Find MIN -values but maintain row values in PHP mysqli - php

Question

I have a table with 32 rows, with pairwise rows containing same "name-values", but with different raspberry-values (respectively "one" and "two".)
I want to extract each row with a unique name and the lowest average_distance - giving me 16 rows, and for that I am using this query:
SelectFinally();
function SelectFinally (){
$con = connectToDB();
$sql = "SELECT name,MIN(average_distance),raspberry From average GROUP BY name";
$result= mysqli_query($con,$sql);
$num_rows = mysqli_num_rows($result);
echo "number of rows" .$num_rows ."<br />";
while($row=mysqli_fetch_assoc($result)) {
extract($row);
$name = $row['name'];
$distance = $row['MIN(average_distance)']; //."<br />";
$raspberry = $row['raspberry']; //."<br />";
echo "select inside selectFinally name: " .$name ." distance: " .$distance ." raspberry " .$raspberry ."<br />";
}
}
This query gives me the lowest values of the average_distance allright, BUT it messes up my raspberry values. e.g. blå_bil should have a raspberry value of "two", hence it has the lowest average_distance - value.
I can not seem to get it right. Would somebody please help me to get it right?

Answer 1

try:
SELECT a.name, a.raspberry
FROM average a
INNER JOIN
(
SELECT name, MIN(average_distance) as avg_dist
FROM average
GROUP BY name
) a2 ON a.name = a2.name AND a.average_distance = a2.avg_dist
Instead of SELECT name,MIN(average_distance),raspberry From average GROUP BY name

Answer 2

thanks Nishant Matha
It worked - I simply needed to add te raspberry in my first select. Now it adds the average_distance to the output.
$sql = "SELECT a.name, a.average_distance, a.raspberry
from average a
INNER JOIN
(
select name,MIN(average_distance) AS avg_dist,raspberry
FROM average
GROUP BY name
)
a2 ON a.name=a2.name AND a.average_distance = a2.avg_dist ";