Using String as array and use it in a query - php

I am working on a PHP file and getting via POST this string:
$temas = $_POST['temas']; //$temas = ".45.12.34"
Where each of the numbers should be the id for a table record.
And I have following query
$query = "SELECT * FROM tb_preguntas WHERE tema = '".$temas."'";
I need to put in the WHERE part of the query each of the received id
Something like that: ... WHERE tema = 45 OR tema = 12 OR tema = 34
Of course, on each execution the string changes.
I have tried using the PHP explode function, but I don't know how to implement the result in the query.

My answer won't differ too much from everyone else's but it is an answer to address SQL injection + a solution
$temas = implode(',', explode('.', $_POST['temas']));
$temas = trim($temas);
$res = $conn->prepare('select * from `tb_preguntas` WHERE `tema` in (:temas)');
$res->execute(array(':temas' => $temas));
here we use a prepared statement, now you're code is safe woop woop

As suggested above you can use the IN() function of mysql, however you have to remove the first period '.' and change the rest to commas ','.
$query = "SELECT * FROM `tb_preguntas` WHERE `tema` IN('".str_replace('.',',',trim($temas,'.'))."') ";

best case scenario
$temas = implode(',', explode( '.', $_POST['temas']));
$query = "select * from tb_preguntas WHERE tema in (" . $temas . ")";
but your case, . comes first that makes life so much harder, so a better solution would be
$temas1 = explode( '.', $_POST['temas'] );
$temas2 = array();
foreach( $temas1 as $value ) {
if( is_numeric( $value )) $temas2[] = $value;
}
$query = "select * from tb_preguntas WHERE tema in (" . implode( ',' , $temas2 ) . ")";

Use explode() to split those numbers by .And it must turn into array.
Then run your queries into a loop using the lenth of the array like this:
$id = explode('.',$temas);
foreach($id as $temas_id) {
$query = "SELECT * FROM tb_preguntas WHERE tema = '".$temas_id."'";
if(isset($conn->query(query ))) {
// Execute code here if there's a result.
}
}

Please try this code.
$temas = $_POST['temas'];
$temas = explode('.',$temas);
$query = mysql_query("SELECT * FROM test_stipe WHERE tema in '".implode("', '", $temas)."'");
This code is working fine.

Related

Dynamic "Where" clause in wpdb->prepare query

In the form, none of the inputs are mandatory. So, I want to have a dynamic "where" clause inside the wpdb query.
Presently this is the query:
$data = $wpdb->get_results($wpdb->prepare("SELECT * FROM
`wp_gj73yj2g8h_hills_school_data` where
`school_zipcode` = %d AND `school_type` = %s AND `school_rating` = %s
;",$selectedZip,$selectedType,$selectedRating));
if a user enters only school_zipcode then the where clause should have only "school_zipcode" column.
Same way for other combinations.
I would not make things complicated with dynamic where clauses... I would write PHP code which creates the query. For example...
NOTE!! THIS CODE IS NOT TESTED ON SERVER, IT'S JUST AN IDEA HOW TO SOLVE THE PROBLEM!
<?php
$where_query = array();
// Make sure to escape $_POST
if (!empty($_POST['school_zipcode')) {
$where_query[] = "school_zipcode='" . $_POST['school_zipcode'] . "'";
}
// Make sure to escape $_POST
if (!empty($_POST['school_type')) {
$where_query[] = "school_type='" . $_POST['school_type'] . "'";
}
// Should result in WHERE school_zipcode='123' AND school_type='text'
$where_query_text = " WHERE " . implode(' AND ', $where_query);
$data = $wpdb->get_results($wpdb->prepare("SELECT * FROM `wp_gj73yj2g8h_hills_school_data` " . $where_query_text . ";"));

PHP: search comma separated string in mysql?

I have a mysql query which simply looks into mysql to find LIKE strings and displays the result.
Within the same mysql query, I have 2 LIKE.
1 is always a single string and the other one can be single and sometimes multiple strings separated by commas.
when I use my code, I get no results at all even though I have all the fields in the mysql database and I also have all the search strings in the columns.
This is my code:
$area = 'London';
$res = 'santandar, HSBC, RBS, ';
$sql = "SELECT * FROM banks WHERE location LIKE '%$area%' AND name LIKE '%$res'";
I also tried it with preg_match and it didn't return anything:
$sql = "SELECT * FROM banks WHERE location LIKE '%$area%' AND name LIKE '".preg_match($res)."'";
If I remove the second LIKE and my code looks like below, it works just fine:
sql = "SELECT * FROM banks WHERE location LIKE '%$area%'";
So the issue starts when I try to search using a comma separated string.
Could someone please advise on this issue?
EDIT:
The PHP varibles are POSTS so they can be anything in each post.
they are like so:
$area = $_POST['area'];
$res = $_POST['res'];
you should use an OR condition:
$res_array = explode(',' $res)
$num_elem= count($res_array) // with this value you can build dinamically the query
"SELECT * FROM banks WHERE location LIKE '%$area%'
AND ( name LIKE concat('%', $res_array[0]),
OR LIKE concat('%', $res_array[1])
OR LIKE concat('%', $res_array[2]) ";
You are going to need to blow this out into separate LIKEs with an OR, such as:
...WHERE location LIKE '%{$area}' AND (name LIKE '%{$name1}%' OR name LIKE '%{$name2}' OR ...)
You could write this fairly simply with some PHP logic:
function build_like_or( $values, $field_name ) {
// Create an array from the comma-separated values
$names = explode( ',', $values );
// Trim all the elements to remove whitespaces
$names = array_map( 'trim', $names );
// Remove empty elements
$names = array_filter( $names );
$where = array();
// Loop over each, placing the "LIKE" clause into an array
foreach( (array)$names AS $name ) {
$where[] = "{$field_name} LIKE '%{$name}%'";
}
// Glue up the LIKE clauses.
$where = '(' . implode(' OR ', $where) . ')';
// Results will be something like:
// $where = "(name LIKE '%santadar%' OR name LIKE '%HSBC%')"
return $where;
}
Usage:
$area = 'London';
$res = 'santandar, HSBC, RBS, ';
$name_where = build_like_or( $res, 'name');
$sql = "SELECT * FROM banks WHERE location LIKE '%$area%' AND {$name_where}";
// echo $sql outputs "SELECT * FROM banks WHERE location LIKE 'London' AND (name LIKE '%santadar%' OR name LIKE '%HSBC%' OR name LIKE '%RBS%')

PHP variable used in SQL

My code checks if there is $GET value, if not then assign ALL values of array.
Seems like simple thing,not sure why its not working.
if(isset($_GET["smonth"])) {$smonth= $_GET["smonth"];
}
else {$smonth =12;} working , but not what I want
else {$smonth =array (1,2,3,4,5,6,7,8,9,10,11) ;}
After that I would like to use it in SQL :
and d.month_of_year = '".$smonth."%'
That would be something like
and month_of_year = (all values of array) or 1 value)
My Question:
What would be best solution to check, if active month is available? If not, assign All months to query.Thank You
The built-in PHP functions of in_array and implode should solve your issue:
in_array('1', $_GET["smonth"]); // checks if January is in $_GET["smonth"]
implode("," , $_GET["smonth"]); // Pull all of the values out of $_GET["smonth"] as a A STRING
Try in your statement and d.month_of_year IN (" . implode(',', $smonth) . ")
= operator checks for single value. If you want to check multiple values, use in.
and d.month_of_year in (".$smonth.")
You also have a % there, which works with LIKE queries.
<?php
if(isset($_GET['month'])){
$month = date('m'); //This would give you the index of the current month.
$array = array('01','02','02');
$query = "select * from table where month = ";
if(in_array($month,$array)){
$query = "select * from table where month = '".$month."'";
//Then query here
}
else
{
$query = "select * from table";
$where = "";
foreach($month as $m){
$where .= ' month = "'.$m.'" and ';
}
//There would be a ending and pls just try remove it
$query .= $where;
// then query here
}
}
?>

Php using a variable in a string (concatenation)

why i can't use this code ? and could anyone tell me what is the correct code ?
$lfr_prfid = "profile='$log_id'";
$lfrsql = "SELECT * FROM friends WHERE user2='$log_id' AND accepted='1'";
$lfrquery = mysqli_query($db_conx, $lfrsql);
while ($lfrrow = mysqli_fetch_array($lfrquery, MYSQLI_ASSOC)) {
$lfr_id = $lfrrow["id"];
$lfr_user1 = $lfrrow["user1"];
$lfr_user2 = $lfrrow["user2"];
$lfr_prfid += " OR profile='".$lfr_user1."'";
}
the last line i wrote this ( += ) and the code doesn't work so how can i do this in another way ? so i can use this in a SELECT statement .
$psql = "SELECT * FROM posts WHERE ".$lfr_prfid." ORDER BY postdate DESC LIMIT 0,20";
$pquery = mysqli_query($db_conx, $psql);
$lfr_prfid.=
Concatenate with . not with +. The + is concatenation in javascript.
so, in php: $myVar.= 'foo';
and in javascript: myVar+= 'foo';
Update based on your edit:
Please, DO NOT use that in a database query. Use prepared statements or your code is dangerous.
Change your code to:
$lfr_prfid .= " OR profile='".$lfr_user1."'";
Concatenation in PHP is done with ., not with += as you have written.
Hope this helps!

select table filter by querystring php

ok so I've been trying for a while now to get this to work but there has to be a better solution than what im thinking about. I'm fairly new to php/mysql so not sure how to do the following:
I have a search box that contains dropdowns for country, state, city
Now if the user only selects country and clicks on search it needs to filter the select by just country and show everything else.
if(!empty($_REQUEST['city']))
$city = $_REQUEST['city'];
else
$city= "%";
if(!empty($_REQUEST['state']))
$state= $_REQUEST['state'];
else
$state= "%";
if(!empty($_REQUEST['country']))
$country= $_REQUEST['country'];
select * from table where country = $country and state = $state and city = $city
problem with this is that those columns are ints so I can't use the "%" to filter it. I hope I was able to explain it any help is more than welcome. Thanks in advance
If you don't want to constrain a column, simply omit it from your query
never insert a string from $_REQUEST directly into a query string -- classic SQL injection flaw.
you probably want to enforce some sort of limit, lest the query return every single result in your database.
example:
<?php
$conditions = array();
if(!empty($_REQUEST['city']))
$conditions[] = "city = " . mysql_real_escape_string($_REQUEST['city']);
if(!empty($_REQUEST['state']))
$conditions[] = "state = " . mysql_real_escape_string($_REQUEST['state']);
if(!empty($_REQUEST['country']))
$conditions[] = "country = " . mysql_real_escape_string($_REQUEST['country']);
$sql = 'select * from table ';
if(!empty($conditions))
$sql .= ' where '. implode(' AND ', $conditions);
$sql .= ' LIMIT 1000';
$where = array();
if(!empty($_REQUEST['city'])) $where[] = "city = '".(int)$_REQUEST['city']."'";
if(!empty($_REQUEST['state'])) $where[] = "state = '".(int)$_REQUEST['state']."'";
if(!empty($_REQUEST['country'])) $where[] = "country = '".(int)$_REQUEST['country']."'";
$wherestring = if(count($where) != 0) ? " WHERE ".implode(' AND ', $where) : "" ;
$query = "SELECT * FROM table".$wherestring;
You may want to consider writing several query strings, one for just country, one for state and country and one for city, state and country. Alternatively you can assemble the query string based upon the different parameters you have to work with.
Example:
if(isset() || isset() || isset() ) //make sure at least one is set
{
$query_string = "SELECT * FROM table WHERE ";
if(isset($_REQUEST['country']))
{
$country = $_REQUEST['country'];
$query_string .= " country = $country";
}
if(isset($_REQUEST['state']))
{
$state = $_REQUEST['state'];
$query_string .= " state = $state";
}
if(isset($_REQUEST['city']))
{
$city = $_REQUEST['city'];
$query_string .= " city = $city";
}
}
else
{
//Else, if none are set, just select all the entries if no specifications were made
$query_string = "SELECT * FROM table";
}
//Then run your query...
So in english, the first thing you do is check your parameters, making sure you have something to work with before you try and concatenate empty variables together.
Then you make the base query string (as long as we have parameters) and leave it open ended so that we can add whatever parameters you need.
Next check each parameter, and if it is set, then concatenate that parameter onto the end of the query string.
Finally process the query by sending it to the SQL server.
Good luck!
h
Here're my suggestions.
I'm giving you an answer, even though you have three already. I'm thinking mine may be easier on the code-eyes.
Do not use the raw $_REQUEST value, as it's likely that the user can poison your database by feeding it fake $_REQUEST data. Though there may be better ways to do it, keep in mind the command "mysql_real_escape_string($string)".
A common method I've seen for solving this problem is written below. (The implode idea, basically. Frank Farmer does it as well in his.)
-
$__searchWheres = array(); //Where we'll store each requirement used later
foreach( array('city','state','country') as $_searchOption) {
if ( ! empty( $_REQUEST[$_searchOption] ) ) {
$__searchWheres[] = $_searchOption . '= "' . mysql_real_escape_string( $_REQUEST[$_searchOption] ) . '"';
}
}
$__query = 'select * from table' . (count($__searchWheres) > 0 ? ' WHERE ' . implode(' AND ',$__searchWheres) : ''); //Implode idea also used by Frank Farmer
//Select from the table, but only add the 'WHERE' key and where data if we have it.
mysql_query($__query);

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