regex with php pattern [closed] - php

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<h3 class="r">curl - Google search results with php - Stack Overflow</h3>
data-href value regex pattern please.


Can try using this pattern
$str = '<h3 class="r">curl - Google search results with php - Stack Overflow</h3>';
$re = '/data-href=["\']?([^"\' ]*)["\' ]/is';
preg_match($re, $str, $m);
$attr_value = trim(str_replace('data-href=', '', $m[0]), '"');
echo $attr_value;
Output:
http://stackoverflow.com/questions/18682352/google-search-results-with-php

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Replace string with some condition in PHP [closed]

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I have this string
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
Now the part BYDAY=MO,SU can be in any position like
RRULE:FREQ=WEEKLY;BYDAY=WE,TH;INTERVAL=2;COUNT=5; -> BYDAY=WE
I just want to replace the value of BYDAY=value
let's say I have updated value of BYDAY=FR
I've tried to use str_replace() but the given value of of BYDAY can be anything like MO,TU,WE,TH

Using preg_replace, we can try:
$input = "RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU";
$output = preg_replace("/\bBYDAY=[^;]+/", "BYDAY=FR", $input);
echo $input . "\n" . $output;
This prints:
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=FR

extract data from string and between characters in php [closed]

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I want extract data from string
Example, i have this :
n97(nok)_100(ok)_n41(145)_23(ok)
I want get the 2 string beginning by "n" :
n97(nok) and n41(145)
And after for this 2 string i need get in variable
97 => nok and 41 => 145
can you help me ?
Thanks you

Use regex /n(\d+)\((.+?)\)/ to find patern and array_combine to get result
$str = 'n97(nok)_100(ok)_n41(145)_23(ok)';
if(preg_match_all('/n(\d+)\((.+?)\)/', $str, $m)) {
$res = array_combine($m[1], $m[2]);
}
print_r($res);
demo

delete Persian's Chars of string in php [closed]

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In PHP, i have strings , similar:
"www.mysite.com/fa/doc/report/67571/مطذح کردنو تت";
"www.mysite.com/fa/571/نهتال اهخع";
"www.mysite.com/fa/";
I want if there are Persian's Chars of string, delete them.
Output:
www.mysite.com/fa/doc/report/67571/
www.mysite.com/fa/571/
www.mysite.com/fa/
How can i do this?

You should try this code.
<?php
echo remove_persian("www.mysite.com/fa/doc/report/67571/مطذح کردنو تت");
function remove_persian($text)
{
return preg_replace('#[^a-zA-Z0-9./]#', '', $text);
}
This will output like this:
www.mysite.com/fa/doc/report/67571/

You can use a regex :
$clean = preg_replace('[^a-zA-Z\/\d\s:]', '', $url);

Extracting domain name from strings [closed]

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This is my code:
From: =?Shift_JIS?B?Y2VudGVyQHlhbWJnbGUuaW4ubmV0?= < center#yambgle.in.net >
From: =?x-sjis?B?+O6C6IKogvH47iAg?= < autovbxds#netltf.ladankhda.in.net >
I have the php code for the same, but I would like to have a preg_match code for the same.
Please help.

The following regex should do it
$data = 'From: =?x-sjis?B?+O6C6IKogvH47iAg?= < center#yambgle.in.net >';
if(preg_match('/#([^ ]*) /',$data,$result)){
$domain = $result[1];
echo $domain;
}
Result: yambgle.in.net

Super easy php link construct [closed]

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$out_terms[$term->name] = '' . $text . '';
Please help me check where the code gone wrong,any missing notes etc,as I am really 0 into php

$out_terms[$term->name] = sprintf('%s', $term_link, $text);

Try this (best construct) :
$out_terms[$term->name] = "$text";
or :
$out_terms[$term->name] = ''.$text.'';

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