My form
<div class="replymsg">
<form class="mainform" action="reply.php" method="POST">
<textarea class="replytext" ></textarea>
<button data-value="<?php echo $id; ?>"
class="replybutton">Submit</button>
</form>
</div>
$id comes from a MYSQL database. The following "test" code gives me the id of the reply form using Jquery:
<script>
$(".replybutton").click(function(){
alert($(this).data("value"));
});
</script>
Value of commentid :id is not passed when I use "actual" code for the website as follows (reply:replytext ... sends message is working):
<script>
$(document).ready(function(){
$(".replybutton").click(function(){
var id = $(this).data("value");
var replytext = $(".replytext").val();
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
Any ideas,any help is appreciated?
Most probably you should stop the form to submit if you are using ajax because a buttons default behavior is to submit the form:
<script>
$(document).ready(function(){
$(".replybutton").click(function(e){
e.preventDefault(); //<---------------stops the form submission here
var id = $(this).data("value");
var replytext = $(".replytext").val();
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
or add a type to the button:
<button type='button' data-value="<?php echo $id; ?>" class="replybutton">Submit</button>
//------^^^^^^^^^^^^
another way is to use .submit() event:
<script>
$(document).ready(function(){
$(".mainform").submit(function(e){ //<-----pass the event here
e.preventDefault(); //<---------------still you need this
var id = $(this).find('.replybutton').data("value"); // find the elements
var replytext = $(this).find(".replytext").val(); // and here.
$.post("reply.php",{ commentid: id, reply: replytext },function(data){
$("#result").html(data);
});
});
});
</script>
and in this case you don't need to have a type to your button, but it's good to have it.
Submitting form with AJAX
In form
<div class="replymsg">
<form class="mainform" action="" method=" ">
<textarea class="replytext" ></textarea>
<input type="text" value="<?php echo $id; ?>" name="comment_id" id="comment_id" style="display: none"> <!-- this contain the ID-->
<input type="submit" class="replybutton" id="replybutton" value="Submit">
</form>
</div>
use AJAX
<script>
$(function(){
$( "#replybutton" ).click(function(event)
{
event.preventDefault();
var comment_id = $("#comment_id").val();
var replytext = $(".replytext").val();
$.ajax(
{
type:"post",
url: "./reply.php",
data:{ id:comment_id, reply:replytext,},
success:function($data)
{
$("#result").html(data);
}
});
});
});
</script>
$(document).ready(function(){
$(".replybutton").click(function(e){
e.preventDefault();
var id = $(this).data("value");
var replytext = $(this).prev().val();
$.post("reply.php",{ commentid: id, reply: replytext
},function(data){
$("#result").html(data);
});
});
});
Thanks for the help,I figured it out,my problem was sending Id and replytext in a comment/reply system when clicking replybutton. Working code above.
Related
I've used jquery to get an "id" as a value for an input according to a dropdown value. Now the problem is, I want to use the 'id' to insert value to some other inputs. I don't know which event method to be used. For testing, I used the keyup method to check if the code works, when I manually type in a number, it works. So the problem is with the event method I choose. Please give me some suggestions.
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
var data_String = 'sid=' + sid;
$.get('search1.php', data_String, function(result) {
$.each(result, function(){
$('#can').val(this.c_id);
});
});
});
//display other information
$('#can').change(function() {
var id = $(this).val();
var data_String1 = 'id=' + id;
$.get('search.php', data_String1, function(result1) {
$.each(result1, function(){
$('#morning_rate').val(this.cMorning);
$('#night_rate').val(this.cNight);
$('#ot_rate').val(this.clientOt);
});
});
});
});
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>
<input type="hidden" name="can" id="can" class="form-control" >
You can trigger the keyup() event from the id code, this will then work through a manual or jQuery edit,
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha512-894YE6QWD5I59HgZOGReFYm4dnWc1Qt5NtvYSaNcOP+u1T9qYdvdihz0PPSiiqn/+/3e7Jo4EaG7TubfWGUrMQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
$('#can').val(sid).keyup();
});
});
//display other information
$(document).on('keyup', '#can', function() {
console.log($(this).val())
});
</script>
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>
<input type="text" name="can" id="can" class="form-control" />
If you are going to hide the second input then I might suggest using a function instead without an input,
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha512-894YE6QWD5I59HgZOGReFYm4dnWc1Qt5NtvYSaNcOP+u1T9qYdvdihz0PPSiiqn/+/3e7Jo4EaG7TubfWGUrMQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
//Get id
$(document).ready(function() {
$('#salary_eid').change(function() {
var sid = $(this).val();
display_info(sid)
});
});
//display other information
function display_info(value) {
console.log(value)
};
</script>
<label>Name</label>
<input type="text" name="salary_eid" />
<select id="salary_eid">
<option>opt1</option>
<option>opt2</option>
</select>
I have this code:
<div id = "askpost" class="row">
<input type="hidden" name="askid" id="askid" value="<?php echo $askpostid ?>">
</div>
and i want to get the id of the hidden input but when tried using this:
<script>
$(document).ready(function() {
$('input[name="iaskcomment"]').on('keyup', function(e){
e.preventDefault();
var comment = $(this).val();
var ask_id = $(this).siblings('.askid').val();
alert(ask_id); <----undefined
});
});
</script>
i even used this code :
var sid = $(this).closest("div#askpost").find("input[type='hidden']").val();
but also i get "undefined". what i wanted to do is to get the id of $askpostid
direct use $("#askid").val(). No need to use anything like siblings()
Example:-
$(document).ready(function() {
$('input[name="iaskcomment"]').on('keyup', function(e){
e.preventDefault();
var comment = $(this).val();
var ask_id = $('#askid').val();
alert(ask_id);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id = "askpost" class="row">
<input name = "iaskcomment"><br>
<input type="hidden" name="askid" id="askid" value="2">
</div>
Note:- Your code doesn't have any input with name iaskcomment. I have added in my example to just show you how it will work.So check at your end.
I'm trying to detect which was button was pressed with jQuery and then server-side do different things depending on the outcome.
The jQuery works fine (although I may have gone about it in a long- handed way) but I can't figure out why in my code whichever button I press I get the same response from php: "Add button detected". I hope someone can tell me what I've got wrong?
The jQuery
$(document).ready(function() {
$(".btn_add").on("click", function() { //If add btn pressed
var id = this.id;
var url = "process_ajax4.php?btn=" + this.id;
var formdata = $('.myForm').serialize();
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
$(".btn_remove").on("click", function() { //If remove btn pressed
var id = this.id;
var url = "process_ajax4.php?btn=" + this.id;
var formdata = $('.myForm').serialize();
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
});
The Php
<?php
$btn=$_POST["btn"]; //Other posted variables removed for simplicity
if($btn="btn_add"){
echo "<h1>Add button detected</h1>";
//Do stuff
}
elseif($btn="btn_remove"){
echo "<h1>Remove button detected</h1>";
//Do other stuff
}
?>
The html Form
<td>
<form id=\ "myForm\" class=\ "myForm\" action=\ "\" method=\ "post\" enctype=\ "multipart/form-data\">
<input type=\ "hidden\" name=\ "user_id\" value=". $collab_userid." />
<input type=\ "hidden\" name=\ "id\" value=".$upload_id." />
<button type=\ "submit\" id=\ "btn_remove\" class=\ "btn_remove\" name=\ "btn_remove\">Remove</button>
<button type=\ "submit\" id=\ "btn_add\" class=\ "btn_add\" name=\ "btn_add\">Approve</button>
</form>
</td>
You should add the pressed button to your formdata, otherwise the click couldn't be detected.
$(document).ready(function() {
$(".btn_add").on("click", function() { //If add btn pressed
var id = this.id;
var url = "process_ajax4.php?btn=" + this.id;
var formdata = $('.myForm').serialize();
formdata += "&btn=btn_add"; // added the btn
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
$(".btn_remove").on("click", function() { //If remove btn pressed
var id = this.id;
var url = "process_ajax4.php?btn=" + this.id;
var formdata = $('.myForm').serialize();
formdata += "&btn=btn_remove"; // added the btn
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
});
Change php code as follows
<?php
$btn=$_POST["btn"]; //Other posted variables removed for simplicity
if ($btn=="btn_add") {
echo "<h1>Add button detected</h1>";
//Do stuff
} elseif ($btn=="btn_remove"){
echo "<h1>Remove button detected</h1>";
//Do other stuff
}
?>
You need not have two separate function for jquery button handling. Also you can remove the button type="submit" from your code since you are detecting the click event
$(document).ready(function() {
$("button").on("click", function() { //If add btn pressed
var id = this.id;
var url = "process_ajax4.php?btn=" + this.id;
console.log(url);
var formdata = $('.myForm').serialize();
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<td>
<form id="myForm" class="myForm" action="\" method= "post" enctype="multipart/form-data">
<input type="hidden" name="user_id" value=". $collab_userid." />
<input type="hidden" name="id" value=".$upload_id." />
<button type="submit" id="btn_remove" class="btn_remove" name= "btn_remove">Remove</button>
<button id="btn_add" class= "btn_add" name="btn_add">Approve</button>
</form>
</td>
You can use the parse_url() and parse_str() for getting the query string in php. In order to use $btn=$_POST["btn"]; tbn attribute must be passed as a form data, query parameters wont will be available through this method
<?php
$parts = parse_url($url);
parse_str($parts['query'], $query);
$btn = $query['btn'];
if($btn=="btn_add"){
echo "<h1>Add button detected</h1>";
//Do stuff
}
elseif($btn=="btn_remove"){
echo "<h1>Remove button detected</h1>";
//Do other stuff
}
?>
Your code works just make var url = process_ajax4.php that will fix your problem.in PHP use == instead of =, also add e.preventDefault() to your button clicks to prevent the form from being submitted with action='url'
$(document).ready(function() {
$(".btn_add").on("click", function(e) { //If add btn pressed
e.preventDefault();
var id = this.id;
var url = "process_ajax4.php";
var formdata = $('.myForm').serialize();
formdata += "&btn=btn_add"; // added the btn
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
$(".btn_remove").on("click", function(e) { //If remove btn pressed
e.preventDefault();
var id = this.id;
var url = "process_ajax4.php";
var formdata = $('.myForm').serialize();
formdata += "&btn=btn_remove"; // added the btn
$.post(url, formdata,
function(data) {
$("#results").html(data); //Response
});
});
});
i think your code looks ok.
i think in php you cannot compare string by =
you may need to change it to strcmp(strA,strB)==0 in order to ensure the input parameter is add button or remove button.
You don't actually need the jQuery code at all. Since both btn_remove and btn_add are submit buttons, you can check which of the buttons where used to submit the form by using:
if(isset($_POST["btn_remove"])) {
//Remove button was pressed.
}
the problem is that i am unable to insert data in my database without reloading
i have tested it without the note_sql.js and my note_sql.php works fine but there seems to be a problem in my js file if some body could point me in the right direction it would be wonderful
Index.php
<form id="noteform" action="note_sql.php" method="POST">
<input type="text" name="note"></input>
<input id="sub" type="submit" value="Save Note" />
</form>
<span id="result_note"><span>
<script type ="text/javascript" src="jquery/note_sql.js"></script>
note_sql.js
$("#sub").click(function(){
var data = $("#noteform: input").serializeArray();
$.post($("#noteform").attr("action"),data,function(info){$("result_note").html(info); });
clearInput();
});
$("#noteform").submit(function(){
return false;
});
function clearInput(){
$("#noteform :input").each(function(){
$(this).val('');
});
}
Use Jquery Ajax the working code is given below :
please add ID to Note Form Element :
<pre>
<script>
$(document).ready(function () {
$("#sub").click(function () {
var name = $("#note").val();
var message = $("#message").val();
$.ajax({
type: "post",
url: "note_sql.php",
data: "name=" + name,
success: function (data) {
alert(data);
}
});
});
});
</script>
</pre>
I have two submit buttons in html "form":
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript" src="ajax.js"></script>
<input type="text" name="field1" id="field1" />
<input type="text" name="field2" id="field2" />
<form id="form1" action="" method ="post">
<input type="submit" value="check data" id="checkdata" name="checkdata" /><p>
<input type="submit" value="download" id="download" name="download" /><p>
which I have to get the query results of the button clicks from two separate "php" codes in the "same page" by ajax call. I have the script for the first button but I have trouble to assign the query for the second button which has to be referred to another php code:
$(document).ready(function(){
$("#checkdata").click(function(){
var field1 = $("#field1").val();
var field2 = $("#field2").val();
var datastr ='&field1=' + field1 + '&field2=' + field2;
$("#response").css("display", "block");
$("#response").html("setting parameters... ");
$("#response").fadeIn("slow");
setTimeout("send('"+datastr+"')",2000);
return false;
});
});
function send(datastr){
$.ajax({
type: "POST",
url: "some_php_code.php",
data: datastr,
cache: false,
success: function(html){
$("#response").fadeIn("slow");
$("#response").html(html);
setTimeout('$("#response").fadeOut("slow")',2000);
}
});
}
could you please give me some hint on this or is there any other method to do that?
(I have checked all the relevant questions that you might refer me to.
like this question which is related to only one ajax call
jQuery submit ajax form with 2 submit buttons)
Just add the following function.
$(document).ready(function(){
$("#download").click(function(){
var field1 = $("#field1").val();
var field2 = $("#field2").val();
var datastr ='&field1=' + field1 + '&field2=' + field2;
$("#response").css("display", "block");
$("#response").html("setting parameters... ");
$("#response").fadeIn("slow");
setTimeout("send('"+datastr+"')",2000);
return false;
});
});
Or better:
$(document).ready(function(){
$("#checkdata").click(function(){
SendData();
});
$("#download").click(function(){
SendData();
});
});
function SendData() {
var field1 = $("#field1").val();
var field2 = $("#field2").val();
var datastr ='&field1=' + field1 + '&field2=' + field2;
$("#response").css("display", "block");
$("#response").html("setting parameters... ");
$("#response").fadeIn("slow");
setTimeout("send('"+datastr+"')",2000);
return false
}
hth