How can I check only file name not extension is exists - php

Question

How can I check only file name not extension like jpeg, jpg, doc, xls. and then copy its complete name like example.jpeg or example.doc
and if possible can we store its upper two parent directory like
if example.jpeg stored in
main_dir/second_dir/example.jpeg
so I want to store this path in php variable.
I know I can use glob()
$result = glob ("./uploads/filename.*");
and check $result value.
But I want to store complete file name and possible its two parent directory path.
Below is my code
$filename = '/www/test1/'. $file . '*' ;
if (count(glob($filename)) > 0) {
echo "The file $filename exists";
} else {
echo "The file $filename does not exist";
}
Edit
Updated query as per luweiqi solution
foreach(glob("/uploads/".$productnumber."/". $productnumber."b.*", GLOB_NOSORT) as $file) {
echo "Filename: " . $file . "<br />";
$image2 = "/uploads/".$productnumber."/".$file;
}
Last letter of image varies like a to f . so can you make some correction in it.
I want to check image is exist on uploads/productnumber/productnumber (a/b/c/d/e/f).jpg or png or jpeg etc. and store that file name in php variable.

Answer 1

You can use file_exists() function.
$pngFile = '/path/to/foo.png';
$docFile = '/path/to/foo.doc';
// Returns TRUE if the file or directory specified by filename exists; FALSE otherwise.
if (file_exists($filename) || file_exists($docFile)) {
echo "The file $filename exists";
} else {
echo "The file $filename does not exist";
}
OR
Use glob function
$files=[];
$result = glob ("/path/to/foo.*");
foreach ($result as $file) {
echo "$file size " . filesize($file) . "\n";
$files[] = $file;
}
echo '<pre>'; print_r($files);

Answer 2

You can use:
<?php
foreach(glob("../directory/*{a,b,c,e,f}.*", GLOB_BRACE) as $file) {
echo "Filename: " . $file . "<br />";
}
?>
This code would get the file name and echo it, you can change it accordingly if you want to assign it to a variable.