I have two tables: users and threads. When a thread is created, it will store the user_id in the table as author_id. I want to display the thread name and the username of its author with the same query. I am currently using two querys as shown:
$query2 = mysql_query("SELECT author_id FROM threads WHERE id = $threadId") or die(mysql_error());
$result2 = mysql_fetch_array($query2);
$author_id = $result2['author_id'];
$query3 = mysql_query("SELECT username FROM users WHERE id = $author_id") or die(mysql_error());
$result3 = mysql_fetch_array($query3);
$author_name = $result3['username'];
<?php
$sql = '
SELECT t.name, u.username
FROM threads t
JOIN users u ON t.author_id = u.id
WHERE t.id = ' . (int)$threadId . '
';
list($thread_name, $author_name) = mysql_fetch_row(mysql_query($sql));
P.S. Mysql php extension is deprecated.
Try this query:
SELECT username
FROM users
WHERE id = (SELECT author_id
FROM threads
WHERE id = $threadId
LIMIT 1)
Note: Limit 1 is not mandatory as id is unique.
Related
I need to get 3 tables's values , from first I need to get aff_id where v_id = 5 , from second I need to get user id where aff_id = first's aff_id , and from third I need to get username , email , id where id = second's aff_id . I can't write correct mysql query to get data , please , help me to get it . Here is my wrong code
SELECT * FROM wp_vendor_affiliates WHERE vendor_id = 21 LEFT JOIN wp_affiliate_wp_affiliates
SELECT wp_vendor_affiliates.affiliate_id ,
wp_affiliate_wp_affiliates.user_id
FROM wp_vendor_affiliates
INNER JOIN wp_affiliate_wp_affiliates INNER JOIN
Please , hetp me , and correct my query . Thanks fot helping and for support
Use this code
$id1 = 5;
$query1 = "SELECT * FROM table1 WHERE v_id='{$id1}'";
$result1 = mysqli_query($con,$query1);
$row1 = mysqli_fetch_array($result1);
$id2 = $row1['aff_id'];
$query2 = "SELECT * FROM table2 WHERE aff_id='{$id2}'";
$result2 = mysqli_query($con,$query2);
$row2 = mysqli_fetch_array($result2);
$id3 = $row2['aff_id'];
$query3 = "SELECT * FROM table3 WHERE id='{$id3}'";
$result3 = mysqli_query($con,$query3);
$row3 = mysqli_fetch_array($result3);
$id2 = $row3['aff_id'];
Here $con is the connection to your database
$con= mysqli_connect("localhost","root","","data_base");
I used here connection to the localhost. which you'd have to change most certainly. It's a bit long but basic
I have a forum where users can post questions and can upvote and downvote.
I want to get the upvote and downvote of each post.
What i did previously was do that in 3 sets queries.
$data = mysqli_query($con,"select * from posts");
while($row = mysqli_fetch_assoc($data)){
$pid = $row['post_id'];
$up = mysqli_fetch_assoc(mysqli_query("SELECT COUNT(*) as c FROM up WHERE post_id = $pid"))['c'];
$down = mysqli_fetch_assoc(mysqli_query("SELECT COUNT(*) as c FROM down WHERE post_id = $pid"))['c'];
}
Can anyone show me how can i do these things in one single query because if a get a lot of posts in 1st query then there will be lots of queries to do.
You can use subqueries and put everything in the first query.
This could be a good start :
$data = mysqli_query($con, "select posts.*, " .
"(SELECT COUNT(*) FROM up WHERE post_id = posts.post_id) as totalUp, " .
"(SELECT COUNT(*) FROM down WHERE post_id = posts.post_id) as totalDown " .
"from posts");
while($row = mysqli_fetch_assoc($data)){
// ...
}
you can use corelated subquery for this where upvotes
and downvotes are counted based on the post id
SELECT p.*,
( select count(*) from up where post_id = p.post_id ) as upVotesCount,
( select count(*) from down where post_id = p.post_id ) as downVotesCount,
FROM posts p
I'm trying to display a list of status updates from artists that a logged in user is following.
So far I have this:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
}
But i'm not sure how to loop through and display the returned status updates?
This isn't a strong point of mine, so any pointers would be greatly appreciated!
What prevented you from doing similar to what you'd already done for the first query? Something like follows:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
while($status_result_row = mysqli_fetch_assoc($status_result)) {
echo $status_result_row['mycol']; // This is where you know better than us
}
}
Or if those two tables artist_likes and status_updates have artist_id in common then you could just use one query with a join. (But don't know if you are asking for that).
Just for avoiding multiple query, you can use one query like this:
SELECT l.*, s.*
from artist_likes l, status_updates s
WHERE
l.artist_id = s.artist_id and
l.user_id = '1'
or
SELECT l.*, s.*
from artist_likes l
JOIN status_updates s on (l.artist_id = s.artist_id)
WHERE
l.user_id = '1'
I am getting a bunch of id's from the database - for each id, I want to do a mysql query to get the relating row in another table. This works fine although I also need to get similiar data for the logged in user. With the mysql query I am using - it duplicates the logged in user data according to how many id's it originally pulled. This makes sense although isnt what I want. I dont want duplicate data for the logged in user and I need the data to come from one query so I can order things with the timestamp.
<?php
mysql_select_db($database_runner, $runner);
$query_friends_status = "SELECT DISTINCT rel2 FROM friends WHERE rel1 = '" . $_SESSION ['logged_in_user'] . "'";
$friends_status = mysql_query($query_friends_status, $runner) or die(mysql_error());
$totalRows_friends_status = mysql_num_rows($friends_status);
while($row_friends_status = mysql_fetch_assoc($friends_status))
{
$friends_id = $row_friends_status['rel2'];
mysql_select_db($database_runner, $runner);
$query_activity = "SELECT * FROM activity WHERE user_id = '$friends_id' OR user_id = '" . $_SESSION['logged_in_user'] . "' ORDER BY `timestamp` DESC LIMIT 15";
$activity = mysql_query($query_activity, $runner) or die(mysql_error());
$totalRows_activity = mysql_num_rows($activity);
echo "stuff here";
}
?>
You can try this single query and see if it does what you need
$userID = $_SESSION['logged_in_user'];
"SELECT * FROM activity WHERE user_id IN (
SELECT DISTINCT rel2 FROM friends
WHERE rel1 = '$userID')
OR user_id = '$userID' ORDER BY `timestamp` DESC LIMIT 15";
You probably want something like this:
$user = $_SESSION['logged_in_user'];
$query_friends_status = "SELECT * FROM friends, activity WHERE activity.user_id = friends.rel2 AND rel1 = '$user' ORDER BY `timestamp` DESC LIMIT 15";
You can replace * with the fields you want but remember to put the table name before the field name like:
table_name.field_name
I hope this helps.
<?php
require_once "connect.php";
$connect = #new mysqli($host, $db_user, $db_password, $db_name);
$result = $connect->query("SELECT p.name, p.user, p.pass, p.pass_date_change,p.email, p.pass_date_email, d.domain_name, d.domain_price, d.domain_end, d.serwer, d.staff, d.positioning, d.media FROM domains d LEFT JOIN persons p
ON d.id_person = p.id AND d.next_staff_id_person != p.id");
if($result->num_rows > 1)
{
while($row = $result->fetch_assoc())
{
echo '<td class="box_small_admin" data-column="Imię i nazwisko"><div class="box_admin">'.$row["name"].'</div></td>';
echo '<td class="box_small_admin" data-column="Domena"><div class="box_admin">'.$row["domain_name"].'</div></td>';
}}
?>
How can I grab the count value from the query MySQL query below using PHP.
Here is My MySQL code.
$dbc = mysqli_query($mysqli,"SELECT COUNT(*) FROM((SELECT users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.user_id = users.user_id
WHERE users_friends.user_id = 1
AND users_friends.friendship_status = '1')
UNION
(SELECT users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.friend_id = users.user_id
WHERE users_friends.friend_id = 1
AND users_friends.friendship_status = '1')) as friends");
using SQL_CALC_FOUND_ROWS should simplify things:
$dbc = mysqli_query($mysqli,"SELECT SQL_CALC_FOUND_ROWS users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.user_id = users.user_id
WHERE users_friends.user_id = 1
AND users_friends.friendship_status = '1'
");
then afterwards do
$rs = mysqli_query($mysqli, "SELECT FOUND_ROWS()"));
$rec = $rs->fetch_array();
$count = $rec[0];
This method will return the number of records that match the query, ignoring any LIMIT statement, whereas using $rs->num_rows will only give you the number of records actually returned. Depends which one you want.
if ($result = mysqli_query($link, "SELECT Name FROM City LIMIT 10")) {
printf("Select returned %d rows.\n", mysqli_num_rows($result));
/* free result set */
mysqli_free_result($result);
http://us.php.net/manual/en/mysqli.query.php
Assuming that you are correctly connected to the MySQL server and your query are executed correctly, you can use the following code:
$values = mysql_fetch_row($dbc);
$count = $values[0];
Your query should look like SELECT COUNT(*) as numThings FROM xxx
The numThings is what you will reference in PHP:
$result = mysql_query("SELECT COUNT(*) as `numThings` FROM xxx");
$row = mysql_fetch_assoc($result);
$count = $row['numThings'];