PHP variable used in SQL - php

Question

My code checks if there is $GET value, if not then assign ALL values of array.
Seems like simple thing,not sure why its not working.
if(isset($_GET["smonth"])) {$smonth= $_GET["smonth"];
}
else {$smonth =12;} working , but not what I want
else {$smonth =array (1,2,3,4,5,6,7,8,9,10,11) ;}
After that I would like to use it in SQL :
and d.month_of_year = '".$smonth."%'
That would be something like
and month_of_year = (all values of array) or 1 value)
My Question:
What would be best solution to check, if active month is available? If not, assign All months to query.Thank You

Answer 1

The built-in PHP functions of in_array and implode should solve your issue:
in_array('1', $_GET["smonth"]); // checks if January is in $_GET["smonth"]
implode("," , $_GET["smonth"]); // Pull all of the values out of $_GET["smonth"] as a A STRING

Answer 2

Try in your statement and d.month_of_year IN (" . implode(',', $smonth) . ")

Answer 3

= operator checks for single value. If you want to check multiple values, use in.
and d.month_of_year in (".$smonth.")
You also have a % there, which works with LIKE queries.

Answer 4

<?php
if(isset($_GET['month'])){
$month = date('m'); //This would give you the index of the current month.
$array = array('01','02','02');
$query = "select * from table where month = ";
if(in_array($month,$array)){
$query = "select * from table where month = '".$month."'";
//Then query here
}
else
{
$query = "select * from table";
$where = "";
foreach($month as $m){
$where .= ' month = "'.$m.'" and ';
}
//There would be a ending and pls just try remove it
$query .= $where;
// then query here
}
}
?>