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$out_terms[$term->name] = '' . $text . '';
Please help me check where the code gone wrong,any missing notes etc,as I am really 0 into php
$out_terms[$term->name] = sprintf('%s', $term_link, $text);
Try this (best construct) :
$out_terms[$term->name] = "$text";
or :
$out_terms[$term->name] = ''.$text.'';
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I tried things like
$query = parse_url($url, PHP_URL_QUERY);
// Returns a string if the URL has parameters or NULL if not
if ($query) {
$url .= '&category=1';
} else {
$url .= '?category=1';
echo "hi";
}
?>
but still i cant seem to find the answer.
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I have this string
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
Now the part BYDAY=MO,SU can be in any position like
RRULE:FREQ=WEEKLY;BYDAY=WE,TH;INTERVAL=2;COUNT=5; -> BYDAY=WE
I just want to replace the value of BYDAY=value
let's say I have updated value of BYDAY=FR
I've tried to use str_replace() but the given value of of BYDAY can be anything like MO,TU,WE,TH
Using preg_replace, we can try:
$input = "RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU";
$output = preg_replace("/\bBYDAY=[^;]+/", "BYDAY=FR", $input);
echo $input . "\n" . $output;
This prints:
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=MO,SU
RRULE:FREQ=WEEKLY;COUNT=13;BYDAY=FR
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In PHP, i have strings , similar:
"www.mysite.com/fa/doc/report/67571/مطذح کردنو تت";
"www.mysite.com/fa/571/نهتال اهخع";
"www.mysite.com/fa/";
I want if there are Persian's Chars of string, delete them.
Output:
www.mysite.com/fa/doc/report/67571/
www.mysite.com/fa/571/
www.mysite.com/fa/
How can i do this?
You should try this code.
<?php
echo remove_persian("www.mysite.com/fa/doc/report/67571/مطذح کردنو تت");
function remove_persian($text)
{
return preg_replace('#[^a-zA-Z0-9./]#', '', $text);
}
This will output like this:
www.mysite.com/fa/doc/report/67571/
You can use a regex :
$clean = preg_replace('[^a-zA-Z\/\d\s:]', '', $url);
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This is my code:
From: =?Shift_JIS?B?Y2VudGVyQHlhbWJnbGUuaW4ubmV0?= < center#yambgle.in.net >
From: =?x-sjis?B?+O6C6IKogvH47iAg?= < autovbxds#netltf.ladankhda.in.net >
I have the php code for the same, but I would like to have a preg_match code for the same.
Please help.
The following regex should do it
$data = 'From: =?x-sjis?B?+O6C6IKogvH47iAg?= < center#yambgle.in.net >';
if(preg_match('/#([^ ]*) /',$data,$result)){
$domain = $result[1];
echo $domain;
}
Result: yambgle.in.net
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I don't know exactly how to say this, I'll use an example.
//[$var:Username|n] will print username with n length
$myText = 'The participants are [$var:Username|10], [$var:Username|8], and [$var:Username|6]';
$username = array('Alexandrite', 'Maximillian', 'Angelina');
$result = someFunction('[$var:Username|n]', $username, $myText);
echo $result;
//The participants are Alexandrit, Maximill, and Angeli
Any idea how to do this? Maybe using preg_replace?
I'm interested to know why you would even need to do this. Regardless:
preg_replace_callback('/\[\$var:Username\|(\d+)\]/', function ($match)
use (&$count, $username
) {
return substr($username[$count++], 0, $match[1]);
}, $myText);