the table. However, in this case, I don’t want the users to be redirected away from wherever they are. I just want the link to send off the request, and maybe display a small message after it is successful.
I figured jQuery/AJAX would be best for this, but as I’m not too familiar with it, I’m not sure what to do. Any tips are appreciated!
You have to do something like
$('.classofyourlink').click(function(e){
e.preventDefault();//in this way you have no redirect
$.post(...);//Make the ajax call
});
in this way the user makes an ajax call by clicking a link without redirecting. Here are the docs for $.post
EDIT - to pass the value to jQuery in your case you should do something like
$('.order_this').click(function(e){
e.preventDefault();//in this way you have no redirect
var valueToPass = $(this).text();
var url = "url/to/post/";
$.post(url, { data: valueToPass }, function(data){...} );//Make the ajax call
});
HTML
<a id="aDelete" href="mypage.php">Delete</a>
Script
$(function(){
$("#aDelete").click(function(){
$.post("ajaxserverpage.php?data1=your_data_to_pass&data2=second_value",function(data){
//do something with the response which is available in the "data" variable
});
});
return false;
});
See http://api.jquery.com/jQuery.ajax/
$('#my-link').click(function(){
$.ajax({
url: "mypage.php",
context: document.body,
success: function(){
$(this).addClass("done");
}
});
return false;
});
$('.classOfYourLinkToBecliked').click(function(){
$.ajax({
type:'GET',
'url':'yoururl',
data: {yourdata},
processData: false,
contentType: false,
cache: false,
dataType: 'json',
success: function(response){
alert(response);
}
});
});