Can help me, I have something problem about query select distinct, :
My table
table_pemesan
id_pms
table_pesan
no_psn
id_pms
table_dpesan
no_psn
My query mysql
select pm.id_pms,
pm.nama,
pm.date_create,
ps.no_psn,
ps.status,
dps.no_dpsn
FROM pemesan as pm
INNER JOIN pesan ps on ps.id_pms=pm.id_pms
INNER JOIN dpesan dps on dps.no_psn=ps.no_psn
ORDER BY pm.id_pms ASC
//output
Array
(
[0] => Array
(
[id_pms] => 1
[nama] => Isnan
[date_create] => 2014-05-28 23:54:54
[no_psn] => 1
[status] => sedang diproses
[no_dpsn] => 1
)
[1] => Array
(
[id_pms] => 1
[nama] => Isnan
[date_create] => 2014-05-28 23:54:54
[no_psn] => 1
[status] => sedang diproses
[no_dpsn] => 2
)
)
the array index 0 & 1 the same data, and my question how to distinct the query? thanks b4, sorry my english not good..
Try to use this query:-
SELECT DISTINCT pm.id_pms, pm.nama, pm.date_create, ps.no_psn, ps.status, dps.no_dpsn
FROM pemesan as pm
INNER JOIN pesan ps on ps.id_pms=pm.id_pms
INNER JOIN dpesan dps on dps.no_psn=ps.no_psn
ORDER BY pm.id_pms ASC
Related
I have two tables:
table1:
id email
1 john#gmail.com
2 doe#gmail.com
table2:
userid key value
1 firstname john
1 phone 112233
2 firstname doe
2 phone 223344
This is mysql query without condition:
SELECT a.*,
b.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
This is result:
array(
[id] => 1
[email] => john#gmail.com
[userid] => 1
[key] => firstname,phone
[value] => john,112233
)
array(
[id] => 2
[email] => doe#gmail.com
[userid] => 2
[key] => firstname,phone
[value] => doe,223344
)
This is mysql query with condition:
SELECT a.*,
b.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
WHERE b.key = "firstname"
AND b.value LIKE '%jo%'
And this is result:
array(
[id] => 1
[email] => john#gmail.com
[userid] => 1
[key] => firstname
[value] => john
)
But I want this:
array(
[id] => 1
[email] => john#gmail.com
[userid] => 1
[key] => firstname,phone
[value] => john,112233
)
There any way to do this? thank for any help!
Your queries are lacking the GROUP BY clause to get a row per user. Then use a HAVING clause to make sure the aggregated row includes a firstname '%jo%':
SELECT a.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
GROUP BY a.id
HAVING sum(b.key = 'firstname'
AND b.value LIKE '%jo%') > 0;
true results in 1, false in 0 in MySQL. So checking whether the sum is greater than zero means checking whether the condition is true at least once.
This is my User table
This is my Message table
And tHis is my Listing Table
Now I get successfully get the last message with this query
enter code here
$coreQueryUser = $this->Message->query('
select m.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
');
when i run this query it gives me following output:-
enter code here
<pre>Array
(
[0] => Array
(
[m] => Array
(
[id] => 2
[sender_id] => 10
[reciever_id] => 21
[list_id] => 3
[message] => hello sir
[add_date] => 2016-09-25 08:24:38
[is_check] => 0
)
)
[1] => Array
(
[m] => Array
(
[id] => 7
[sender_id] => 10
[reciever_id] => 22
[list_id] => 3
[message] => hmm
[add_date] => 2016-09-27 00:00:00
[is_check] => 0
)
)
)
Now you see in the output in first array sender_id =10 and reciver_id = 21
and list_id = 3
List is created by user whose id is 10. in the output i want to fetch the User data whose user id 21. Remember that when reciever send the message to sender the ids are interchanging. in that case i also want the data of whose user id is 21
Please help me:(
Finallly i find the solution of my own
enter code here
$coreQueryUser = $this->Message->query('
select m.* ,u.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = " '. $data['list_id'] .'"
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
join
users u ON u.id = (CASE WHEN m.sender_id = 10
THEN m.reciever_id
ELSE m.sender_id
END)
');
I am using corequery of mysql in cakephp. I want the records in descending order. This is my table structure
enter code here
$coreQueryUser = $this->Message->query(
"select * from messages where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
order by id desc
"
);
I want last message that belongs to (sender_id and reciver_id and viceversa) that belongs to list id 3
when i run this query i get the following output
<pre>Array
(
[0] => Array
(
[messages] => Array
(
[id] => 1
[sender_id] => 21
[reciever_id] => 10
[list_id] => 3
[message] => hello
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 3
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => hello s
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
but i wnat result like that:
Array
(
[0] => Array
(
[messages] => Array
(
[id] => 2
[sender_id] => 10
[reciever_id] => 21
[list_id] => 3
[message] => hello sir
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 6
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => new
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
Can anyone help me :(
The problem is that your query is against the sql standard because you have several fields in the select list that are neither in the group by list, nor are subject of an aggregate function, such as sum(). MySQL unfortunately allows such invalid queries to run under certain sql mode settings (the default settings of the most recent versions of MySQL would prevent such queries from running).
As MySQL documentation on group by clause says (bolding is mine):
If ONLY_FULL_GROUP_BY is disabled, a MySQL extension to the standard
SQL use of GROUP BY permits the select list, HAVING condition, or
ORDER BY list to refer to nonaggregated columns even if the columns
are not functionally dependent on GROUP BY columns. This causes MySQL
to accept the preceding query. In this case, the server is free to
choose any value from each group, so unless they are the same, the
values chosen are indeterminate, which is probably not what you want.
Furthermore, the selection of values from each group cannot be
influenced by adding an ORDER BY clause. Result set sorting occurs
after values have been chosen, and ORDER BY does not affect which
value within each group the server chooses.
You apparently want the latest record (with max(id) for each group. The proper way is to have a subquery that returns the max(id) per group and in the outer query join back to your main table using the ids to get the value of the other fields:
select m.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
This code working:
SELECT * FROM generate_invoice
WHERE id IN
(
SELECT max(id) as id
FROM generate_invoice
GROUP by pay_id
ORDER by id DESC
)
How to group by DESC order
Try
SELECT * FROM ( SELECT * FROM generate_invoice ORDER BY id DESC ) AS g GROUP BY g.pay_id
OR
Use this code
SELECT m1.*,m2.* FROM generate_invoice m1 LEFT JOIN generate_invoice m2 ON (m1.pay_id = m2.pay_id AND m1.id < m2.id ) order by m1.id desc
Is it possible to make a query that will return one time the value of the second table and set the otherones at NULL. Im stuck with this.
This is my query
return $this->db->get_results(
"
SELECT id, name, type, check_in_days, check_out_days, all_check_out_days, minimum_stay, maximum_stay, all_accom, GROUP_CONCAT( accom_id ) as accom, GROUP_CONCAT( seasons_id ) as seasons, conditional_type
FROM $this->booking_rules_table
LEFT JOIN $this->booking_rules_accom_table
ON $this->booking_rules_table.id = $this->booking_rules_accom_table.rule_id
LEFT JOIN $this->booking_rules_seasons_table
ON $this->booking_rules_table.id = $this->booking_rules_seasons_table.rule_id
GROUP BY id
"
, ARRAY_A );
This returns a array like this
[2] => Array
(
[id] => 54
[name] =>
[type] => minimum_stay
[check_in_days] => 0,1,2,3,4,5,6
[check_out_days] => 0,1,2,3,4,5,6
[all_check_out_days] => 1
[minimum_stay] => 0
[maximum_stay] => 9999
[all_accom] => 0
[accom] => 7,7,7
[seasons] => 1,3,4
[conditional_type] => compulsory
)
You see that [accom] is returning the 7 3 times because the [seasons] has 3 values.
can i fix this with my query or is there an other solution. I dont want to explode it and build the array again.
I have my output array named "Feed Items" (fi):
(
[0] => Array
(
[reg] => 2015-08-03 13:39:00
[id] => fd7ec4107d16b07c1a13cbdd386af8d2cb05ffca
[user_id] => de5fd44db1760b006b1909cf1db11a78b38e455c
[img] => edee88e88cf6e17732e393b5433cfd894662902e
[type] => new_join_ambition
)
)
I generate an array named "RemovedFeedItems" (rfi) that has the following structure:
(
[0] => Array
(
[object_id] => fd7ec4107d16b07c1a13cbdd386af8d2cb05ffca
[postee_id] => de5fd44db1760b006b1909cf1db11a78b38e455c
[type] => new_join_ambition
)
)
My mission is to not get the records that have the following condition:
ri.id == rfi.object_id && ri.user_id == rfi.postee_id && ri.type == rfi.type
The query that I use to get the Feed Items array is:
SELECT
i.registered AS reg,
a.id,
u.id AS user_id,
ui.image_id AS img,
'new_join_ambition' AS type,
FROM x_ambition_invites i
LEFT JOIN x_user u
ON i.to = u.id
LEFT JOIN x_user_images ui
ON u.id = ui.user_id
LEFT JOIN x_ambitions a
ON i.ambition_id = a.id
WHERE a.registered
BETWEEN '2014-07-21 14:25:03' AND '2015-08-05 12:04:41'
AND i.to != '8fa7a1679560876eaf2f8060abd916b692c719dc'
AND i.to IN ('de5fd44db1760b006b1909cf1db11a78b38e455c')
How can I adapt my query to implement the condition to remove the stated record from the FeedItems Array?
Thanks in advance.
Try with an inline table:
SELECT ... FROM ... WHERE (a,b,c) NOT IN (SELECT a1, b1, c1 UNION SELECT a2, b2, c2 UNION SELECT...)
The drawback is that you'll have to build a large query string. :-(