how to find last message from message table and also find users - php

Question

This is my User table
This is my Message table
And tHis is my Listing Table
Now I get successfully get the last message with this query
enter code here
$coreQueryUser = $this->Message->query('
select m.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
');
when i run this query it gives me following output:-
enter code here
<pre>Array
(
[0] => Array
(
[m] => Array
(
[id] => 2
[sender_id] => 10
[reciever_id] => 21
[list_id] => 3
[message] => hello sir
[add_date] => 2016-09-25 08:24:38
[is_check] => 0
)
)
[1] => Array
(
[m] => Array
(
[id] => 7
[sender_id] => 10
[reciever_id] => 22
[list_id] => 3
[message] => hmm
[add_date] => 2016-09-27 00:00:00
[is_check] => 0
)
)
)
Now you see in the output in first array sender_id =10 and reciver_id = 21
and list_id = 3
List is created by user whose id is 10. in the output i want to fetch the User data whose user id 21. Remember that when reciever send the message to sender the ids are interchanging. in that case i also want the data of whose user id is 21
Please help me:(

Answer 1

Finallly i find the solution of my own
enter code here
$coreQueryUser = $this->Message->query('
select m.* ,u.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = " '. $data['list_id'] .'"
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
join
users u ON u.id = (CASE WHEN m.sender_id = 10
THEN m.reciever_id
ELSE m.sender_id
END)
');