SQL query not working but works in PHPMyAdmin - php

I have a web application and I'm trying to modify one of the queries. The query fetches information (from a table named voyage_list) and returns various fields.
I want to modify the query so that it is based on certain filters the user applies (which will be placed in the URL).
I can't get the query to work in the web application, but if I copy the query and execute it directly within PHPMyAdmin, it works fine.
$vesselFilter = $_GET['vesselFilter'];
$vesselArray = explode(',', $vesselFilter);
$arrayCount = count($vesselArray);
$sqlExtend = ' status = 1 AND';
foreach ($vesselArray as $value) {
$i = $i + 1;
$sqlExtend .= " vesselID = '$value'";
if ($i < $arrayCount){
$sqlExtend .= " OR";
}
}
$newQuery = "SELECT * FROM voyage_list WHERE" . $sqlExtend;
echo $newQuery;
$query = $db->query($newQuery)->fetchAll();
I appreciate the above is pretty messy, but it's just so I can try and figure out how to get the query to work.
Any help would be greatly appreciated!
Thanks

That query probably doesn't return what you think it does. AND takes precedence over OR, so it will return the first vessel in the list if the status is 1, and also any other vessel in the list, regardless of status.
You'd do better to create a query with an IN clause like this:
SELECT * FROM voyage_list WHERE status = 1 AND vesselID IN(8,9,10)
Here's some code to do just that:
$vesselFilter = $_GET['vesselFilter'];
// Validate data. Since we're expecting a string containing only integers and commas, reject anything else
// This throws out bad data and also protects against SQL injection.
if (preg_match('/[^0-9,]/', $vesselFilter)) {
echo "Bad data in input";
exit;
}
// filter out any empty entries.
$vesselArray = array_filter(explode(',', $vesselFilter));
// Now create the WHERE clause using IN
$sqlExtend = 'status = 1 AND vesselID IN ('.join(',', $vesselArray).')';
$newQuery = "SELECT * FROM voyage_list WHERE " . $sqlExtend;
echo $newQuery;
$query = $db->query($newQuery)->fetchAll();
var_dump($query);

Related

Dynamic select query in mysql?

I am using mysql as my database and php as server side language.
As we know that we can select data from database using select query.
Below example is important!!
select * from table
select name from table
select name,salary from table where salary > 10000
etc..........
now, for different select query of a table we need different select method. because every time select * is not good because it takes a huge time.
Now, My Question is how write dynamic single get method of a single table by which we can achieve our requirement (shown in example...)?
I will pass the array of parameters in the argument of the function.. for ex. in php
public get($arr)
{
//code goes here
}
I want to fetch the $arr and want to change the sql dynamically..
Don't want any join query just simple select as shown in above..
Depending on how you want to do it, you can do something like this:
public get($arrfield, $arrtable, $arrwhere)
{
$str = "SELECT " . $arrfield . " FROM " . $arrtable . " WHERE " . $arrwhere;
return $str;
// You can return the query string or run the query and return the results
}
Trust me, to write all three queries is not that too hard a job that have to be avoided at any cost.
Please, do not obfuscate a precious SQL language into unreadable gibberish. Not to mention innumerable security breaches of your approach.
What you should think of is a function that lets you to use parameters. Thus, better make our function like this
function mysqli($mysqli, $query, $params, $types = NULL)
{
$statement = $mysqli->prepare($select);
$types = $types ?: str_repeat('s', count($params));
$statement->bind_param($types, ...$params);
$statement->execute();
return $statement;
}
and run your every query as is, only providing placeholders instead of variables
select * from table:
you'll never need a query like this
select name from table
$names = mysqli($db, "select name from table")->get_result->fetch_all();
`select name,salary from table:
$stmt = mysqli($db, "select name from table where salary > ?", [10000]);
$names = $stmt->get_result->fetch_all();
See - the query itself is the least code portion. Your concern should be not SQL but useless reprtitive parts of PHP code used to run a query and to fetch the data.
Here is the structure of the dynamic query.Please add required validation.You can add 'Or' clause also.On the basis of parameter or data type you can do it. Like
public SelectTable($arrfield, $table, $arrwhere, $arrgroup)
{
if(!empty($arrfield))
{
$fields = implode('`,`',$arrfield);
}
else
{
$fields = '*';
}
if(!empty($arrwhere))
{
foreach($arrwhere as $fieldName=>$fieldValue)
{
if(is_array($fieldValue))
{
$cond .= "`fieldName` in (". implode(',',$fieldValue) );
}
else
$cond .= "`fieldName` = '" . addslashes($fieldValue)."'";
}
}
else
{
$cond = '1';
}
if(!empty($arrgroup))
{
$groupBy .= " group by ";
foreach($arrgroup as $field=>$value)
{
$groupBy .= $field . " " . $vale;
}
}
}
$str = "SELECT " . $fields . " FROM " . $table . " WHERE " . $cond . $groupBy;
return $str;
// You can return the query string or run the query and return the results
}

SQL Query not completing correctly - not sure why

Alright,
I've got a multiple select dropdown on a page called week-select, its selections get passed via ajax to my php page.
I can get the data just fine, but when the query runs it doesn't complete appropriately.
I've got this:
//Deal with Week Array
$weekFilter = $_GET['week']; /*This is fine, if it's 1 week the query works great (weeks are numbered 12-15), but if it is 2 weeks the result is formatted like this 12-13 or 13-14-15 or whichever weeks are selected*/
$weekFilter = str_replace("-",",",$weekFilter); /*This works to make it a comma separated list*/
.../*I deal with other variables here, they work fine*/
if ($weekFilter) {
$sql[] = " WK IN ( ? ) ";
$sqlarr[] = $weekFilter;
}
$query = "SELECT * FROM $tableName";
if (!empty($sql)) {
$query .= ' WHERE ' . implode(' AND ', $sql);
}
$stmt = $DBH->prepare($query);
$stmt->execute($sqlarr);
$finalarray = array();
$count = $stmt->rowCount();
$finalarray['count'] = $count;
if ($count > 0) { //Check to make sure there are results
while ($result = $stmt->fetchAll()) { //If there are results - go through each one and add it to the json
$finalarray['rowdata'] = $result;
} //end While
}else if ($count == 0) { //if there are no results - set the json object to null
$emptyResult = array();
$emptyResult = "null";
$finalarray['rowdata'] = $emptyResult;
} //end if no results
If I just select one week it works great and displays the appropriate data.
If I select multiple options (say weeks 12, 14 and 15) it runs the query but only displays week 12.
When I manually input the query in SQL, how I imagine this query is getting entered - it runs and displays the appropriate data. So if I put SELECT * FROM mytablename WHERE WK IN ( 12, 14, 15 ) it gets exactly what I want.
I can't figure out why my query isn't executing properly here.
Any ideas?
**EDIT: I make the array from the multiple selections a string using javascript on the front end before it is passed to the backend.
Your resulting query with values probably looks like this with a single value in IN:
… WK IN ("12,14,15") …
Either use one placeholder for each atomic value:
if ($weekFilter) {
$values = explode(",", $weekFilter);
$sql[] = " WK IN ( " . implode(",", array_fill(0, count($values), "?")) . " ) ";
$sqlarr = array_merge($sqlarr, $values);
}
Or use FIND_IN_SET instead of IN:
$sql[] = " FIND_IN_SET(WK, ?) ";
I don't think you can bind an array to a singular ? placeholder. Usually you have to put in as many ? values as there are elements in your array.
If your HTML is correct and your week select has name="week[]", then you will get an array back with $_GET['week'];, otherwise without the [] it will only give you 1 value. Then, you're doing a string replace, but it's not a string. Instead, try this:
$weekFilter = implode(',', $_GET['week']);

Passing multiple $_POST fields through MySQL search query

I have a search form with a possible 15 or so fields, however not all are required to carry out a search, for instance;
a user might search for a registered user in 'London' who works in 'Finance' but leave all other fields blank, such as $availability or $salary etc, so $_POST data may look something like:
$location = $_POST['location']; // Value - London
$sector = $_POST['sector']; // Value - Finance
$available = $_POST['available']; // Value - Any
$salary = $_POST['salary']; // Value - Any
Bearing in mind I may have another 12 or so 'Any' values from other fields, what is the best way to query the database (PHP/MySQL) to return results without looping through what would probably be dozens of queries.
To try and be a bit clearer, what i'd like is a query which would work something like (deliberate pseudo code):
SELECT * FROM table where location = 'location' AND if($availability !='Any') { available = '$available' } etc etc
Is something like this possible?
Or can I create a single string of all $_POST fields that !='Any' and then carry out a search on a row that contains all the words in the string (which I think would work in theory)?
I hope this makes sense to someone and you can point me in the right direction.
P.S. All $_POST is escaped and secured before interacting with database, just not included here :)
Try this:
$sql = "SELECT * FROM table where 1 ";
foreach ($_POST as $key => $post) {
if ($post != 'Any') {
$sql .= " AND $key = '$post' ";
}
}
// now you can run $sql against the database
Could you for argument sake collect all of the $_POST into a foreach($key=>$val) and then run the key through a switch or if statments that appends "AND x=x " to the statement?
Something like:
$sql = "SELECT * FROM table WHERE required='required'";
foreach($_POST as $key=>$val){
if(!empty($val)){ $sql .= " AND ".$key."='".$val"'"; }
}
Not sure if that works but in theory that is what i thought of first.
Thanks to those who offered answers, however I used the suggested answer found in the link above my question as it was clearer to me. Sample code pasted below FYI:
$tmp = "where ";
if($A and $A!="any" and $A!="not used")
$tmp .= "row1 = '".$A."'";
if($B and $B!="any" and $B!="not used")
$tmp .= "AND row2 = '".$B. "'";
if($C and $C!="any" and $C!="not used")
$tmp .= "AND row3 = '".$C."'";
$db_q = "Select * from table $tmp";
Thanks again, don't know where I'd be without SO.

mysql PHP query question

Ok, i have a problem here...
I am sending values of drop down lists via ajax to this PHP file.
Now I want to search a mysql database using these values, which I have managed to do, BUT, only if I set the values to something...
Take a look:
$query = "SELECT * FROM cars_db WHERE price BETWEEN '$cars_price_from' AND '$cars_price_to' AND year BETWEEN '$cars_year_from' AND '$cars_year_to' AND mileage BETWEEN '$cars_mileage_from' AND '$cars_mileage_to' AND gearbox = '$cars_gearbox' AND fuel = '$cars_fuel'";
now, what if the user doesnt select any "price_from" or "year_from"... The fields are only optional, so if the user doesnt enter any "price from" or "year from", then the user wants ALL cars to show...
Do I have to write a query statement for each case or is there another way?
I do something similar to davethegr8 except I put my conditions in an array and then implode at the end just so I don't have to worry about which conditions got added and whether I need to add extra AND's.
For example:
$sql = "SELECT * FROM car_db";
// an array to hold the conditions
$conditions = array();
// for price
if ($car_price_from > 0 && $car_price_to > $car_price_from) {
$conditions[] = "(price BETWEEN '$cars_price_from' AND '$cars_price_to')";
}
elseif ($car_price_from > 0) {
$conditions[] = "(price >= '$cars_price_from')";
}
elseif ($car_price_to > 0) {
$conditions[] = "(price <= '$cars_price_from')";
}
else {
//nothing
}
// similar for the other variables, building up the $conditions array.
// now append to the existing $sql
if (count($conditions) > 0){
$sql .= 'WHERE ' . implode(' AND ', $conditions);
}
You could simply detect which parameters are missing in your PHP code and fill in a suitable default. eg
if (!isset($cars_mileage_to))
$cars_mileage_to = 500000;
You can build you query, adding the "where" part only if your variables are different from "".
or if you're using mysql 5.x, you can also use subselects:
http://dev.mysql.com/doc/refman/5.0/en/subqueries.html
don't forget to validate the input. It's trivial with firebug, for example, to inject some tasty sql.

Sql query only printing first row

I am coding in php and the code takes data from an array to fetch additional data from a mysql db. Because I need data from two different tables, I use nested while loops. But the code below always only prints out (echo "a: " . $data3[2]; or echo "b: " . $data3[2];) one time:
foreach($stuff as $key)
{
$query3 = "SELECT * FROM foobar WHERE id='$key'";
$result3 = MySQL_query($query3, $link_id);
while ($data3 = mysql_fetch_array($result3))
{
$query4 = "SELECT * FROM foobar_img WHERE id='$data3[0]'";
$result4 = MySQL_query($query4, $link_id);
while ($data4 = mysql_fetch_array($result4))
{
$x += 1;
if ($x % 3 == 0)
{
echo "a: " . $data3[2];
}
else
{
echo "b: " . $data3[2];
}
}
}
}
First and foremost, improve your SQL:
SELECT
img.*
FROM
foobar foo
INNER JOIN foobar_img img ON
foo.id = img.id
WHERE
foo.id = $key
You will only have to iterate through one array.
Also, it appears that you're actually only selecting one row, so spitting out one row is expected behavior.
Additionally, please prevent yourself from SQL injection by using mysql_real_escape_string():
$query3 = "SELECT * FROM foobar WHERE id='" .
mysql_real_escape_string($key) . "'";
Update: As Dan as intimated, please run this query in your MySQL console to get the result set back, so you know what you're playing with. When you limit the query to one ID, you're probably only pulling back one row. That being said, I have no idea how many $keys are in $stuff, but if it spins over once, then it will be one.
You may be better off iterating through $stuff and building out an IN clause for your SQL:
$key_array = "";
foreach($stuff as $key)
{
$key_array .= ",'" . mysql_real_escape_string($key) . "'";
}
$key_array = substr($key_array, 1);
...
WHERE foo.id IN ($key_array)
This will give you a result set with your complete list back, instead of sending a bunch of SELECT queries to the DB. Be kind to your DB and please use set-based operations when possible. MySQL will appreciate it.
I will also point out that it appears as if you're using text primary keys. Integer, incremental keys work best as PK's, and I highly suggest you use them!
You should use a JOIN between these two tables. It the correct way to use SQL, and it will work much faster. Doing an extra query inside the loop is bad practice, like putting loop-invariant code inside a loop.

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