How to do auto complete for same class - php

The textarea will show when I click add row. The textarea has item in autosuggestion on keyup. My problem is the first one shows autocomplete. anothers are not working
<textarea id="name" class="name" name="name"></textarea><ul></ul>
<textarea id="name" class="name" name="name"></textarea><ul></ul>
<textarea id="name" class="name" name="name"></textarea><ul></ul>
<script type="text/javascript">
$(document).ready(function(){
$(".name").keyup(function(){
var name = $(this).val();
$.ajax({
url:"ajax.php",
type:"POST",
data:{name:name},
success:function(res)
{
$(".name + ul").append("<li class=item>"+res+"</li>");
}
});
});
$("ul").on("click", "li", function(){
var item = $(this).text();
$(".name").val(item);
$("ul li").remove();
});
});
</script>

Here is an example that does not need any id associated with the text areas.
<textarea class="name" name="name1"></textarea><ul></ul>
<textarea class="name" name="name2"></textarea><ul></ul>
<textarea class="name" name="name3"></textarea><ul></ul>
<script type="text/javascript">
$(document).ready(function(){
$(".name").keyup(function(){
var field = $(this);
var name = field.val();
$.ajax({
url:"ajax.php",
type:"POST",
data:{name:name},
success:function(res)
{
field.next("ul").append("<li class=item>" + res + "</li>");
}
});
});
$("ul").on("click", "li", function(){
var li = $(this);
var item = li.text();
li.parent('ul').empty().prev('.name').val(item);
});
});
</script>

try
var name = $(this).val();
var data = name + "&Sessid=" + Math.random();
$.ajax({
url:"ajax.php",
type:"POST",
data:data,
success:function(res)
{
$(".name + ul").append("<li class=item>"+res+"</li>");
}
});
});

First of all, change id and name fields for your textarea. It's not good idea to give same id name to your elements.
<textarea id="name1" class="name" name="name1"></textarea><ul></ul>
<textarea id="name2" class="name" name="name2"></textarea><ul></ul>
<textarea id="name3" class="name" name="name3"></textarea><ul></ul>
Now, get id name by this:
var which_id = $(this).attr('id');
And use which_id variable to your ajax response.
$.ajax({
url:"ajax.php",
type:"POST",
data:{name:name},
success:function(res)
{
$("#"+which_id+" + ul").append("<li class=item>"+res+"</li>");
}
});

Related

jquery event method to get input

I've used jquery to get an "id" as a value for an input according to a dropdown value. Now the problem is, I want to use the 'id' to insert value to some other inputs. I don't know which event method to be used. For testing, I used the keyup method to check if the code works, when I manually type in a number, it works. So the problem is with the event method I choose. Please give me some suggestions.
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
var data_String = 'sid=' + sid;
$.get('search1.php', data_String, function(result) {
$.each(result, function(){
$('#can').val(this.c_id);
});
});
});
//display other information
$('#can').change(function() {
var id = $(this).val();
var data_String1 = 'id=' + id;
$.get('search.php', data_String1, function(result1) {
$.each(result1, function(){
$('#morning_rate').val(this.cMorning);
$('#night_rate').val(this.cNight);
$('#ot_rate').val(this.clientOt);
});
});
});
});
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>
<input type="hidden" name="can" id="can" class="form-control" >
You can trigger the keyup() event from the id code, this will then work through a manual or jQuery edit,
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha512-894YE6QWD5I59HgZOGReFYm4dnWc1Qt5NtvYSaNcOP+u1T9qYdvdihz0PPSiiqn/+/3e7Jo4EaG7TubfWGUrMQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
$('#can').val(sid).keyup();
});
});
//display other information
$(document).on('keyup', '#can', function() {
console.log($(this).val())
});
</script>
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>
<input type="text" name="can" id="can" class="form-control" />
If you are going to hide the second input then I might suggest using a function instead without an input,
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha512-894YE6QWD5I59HgZOGReFYm4dnWc1Qt5NtvYSaNcOP+u1T9qYdvdihz0PPSiiqn/+/3e7Jo4EaG7TubfWGUrMQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
display_info(sid)
});
});
//display other information
function display_info(value) {
console.log(value)
};
</script>
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>

$(this).data("value") not passing value using $.post

My form
<div class="replymsg">
<form class="mainform" action="reply.php" method="POST">
<textarea class="replytext" ></textarea>
<button data-value="<?php echo $id; ?>"
class="replybutton">Submit</button>
</form>
</div>
$id comes from a MYSQL database. The following "test" code gives me the id of the reply form using Jquery:
<script>
$(".replybutton").click(function(){
alert($(this).data("value"));
});
</script>
Value of commentid :id is not passed when I use "actual" code for the website as follows (reply:replytext ... sends message is working):
<script>
$(document).ready(function(){
$(".replybutton").click(function(){
var id = $(this).data("value");
var replytext = $(".replytext").val();
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
Any ideas,any help is appreciated?
Most probably you should stop the form to submit if you are using ajax because a buttons default behavior is to submit the form:
<script>
$(document).ready(function(){
$(".replybutton").click(function(e){
e.preventDefault(); //<---------------stops the form submission here
var id = $(this).data("value");
var replytext = $(".replytext").val();
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
or add a type to the button:
<button type='button' data-value="<?php echo $id; ?>" class="replybutton">Submit</button>
//------^^^^^^^^^^^^
another way is to use .submit() event:
<script>
$(document).ready(function(){
$(".mainform").submit(function(e){ //<-----pass the event here
e.preventDefault(); //<---------------still you need this
var id = $(this).find('.replybutton').data("value"); // find the elements
var replytext = $(this).find(".replytext").val(); // and here.
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
and in this case you don't need to have a type to your button, but it's good to have it.
Submitting form with AJAX
In form
<div class="replymsg">
<form class="mainform" action="" method=" ">
<textarea class="replytext" ></textarea>
<input type="text" value="<?php echo $id; ?>" name="comment_id" id="comment_id" style="display: none"> <!-- this contain the ID-->
<input type="submit" class="replybutton" id="replybutton" value="Submit">
</form>
</div>
use AJAX
<script>
$(function(){
$( "#replybutton" ).click(function(event)
{
event.preventDefault();
var comment_id = $("#comment_id").val();
var replytext = $(".replytext").val();
$.ajax(
{
type:"post",
url: "./reply.php",
data:{ id:comment_id, reply:replytext,},
success:function($data)
{
$("#result").html(data);
}
});
});
});
</script>
$(document).ready(function(){
$(".replybutton").click(function(e){
e.preventDefault();
var id = $(this).data("value");
var replytext = $(this).prev().val();
$.post("reply.php",{ commentid: id, reply: replytext
},function(data){
$("#result").html(data);
});
});
});
Thanks for the help,I figured it out,my problem was sending Id and replytext in a comment/reply system when clicking replybutton. Working code above.

ajax: not getting value

i'm not getting company_name value to show_house_members.php.
but event_name can get over there. is there any error in this ajax code? i'm just a beginner in this.
$(document).ready(function() {
$("#add_mem").click(function() {
$(this).after('<div class="loader1"><img src="imgdropdown/loading.gif" alt="loading subcategory" /></div>');
var datastring = "&company_name="+$('#company_name').val()+"&event_name="+$('#event_name').val();
$.ajax({
url: 'show_house_members.php',
data: datastring,
type: 'get',
success: function(data) {
console.log(data);
$('.loader1').hide();
$("#house_members").after(data);
}
});
});
});
and here is my form
<p><label>company name</label>
<select name="company_name" id="company_name">
<?php
include("config/dbconfig.php");
$res=mysql_query("select *from tbl_company");
while($row=mysql_fetch_array($res))
{
echo "<option value=".$row[0].">".$row[1]."</option>";
}
?>
</select></p>
<!--event names dynamically added here by using jquery ajax -->
<p><label>Event name</label>
<select name="event_name" id="event_name">
</select></p>
<img title='add_house_members' src='images/button.png'/><form action="add_house_entry.php" method="GET|POST" enctype="multipart/form-data" name="f3" class="smart-green" style="width: 450px; height:290px;padding-top: 50px;padding-left: 20px;" >
<h1>Enter House details </h1>
Try to remove the & before company_name in your datastring value:
var datastring = "&company_name="+$('#company_name').val()+"&event_name="+$('#event_name').val();
// ------------- ^ remove this
you can use serialize() method to get the datastring like below
var datastring = $('#form').serialize();
it will generate datastring automatically!
Try using
data : { datastring : datastring },
Instead of
data : datastring,
Please refer to http://api.jquery.com/jquery.ajax/

Get a value from an input field

I am using the code below using jQuery and AJAX, to update my database.
Deletion works perfectly, but the edit function is not working. How is it possible to get the value from each input field?
<ol class="update">
<?php
$ss = mysql_query ("SELECT * FROM users_channels WHERE u_id='$uid'");
while ($chann = mysql_fetch_assoc($ss)) {
echo'
<li>
<input name="channelName" type="text" id="channelName" style="float:left; width:300px; border:1px solid #CCC;" value="'.$chann['channel_name'].'" />
<span id="rcolor">Delete</span>
<span id="gcolor">Save</span>
</li>';
}
?>
</ol>
Javascript code:
$(document).ready(function() {
$(function() {
$(".save_button").click(function() {
var id = $(this).attr("id");
var cvalue = $(this).attr("cvalue");
var dataStringe = 'id=' + id + '&cvalue=' + cvalue;
var parent = $(this).parent();
alert(cvalue);
$.ajax({
type: "POST",
url: "update_channel.php",
data: dataStringe,
cache: false,
beforeSend: function() {
parent.animate({'backgroundColor':'#fb6c6c'}, 300).animate({ opacity: 0.35 }, "slow");
},
success: function() {
//parent.slideUp('slow', function() {$(this).remove();});
}
});
return false;
});
});
});
Add this in your java script function
$(document).ready(function() {
$(function() {
$(".save_button").click(function() {
var inputVal=$("#channelName").val();
//rest of your code
return false;
});
});
});
you'll get the value of an input field(as per your question) in inputVal variable.
In order to get the values of all input fields,give them a common class name instead of giving style there like this
<input class="myInput" type="text" value="red" id="one"/>
<input class="myInput" type="text" value="France" id="two" />
and then in your javascript add this
var inputValues= {};
$(".myInput").each(function() {
inputValues[$(this).attr("id")] = $(this).val();
});
alert(inputValues.one); // "red"
you'll get the value of all input fields in inputValues variable
can u be more explicit? What do you need to get? Value of all input elements? if yes .. use $('input[name=example]').each(function(){})
this will get all values of all input with specified name
I guess what you're trying to do is submit the value of your input field as cvalue? To do this, the best approach would be:
$(".save_button").click(function() {
var id = $(this).attr("id");
var parent = $(this).parent();
var cvalue = parent.find('input').val(); // this gets the value of the <input> field
var dataStringe = 'id='+ id + '&cvalue='+ cvalue;
// the rest of your code...
});

Page refresh instead of Ajax Load without

On form submit i want to load a div with an updated list of a mysql table. I'am sending the form variables across to a php and posting them into a mysql table. the same page displays the full table data. I want to load the data into the same div tag as the form. So it appears that the information is being loaded above the form.
My Javascript
$("#formSubmit").submit(function(){
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
My form -
<div id="2">
<p>Add a Comment</p>
<form id="formSubmit" method="POST">
<div>
<input type="hidden" name="hidden" id="hidden" value="2">
<label for="name">Your Name</label>
<input type="text" name="name" id="name" />
<label for="body">Comment Body</label>
<textarea name="comment" id="comment" cols="20" rows="5"></textarea>
<input type="submit" id="comment" class="button" value="Submit" />
</form>
</div>
All it is doing is refreshing the page and not loading the information in to div 2 :S
thanks for your help
You need to prevent the form from redirecting the page using the preventDefault method on the event object:
$("#formSubmit").submit(function(e){ // add the event object as an argument to your function
e.preventDefault(); // right here
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
});
add a return false to the end to stop the form from submitting. or if you want to be more elegant use the preventDefault(); method. personally for something as simple as this though i just stick with return false;
$("#formSubmit").submit(function(e){ // add the event object as an argument to your function
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
return false;//right here
});

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