I want to extract variable lengths of information from a jpeg-file using PHP, but it is not exif-data.
If I open the jpeg with a simple text editor, I can see that the wanted informations are at the end of the file and seperated by \00.
Like this:
\00DATA\00DATA00DATA\00DATA\000\00DATA
Now if I use PHP's file_get_contents() to load the file into a string, the dividers \00 are gone and other symbols show up.
Like so:
ÿëžDATADATADATADATADATA ÿÙ
Could somebody please eplain:
Why do the \00 dividers vanish?
How to get the informations using PHP?
EDIT
The question is solved, but for those seeking a smarter solution, here is the file I try to obtain the DATA parts from: https://www.dropbox.com/s/5cwnlh2kadvi6f7/test-img.jpg?dl=0 (yes I know its corrupted)
Use instead $data = exif_read_data("PATH/some.jpg") it will give you all headers data about image, you can check its manual here - http://php.net/manual/en/function.exif-read-data.php
I came up with a solution on my own. May not be pretty, but works for me.
Using urlencode(file_get_contents()) I was able to retrieve the \00 parts as %00.
So now it reads like this:
%00DATA%00DATA%00DATA%00DATA%000%00DATA
I can split the string at the %00 parts.
I am going to accept this answer, once SO lets me do so and nobody comes up with a better solution.
Related
yeah, I know, the title is kind of confusing, but no better title came to my mind.
Here is my problem:
I want to use a link in my application, which would look like this:
localhost/index?jumpto=some_folder/somescript.php?someparam1=1234&someparam2=4321
The problem is that &someparam2 is meant to hang on the second $_GET-Param.
It would be like this:
localhost/index?jumpto=some_folder/somescript.php?someparam1=1234&someparam2=4321
Instead, PHP interprets that &someparam2 hangs on the first $_GET-Param.
localhost/index?jumpto=some_folder/somescript.php?someparam1=1234&someparam2=4321
Does anyone know a solution for this?
I already tried
localhost/index?jumpto='some_folder/somescript.php?someparam1=1234&someparam2=4321'
but of course that didn't work.
I hope you can understand my problem.
Thank you for your time.
You will need to URL encode your string some_folder/somescript.php?someparam1=1234 so that php will not parse & in the query string as a param separator.
use urlencode("some_folder/somescript.php?someparam1=1234");
I have a website where users can upload files to share with others. But first I need to verify them.
Lately someone uploaded a .php file with the following commands:
‰PNG
<?php
eval(gzinflate(base64_decode("very large strings of characters")));
?>
I figured it might be harmful, so I didnt open it.
Does anyone have any idea what it does?
nobody can tell you, just do
<?php echo gzinflate(base64_decode("very large strings of characters")) ?>
to see what it would do....
edit: well now that you've posted the whole string i decoded it and pasted it here
Seems like the attacker's code was base64 encoded and gzipped.
So first the code is decoded from base64 encoding, and then it is unzipped basically until a string of code.
And then eval is called on the resulting string, which will execute the code that has been decoded and unzipped.
But without seeing what code gets generated, it is hard to say what it will do when the code is run.
I decoded the encoded text. Using the following approach
(I guess writing to file was a bad idea now that I think of it. Mainly if you're on Windows. I guess it is a bit safer on Linux with the execute bit turned off. So I was kind of lucky in this case!)
<?php
$test = gzinflate(base64_decode("encoded_text"));
$myFile = "testFile.txt";
$fh = fopen($myFile, 'w');
fwrite($fh, $test);
fclose($fh);
I wrote the output to file just in case there was some random html or javascript that could infect my computer if I just echoed it to my browser. That may be why you got an anti-virus warning.
I'm not sure what it does yet.
Just skimming through the code, which is like 4,750 lines of code, it seems like it sets up Basic Auth. And then there's a lot of database functions and some basic html interface. This in PHP. There's also some perl too. Near the end.
Basically what it seems to do is this: Every page where that image is displayed it will output parts of that code and execute it along with your code, and it will try to get input data, or try to find session data and or database values.
Then other parts of the code basically create an admin interface when the url is visited like this: url?admin=1, which brings up a Basic Auth authentication. And then there is an simple interface phpmyadmin like interface where the user can try out different queries and gather out metadata about your db. Probably other stuff run to exec, etc too.
I could be wrong, but that's the gist I get from going through the code.
The code is fine the only thing you need to take care is the long string that is encrypted
< ?php eval(gzinflate(base64_decode("very large strings of characters")));
for the reference of this kind of the statement you can refer to
http://php.net/manual/en/function.gzinflate.php
I need to read certain parts from a complex PDF. I searched the net and some say FPDF is good, but it cant read PDF, it can only write. Is there a lib out there which allows to get certain content of a given PDF?
If not, whats a good way to read certain parts of a given PDF?
Thanks!
I see two solutions here:
converting your PDF file into something else before: text, html.
using a library to do so and bad news here, most of them are written in Java.
https://whatisprymas.wordpress.com/2010/04/28/lucene-how-to-index-pdf-files/
What about that ?
http://www.phpclasses.org/package/702-PHP-Searches-pdf-documents-for-text.html
ps: I don't test this class, just read the description.
$result = pdf2text ('sample.pdf');
echo "<pre>$result</pre>";
How to get “clean” text :source code pdf2text
http://webcheatsheet.com/php/reading_clean_text_from_pdf.php
I want to create a PHP script that grabs the content of a website. So let's say it grabs all the source code for that website and I say which lines of code I need.
Is there a function in PHP that allows you too do this or is it impossible?
Disclaimer: I'm not going to use this for any illegal purposes at all and not asking you too write any code, just tell me if its possible and if you can how I'd go about doing it. Also I'm just asking in general, not for any specific reason. Thanks! :)
file('http://the.url.com') returns an array of lines from a url.
so for the 24th line do this:
$lines = file('http://www.whatever.com');
echo $lines[23];
This sounds like a horrible idea, but here we go:
Use file_get_contents() to get the file. You cannot get the source if the web server first processes it, so you may need to use an extension like .txt. Unless you password protect the file, obviously anybody can get it.
Use explode() with the \n delimiter to split the source code into lines.
Use array_slice() to get the lines you need.
eval() the code.
Note: if you just want the HTML output, then ignore the bit about the source in step 1 and obviously you can skip the whole eval() thing.
So i am using this wordpress function to get the users image
the_author_meta('author_image', the_author_ID()
and it will either return something.jpg or something.png or something.gif if it finds an image otherwise it will return an integer like 2330. How would i do a preg_match or some conditional to let me know if an image is present. I was thinking of doing a preg_match to see if there is a period in the name but if someone has a better idea that would be great..
Simpler:
if (is_numeric($author_image)){
// this is presumably not a file
}
If all you want to do is check the extension of the file to see if it ends with something (ex. '.jpg', '.png', etc.) you can use the solution presented here:
startsWith() and endsWith() functions in PHP
I do not have familiarity with the library that you are using, but there really should be a better way to detect if the file is actually an image (some sort of meta data). Maybe reading the documentation will help?
EDIT: I misread the part about the function returning integers if an image is not found. The is_numeric() solution is probably enough, but I'll leave my answer up to give you options (for example, if you want to distinguish between image types).