Page refresh instead of Ajax Load without - php

Question

On form submit i want to load a div with an updated list of a mysql table. I'am sending the form variables across to a php and posting them into a mysql table. the same page displays the full table data. I want to load the data into the same div tag as the form. So it appears that the information is being loaded above the form.
My Javascript
$("#formSubmit").submit(function(){
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
My form -
<div id="2">
<p>Add a Comment</p>
<form id="formSubmit" method="POST">
<div>
<input type="hidden" name="hidden" id="hidden" value="2">
<label for="name">Your Name</label>
<input type="text" name="name" id="name" />
<label for="body">Comment Body</label>
<textarea name="comment" id="comment" cols="20" rows="5"></textarea>
<input type="submit" id="comment" class="button" value="Submit" />
</form>
</div>
All it is doing is refreshing the page and not loading the information in to div 2 :S
thanks for your help

Answer 1

You need to prevent the form from redirecting the page using the preventDefault method on the event object:
$("#formSubmit").submit(function(e){ // add the event object as an argument to your function
e.preventDefault(); // right here
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
});

Answer 2

add a return false to the end to stop the form from submitting. or if you want to be more elegant use the preventDefault(); method. personally for something as simple as this though i just stick with return false;
$("#formSubmit").submit(function(e){ // add the event object as an argument to your function
var name = $("input#name").val();
var comment = $("input#comment").val();
var filmnumber = $("input#hidden").val();
var dataString = 'name='+ name + '&comment=' + comment + '&filmnumber=' + filmnumber;
$.ajax({
type: "POST",
url: "comment.php",
data: dataString,
success: function() {
$('#2').load('comment.php');
}
});
return false;//right here
});