I am having trouble googling this, so please bear with me.
I have a code example that is about uploading files and there is the assignment of a temporary file to an array like this:
$postparam['file1'] = '#../res/example.pdf';
I would like to know what the effect of the # character is. I know about error suppression with # but i am confused about the use inside the string.
Thanks.
I found the answer: The example uses cURL and that is why the # is required as a prefix to the filename.
#filename
This will make curl load data from the given file (including any newlines), URL-encode that data and pass it on in the POST.
Source
Related
I want to extract variable lengths of information from a jpeg-file using PHP, but it is not exif-data.
If I open the jpeg with a simple text editor, I can see that the wanted informations are at the end of the file and seperated by \00.
Like this:
\00DATA\00DATA00DATA\00DATA\000\00DATA
Now if I use PHP's file_get_contents() to load the file into a string, the dividers \00 are gone and other symbols show up.
Like so:
ÿëžDATADATADATADATADATA ÿÙ
Could somebody please eplain:
Why do the \00 dividers vanish?
How to get the informations using PHP?
EDIT
The question is solved, but for those seeking a smarter solution, here is the file I try to obtain the DATA parts from: https://www.dropbox.com/s/5cwnlh2kadvi6f7/test-img.jpg?dl=0 (yes I know its corrupted)
Use instead $data = exif_read_data("PATH/some.jpg") it will give you all headers data about image, you can check its manual here - http://php.net/manual/en/function.exif-read-data.php
I came up with a solution on my own. May not be pretty, but works for me.
Using urlencode(file_get_contents()) I was able to retrieve the \00 parts as %00.
So now it reads like this:
%00DATA%00DATA%00DATA%00DATA%000%00DATA
I can split the string at the %00 parts.
I am going to accept this answer, once SO lets me do so and nobody comes up with a better solution.
I have some flash swf files where i hard coded some variables to use with action script like
p='mydomain.com'
I want to replace the value of mydomain.com with a given string using a php script . I know this can be done using Binary operation, but it failed for me . Can anyone help me to find a solution using php 's built in functions only (No third party language) .
Thanks
You can have PHP pass variables to the swf file using GET variables.
http://www.kirupa.com/developer/actionscript/flash_php_mysql.htm
The magic line is this:
loadVariables("http://localhost/test.php", this, "GET");
EDIT:
After considering the options, you may want to store strings that are likely to change in an XML file and read the values at runtime.
http://www.kirupa.com/web/xml/XMLwithFlash3.htm
http://www.kirupa.com/developer/flashcs3/using_xml_as3_pg1.htm
I'm using cakephp. In my users model I allow ppl to upload a pic. Once it uploads ok I save the url of the pic to $this->data['User']['image_url'] and save it. To upload I use the kind advice given here: http://www.jamesfairhurst.co.uk/posts/view/uploading_files_and_images_with_cakephp
After the upload is done I want to resize the photo so I have a thumbnail. I'm using the advice here: http://bakery.cakephp.org/articles/Perkster/2008/04/12/image-resizer-crop
All is ok, except for the value in $this->data['User']['image_url'] looks like files/photos/userimage.jpg
The upload script I'm using seems to be expecting the urls with backslashes rather than forward ones coz when I run it I get the error
getimagesize(C:\xampp\htdocs\MyNewSite\app\webroot\img\files/photos\$image_name) [function.getimagesize]: failed to open stream:
What can I do to fix this?
The slashes are not the problem, the $image_name is. It's impossible to tell without seeing the code, but you probably are using single quotes when assigning the file name, leading to the variable not getting parsed properly.
Windows accepts both directory separators \ and /, thus the problem must be somewhere else. This is taken from the error message
C:\xampp\htdocs\MyNewSite\app\webroot\img\files/photos\$image_name
I assume, that there is no file $image_name ;) It seems, that you didnt let PHP evaluate the variables when calling getimagesize()
I have a weird problem with $_GET method. I have a php code like this:
$fopen("files/" . $_GET['file'], "r");
When i write file path parameter my self It's run good but when I get the file name from $_GET method it shows me some error like the path is wrong.
What's wrong with it ?
Is there any special encoding for $_GET method to decode it to the right string style. I tried urldecode but it wasn't make any change.
Number one rule is to sanitize your input. Using $_GET like that is just asking for trouble.
Do the right thing. Put the $_GET value into a variable, verify that it is valid input THEN try to open the file.
As said at the bottom:
Try to dump the $_GET with print, print_r or var_dump
Try to sanitize the input
Remove the leading $ in your code (**$**fopen)
Test if file exists in the specified directory with if(is_file($path)
Isn't the problem caused by file extencion or permissions?
There could be more. It also depends on system you use (Win, Unix, Mac..).
Don't EVER use user input without validation, especially not for opening files on the host computer! I cannot overstate just how dangerous this is. What if someone entered a GET string with the value '../../../../../etc/password' into your application?
i have a download.php file which gets and opens files. i have a problem is that files were named using '&' in the file name so i get file not found when trying to access files with '&' in them.
example: download.phpf=one_&_another.pdf
in the download.php file i use get to the the file name ($_GET['f']) the example above throws the error file not found if i change the file name to one_and_another.pdf it works.
Yes renaming would be nice if there wasnt a whole lot of these files named this way.
I need to know how to ignore the fact that '&' doesnt mean im about to pass another var in php.
If you can control the query strings, you need to URL encode the ampersands so they look like this:
download.php?f=one_%26_another.pdf
Then look for $_GET['f'] as usual. Otherwise a literal ampersand & would break $_GET into
{ 'f' => 'one_', '_another.pdf' => '' }
You will probably just need to urlencode() the & properly in your links:
download.php?f=one_%26_another.pdf
Rule number 1 for accepting user input: do not trust it.
Refer to this StackOverflow answer for your solution.