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I have this string
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
Now the part BYDAY=MO,SU can be in any position like
RRULE:FREQ=WEEKLY;BYDAY=WE,TH;INTERVAL=2;COUNT=5; -> BYDAY=WE
I just want to replace the value of BYDAY=value
let's say I have updated value of BYDAY=FR
I've tried to use str_replace() but the given value of of BYDAY can be anything like MO,TU,WE,TH
Using preg_replace, we can try:
$input = "RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU";
$output = preg_replace("/\bBYDAY=[^;]+/", "BYDAY=FR", $input);
echo $input . "\n" . $output;
This prints:
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=FR
Related
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I want extract data from string
Example, i have this :
n97(nok)_100(ok)_n41(145)_23(ok)
I want get the 2 string beginning by "n" :
n97(nok) and n41(145)
And after for this 2 string i need get in variable
97 => nok and 41 => 145
can you help me ?
Thanks you
Use regex /n(\d+)\((.+?)\)/ to find patern and array_combine to get result
$str = 'n97(nok)_100(ok)_n41(145)_23(ok)';
if(preg_match_all('/n(\d+)\((.+?)\)/', $str, $m)) {
$res = array_combine($m[1], $m[2]);
}
print_r($res);
demo
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I have a array of random generated strings looking like this:
63njpn5u
byrtg1za
ht6wnz39
em1yyrju
2ytoxfxl
n5kaho14
zg92pg4n
gr9e7i01
u3t07ai4
I need a php code that will cycle trough these and output the ones back that contain one number. So in the example above I would've gotten back:
2ytoxfxl
em1yyrju
byrtg1za
I've tried using preg_match_all but I cant figure out how to use this with a array.
What you need is preg_grep:
print_r(preg_grep('/^\D*\d\D*$/', $your_array));
You can count like using string method :
$string = "2ytoxfx3l";
echo $int = strlen(intval(preg_replace('/[^0-9]+/', '', $string), 10));
Group of element:
$string = array( "63njpn5u","byrtg1za","ht6wnz39");
foreach($string as $str){
echo strlen(intval(preg_replace('/[^0-9]+/', '', $str), 10));
}
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I have a function that builds a regex based on an array. The problem is that PHP keeps adding backslashes to some of the characters, and it keeps messing up the regex.
Here is my function:
private static $allowedPermissions = [
/*SV*/
'user_add',
'user_edit',
'user_delete',
'user_view'];
$regexrule = '/';
foreach (self::$allowedPermissions as $allowedPermission) {
$regexrule .= '\b'.$allowedPermission.'\b';
if(end(self::$allowedPermissions) !== $allowedPermission) $regexrule .='|';
}
$regexrule .= "/";
return 'regex:'.$regexrule;
It is adding backslashes where I don't expect them:
regex:\/\\buser_add\\b|\\buser_edit\\b|\\buser_delete\\b|\\buser_view\\b|\\bpatient_add\\b|\\bpatient_edit\\b|\\bpatient_delete\\b|\\bpatient_view\\b|\\bmake_per\\b|\\bmake_per_withconfirmation\\b|\\bconfirm_per\\b|\\beval_per\\b|\\beval_per_withconfirmation\\b|\\bconfirm_per_report\\b\/
Backup screenshot of regex
Is there a workaround?
I found out that returning it in json format was adding the backslashes.
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In PHP, i have strings , similar:
"www.mysite.com/fa/doc/report/67571/مطذح کردنو تت";
"www.mysite.com/fa/571/نهتال اهخع";
"www.mysite.com/fa/";
I want if there are Persian's Chars of string, delete them.
Output:
www.mysite.com/fa/doc/report/67571/
www.mysite.com/fa/571/
www.mysite.com/fa/
How can i do this?
You should try this code.
<?php
echo remove_persian("www.mysite.com/fa/doc/report/67571/مطذح کردنو تت");
function remove_persian($text)
{
return preg_replace('#[^a-zA-Z0-9./]#', '', $text);
}
This will output like this:
www.mysite.com/fa/doc/report/67571/
You can use a regex :
$clean = preg_replace('[^a-zA-Z\/\d\s:]', '', $url);
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$out_terms[$term->name] = '' . $text . '';
Please help me check where the code gone wrong,any missing notes etc,as I am really 0 into php
$out_terms[$term->name] = sprintf('%s', $term_link, $text);
Try this (best construct) :
$out_terms[$term->name] = "$text";
or :
$out_terms[$term->name] = ''.$text.'';